15:16 20/3/25 Quiz: Midterm Test Midterm Test Started: Mar 20 at 3:15pm Quiz Instructions Question 1 1 pts The independent variable of interest in an ANOVA procedure is called a partition. factor. response. treatment. An experimental design where the experimental units are randomly assigned to the treatments is known as _____ design. Question 2 1 pts factor block random factor completely randomized randomized treatment Question 3 1 pts The cumulative probability distribution shows the probability: of all possible events occurring. that a random variable is less than or equal to a particular value. that a random variable takes on a particular value given that another event has happened. of two or more events occurring at once. https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 1/21 15:16 20/3/25 Quiz: Midterm Test Question 4 1 pts The expected value of a discrete random variable: is the outcome that is most likely to occur. is computed as a weighted average of the possible outcome of that random variable, where the weights are the probabilities of that outcome. equals the population median. can be found by determining the 50% value in the c.d.f. Question 5 1 pts Let Y be a random variable. Then var(Y) equals: . E . E E . . Question 6 1 pts For a normal distribution, the skewness and kurtosis measures are as follows: 0 and 3 1.96 and 4 0 and 0 1 and 2 Question 7 1 pts The conditional expectation of Y given X, E(Y https://canvas.instructure.com/courses/10915497/quizzes/21422656/take , is calculated as follows: 2/21 15:16 20/3/25 Quiz: Midterm Test Pr(X = xi) E Question 8 1 pts Two random variables X and Y are independently distributed if all of the following conditions hold, with the exception of: E(Y) = E[E(Y )]. knowing the value of one of the variables provides no information about the other. Pr(Y = y if the conditional distribution of Y given X equals the marginal distribution of Y. = x) = Pr(Y = y). Question 9 1 pts The correlation between X and Y: is given by corr(X, Y) = . is the covariance squared. can be calculated by dividing the covariance between X and Y by the product of the two standard deviations. cannot be negative since variances are always positive. Question 10 1 pts Two variables are uncorrelated in all of the cases below, with the exception of: being independent. https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 3/21 15:16 20/3/25 Quiz: Midterm Test having a zero covariance. E(Y ) = 0. Question 11 1 pts Assume that Y is normally distributed N(μ, σ2). Moving from the mean (μ) 1.96 standard deviations to the left and 1.96 standard deviations to the right, then the area under the normal p.d.f. is: 0.95 0.67 0.05 Question 12 1 pts 0.33 The Student t distribution is: always well approximated by the standard normal distribution. the distribution of a random variable with a chi-squared distribution with m degrees of freedom, divided by m. the distribution of the ratio of a standard normal random variable, divided by the square root of an independently distributed chi-squared random variable with m degrees of freedom divided by m. the distribution of the sum of m squared independent standard normal random variables. Question 13 1 pts When there are ∞ degrees of freedom, the t∞ distribution: has a bell shape similar to that of the normal distribution, but with "fatter" tails. equals the standard normal distribution. https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 4/21 15:16 20/3/25 Quiz: Midterm Test can no longer be calculated. equals the distribution. Question 14 1 pts The sample average is a random variable and: has a probability distribution that is the same as for the Y1,..., Yn i.i.d. variables. is a single number and as a result cannot have a distribution. has a probability distribution called the standard normal distribution. has a probability distribution called its sampling distribution. Question 15 1 pts Consistency for the sample average can be defined as follows, with the exception of: μY . the probability of being in the range μY ± c becomes arbitrarily close to one as n increases for any constant c > 0. has the smallest variance of all estimators. converges in probability to μY. Question 16 1 pts The mean and variance of a Bernoulli random variable