PURE MATHEMATICS 1 (9709/1) CHAPTER SUMMARIES Pass Maths with Tr. Simon +250780873489 & +256701223968 simonsilva968@gmail.com Chapter 1: QUADRATICS Quadratic equations can be solved by: ● factorisation ● completing the square ● using the quadratic formula x = −b ± b 2 − 4ac . 2a Solving simultaneous equations where one is linear and one is quadratic ● Rearrange the linear equation to make either x or y the subject. ● Substitute this for x or y in the quadratic equation and then solve. Maximum and minimum points and lines of symmetry For a quadratic function f( x ) = ax 2 + bx + c that is written in the form f( x ) = a( x − h )2 + k : b ● the line of symmetry is x = h = − 2a ● if a . 0, there is a minimum point at ( h, k ) ● if a , 0, there is a maximum point at ( h, k ). Quadratic equation ax 2 + bx + c = 0 and corresponding curve y = ax 2 + bx + c ● Discriminant = b 2 − 4ac. ● If b 2 − 4ac . 0, then the equation ax 2 + bx + c = 0 has two distinct real roots. ● If b 2 − 4ac = 0, then the equation ax 2 + bx + c = 0 has two equal real roots. ● If b 2 − 4ac , 0, then the equation ax 2 + bx + c = 0 has no real roots. ● The condition for a quadratic equation to have real roots is b 2 − 4ac ù 0. Intersection of a line and a general quadratic curve ● If a line and a general quadratic curve intersect at one point, then the line is a tangent to the curve at that point. ● Solving simultaneously the equations for the line and the curve gives an equation of the form ax 2 + bx + c = 0. ● b 2 − 4ac gives information about the intersection of the line and the curve. b 2 − 4 ac Nature of roots Line and parabola .0 two distinct real roots two distinct points of intersection =0 two equal real roots one point of intersection (line is a tangent) ,0 no real roots no points of intersection Pass Maths with Tr. Simon +250780873489 & +256701223968 simonsilva968@gmail.com Cambridge International AS & A Level Mathematics: Pure Mathematics 1 Chapter 2: FUNCTIONS Functions ● A function is a rule that maps each x value to just one y value for a defined set of input values. ● A function can be either one-one or many-one. ● The set of input values for a function is called the domain of the function. ● The set of output values for a function is called the range (or image set) of the function. Composite functions ● fg( x ) means the function g acts on x first, then f acts on the result. ● fg only exists if the range of g is contained within the domain of f. ● In general, fg( x ) ≠ gf( x ). Inverse functions ● The inverse of a function f( x ) is the function that undoes what f( x ) has done. f f −1( x ) = f −1 f( x ) = x or if y = f( x ) then x = f −1( y ) ● The inverse of the function f( x ) is written as f −1 ( x ). ● The steps for finding the inverse function are: Step 1: Write the function as y = Step 2: Interchange the x and y variables. Step 3: Rearrange to make y the subject. ● The domain of f −1 ( x ) is the range of f( x ). ● The range of f −1 ( x ) is the domain of f( x ). ● An inverse function f −1 ( x ) can exist if, and only if, the function f( x ) is one-one. ● The graphs of f and f −1 are reflections of each other in the line y = x. ● If f( x ) = f −1 ( x ), then the function f is called a self-inverse function. ● If f is self-inverse then ff( x ) = x. ● The graph of a self-inverse function has y = x as a line of symmetry. Transformations of functions ● 0 The graph of y = f( x ) + a is a translation of y = f( x ) by the vector . a ● The graph of y = f( x + a ) is a translation of y = f( x ) by the vector ● The graph of y = − f( x ) is a reflection of the graph y = f( x ) in the x-axis. ● The graph of y = f( − x ) is a reflection of the graph y = f( x ) in the y-axis. −a . 