End time 16:54
1/1P
Q. 1
SITUATION. A rectangular footing 2.5 m. wide along the x-axis and 3 m. long parallel to the y-axis
supports a concentrically located column 0.6 m x 0.6 m in area.
Given: Footing ultimate loads.
Axial load, Pu = 1500 kN Concrete, fc’ = 20.7 MPa
Moment about the y-axis, Muy = 180 kN.m.
Steel, Fy = 415 MPa
Effective depth of footing = 350 mm
Find the max. punching shear stress (MPa) due to
the axial load only.
1.17
1.33
1.0
0.88
Score 1/1P
Q. 2
SITUATION. A rectangular footing 2.5 m. wide along the x-axis and 3 m. long parallel to the y-axis
supports a concentrically located column 0.6 m x 0.6 m in area.
Given: Footing ultimate loads.
Axial load, Pu = 1500 kN Concrete, fc’ = 20.7 MPa
Moment about the y-axis, Muy = 180 kN.m.
Steel, Fy = 415 MPa
Effective depth of footing = 350 mm
What is the maximum wide beam shear stress (MPa)
due to the given footing loads?
0/1P
0.65
0.42
0.56
0.37
Score 0/1P
1/1P
Q. 3
SITUATION. A rectangular footing 2.5 m. wide along the x-axis and 3 m. long parallel to the y-axis
supports a concentrically located column 0.6 m x 0.6 m in area.
Given: Footing ultimate loads.
Axial load, Pu = 1500 kN Concrete, fc’ = 20.7 MPa
Moment about the y-axis, Muy = 180 kN.m.
Steel, Fy = 415 MPa
Effective depth of footing = 350 mm
How much additional moment (kN.m.) can the footing
carry without causing uplift of the footing?
534
625
445
435
Score 1/1P
Q. 4
SITUATION. A continuous beam with supports at A, B, C and D have equal spans of 8 m. It carries a
dead load of 10 kN/m and a live load of 20 kN/m.
What length (m) of the beam should be loaded by the live load of 20 kN/m in order to have a maximum
positive moment at AB and CD.
1/1P
8
16
24
0
Score 1/1P
1/1P
Q. 5
SITUATION. A continuous beam with supports at A, B, C and D have equal spans of 8 m. It carries a
dead load of 10 kN/m and a live load of 20 kN/m.
What length (m) of the beam should be loaded by the live load in order to have a maximum reaction at
C.
8
16
24
0
Score 1/1P
Q. 6
1/1P
SITUATION. A continuous beam with supports at A, B, C and D have equal spans of 8 m. It carries a
dead load of 10 kN/m and a live load of 20 kN/m.
What length (m) of the beam should be loaded by the live load in order to produce minimum negative
moment at B.
8
16
24
0
Score 1/1P
1/1P
Q. 7
SITUATION. A reinforced concrete beam having a width of 400 mm and an overall depth of 600 mm
has a spacing of 3 m. on centers supports a slab 100 mm in thickness. The super imposed dead load
= 3.2 kPa (includes floor finish, ceiling, fixtures.. etc). Live load = 3.6 kPa. Columns E and H are omitted
such that the girder BEHK support beams, DEF at E and GHI at H. Unit weight of concrete is 24 kN/m3.
Assume El to be constant.
Given:
L1 = L2 = 7.5 m
s=3m
Compute the ultimate uniform load of the beam GHI.
32.4
21.6
43.2
49.3
Score 1/1P
Q. 8
SITUATION. A reinforced concrete beam having a width of 400 mm and an overall depth of 600 mm
has a spacing of 3 m. on centers supports a slab 100 mm in thickness. The super imposed dead load
= 3.2 kPa (includes floor finish, ceiling, fixtures.. etc). Live load = 3.6 kPa. Columns E and H are omitted
0/1P
such that the girder BEHK support beams, DEF at E and GHI at H. Unit weight of concrete is 24 kN/m3.
Assume El to be constant.
Given:
L1 = L2 = 7.5 m
s=3m
Compute the maximum shear of beam GHI when H is assumed to be
hinged and G and I are fixed.
202.5
121.5
324
162
Score 0/1P
Q. 9
0/1P
SITUATION. A reinforced concrete beam having a width of 400 mm and an overall depth of 600 mm
has a spacing of 3 m. on centers supports a slab 100 mm in thickness. The super imposed dead load
= 3.2 kPa (includes floor finish, ceiling, fixtures.. etc). Live load = 3.6 kPa. Columns E and H are omitted
such that the girder BEHK support beams, DEF at E and GHI at H. Unit weight of concrete is 24 kN/m3.