are given as: np and np(1-p) p and (1- p) cannot be calculated p and https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 5/21 15:16 20/3/25 Quiz: Midterm Test Question 17 1 pts Consider the following linear transformation of a random variable y = where μx is the mean of x and σx is the standard deviation. Then the expected value and the standard deviation of Y are given as: 0 and 1 1 and 1 Cannot be computed because Y is not a linear function of X and σx Question 18 1 pts Let Y be the total number (outcomes) of rolling a pair of dice, where Pr(Y=2)=Pr(Y=12)=1/36, etc. The following statements are true, EXCEPT: = 5.83 Pr(Y≤ 7)= 0.5 E(Y) = 7 skewness = 0 Question 19 1 pts Bayes' Rule states: Pr( Y = y ∣ X = x) = Pr( Y = y ∣ X = x) = Pr( Y = y ∣ X = x) = Pr( X = x ∣ Y = y) Pr( Y = y ∣ X = x) = Question 20 1 pts https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 6/21 15:16 20/3/25 Quiz: Midterm Test In a completely randomized design involving four treatments, the following information is provided. Treatment 1 Treatment 2 Treatment 3 Treatment 4 Sample Size 55 18 15 20 Sample Mean 35 38 42 50 The overall mean (the grand mean) for all treatments is 39.25. 40.76. 40.0. Question 21 1 pts 41.25. An ANOVA procedure is used for data obtained from five populations. Five samples, each comprised of 25 observations, were taken from the five populations. The numerator and denominator (respectively) degrees of freedom for the critical value of F are 4 and 124. 5 and 25. 4 and 120. 4 and 25. Question 22 1 pts The critical F value with 8 numerator and 29 denominator degrees of freedom at α = 0.05 is 3.64. 3.33. https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 7/21 15:16 20/3/25 Quiz: Midterm Test 2.28. 3.20. Question 23 1 pts Consider the following information. SSTR = 6,750 H0: μ1 =μ2 =μ3 =μ4 = μ5 SSE = 8,000 Ha: At least one mean is different The mean square due to treatments (MSTR) equals 1,350. 500. 400. 1,687.5. Question 24 1 pts Consider the following information with n = 5. SSTR = 6,750 H0: μ1 = μ2 = μ3 = μ4 = μ5 SSE = 8,000 Ha: At least one mean is different The null hypothesis is to be tested at the 5% level of significance. The p–value is greater than 0.10. between 0.025 and 0.05. less than 0.01. https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 8/21 15:16 20/3/25 Quiz: Midterm Test between 0.01 and 0.025. Question 25 1 pts Consider the following ANOVA table. Source Sum Degrees Mean of Variation of Squares of Freedom Square Between Treatments 2,073.6 4 Between Blocks 6,000 5 1,200 Error 20 288 Total 29 F The null hypothesis for this ANOVA problem is μ1 = μ2 = μ3 = μ4. μ1 = μ2 = ... = μ20. μ1 = μ2 = μ3 = μ4 = μ5. μ1 = μ2 = μ3 = μ4 = μ5 = μ6. Question 26 1 pts Consider the following ANOVA table. Source Sum Degrees Mean of Variation of Squares of Freedom Square Between Treatments 2,073.6 4 6,000 5 Between Blocks https://canvas.instructure.com/courses/10915497/quizzes/21422656/take F 1,200 9/21 15:16 20/3/25 Quiz: Midterm Test Error 20 Total 29 288 The mean square due to treatments equals 518.4. 1,200. 8,294.4. 288. Question 27 1 pts Assume that the relationship between test scores and the student-teacher ratio can be modeled as a linear function with an intercept of 698.9 and a slope of (-2.28). A decrease in the student-teacher ratio by 2 will: reduce test scores by 2.56 on average result in a test score of 698.9 reduce test scores by 2.28 on average reduce test scores by 4.56 for every school district Question 28 1 pts Consider the following ANOVA table. Source Sum Degrees Mean of Variation of Squares of Freedom Square Between Treatments 2,073.6 4 6,000 5 Between Blocks https://canvas.instructure.com/courses/10915497/quizzes/21422656/take F 1,200 10/21 15:16 20/3/25 Quiz: Midterm Test Error 20 Total 29 288 The null hypothesis is to be tested at the 1% level of significance. The null hypothesis should not be rejected. be revised. not be tested. be rejected. Question 29 1 pts To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments. You are given the results below. Treatment Observations A 20 30 25 33 B 22 26 20 28 C 40 30 28 22 The null hypothesis for this ANOVA problem is μ1 = μ2 = ... = μ12. μ1 = μ2. μ 1 = μ 2 = μ 3. https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 11/21 15:16 20/3/25 Quiz: Midterm Test μ1 = μ2 = μ3 = μ4. Question 30 1 pts To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assigned to the 3 treatments. You are given the results below. Treatment Observations A 20 30 25 33 B 22 26 20 28 C 40 30 28 22 The mean square due to error (MSE) equals 34. 