Materials Science Joachim Rösler, Sebastian Piegert, Britta Laux, Michaela Necker July 18, 2024 This script written by me, Joachim Rösler, assisted by Sebastian Piegert, Britta Laux und Michaela Necker, is subject to German copyright law. It may only be used for personal use for the purpose of studying. In particular, it is not allowed to edit, translate, or copy the script or parts of it and to pass it on to other persons, neither as a copy nor electronically via email, on storage media (e.g. CD, USB stick, etc.), via databases or other media and systems. Only the production of copies and downloads for personal, private and non-commercial use is permitted. Contents 1 Introduction 4 2 Elastic stiness, atomic bonding and material structure 10 1.1 1.2 2.1 2.2 2.3 Importance of materials science in mechanical engineering . . . . . . . . . Material classes, prices and availability . . . . . . . . . . . . . . . . . . . . Phenomenological description of elastic deformation . . . . . . . . . . . . 2.1.1 Nominal stress, nominal strain, elastic constants . . . . . . . . . . 2.1.2 True stress and strain . . . . . . . . . . . . . . . . . . . . . . . . . 2.1.3 The tensile test . . . . . . . . . . . . . . . . . . . . . . . . . . . . . The atomic bond . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2.2.1 Basics . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2.2.2 The ionic bond . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2.2.3 The covalent bond . . . . . . . . . . . . . . . . . . . . . . . . . . . 2.2.4 The metallic bonding . . . . . . . . . . . . . . . . . . . . . . . . . 2.2.5 Secondary Bonds . . . . . . . . . . . . . . . . . . . . . . . . . . . . The structure of the materials . . . . . . . . . . . . . . . . . . . . . . . . . 2.3.1 Metals . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2.3.2 Ceramics . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2.3.3 Polymers . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Structure of the polymer groups . . . . . . . . . . . . . . . . . . . Examples of important polymers . . . . . . . . . . . . . . . . . . . 3 Strength and phase diagrams 3.1 3.2 3.3 3.4 The ideal strength . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Dislocations in crystals . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3.2.1 Forces between dislocations . . . . . . . . . . . . . . . . . . . . . . Measures to increase strength . . . . . . . . . . . . . . . . . . . . . . . . . 3.3.1 Work hardening . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3.3.2 Strengthening by grain size reduction . . . . . . . . . . . . . . . . 3.3.3 Solid solution strengthening . . . . . . . . . . . . . . . . . . . . . . 3.3.4 Particle strengthening . . . . . . . . . . . . . . . . . . . . . . . . . 3.3.5 Quenched and tempered steels . . . . . . . . . . . . . . . . . . . . Phase diagrams . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3.4.1 Solubility, states of aggregation, Gibbs phase rule . . . . . . . . . . 3.4.2 Binary systems and microstructure formation . . . . . . . . . . . . 3.4.3 The Iron-Carbon Diagram . . . . . . . . . . . . . . . . . . . . . . . 2 4 4 10 10 14 15 18 18 20 22 27 29 31 31 36 39 39 54 62 62 64 68 69 69 70 72 74 83 87 87 89 97 Contents 4 Processes at High Temperatures 104 5 Oxidation and corrosion 122 Bibliography 137 4.1 4.2 4.3 4.4 5.1 5.2 Vacancies . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 104 Diusion . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 108 Recrystallization . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 117 Recovery . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 121 Oxidation . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 122 Corrosion . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 125 5.2.1 Fundamentals . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 125 5.2.2 Kinetics of corrosion . . . . . . . . . . . . . . . . . . . . . . . . . . 127 5.2.3 Corrosion protection measures . . . . . . . . . . . . . . . . . . . . 129 5.2.4 Degradation of polymers . . . . . . . . . . . . . . . . . . . . . . . . 133 3 1 Introduction 1.1 Importance of materials science in mechanical engineering During the design and construction of components, an ever increasing number of possible materials are available to the mechanical engineer. While at the end of the nineteenth century there were still several hundred, today there are more than one hundred thousand. For example, synthetically produced polymers, technical ceramics, titanium alloys, high-temperature resistant nickel alloys or modern composite materials have essentially been developed over the past fty years and new material variants are constantly being added. Accordingly, there is great potential for improving products by selecting the right material, reducing costs or enabling previously unimaginable properties. For example, eyeglass frames can now be made from high-strength titanium alloys or so-called shape memory alloys, which do not break or bend permanently even in the worst cases of misuse. On the other hand, wrong decisions can also have catastrophic consequences. One example is the so-called Liberty ships built during the Second World War. Due to the use of an unsuitable welding material with too low fracture toughness, the ships broke apart at sea along the welded joints. The aim of teaching materials in mechanical engineering is to impart the necessary knowledge for proper material selection in the design and construction of systems and assemblies. The lecture Materials Science gives a rst overview of the dierent material classes and their most important properties. 