Assume El to be constant.
Given:
L1 = L2 = 7.5 m
s=3m
Compute the maximum negative moment in span GH only, when it is assumed to be hinged at H and
fixed at G.
1215
0
303.8
170.9
Score 0/1P
Q. 10
SITUATION. A four span beam shown has a clear span length of AB = 8 m., BC = 9 m., CD = 8 m. and DE
= 7 m.
If the factored moment of beam MBA = - 96 kN.m, find the max. factored live load that beam AB could
carry if the factored dead load is 8 kN/m.
1/1P
2.31
5.29
7.0
3.38
Score 1/1P
1/1P
Q. 11
SITUATION. A four span beam shown has a clear span length of AB = 8 m., BC = 9 m., CD = 8 m. and DE
= 7 m.
If the factored live load is 12 kN/m and the factored dead load is 8 kN/m, what is the factored moment
MCB.
147.37
131.36
144.50
162.0
Score 1/1P
Q. 12
SITUATION. A four span beam shown has a clear span length of AB = 8 m., BC = 9 m., CD = 8 m. and DE
= 7 m.
1/1P
If the factored moment MDE = - 84.38 kN.m, what is the safe service live load that beam DE could
carry if the service dead load is 6.67 kN/m (including its own weight).
15
8.33
4.38
8.50
Score 1/1P
Q. 13
1/1P
SITUATION: The bridge truss shown in the figure is subjected to moving loads, L=5m, s=2.5m, P = 0
kN, .
Find the maximum ordinate of the influence line for member JK.
1.5
0.5
0.75
1.0
Score 1/1P
1/1P
Q. 14
SITUATION: The bridge truss shown in the figure is subjected to moving loads, L=5m, s=2.5m, P = 0
kN, .
Compute the axial stress in member JK (MPa) due to a standard H-loading with wheel base of 4.3 m,
front wheel load = 72.4 kN and rear wheel load = 19.6 kN. The cross sectional area is 1500 mm2.
50.09 C
50.09 T
75.14 C
75.14 T
Score 1/1P
Q. 15
SITUATION: The bridge truss shown in the figure is subjected to moving loads, L=5m, s=2.5m, P = 0
kN, .
1/1P
Given:
Front wheel load = 72.4 kN
Rear wheel load = 19.6 kN.
Wheel base = 4.3 m
Uniform highway load = 9.35 kN/m
The cross sectional area is 100 mm x 100 mm.
Compute the ratio of the actual to allowable stress of steel member JK. Yield strength, Fy = 248 MPa.
Use FS = 1.67.
0.66
0.40
0.59
0.35
Score 1/1P
0/1P
Q. 16
SITUATION. A simply supported steel beam BF is subjected to uniformly distributed loads.
Given:
S=2m
Superimposed dead load = 5 kPa
L = 10 m
Live load = 3.6 kPa
Properties of Beam BF: W 310 x 158
A= 11000mm2
tw= 9.14 mm
k=31.5 mm
d= 310 mm
rx= 134 mm
bf= 254 mm
Zx=1420 x 103 mm4
tf= 16.3 mm
J= 874 x103 mm4
Ix= 198x 106 mm4
ry= 63.8 mm
Sx=1280x 103 mm4
Iy=44.5 x 106 mm4
Yield Strength Fy=345 MPa
Factored Load Combination, U= 1.2D + 1.6L
Strength reduction factor (for flexure), 𝜙 = 0.90.
rt (radius of gyration of a section comprising the compression flange plus 1/3 of the compression
web area of compression flange =71.4 mm.
Consider bending about the x-axis.
What is the ultimate bending moment in beam BF in kN -m?
400.34
204.55
315.32
308.25
Score 0/1P
1/1P
Q. 17
SITUATION. A simply supported steel beam BF is subjected to uniformly distributed loads.