5.86. 36. 1.872. Question 31 1 pts In a completely randomized experimental design involving five treatments, 13 observations were recorded for each of the five treatments (a total of 65 observations). Also, the design provided the following information. SSTR = 300 (Sum of Squares Due to Treatments) SST = 800 (Total Sum of Squares) The sum of squares due to error (SSE) is 500. https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 12/21 15:16 20/3/25 Quiz: Midterm Test 300. 1,600. 1,100. Question 32 1 pts In a completely randomized experimental design involving five treatments, 13 observations were recorded for each of the five treatments (a total of 65 observations). Also, the design provided the following information. SSTR = 300 (Sum of Squares Due to Treatments) SST = 800 (Total Sum of Squares) The number of degrees of freedom corresponding to between-treatments is 59. 60. 4. 5. Question 33 1 pts An important application of the chi-square distribution is testing for goodness of fit. testing for the independence of two categorical variables. All of these alternatives are correct. making inferences about a single population variance. Question 34 1 pts https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 13/21 15:16 20/3/25 Quiz: Midterm Test Consider the following regression line: = 698.9 – 2.28 × STR. You are told that the t-statistic on the slope coefficient is 4.38. What is the standard error of the slope coefficient? 4.38 -1.96 0.52 1.96 Question 35 1 pts Consider the estimated equation from your textbook = 698.9 - 2.28 STR, R2 = 0.051, SER = 18.6 (10.4)(0.52) 4.38. The t-statistic for the slope is approximately: 67.20. 0.52. 1.76. Question 36 1 pts In a completely randomized experimental design involving five treatments, 13 observations were recorded for each of the five treatments (a total of 65 observations). Also, the design provided the following information. SSTR = 300 (Sum of Squares Due to Treatments) SST = 800 (Total Sum of Squares) The mean square due to treatments (MSTR) is 10. https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 14/21 15:16 20/3/25 Quiz: Midterm Test 12. 75. 60. Question 37 1 pts Part of an ANOVA table is shown below. Source of Sum of Degrees Mean Variation Squares of Freedom Square Between Treatments 64 Within Treatments (Error) 8 2 100 Total F The number of degrees of freedom corresponding to between-treatments is 18. 2. 3. 4. Question 38 1 pts If you had a two regressor regression model, then omitting one variable which is relevant: will have no effect on the coefficient of the included variable if the correlation between the excluded and the included variable is negative. makes the sum of the product between the included variable and the residuals different from 0. https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 15/21 15:16 20/3/25 Quiz: Midterm Test can result in a negative value for the coefficient of the included variable, even though the coefficient will have a significant positive effect on Y if the omitted variable were included. will always bias the coefficient of the included variable upwards. Question 39 1 pts In multiple regression, the R2 increases whenever a regressor is: added unless there is heteroskedasticity. added. added unless the coefficient on the added regressor is exactly zero. greater than 1.96 in absolute value. β0 + β1x1 + + β2x2 , the interpretation of β1 is: Question 40 1 pts In the linear multiple regression model with two independent variables, where E(Yi ∣ X1i = x1, X2i = x2) = is the predicted difference in Y between two observations for a change of X1i by β1, controlling for X2i. is the predicted difference in Y between two observations with a unit difference in X2 holding X1 constant. the same as in the simple regression model when X1i was the only regressor. is the predicted difference in Y between two observations with a unit difference in X1, holding X2 constant. Question 41 1 pts A control