1.2 Material classes, prices and availability Materials can be divided into three large groups, each with typical properties: metals, ceramics and polymers. Signicant examples of metals are steels (i.e. ferrous materials containing carbon as an additional element within certain limits), the especially light metals (aluminium, magnesium and titanium), nickel and copper alloys. As shown in Tab. 1.1, they are characterized by high strength and good formability. This good formability - often called ductility - leads to good processability of metals. For example large steel bars may be rolled into thin sheets and then deep drawn to car body parts with complex nal shapes. In addition, metals have good electrical and thermal conductivity. This is especially the case for copper, aluminium, silver and gold. Therefore, these materials can be used, for example, as conductor paths in the semiconductor industry. However, metals are usually chemically unstable and have a relatively high density. With a global annual production of about 1.6 billion tons, steels are by far the most important material group in mechanical engineering. They can be found in all areas of mechanical engineering. In comparison, several tens of millions of tons of aluminum and 4 1 Introduction group elements main 1 IA H VIIIA 2 hcp 3 IIA 4 bcc 11 hcp 12 bcc 19 hcp 20 IIIB IVB VB VIB VIIB 21 22 23 24 25 26 VIIIB 27 28 bcc 37 fcc 38 hcp 39 hcp 40 bcc 41 fcc 42 cub 43 bcc 44 hcp 45 bcc 55 fcc 56 hcp 57 hcp 72 bcc 73 bcc 74 hcp 75 hcp 76 bcc 87 bcc 88 hcp 89 hcp 104 bcc bcc hcp hcp (bcc) krz fcc Li Be Na Mg K Rb Cs Fr Ca Sr Ba Ra VIA VIIA hcp 8 9 10 tet 13 dia 14 hcp 15 cub 16 mon 17 fcc 18 IB 29 IIB fcc 30 31 dia 32 cub 33 ort 34 ort 35 fcc 36 fcc 46 fcc 47 hcp 48 ort 49 dia 50 rho 51 hcp 52 ort 53 fcc 54 fcc 77 fcc 78 fcc 79 hcp 80 tet 81 dia 82 rho 83 hcp 84 ort 85 fcc 86 fcc fcc fcc rho hcp fcc rho cub transition metals Sc Y La Ac Ti Zr Hf V Cr Nb Mo Ta W Mn Tc Re Fe Ru Os B Co Ni Rh Pd Ir Pt Cu Ag Au Al Zn Cd Hg Ga In Tl C Si Ge Sn Pb N P As Sb Bi O S Se Te Po F Cl Br I At Ne Ar Kr Xe Rn (fcc) Rf metal semi-metal hcp hexagonal close-packed fcc He IIIA IVA VA 5 6 7 face-centered cubic nonmetal bcc body-centered cubic kub cubic ort orthorhombic tet rho rhombohedral dia diamond lattice tetragonal Figure 1.1: Periodic table of the elements excluding lanthanides atomic numbers 58 to 71) and actinides (atomic numbers 90 to 103). The crystal structures will be explained in section 2.3. Semi-metals have bonds of a mixed covalent-metallic type. Some materials exhibit dierent crystal structures depending on the temperature [26]. a little over hundred thousand tons of titanium are produced each year. Taking the high conductivity as an example of a typical characteristic of metals, the elements of the periodic table can be easily divided into metals and nonmetals (Fig. 1.1). Apparently most elements belong to the metals, being located on the left side of the periodic table. However, many metals have not achieved any signicance in mechanical engineering, e.g. because, like mercury, they are already liquid at ambient temperature, toxic (e.g. beryllium) or extremely expensive (e.g. gold or platinum). Important representatives of ceramics include aluminium oxide (Al2 O3 ), silicon nitride (Si3 N4 ), silicon carbide (SiC) and carbon, which is used in particular in the form of carbon bres and hard coatings (diamond coatings). There are also a number of mixed oxides which are of great technical importance. These include glass, which consists mainly of silicon oxide (SiO2 ) but also contains sodium oxide (Na2 O) and calcium oxide (CaO), as well as cement, which consists mainly of calcium oxide, silicon oxide and aluminium oxide. Ceramics are extremely hard, wear- and heat-resistant. For this reason they are used, for instance, to make cutting tools for metalworking. However, they are also brittle (the opposite of ductile). They are electrically isolating or semiconducting and, with a few exceptions, have low thermal conductivity. In addition, they have good chemical resistance. As can be seen from the examples, ceramics are mostly inorganic compounds between a metal (e.g. Al) and a non-metal (e.g. O). As already mentioned the carbon materials are also counted as ceramics. 5 1 Introduction Polymers are synthetically produced organic materials (i.e. materials composed of compounds of carbon with other elements). They consist of long chain molecules that are woven together like a ball of wool threads. With a few exceptions, there are only carbon atoms along the threads. In addition, one or two side groups hang on each carbon atom. In the simplest case, polyethylene, the side groups consist only of hydrogen (H). However, the side groups can also contain other atoms, such as chlorine (Cl), or consist of molecules, such as CH3 . Other examples of technically important polymers are polycarbonate, from which compact discs or the glazing of automobile headlights are made, and polyamides, from which radiator fans for automobiles are made. Because polytetrauoroethylene (PTFE) has a very low coecient of friction, it is used, for example, to make plain bearings. The Teon coating of the frying pan also consists of this material, whereby the term Teon is only a trade name for PTFE. Polymers are characterized by a low density (polyethylene is even slightly lighter than water). They are generally insulating both electrically and thermally, have good chemical resistance and are partly optically transparent. In addition, they are very easy to shape and to process, which is why it is particularly easy to produce components with complex geometries from them. However, their strength is limited and they are very exible. This is a disadvantage when a particularly rigid structure, such as an automobile body, is required. However, for an snap closure this exibility is advantageous. In addition, their thermal durability is low because they melt early or decompose through reaction with atmospheric oxygen. Figure 1.2: Classication of materials adapted from [1]. A material does not have to consist of only one representative of the material groups mentioned above. Often particularly advantageous properties are achieved in so-called composite materials, which are composed of more than one representative (Fig. 1.2 ). 