Given:
S=2m
Superimposed dead load = 5 kPa
L = 10 m
Live load = 3.6 kPa
Properties of Beam BF: W 310 x 158
A= 11000mm2
tw= 9.14 mm
k=31.5 mm
d= 310 mm
rx= 134 mm
ry= 63.8 mm
bf= 254 mm
Zx=1420 x 103 mm4
tf= 16.3 mm
J= 874 x103 mm4
Ix= 198x 106 mm4
Sx=1280x 103 mm4
Iy=44.5 x 106 mm4
Yield Strength Fy=345 MPa
Factored Load Combination, U= 1.2D + 1.6L
Strength reduction factor (for flexure), 𝜙 = 0.90.
rt (radius of gyration of a section comprising the compression flange plus 1/3 of the compression
web area of compression flange =71.4 mm.
Consider bending about the x-axis.
The beam is fully laterally supported. With this condition, what is the safe ultimate uniform load in
kN/m?
20.7
28.7
24.3
35.2
Score 1/1P
1/1P
Q. 18
SITUATION. A simply supported steel beam BF is subjected to uniformly distributed loads.
Given:
S=2m
Superimposed dead load = 5 kPa
L = 10 m
Live load = 3.6 kPa
Properties of Beam BF: W 310 x 158
A= 11000mm2
tw= 9.14 mm
k=31.5 mm
d= 310 mm
rx= 134 mm
ry= 63.8 mm
bf= 254 mm
Zx=1420 x 103 mm4
tf= 16.3 mm
J= 874 x103 mm4
Ix= 198x 106 mm4
Sx=1280x 103 mm4
Iy=44.5 x 106 mm4
Yield Strength Fy=345 MPa
Factored Load Combination, U= 1.2D + 1.6L
Strength reduction factor (for flexure), 𝜙 = 0.90.
rt (radius of gyration of a section comprising the compression flange plus 1/3 of the compression
web area of compression flange =71.4 mm.
Consider bending about the x-axis.
Lateral supports are to be provided. Find the biggest distance (m) between lateral supports so that
the maximum flexural strength can be utilized.
3.0
2.5
2.0
4.0
Score 1/1P
Q. 19
SITUATION:
Given the following data:
Total length of beam = 25 m
Dead load = 10 kN/m
Live load = 71 kN
Refer to shear and moment diagram:
V1 = 54.69 kN
V2 = 70.31 kN
V3 = 7.81 kN
M­max = 149.54 kN -m
M1 = 97.66 kN -m
Refer to shear and moment diagram:
V1 = 28.84 kN
V2 = 42.16 kN
V3 = 6.66 kN
1/1P
M­max = 180.27 kN -m
M1 = 83.20 kN -m
Which of the following gives the value of R2 (kN) due to dead load only?
56.87
78.13
69.34
81.65
Score 1/1P
Q. 20
SITUATION:
Given the following data:
Total length of beam = 25 m
Dead load = 10 kN/m
Live load = 71 kN
Refer to shear and moment diagram:
V1 = 54.69 kN
V2 = 70.31 kN
1/1P
V3 = 7.81 kN
M­max = 149.54 kN -m
M1 = 97.66 kN -m
Refer to shear and moment diagram:
V1 = 28.84 kN
V2 = 42.16 kN
V3 = 6.66 kN
M­max = 180.27 kN -m
M1 = 83.20 kN -m
Which of the following gives the value of R2 due to concentrated live load only?
48.81
57.33
34.21
61.35
Score 1/1P
Q. 21
SITUATION:
Given the following data:
Total length of beam = 25 m
Dead load = 10 kN/m
Live load = 71 kN
Refer to shear and moment diagram:
V1 = 54.69 kN
V2 = 70.31 kN
V3 = 7.81 kN
M­max = 149.54 kN -m
M1 = 97.66 kN -m
Refer to shear and moment diagram:
1/1P
V1 = 28.84 kN
V2 = 42.16 kN
V3 = 6.66 kN
M­max = 180.27 kN -m
M1 = 83.20 kN -m
What is the MAXIMUM positive moment at the first span considering dead load and live load?
329.81
387.36
326.75
390.31
Score 1/1P
Q. 22
Given: P=360 kN
Allowable weld stress, Fvw = 93 MPa
a=0.2m, b=0.5m, c=0.5m
0/1P
Calculate the moment of inertia (106 mm4/mm) about the neutral axis of the weld group.
25.78
83.33
105.47
46.67
Score 0/1P
Q. 23
Given: P=360 kN
Allowable weld stress, Fvw = 93 MPa
a=0.2m, b=0.5m, c=0.5m
0/1P
Calculate the resultant force per unit length of weld (N/mm) due to eccentric load.