0 The graph of y = a f( x ) is a stretch of y = f( x ), stretch factor a, parallel to the y-axis. 1 ● The graph of y = f( ax ) is a stretch of y = f( x ), stretch factor , parallel to the x-axis. a ● Combining transformations ● When two vertical transformations or two horizontal transformations are combined, the order in which they are applied may affect the outcome. ● When one horizontal and one vertical transformation are combined, the order in which they are applied does not affect the outcome. ● Vertical transformations follow the ‘normal’ order of operations, as used in arithmetic ● Horizontal transformations follow the opposite order to the ‘normal’ order of operations, as used in arithmetic. Pass Maths with Tr. Simon +250780873489 & +256701223968 simonsilva968@gmail.com Chapter 3: COORDINATE GEOMETRY Midpoint, gradient and length of line segment Q (x2, y2) M P (x1, y1) ● x + x2 y1 + y2 , Midpoint, M, of PQ is 1 . 2 2 ● Gradient of PQ is ● Length of segment PQ is y2 − y1 . x2 − x1 ( x2 − x1 )2 + ( y2 − y1 )2 Parallel and perpendicular lines ● If the gradients of two parallel lines are m1 and m2 , then m1 = m2. ● If the gradients of two perpendicular lines are m1 and m2 , then m1 × m2 = −1. The equation of a straight line is: ● y − y1 = m( x − x1 ), where m is the gradient and ( x1, y1 ) is a point on the line. The equation of a circle is: ● ( x − a )2 + ( y − b )2 = r 2 , where ( a, b ) is the centre and r is the radius. ● x 2 + y 2 + 2 gx + 2 fy + c = 0 , where ( − g, − f ) is the centre and Pass Maths with Tr. Simon g 2 + f 2 − c is the radius. +250780873489 & +256701223968 simonsilva968@gmail.com Chapter 4: CIRCULAR MEASURE Radians and degrees r r 1 rad O r ● One radian is the size of the angle subtended at the centre of a circle, radius r, by an arc of length r. ● π radians = 180° ● To change from degrees to radians, multiply by π . 180 ● To change from radians to degrees, multiply by 180 . π Arc length and area of a sector B r θ O r A When θ is measured in radians, the length of arc AB is rθ . 1 2 ● When θ is measured in radians, the area of sector AOB is r θ. 2 ● Pass Maths with Tr. Simon +250780873489 & +256701223968 simonsilva968@gmail.com Chapter 5: TRIGONOMETRY Exact values of trigonometric functions sin θ cos θ tan θ θ = = 30° = π 6 1 2 3 2 1 3 θ = 45° = π 4 1 2 1 2 1 θ = 60° = π 3 3 2 1 2 3 Positive and negative angles ● Angles measured anticlockwise from the positive x-direction are positive. ● Angles measured clockwise from the positive x -direction are negative. Diagram showing where sin, cos and tan are positive 90° Sin 180° All 0°, 360° O Tan Cos 151 270° ● Useful mnemonic: ‘A ll Students Trust Cambridge’. Graphs of trigonometric functions y 1 y = sin x –360 –270 –180 –90 O 90 180 270 360 x 270 360 x –1 y 1 y = cos x –360 –270 –180 –90 O 90 180 –1 Pass Maths with Tr. Simon +250780873489 & +256701223968 simonsilva968@gmail.com Cambridge International AS & A Level Mathematics: Pure Mathematics 1 y y = tan x –360 –270 –180 –90 O 90 180 270 360 x ● The graph of y = a sin x is a stretch of y = sin x , stretch factor a, parallel to the y -axis. ● The graph of y = sin( ax ) is a stretch of y = sin x , stretch factor ● ● 1 , parallel to the x -axis. a 0 The graph of y = a + sin x is a translation of y = sin x by the vector . a −a . 