6 1 Introduction The following are examples: glass/carbon ber-reinforced polymers (e.g. tennis rackets), which are characterized by high stiness and low weight, WC-Co "cemented carbides" which are characterised by high hardness and sucient toughness, polymer-steel composites (e.g. car tires) and reinforced concrete. Table 1.1: Material classes, typical representatives and their most important characteristics. material class typical representative metals iron, steel high thermal and titanium alloys electrical conductivity, ceramics polymers characteristics magnesium alloys high tensile strength, nickel alloys good formability, copper alloys mostly chemically unstable aluminium oxide (Al2 O3 ) isolating, silicon carbide (SiC) high compression strength, silicon nitride (Si3 N4 ) brittle, cement (CaO-Sio2 ) generally hard to process, glass chemically resistant, diamond high melting point polyethylene (PE) mostly isolating, polymethylmetacrylat low specic weight, (Plexiglas or PMMA) chemically resistant, polypropylen (PP) gut verarbeitbar, polyamide (PA) low thermal stability, rubber (melting, decomposition) An important criterion for the selection of a material is usually the price. For example, assuming a price of 10,000 e and a weight of 1,000 kg for a small car, a material with a price of 10 e/kg would already represent 100 % of the estimated costs. In reality, a material for the automotive industry may cost a maximum of several e/kg in order to be able to manufacture a reasonably competitive product. The costs of important structural materials are shown in Fig. 1.3. If we compare the prices between steel and aluminium, it is clear, why aluminium bodies are currently oered in the top market segment exclusively. As expected, the most common materials (concrete, steel, wood, polyethylene and polypropylene) belong to the lowest price segment. Assuming the costs of iron and nickel would be reversed our environment would be predominately determined by nickel constructions instead of steel constructions. The costs of a material are partly determined by its availability (other factors: mining costs, energy costs, processing costs). Tab. 1.2 summarizes the materials most commonly present in the terrestrial crust. 7 1 Introduction Figure 1.3: Approximate cost of important materials. It is obvious that the components for ceramic materials (silicon, oxygen, nitrogen, carbon) and polymers (carbon, hydrogen) are present on a large scale. The same refers to the metals aluminium, iron, magnesium and titanium. However, other metals such as cobalt, copper or rhenium occur in far lower amounts and may be considered strategically important. Table 1.2: Occurrence of the elements in the terrestrial crust in weight percentages. element occurrence / wt.-% oxygen 47 silicon 27 aluminium 8 iron 5 calcium 4 sodium 3 potassium 3 magnesium 2 titanium 0,4 hydrogen 0,1 carbon 0,02 Especially helpful for material selection are material diagrams in which the target values for dierent materials are plotted. As an example, if good electrical conductivity combined with low material costs are required for a material of a power line, copper and aluminium are possible choices according to 1.4. 8 1 Introduction Figure 1.4: Ashby diagram: price vs. specic electrical resistivity. Created with help of the Cambridge Engineering Selector Edu Pack 2008. 9 2 Elastic stiness, atomic bonding and material structure If you bend a wire or a paper clip and the stress is low, any deformation caused by the load is completely reversed when the load is released. The material reacts like a spring which returns to its original shape when the load is released. The deformation is therefore reversible and is referred to as elastic deformation. On the other hand, if the load is increased above a critical value, the wire (or paper clip) will not fully return to its original shape. A part of the imposed deformation remains. Those deformations are called irreversible or plastic deformation. The example shows that plastic deformation is always combined with elastic deformation (the wire always springs back a little when released), whereas elastic elongation can also occur alone. This must be considered, for example, if one wants to produce a body sheet of a car by deep drawing, because the nal contour of the sheet does not correspond exactly to the contour of the forming tool due to elastic spring back when released. This is taken into consideration in practice by designing the forming tool suitably. In Chapter 2 we initially focus on elastic deformation. Chapter 2.1 is about describing and calculating elastic deformation. This will lead to an important material parameter, the Young's modulus. It indicates whether a material is particularly sti or particularly exible. This material parameter, which is particularly important for designing structural elements, is determined experimentally by the so-called tensile test, as discussed in Chapter 2.1.3. This is followed by the discussion of the reasons for elastic deformation and the question why polymers can be elastically deformed much easier than metals and ceramics. To understand this, we have to study atomic bonding (Chapter 2.2) and the structure of materials (Chapter 2.3). 2.1 Phenomenological description of elastic deformation 2.1.1 Nominal stress, nominal strain, elastic constants The elastic stiness of a spring is determined by the spring constant, which means a linear relationship exists between load F and elongation ∆l: D= D F ∆l F . ∆l (2.1) spring constant load elongation As explained above, the term elastic means that the elongation is reversible when the load is released. Likewise, the Young's modulus E is dened as a measure of the elastic 10 2 Elastic stiness, atomic bonding and material structure Figure 2.1: Illustration of the elastic stiness using a spring model. stiness of materials. If imagining the material as a three-dimensional arrangement of springs (Fig. 2.1), it is obvious that the elongation at a certain force is inversely proportional to the cross-sectional area S0 of the material. In order to eliminate this geometric dependence, the term normal stress is introduced: σ= F , S0 σ S0 (2.2) normal stress initial cross section where F is the applied load oriented perpendicular (i.e. normal) to the surface (Fig. 2.2(a)). The unit of the stress σ is 1 N/m2 = 1 PASCAL (Pa). It is often given in Megapascal (MPa) or Gigapascal (GPa), where 1 MPa = 106 Pa and 1 GPa = 109 Pa. Obviously, the elongation ∆l of the material is proportional to the length l0 in the direction of the load. Therefore a further normalized variable, strain, is introduced: ε= l − l0 ∆l = . l0 l0 ε l l0 (2.3) strain length