154.65
281.17
245.45
300.12
Score 0/1P
Q. 24
Given: P=360 kN
Allowable weld stress, Fvw = 93 MPa
a=0.2m, b=0.5m, c=0.5m
1/1P
The resultant force per unit length of weld (N/mm) is 750 N/mm, find the required effective weld
thickness.
7
6
8
9
Score 1/1P
Q. 25
1/1P
SITUATION. A W-section is supported by a bearing plate 300 mm x 200 mm x 40 mm on a wall with a
thickness of 200 mm.
Properties of Wide Flange Section:
d = 600 mm
tw = 12 mm
bf = 225 mm
tf = 18 mm
k = 36 mm
Concrete compressive strength, fc’ = 24 MPa
Steel yield strength, Fy = 248 MPa
Strength reduction factors
For bearing, = 0.65
For flexure, = 0.90
For web yielding, = 1.00
Determine the maximum factored load beam reaction (kN) of the beam for the following conditions:
Considering bearing of concrete wall.
506.3
795.6
1224.0
327.6
Score 1/1P
Q. 26
1/1P
SITUATION. A W-section is supported by a bearing plate 300 mm x 200 mm x 40 mm on a wall with a
thickness of 200 mm.
Properties of Wide Flange Section:
d = 600 mm
tw = 12 mm
bf = 225 mm
tf = 18 mm
k = 36 mm
Concrete compressive strength, fc’ = 24 MPa
Steel yield strength, Fy = 248 MPa
Strength reduction factors
For bearing, = 0.65
For flexure, = 0.90
For web yielding, = 1.00
Determine the maximum factored load beam reaction (kN) of the beam for the following conditions:
Considering the bending of bearing plates at a distance “k”.
824
2615
2180
687
Score 1/1P
1/1P
Q. 27
SITUATION. A W-section is supported by a bearing plate 300 mm x 200 mm x 40 mm on a wall with a
thickness of 200 mm.
Properties of Wide Flange Section:
d = 600 mm
tw = 12 mm
bf = 225 mm
tf = 18 mm
k = 36 mm
Concrete compressive strength, fc’ = 24 MPa
Steel yield strength, Fy = 248 MPa
Strength reduction factors
For bearing, = 0.65
For flexure, = 0.90
For web yielding, = 1.00
Determine the maximum factored load beam reaction (kN) of the beam for the following conditions:
Considering web yielding at a distance (N + 2.5k).
1295
1741
863
1045
Score 1/1P
1/1P
Q. 28
SITUATION. A 600 mm diameter column contains 20-28 mm & bars arranged in a circle. It has a spiral
bar diam. of 10 mm which has a clear cover of 40 mm. Maximum
size of aggregate is 25 mm. fc' = 21 MPa, fy = 345 MPa.
Minimum steel reinforcement requirement
Maximum clear spacing of spiral = 75 mm
Minimum clear spacing of spiral = 25 mm
Which of the following gives us the spiral steel ratio.
0.00431
0.00781
0.00849
0.00908
Score 1/1P
Q. 29
SITUATION. A 600 mm diameter column contains 20-28 mm & bars arranged in a circle. It has a spiral
bar diam. of 10 mm which has a clear cover of 40 mm. Maximum
size of aggregate is 25 mm. fc' = 21 MPa, fy = 345 MPa.
1/1P
Minimum steel reinforcement requirement
Maximum clear spacing of spiral = 75 mm
Minimum clear spacing of spiral = 25 mm
Which of the following gives us the required spacing of the spirals.
50
70
60
40
Score 1/1P
Q. 30
SITUATION. A 600 mm diameter column contains 20-28 mm & bars arranged in a circle. It has a spiral
bar diam. of 10 mm which has a clear cover of 40 mm. Maximum
size of aggregate is 25 mm. fc' = 21 MPa, fy = 345 MPa.
Minimum steel reinforcement requirement
Maximum clear spacing of spiral = 75 mm
Minimum clear spacing of spiral = 25 mm
Which of the following gives the clear spacing between longitudinal bars
Spacing of longitudinal requirements:
In spirally reinforced or tied reinforced compression members, clear
distance between longitudinal bars shall not be less than
1/1P
a.) 1.5db
b.) 40 mm
c.) 1 1/3 the maximum size of coarse aggregate
46
52
61
67
Score 1/1P
Q. 31
1/1P
SITUATION. Given data for a circular spiral column:
Diameter, D = 800 mm
Concrete, fc’ = 34 MPa
Steel, fyl = 413 MPa, fyv = 413 MPa
Concrete shear stress = 0.99 MPa
Diameter of spiral, ds = 10 mm
Concrete cover, Cc = 40
Maximum clear spacing of spiral = 75 mm
Minimum clear spacing of spiral = 25 mm
What is the nominal shear strength of the column if spacing of stirrups is 90 mm.
