OʻZBEKISTON RESPUBLIKASI AXBOROT
TEXNOLOGIYALARI VA KOMMUNIKATSIYALARINI
RIVOJLANTIRISH VAZIRLIGI
MUHAMMAD AL-XORAZMIY NOMIDAGI TOSHKENT
AXBOROT TEXNOLOGIYALARI UNIVERSITETI
Radio va Mobil aloqa fakulteti 810-22 guruh talabasining
Dasturlash I fanidan
1-topshirig’i
Mavzu: ALGORITMLASH VA DASTURLASHNING ASOSIY
TUSHUNCHALARI
Bajardi: Boltayev Sarvar
Tekshirdi: Begulov O’tkir
TOSHKENT 2022
1- LABARATORIYA TOPSHIRIQLARI
1.
𝑌=
𝑠𝑖𝑛3 𝑐 ∗ 𝑐𝑜𝑠 3 𝑎
5𝑠𝑖𝑛𝑑 𝑏
#include <iostream>
#include <math.h>
using namespace std ;
int main()
{
float Y, cos, sin, a, b, c, d;
cout << "a=" ; cin >> a ;
cout << "b=" ; cin >> b ;
cout << "c=" ; cin >> c ;
cout << "d=" ; cin >> d ;
Y=(pow(sin*c,3)*pow(cos*a,3))/(5*pow(sin*b,d));
cout << "y=" << Y << endl ;
return 0;
}
A=9.5, B=1.365, C=6.6, D=3
𝑤 = |𝑐𝑜𝑠 𝑥 − 𝑐𝑜𝑠 𝑦
4
2
|1+2𝑠𝑖𝑛 𝑦
𝑧2 𝑧3 𝑧4
(1+𝑧+ + + )
2
3
4
x=0.4∗ 104 ,
y=-0.875,
z=-0.475∗ 10−3
w=1.9873
#include <iostream>
#include <math.h>
using namespace std;
int main()
{
float x,y,z,w;
cout<<"x ni kiriting "; cin>>x;
cout<<"y ni kiriting "; cin>>y;
cout<<"z ni kiriting "; cin>>z;
w=pow(abs(cos(x)-cos(y)),(1+2*sin(y)*sin(y)))*(1+z+z*z/2+z*z*z/3+z*z*z*z/4);
cout<<w;
return 0;
}
𝑌=
𝑎2 +𝑏2
4
{
𝑐
+ √𝑎2 + 𝑥, 𝑎𝑔𝑎𝑟 𝑥 ≥ 0
𝑏𝑢 𝑦𝑒𝑟𝑑𝑎 𝑥 =
𝑠𝑖𝑛𝑥+𝑏
, 𝑎𝑔𝑎𝑟 𝑥 < 0
𝑎−𝑏
𝑎2 −𝑏2
𝑐 2 −𝑏
;+
#include <iostream>
#include <math.h>
using namespace std ;
int main()
{
float y, a, b, c, x;
x=(pow(a,2)-pow(b,2))/(pow(c,2)-b);
cout << "a=" ; cin >> a ;
cout << "b=" ; cin >> b ;
cout << "c=" ; cin >> c ;
if (x<0){
y=(sin(x)+b)/(a-b) ;
}
else{
y=((pow(a,2)+pow(b,2))/c)+pow((pow(a,2)+x),1/2);
}
cout << "y=" << y << endl ;
return 0;
}
1
2
a=1
b=2
c=3
a=2
b=3
c=7
Y=-1.090
Y=-2.170