in loaded condition initial length (unloaded) Under a normal load, which can be both a tension and a compression load, the socalled Hooke's law results in analogy to Equation 2.1: (2.4) σ =E·ε , E Young's modulus in which the Young's modulus E is a material-dependent parameter. Since the strain ε is a dimensionless value, the Young's modulus, like the stress, has the unit N/m2 or Pa. 11 2 Elastic stiness, atomic bonding and material structure ∆x S0 l0 F S F γ y ∆l (a) normal load (b) shear load. Figure 2.2: Basic load situations, adepted from [26]. If a material is extended as shown in Fig. 2.2 (a), the atomic distances are elongated and the atoms are moved out of their equilibrium distance r0 . As a result, the equilibrium distance decreases slightly in the transverse direction. This means that the atoms feel more comfortable to move closer in the transverse direction. The elongation in the longitudinal direction imposed by the stress σ thus results in a contraction in the transverse direction. The so-called Poisson's ratio indicates the ratio between transverse strain and longitudinal strain: ν=− εtrans . εlong ν εtrans εlong (2.5) Poisson's ratio transverse strain longitudinal strain (strain) Since εtrans und εlong always have dierent algebraic signs (+-), the minus sign is inserted so that ν is always positive. The Poisson ratio is another material constant characterizing the binding characteristics. Tab. 2.1 shows some typical values for the Poisson's ratio. Table 2.1: Poisson ratio for selected metals, ceramics and polymers. Material Poisson's ratio ν Al 0,34 α-Fe 0,29 Ni 0,31 Al2 O3 SiO2 0,23 0,20 Polystyrene 0,33 Polyethylene 0,40 As a rule of thumb you can remember: ν Metal ≈ 0.3, ν Ceramics ≈ 0.2, ν Polymers ≈ 0.4. 12 2 Elastic stiness, atomic bonding and material structure For ν < 0.5 tensile loading leads to an increase in volume and compressive loading to a decrease in volume. In a similar way to the normal load, where the stress vector is oriented perpendicular to the loaded surface, a relationship for a shear load can be established. In this case, the applied force F is parallel to the surface under consideration S (see Fig. 2.2(b)). The resulting shear stress is therefore dened as follows: τ= F . S (2.6) In contrast to a normal load, a shear load causes no deformation of the surface under consideration S . The surface S remains unchanged and no transverse contraction occurs. The shear stress τ is related to the shear strain γ via the shear modulus G: (2.7) τ =G·γ . shear stress shear modulus shear strain τ G γ γ corresponds to the angle change of an initial right angle (Fig. 2.2 (b)). For small angle changes tan γ is approximately γ and therefore: γ= ∆x . y (2.8) The shear modulus and the Young's modulus are related by the Poisson's ratio ν : G= E . 2(1 + ν) (2.9) This means that the elastic behaviour of an isotropic material is determined by two independent variables. A material is dened as isotropic if its properties are not dependent on the direction of loading, i.e. the same Young's modulus is measured in all directions of loading. This is usually the case for metals, ceramics and polymers with sucient accuracy. Many composite materials, such as ber-reinforced polymers and woods, on the other hand, exhibit a pronounced directional dependence of elastic stiness. They are anisotropic and the description of the elastic behavior becomes much more complicated. By plotting the Young's modulus E for typical structural materials (Fig. 2.3), a remarkable range can be observed. Obviously there is a dierence of up to ve orders of magnitude between the most elastically sti material (diamond) and the most exible materials (elastomers). If a polypropylene rod (E = 1000 MPa) with a length of 100 mm and a cross-sectional area of 10 mm2 were extended by 1 mm under a load of 100 N, this would only be 1 µm for a diamond rod. Furthermore, a clear demarcation between the material classes can be seen. Ceramics and metals are obviously sti, whereas polymers are elastically compliant. These very 13 2 Elastic stiness, atomic bonding and material structure Figure 2.3: Young's modulus for selected structural materials, adapted from [1]. large dierences are related to the dierent atomic structures of ceramics, metals and polymers. In order to gain a deeper understanding of the nature of the elastic behaviour of materials, the structure of matter is discussed in Chapter 2.2. 2.1.2 True stress and strain During normal loading, the transverse contraction causes the cross sectional area of the rod shown in Fig. 2.2 (a) to change with the load. Under tensile loading, the actual cross-sectional area S becomes smaller than the cross-sectional area in the initial state S0 . In case of compressive stress it is exactly the other way around. Strictly taken this should be considered when calculating the existing normal stress. However, if the elongation is small, as is usually the case with elastic loading, the change in cross-section is also small, so that the failure is negligible. Therefore, it is quite possible to work with eq. 2.2 and the calculated stress is called nominal stress. However, if the normal stress is calculated by using the actual cross-sectional area S it is called the true stress σw and the following applies: σw = F . S (2.10) The situation is similar for the strain. In eq. 2.3, the elongation is related to the initial length l0 and the strain ε thus dened is called nominal strain. It would be more accurate to imagine the elongation ∆l divided into many small increments dl and to relate this 14 2 Elastic stiness, atomic bonding and material structure incremental change in length to the current length l. The true strain change dφ occurring with each incremental length change is therefore given by: dφ = dl . l (2.11) In order to calculate the total strain φ from the initial length l0 to the nal length l1 , the strain increment dφ must be summed up by integration: Zl1 φ= dl l1 = ln = ln l l0 l1 − l0 + l0 l0 = ln (1 + ε) . (2.12) l0 Fig. 2.4 shows the nominal and true strain as a function of the normalized elongation ∆l/l0 . It can be seen that the dierence for small elongations is minimal, so that the nominal strain ε is a good approximation for the true strain φ. In general, the true strain for positive strains (tensile range) is less than the nominal strain, for negative strains (compression range) its value is greater than the nominal strain. ε, ϕ 1,0 0,5 −1,0 −0,5 0,0 0,0 0,5 −0,5 1,0 ∆l/l0 ε ϕ −1,0 Figure 2.4: Comparison of nominal and true strain [26]. Under shear stress, the surface on which the shear stress τ occurs does not change and no deformations transverse to the direction of stress occur. Therefore the distinction between nominal and true values is not necessary. 