364.3
506.9
726.2
968.2
Score 1/1P
0/1P
Q. 32
SITUATION. Given data for a circular spiral column:
Diameter, D = 800 mm
Concrete, fc’ = 34 MPa
Steel, fyl = 413 MPa, fyv = 413 MPa
Concrete shear stress = 0.99 MPa
Diameter of spiral, ds = 10 mm
Concrete cover, Cc = 40
Maximum clear spacing of spiral = 75 mm
Minimum clear spacing of spiral = 25 mm
If the diameter of ties is 12 mm, to comply with the code provision of minimum reinforcing steel ratio,
what is value of center to center spacing of the spirals?
60
48
36
55
Score 0/1P
Q. 33
SITUATION. Given data for a circular spiral column:
Diameter, D = 800 mm
Concrete, fc’ = 34 MPa
Steel, fyl = 413 MPa, fyv = 413 MPa
0/1P
Concrete shear stress = 0.99 MPa
Diameter of spiral, ds = 10 mm
Concrete cover, Cc = 40
Maximum clear spacing of spiral = 75 mm
Minimum clear spacing of spiral = 25 mm
What is the diameter of the spiral in order not to exceed 50 mm maximum clear distance?
14
13
11
10
Score 0/1P
Q. 34
1/1P
SITUATION. The reinforced concrete footing is supported on piles.
Use fc' = 21 MPa and fy = 276 MPa,
Service Loads:
DL = 360 kN
LL = 520 kN
Effective depth, d = 350 mm
Pile diameter = 300 mm
Column dimension = 400 mm x 400 mm
Footing dimension:
a = 450 mm
b = 850 mm
c = 900 mm
Determine the nominal wide beam shear stress.
d = 450 mm
0.67
0.50
0.38
0.52
Score 1/1P
Q. 35
SITUATION. The reinforced concrete footing is supported on piles.
Use fc' = 21 MPa and fy = 276 MPa,
Service Loads:
DL = 360 kN
LL = 520 kN
Effective depth, d = 350 mm
Pile diameter = 300 mm
Column dimension = 400 mm x 400 mm
Footing dimension:
1/1P
a = 450 mm
b = 850 mm
c = 900 mm
d = 450 mm
Determine the ultimate punching shear stress.
1.50
1.13
1.61
1.20
Score 1/1P
Q. 36
SITUATION. The reinforced concrete footing is supported on piles.
Use fc' = 21 MPa and fy = 276 MPa,
Service Loads:
DL = 360 kN
LL = 520 kN
Effective depth, d = 350 mm
Pile diameter = 300 mm
Column dimension = 400 mm x 400 mm
Footing dimension:
1/1P
a = 450 mm
b = 850 mm
c = 900 mm
d = 450 mm
Determine the number of 20 mm bars based on critical moment.
14
12
16
17
Score 1/1P
Q. 37
SITUATION. The simply supported beam shown in the figure is crossed by a uniform load of 30 kN /m
over a length of 6 m.
What is the maximum reaction at B in kN?
1/1P
146.25
125.64
138.34
120.71
Score 1/1P
1/1P
Q. 38
SITUATION. The simply supported beam shown in the figure is crossed by a uniform load of 30 kN /m
over a length of 6 m.
What is the maximum shear at C in kN?
153.50
116.75
101.25
134.38
Score 1/1P
Q. 39
SITUATION. The simply supported beam shown in the figure is crossed by a uniform load of 30 kN /m
over a length of 6 m.
0/1P
What is the maximum moment at C in kN – m.
438.75
586.34
444.18
341.61
Score 0/1P
Q. 40
1/1P
A 360 mm x 360 mm reinforced concrete tied column carries an axial dead load of 650 kN and an axial
live load of 800 kN. fc = 28 MPa, fy = 400 MPa
Compute the clear spacing between the longitudinal bars if tie diameter of tie wire is 10 mm o with a
clear cover of 40 mm.
100
150
120
90
Score 1/1P