0 The graph of y = sin( x + a ) is a translation of y = sin x by the vector Inverse trigonometric functions y π – 2 –1 y= y π sin –1x O 1 π –– 2 y = sin −1 x domain: −1 < x < 1 π π range: − < sin −1 x < 2 2 π – 2 x –1 O y π – 2 y = cos –1 x 1 y = tan –1 x O x y = cos −1 x domain: −1 < x < 1 range: 0 < cos −1 x < π x π –– 2 y = tan −1 x domain: x ∈ R π π range: − < tan −1 x < 2 2 Trigonometric identities sin x ● tan x ≡ cos x ● sin2 x + cos2 x ≡ 1 Pass Maths with Tr. Simon +250780873489 & +256701223968 simonsilva968@gmail.com Cambridge International AS & A Level Mathematics: Pure Mathematics 1 Chapter 6: SERIES Binomial expansions n Binomial coefficients, denoted by n C r or , can be found using: r ● Pascal’s triangle ● n n n! n × ( n − 1) × ( n − 2) × … × ( n − r + 1) or = the formulae = . r × ( r − 1) × ( r − 2) × … × 3 × 2 × 1 r r! ( n − r )! r If n is a positive integer, the Binomial theorem states that: n n n n n (1 + x ) n = + x + x 2 + … + x n , where the ( r + 1)th term = x r. r 2 n 0 1 We can extend this rule to give: n n−r r n n n n b. ( a + b ) n = a n + a n − 1b1 + a n − 2 b 2 + … + b n , where the ( r + 1)th term = a r 2 1 n 0 We can also write the expansion of (1 + x ) n as: (1 + x ) n = 1 + nx + n( n − 1) 2 n( n − 1)( n − 2) 3 x + x + … + xn 2! 3! Arithmetic series For an arithmetic progression with first term a, common difference d and n terms: ● the kth term is a + ( k − 1)d the last term is l = a + ( n − 1)d n n ( a + l ) = [2 a + ( n − 1)d ]. ● the sum of the terms is Sn = 2 2 ● Geometric series For a geometric progression with first term a, common ratio r and n terms: ● the kth term is ar k − 1 ● the last term is ar n − 1 ● sum of the terms is Sn = a (1 − r n ) a ( r n − 1) = . 1− r r −1 The condition for an infinite geometric series to converge is −1 < r < 1. When an infinite geometric series converges, S∞ = Pass Maths with Tr. Simon a . 1− r +250780873489 & +256701223968 simonsilva968@gmail.com Cambridge International AS & A Level Mathematics: Pure Mathematics 1 Chapter 7: DIFFERENTIATION Gradient of a curve ● dy represents the gradient of the curve y = f( x ). dx The four rules of differentiation ● Power rule: d ( x n ) = nx n − 1 dx ● Scalar multiple rule: d d [ kf( x )] = k [f( x )] dx dx ● Addition/subtraction rule: d d d [f( x ) ± g( x )] = [g( x )] [f( x )] ± dx dx dx ● Chain rule: du dy dy = × dx dx du Tangents and normals dy at the point ( x1, y1 ) is m, then: dx ● the equation of the tangent at that point is given by y − y1 = m( x − x1 ) 1 ( x − x1 ) . ● the equation of the normal at that point is given by y − y1 = − m If the value of Second derivatives ● d dy d2 y = dx dx dx 2 Pass Maths with Tr. Simon +250780873489 & +256701223968 simonsilva968@gmail.com Cambridge International AS & A Level Mathematics: Pure Mathematics 1 Increasing and decreasing functions • • • y = f( x ) is increasing for a given interval of x if dy . 0 throughout the interval. dx y = f( x ) is decreasing for a given interval of x if dy , 0 throughout the interval. dx Stationary points Stationary points (turning points) of a function y = f( x ) occur when dy = 0. dx First derivative test for maximum and minimum points At a maximum point: • • • • dy = 0 dx the gradient is positive to the left of the maximum and negative to the right. At a minimum point: dy = 0 dx the gradient is negative to the left of the minimum and positive to the right. Second derivative test for maximum and minimum points • • • If d2 y dy = 0 and 2 , 0, then the point is a maximum point. dx dx If d2 y dy = 0 and 2 . 