2.1.3 The tensile test Material characteristics, such as the Young's modulus E , must be determined experimentally. By far the most important test to determine such characteristic values and to describe the deformation behaviour of a material is the so-called tensile test according to DIN EN ISO 6892-1. In tensile tests, specimens are clamped in a testing machine and pulled apart at a constant speed (Fig. 2.5). The prevailing force is measured using a load cell mounted 15 2 Elastic stiness, atomic bonding and material structure Figure 2.5: Strain measurement in tensile test [26]. with the load rod. The specimen strain is determined with the use of a displacement transducer. The sensor consists of two measuring blades whose distance determines the initial length l0 . These measuring blades are pulled apart with the specimen and their extension ∆l is determined with the use of a measuring bridge. For a known crosssectional area S0 of the specimen, all information is available to display the result of the tensile test in the so-called stress-strain diagram. The value pairs for stress σ and strain ε measured at each point are entered into the diagram and the stress-strain curve which is characteristic for the respective material is obtained. In order to understand the stress-strain curves, it is important that the nominal stresses and strains are plotted. Fig. 2.6 shows typical stress-strain curves for two ceramics (Al2 O3 and Si3 N4 ), two metals (the structural steel S 355 and a so-called stainless steel with the designation X 5 CrNi 18 9) and two polymers (Polymethylene methacrylate and Polyethylene). It can clearly be seen that there is a linear relationship between stress and strain at low loads. In this area the material behaves elastically and obeys Hooke's law according to Equation 2.4. In the case of ceramics, this relationship persists until fracture. Thus, they only deform elastically. The other materials have a curve above a critical stress that deviates from the elastic straight line due to plastic deformation in addition to elastic deformation (Fig. 2.7). This critical stress is known as the Yield Stress Rp . It is important that the elastic strain εel can also be determined for a stress σ > Rp using Hooke's law. If the total strain εges is also determined, the plastic strain εpl can be calculated from the dierence between εges and εel . If the specimen is unloaded before it ruptures, the total strain does not remain constant. Instead, it decreases with the elastic strain. During unloading, the stress-strain curve thus forms a straight line with the slope dened by the Young's modulus (Fig. 2.7). The maximum stress the material can withstand is known as the tensile strength Rm . As the examples show, the material does not necessarily have to fracture when reaching Rm . In fact, ductile metals generally deform further before fracture occurs. From this point on, however, the deformation is no longer uniformly 16 2 Elastic stiness, atomic bonding and material structure 600 σ / MPa Si3N4 Si3N4 500 400 X5 CrNi18-9 S 355 300 200 Al2O3 Al2O3 100 Poly(methyl methacrylate) 0 0,0 0,002 0,0 0,1 0,2 0,3 0,4 0,5 0,6 Polyethylene 3,0 3,5 ε/ − Figure 2.6: Stress-strain curves of dierent materials, in the left part a detail view. Al2 O3 and Si3 N4 are ceramics. S 355 is a structural steel, X 5 CrNi 18 9 is an austenitic steel. Poly(methyl methacrylate) (PMMA) and Polyethylene (PE) are polymers. [26]. distributed over the specimen volume, but the material begins to contract at a certain point. This results in a strong local contraction of the cross-section and is the reason why the nominal stress decreases. If, on the other hand, the true stress were plotted, it would rise until fracture. σ Rm R p0,2 0,2% E εel εpl εges Ag A ε Figure 2.7: Schematic stress-strain diagram of a ductile material, important characteristic parameters: Rm : tensile strength, Rp0,2 : Yield stress, (Ag : uniform strain), A: fracture strain, E : Young's modulus, adapted from [26]. In practice, there is a problem in determining the yield strength Rp : because plastic deformation slowly sets in with increasing stress, it is not possible to determine the exact 17 2 Elastic stiness, atomic bonding and material structure beginning of plastic deformation. This is solved by a pragmatic approach by drawing a parallel to the elastic line which is shifted by 0.002 (i.e. 0.2 %) to larger strain values (Fig. 2.7). At the point of intersection between this parallel shifted linear line and the stress-strain curve, the corresponding stress value is read o and referred to as the yield strength Rp0,2 . The numerical value i.o. thus indicates how the yield strength was determined. σ / MPa Rm fracture Rp0,2 σ / MPa necking Rm R eH R eL fracture necking E E A A ε / % ε / % (a) Ductile material without apparent yield poin (b) Ductile material with apparent yield point Figure 2.8: Schematic stress-strain curves, adapted from [26] (see also DIN EN ISO 6892-1). Many steels, such as the structural steel S 355 shown in Fig. 2.6, show a specic property when the critical stress is reached, from which on plastic deformation occurs: the stress suddenly decreases and stabilises at a lower level before increasing again. In this case we do not speak of the yield strength Rp , but - as shown in Fig. 2.8 (b) - of the upper yield strength ReH and the lower yield strength ReL . The tensile test is generally terminated by the fracture of the specimen. The remaining strain after fracture is referred √ to as elongation after fracture A or Ak , where k is calculated from the ratio k = l0 / S0 . If no value is given for k , a ratio of 5.65 is used according to DIN EN ISO 6892-1. 