variable: indicates that it is under the control of the econometrician has a coefficient that always has a causal interpretation, even if it is not of primary interest is a regressor to hold constant factors that, if included, could lead the estimated causal effect of interest to suffer from omitted variable bias https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 16/21 15:16 20/3/25 Quiz: Midterm Test should be excluded from the multiple regression since its coefficient is not a parameter of reduce heteroskedasticity in the error term Question 42 1 pts Part of an ANOVA table is shown below. Source of Sum of Degrees Mean Variation Squares of Freedom Square Between Treatments 64 Within Treatments (Error) Total F 8 2 100 36. The mean square due to treatments (MSTR) is 16. 15. 64. Question 43 1 pts The process of using the same or similar experimental units for all treatments is called replicating. partitioning. factoring. blocking. https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 17/21 15:16 20/3/25 Quiz: Midterm Test Question 44 1 pts A completely randomized design is useful when the experimental units are heterogeneous. homogeneous. clustered. stratified. Question 45 1 pts A statistical test conducted to determine whether to reject or not reject a hypothesized probability distribution for a population is known as a _____ test. comparison probability goodness of fit normality Question 46 1 pts Provide an appropriate response. A researcher wants to know if the time spent in prison for a particular type of crime was the same for men and women. A random sample of men and women were each asked to give the length of sentence received. The data, in years, are listed below. Use the Wilcoxon rank sum test to find W, the sum of the ranks for the smaller sample, to test the claim that there is no difference in the sentence received by each gender. 135.5 155.5 https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 18/21 15:16 20/3/25 Quiz: Midterm Test 115.5 173.5 125.5 Question 47 1 pts Provide an appropriate response. A local school district is concerned about the number of school days missed by its teachers due to illness. A random sample of 10 teachers is selected. The numbers of days absent in one year is listed below. An incentive program is offered in an attempt to decrease the number of days absent. The number of days absent in one year after the incentive program is listed below. Use the Wilcoxon signedrank test to find the test statistic ws to test the claim that the incentive program cuts down on the number of days missed by teachers. Use α = 0.05. The difference is defined as the After Incentive-Before Incentive. -3.16 7 -2 1 2 Question 48 1 pts Provide an appropriate response. A weight-lifting coach claims that a weight-lifter can increase strength by taking vitamin E. To test the theory, the coach randomly selects 9 athletes and gives them a strength test using a bench press. The results are listed below. Thirty days later, after regular training supplemented by vitamin E, they are tested again. The new results are listed below. Use the Wilcoxon signed-rank test to find the critical value to test the claim that the vitamin E supplement is effective in increasing the athletes' strength. Use https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 19/21 15:16 20/3/25 Quiz: Midterm Test The difference is defined as the Before-After. 4.5 5 2 6 31.5 Question 49 1 pts You want to test whether the following sample of 30 observations follows a normal distribution. The mean of the sample 2 3 5 5 7 8 8 9 9 10 11 11 12 12 12 12 13 13 13 14 15 15 15 16 16 17 17 18 18 19 equals 11.83 and the standard deviation equals 4.53. The p-value is less than 0.005. greater than 0.1. between 0.05 and 0.1. between 0.025 and 0.05. Question 50 1 pts https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 20/21 15:16 20/3/25 Quiz: Midterm Test The test statistic for goodness of fit has a chi-square distribution with k – 1 degrees of freedom provided that the expected frequencies for all categories are 5 or more. k or more. 2k. 10 or more. Submit Quiz Quiz saved at 3:16pm https://canvas.instructure.com/courses/10915497/quizzes/21422656/take 21/21
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