0, then the point is a minimum point. dx dx If dy d2 y = 0 and 2 = 0, then the nature of the stationary point can be found using the dx dx first derivative test. Connected rates of change • When two variables, x and y, both vary with a third variable, t, the three variables can be connected using the chain rule: • You may also need to use the rule: Pass Maths with Tr. Simon dy dy dx . = × dt dx dt dx 1 . = y d dy dx +250780873489 & +256701223968 simonsilva968@gmail.com Chapter 8: INTEGRATION 12 The diagram shows the curve y = 4 − x and the line x + 2 y = 4 that intersect at the points (4, 0) and (0, 2). y 2 a Find the volume obtained when the shaded region is rotated through 360° about the x-axis. b Find the volume obtained when the shaded region is rotated through 360° about the y-axis. 13 A mathematical model for the inside of a bowl is obtained by rotating the curve x 2 + y2 = 100 through 360° about the y-axis between y = −8 and y = 0. Each unit of x and y represents 1cm. y =√ 4 – x x + 2y = 4 4 O x y x2 + y2 = 100 a Find the volume of the bowl. The bowl is filled with water to a depth of 3 cm. x b Find the volume of water in the bowl. –8 3 P 14 Use integration to prove that the volume, V cm , of a sphere with radius 4 r cm is given by the formula V = πr 3. 3 Integration as the reverse of differentiation ● d [ F( x ) ] = f( x ), then dx If ∫ f(x ) dx = F(x ) + c. Integration formulae 1 ● ∫ x dx = n + 1 x ● ∫ (ax + b) dx = a( n + 1) (ax + b) n n +1 + c (where c is a constant and n ≠ −1) 1 n n +1 + c ( n ≠ −1 and a ≠ 0) Rules for indefinite integration ● ● ∫ k f(x ) dx = k ∫ f(x ) dx, where k is a constant ∫ [ f(x ) ± g(x ) ] dx = ∫ f(x ) dx ± ∫ g(x ) dx Rules for definite integration ● ● ∫ If ∫ b a b f( x ) dx = F( x ) + c, then k f( x ) d x = k ∫ f(x ) dx = [ F(x ) ] = F(b) − F(a ). b a a b ∫ f(x ) dx, where k is a constant. a Pass Maths with Tr. Simon +250780873489 & +256701223968 simonsilva968@gmail.com Cambridge International AS & A Level Mathematics: Pure Mathematics 1 b ● a ● b b a a ∫ [ f(x ) ± g(x ) ] dx = ∫ f(x ) dx ± ∫ g(x ) dx b a a b ∫ f(x ) dx = − ∫ f(x ) dx Area under a curve y y = f(x) A a O ● x b The area, A, bounded by the curve y = f( x ), the x-axis and the lines x = a and x = b is given by the formula: b ∫ y dx when y ù 0 A= (or A = a b ∫ f(x ) dx when f(x ) ù 0 ). a y 274 b A a x = f(y) O ● x The area, A, bounded by the curve x = f( y ), the y-axis and the lines y = a and y = b is given by the formula: A= b ∫ x dy when x ù 0 (or A = a b ∫ f( y) dy when f( y) ù 0). a y y = f(x) A O a b x y = g(x) Pass Maths with Tr. Simon +250780873489 & +256701223968 simonsilva968@gmail.com ● The area, A, enclosed between y = f( x ) and y = g( x ) is given by the formula: A= b ∫ [ f(x ) − g(x ) ] dx a where a and b are the x-coordinates of the points of intersection of the functions f and g. Improper integrals ∞ ● Integrals of the form ∫ f(x ) dx can be evaluated by replacing the infinite limit with a finite a value, X , and then taking the limit as X → ∞, provided the limit exists. b ● Integrals of the form ∫ f(x ) dx can be evaluated by replacing the infinite limit with a finite −∞ value, X , and then taking the limit as X → −∞, provided the limit exists. b ● Integrals of the form ∫ f(x ) dx where f(x ) is not defined when x = a can be evaluated by a replacing the limit a with an X and then taking the limit as X → a , provided the limit exists. b ● Integrals of the form ∫ f(x ) dx where f(x ) is not defined when x = b can be evaluated by a replacing the limit b with an X and then taking the limit as X → b, provided the limit exists. Volume of revolution ● The volume, V , obtained when the function y = f( x ) is rotated through 360° about the x-axis between the boundary values x = a and x = b is given by the formula V = b ∫ πy dx. 2 a ● The volume, V , obtained when the function x = f( y ) is rotated through 360° about the y-axis between the boundary values y = a and y = b is given by the formula V = b ∫ πx d y. 2 a Pass Maths with Tr. Simon +250780873489 & +256701223968 simonsilva968@gmail.com
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