2.2 The atomic bond We return to the question of why the Young's Modulus of polymers is by far lower than that of ceramics and metals. To address this, we have to consider the atomic bonds between the atoms, which can be quite dierent in the various materials. The occuring bonding types include the ionic bond, the covalent bond, the metallic bond and the secondary bond. As we will see, the type of bonding determines quite substantially the elastic stiness of the material and also other properties - e.g. electrical conductivity . Therefore, the individual types of bonds will be discussed in the following. 2.2.1 Basics Atoms consist of a positively charged atomic nucleus surrounded by negatively charged electrons. The electrons of an atom cannot arrange themselves in an arbitrary way 18 2 Elastic stiness, atomic bonding and material structure around the atomic nucleus. Rather, they are located on so-called electron shells, which are arranged at an increasing distance from the atomic nucleus and can each only hold a limited number of electrons. The further away an electron shell is from the atomic nucleus, the greater the energy of the electrons in this shell, so that electrons on the outer shells are bound to the nucleus weaker than those on the inner shells. Only these outer, energy-rich electrons participate in the chemical bond, because only they feel their environment and can possibly form bonds with other atoms. Electrons cannot be localized at a certain position. One can only state a certain probability that an electron is at a certain position. So there are places in the vicinity of the atomic nucleus where an electron prefers to be, while it avoids other places. The area where the electron can be found is called the electron cloud or orbital. Fig. 2.9 shows some examples of electron orbitals. It can be seen that there are spherical orbitals as well as directional orbitals. An electron shell is generally composed of dierent orbitals. Each of these orbitals can take a maximum of two electrons. z z y z y z y x x (a) s - orbital y x x (b) p - orbitals. z z y z y x x z y y x x (c) d - orbitals. Figure 2.9: Schematic representation of some electron orbitals, adapted from [26]. The basic structure of the electron shell is the same for all atoms. The innermost electron shell of all atoms, called the K-shell, can hold a maximum of two electrons, since it has only one spherically symmetric orbital (the s-orbital). The next shell, the L-shell, holds up to eight electrons, two of which occupy a spherically symmetric sorbital, while the other six take up the three p-orbitals. Since nature strives for low energy states, the electron shells of an atom are always lled from inside to outside according to the energy scheme shown in Fig. 2.10. In the periodic table, the elements where the rst electron shell is lled (H and He) are found in the rst period. The eight elements (Li, Be, B, C, N, O, F, Ne) where the second shell is lled, in the second period and so on. Energetically particularly favourable are states in which the electron shells are fully occupied. This is the case with noble gases, such as helium, neon or argon. Therefore, they are essentially chemically inert. Fluorine, on the other hand, is very 19 2 Elastic stiness, atomic bonding and material structure reactive, because it is anxious to capture an additional electron and, by that, also to form a completely lled electron shell. 6p 6s 5p 5s 4p energy 4s 5d 4f 4d 3d 3p 3s 2p 2s 1s Figure 2.10: Energy levels of electron orbitals in the periodic table. In principle, a bond between atoms takes place when the electron arrangement is energetically more favourable in the bound state than in the unbound state. There are two important principles leading to a low energy electron arrangement: 1. The above mentioned attempt to achieve completely lled electron shells. 2. The attempt of the electrons to occupy a space as large as possible. Ultimately this is responsible for the fact that the electrons do not fall into the nucleus despite attraction by its positive charge. 2.2.2 The ionic bond The ionic bond is formed between two dierent types of atoms. It is always an atom with an almost lled and one with an almost empty outer electron shell such as the alkali metal sodium and the halogen chlorine1 . If the sodium atom gives an electron to the chlorine atom, then the chlorine atom can completely ll the outer electron shell with electrons and also the sodium atom reaches this state because the formerly outermost electron shell is now completely empty and the underlying shell is completely lled. As explained above, this is particularly favourable in terms of energy and therefore an ionic bond is formed between the atoms involved. In the case of sodium and chlorine, common salt (NaCl) results. If one imagines one sodium and one chlorine atom each, which are far away from each other, the formation of the ionic bond between the two elements can still be inspected more closely: First we imagine to remove from the sodium atom the electron in the 1 In this case, only one electron binds to the 3s orbital of sodium. Chlorine requires eight electrons to completely ll the 3s- and 3p-orbitals with electrons, but for this purpose it has only seven electrons available. 20 2 Elastic stiness, atomic bonding and material structure outermost electron shell. This leads to a positively charged Na+ -ion and the ionization energy required for this is 5.1 eV (1 eV = 1.6 · 10−19 J). If the electron is transferred to the chlorine atom, this is energetically favourable because the outermost electron shell of the chlorine atom is now completely lled with electrons. The energy gain is -3.6 eV and a Cl− -ion is created. Altogether, this results in an energy expenditure of 5.1 eV - 3.6 eV = 1.5 eV. However, there exists an attractive electrostatic force between the positively charged Na+ -ion and the negatively charged Cl− -ion. It is given by Fatt = q1 q2 . 4πε0 r2 Fatt q1 , q2 ε0 r (2.13) attractive electrostatic force atomic charges dielectric constant ion spacing Thereby, q1 and q2 are the atomic charges of the two ions, ε0 is the dielectric constant and r is the ion spacing. If both ions are now approached to a distance of 0.4 nm, an energy of -3.6 eV is released. Therefore, the energy gain is 1.5 eV - 3.6 eV. = -2.1 eV and an ionic bond is formed. In common salt, the actual energy gain is even a little bit higher, because not only two but many ions are connected to each other and a Na+ -ion surrounds itself with several Cl− -ions (Fig. 2.11). The same applies to a Cl− -ion. Figure 2.11: Schematic representation of the ionic bond using sodium chloride (NaCl) as an example. The electrostatic attraction is countered by a repulsive force Frep ∼ r−n (n ≫ 2). Therefore, the atoms or ions do not come arbitrarily close, but, as sketched in Fig. 2.12, reach an equilibrium distance r0 , at which the force of attraction and the force of repulsion are balanced. If one looks at the cumulative curve, which results from Coulomb attraction and the repulsive force, one nds out that its shape around r0 resembles a parabola. The parabola can be described by the relationship U = U0 + 1/2 k(r − r0 )2 , where k is a constant. By dierentiating once according to the local coordinate, one obtains the force Fi = −dU/dr, which results when the atoms are deected from their equilibrium position r0 . In the case of the parabola, Fi = k(r0 −r) is obtained. As shown in Fig. 2.12, this equation describes the behavior of a spring with the spring constant k . The behaviour of atomic bonds under mechanical stress is therefore similar to that of a 21 2 Elastic stiness, atomic bonding and material structure spring. Accordingly, we can symbolically represent atomic bonds by elastic springs, as in Fig. 2.1. This simple model is suitable for all bonds. If one dierentiates again according to the local coordinate, one can directly make a statement about the stiness S of the atomic bond and, thus, of the materials: S=− S Fi dFi . dr (2.14) stiness of the atomic bond interaction force between the atoms Now the elastic behaviour of materials becomes understandable. Under mechanical stress, the atomic bonds are obviously stressed and the atomic distances change. If the load is removed from the material, the original bond spacing r0 is established, i.e. the deformation is reversible (= elastic), just like with a spring. Since the elastic strain of technical materials is also very low (it is no more than a few tenths of a percent for metals and ceramics), the rigidity S practically does not change under stress (Fig. 2.12). Therefore, in the tensile test we nd an elastic straight line and with the modulus of elasticity E a constant material property. The dierences in the modulus of elasticity of dierent materials that have already been noticed are now also becoming clear. If the bond between the atoms is particularly strong, the curvature of the potential curve around the equilibrium position r0 also increases. This results in a greater stiness S of the atomic bond and a greater spring constant k of the associated parabola (Fig. 2.13), which is macroscopically reected in a larger Young's modulus. As we have seen, common salt is an inorganic compound between a metal (Na) and a non-metal (Cl) and thus a ceramic, although without technical relevance. Ionic bonds therefore occur in ceramics and belong to the strong bond types, as shown in Table 2.3. This is in accordance with our observation that strong bonds lead to high moduli of elasticity and that ceramics have a high have elastic rigidity. 2.2.3 The covalent bond Also in covalent bonding, the bonding principle is to achieve electron shells that are completely lled. However, in this case atoms are involved with little dierence in electronegativity. The electronegativity is a measure of the force with which an additional free electron is attracted to an atom. In this case, the transfer of an electron from one atom to another does, thus, not succeed. Nevertheless, the partners involved nd a way to ll their electron orbitals completely by sharing electrons. For example, hydrogen with a single electron on the K -shell needs another electron to ll this shell. Two hydrogen atoms can therefore combine and share their electrons. This creates a hydrogen molecule H2 and the bond type is called covalent. Carbon has four electrons on the L-shell, so it must form four covalent bonds to ll it completely with eight electrons. This is the case with the CH4 molecule, for example. As shown in Figure 2.14,this creates four club-shaped orbitals, each of which has a hydrogen atom at its ends, whereas the carbon 22 2 Elastic stiness, atomic bonding and material structure energy U repulsion spring U = U0 + 1/2 k (r-r0)2 ∆E distance r Coulomb attraction r0 rD ~ 1,25 r0 force Fi distance r stiffness S r0 rD ~ 1,25 r0 Technically relevant range distance r Spring analogue: F = k (r0 - r) U = 1/2 k (r0 - r)2 r0 r Figure 2.12: Interaction forces between two atoms with equilibrium distance r0 (Bonding energy U , Interaction force between the atoms Fi d2 U/dr2 ), adapted from [26]. 23 = −dU/dr, Stiness S = 2 Elastic stiness, atomic bonding and material structure energy U Frep1 << Fatt2 k1 << k2 Frep spring U = U01 + 1/2 k1 (r-r01)2 r01 distance r U = U02 + 1/2 k2(r-r02)2 Fatt1 r02 Fatt2 Figure 2.13: Eect of the atomic bond strength on the modulus of elasticity E : A larger Coulomb attraction Fatt leads to a more strongly curved potential curve around r0 and thus to a larger spring constant k . atom is located at the center. The covalent bond is thus directed and the arrangement of the atoms involved is precisely determined by it. Since each orbital is occupied by two electrons, two electrons are arranged around each hydrogen atom and eight electrons around the carbon atom. The principle of completely lled electron shells is fullled. Figure 2.14: Electron orbitals of the methane molecule [8]. 24 2 Elastic stiness, atomic bonding and material structure Another example is diamond, which consists only of carbon atoms. Here, too, each carbon atom forms four club-shaped orbitals, but now there is a further carbon atom at each end, which itself is surrounded by four carbon atoms. The resulting spatial arrangement, in which each carbon atom has four covalent bonds to adjacent carbon atoms, is shown in Figure 2.15. Figure 2.15: Diamond structure with electron orbitals [26]. The example of the diamond shows that the covalent bond also occurs in ceramics and Table 2.3 demonstrates that this type of bond is also one of the strongest bonds. In fact, the carbon-carbon bond is the strongest known bond. This explains why diamond has the highest modulus of elasticity (approx. 1000 GPa) and also the highest hardness and melting temperature (3727 C) of all substances known to us. Technically this is used, for example, by depositing diamond layers on tools (e.g. tools for metal cutting), which enormously improves their wear resistance. Diamond coatings are also used in piezo injection systems for diesel engines in order to minimize friction and wear between components moving against each other. Carbon bers have a dierent arrangement of carbon atoms than diamond. Nevertheless, the strong carbon-carbon bond leads again to high E-moduli, which are between 140 GPa and 820 GPa depending on the ber type. Considering that steel has a modulus of elasticity of about 200 GPa at four times the density, one recognizes the great potential of using carbon bers to create particularly light and rigid structures (such as an aircraft fuselage). Figure 2.15 shows that all orbitals of the carbon atoms in diamond have exactly the same shape. Nevertheless the electrons on these orbitals feel slight dierences. For example, an electron that is bound to the diamond surface notices that it is only halfsided surrounded by neighboring electrons, whereas an electron in the interior nds adjacent electrons on all sides. Therefore, the energy of these electrons is no longer identical. This fact is illustrated in Figure 2.16: When electrons approach from a great distance and combine to a solid, the individual energy levels split into energy bands. The last energy band lled with electrons is called the valence band. In diamond it ° 25 2 Elastic stiness, atomic bonding and material structure is completely lled with electrons, since all orbitals are completely lled with electrons. Generally speaking, it can be said that both the covalent as well as the ionic bond lead to a completely lled valence band, since they are based on the principle of completely lled electron shells. As Figure 2.16 shows, above the valence band (i.e. at higher energies) further permissible energy levels occur, but they are empty. energy U vacant vacant filled partially filled r 0 distance r energy levels insulator metal Figure 2.16: Energy levels of the metallic and covalent bond. Using the example of common salt and diamond, we have seen that ceramics can have covalent or ionic bonds. On closer inspection, however, we nd that the chlorine atom is not able to completely bind the outermost electron of sodium to itself. This means that this electron also orbits the sodium atom, although it is located much more often around the chlorine atom. Thus, there is a smooth transition from the ionic bond to the covalent bond and Table 2.2 shows that ceramic materials generally have partly ionic and partly covalent bonds. However, for diamond the ionic share is zero, because it only consists of one type of atoms. Table 2.2: Percentage bond fraction of the ionic bond in various ceramic materials. material ionic bond fraction /% CaF2 89 NaCl 67 Al2 O3 SiO2 Si3 N4 63 SiC 12 diamond 0 51 30 26 2 Elastic stiness, atomic bonding and material structure 2.2.4 The metallic bonding Already in chapter. 1.2 we have seen that most elements are metals and that they are found on the left side of the periodic table. As the example of sodium shows, they have far too few electrons on the outermost electron shell for it to be possible to completely ll the outermost shell by covalent bonds. This principle of reaching an energetically favourable state obviously does not work with metals. Therefore, metals have no other choice than to fall back on the second principle, namely to distribute the electrons of the outermost shell over as large an area of space as possible. This is easy for them, because these electrons are only weakly bound to the atoms anyway. Therefore, one has to imagine that these outermost electrons in the metal are practically able to move freely. Since they move inside the metal like a gas in a container, one often speaks of an electron gas Figure 2.17: Schematic representation of the metallic bond using sodium as an example. Figure 2.17 illustrates the bonding state schematically, whereby the uniform grey value between the atomic nuclei is intended to symbolize that the probability of the electrons of the outermost shell being present there is the same. This makes clear that the metallic bond is not directed. It is not quite as strong as the ionic and covalent bond. However, the metals compensate for this by a trick, as we will be discussed in chapter 2.3 more closely: While a carbon atom in diamond surrounds itself only with four nearest neighbours and forms four covalent bonds, an aluminium atom, for example, has 12 nearest neighbours. So more bonds are formed and in the nal result the binding energies of metals are, thus, comparable to those of ceramics, as shown in Table 2.3. This makes it understandable, why the elastic rigidity of both groups of materials is at a comparable level (Figure. 2.3). In the case of metals, too, discrete energy levels give rise to energy bands as shown in Figure 2.16. However, since metals are not able to completely ll the outermost electron shell with electrons, the valence band (i.e. the last band still containing electrons) is not completely lled with electrons (Figure 2.16). This has an important consequence if an electric voltage U is applied against a metal. As a result, a force E · e is exerted on the 27 2 Elastic stiness, atomic bonding and material structure electrons, where E is the electric eld strength and e is the charge of an electron, and they are accelerated in the direction of the electric eld. So there is a current, because the electrons of the valence band now move in a certain direction. Through this movement the electrons absorb kinetic energy, i.e. their energy increases. This is not a problem, because in the valence band, unoccupied states are available that allow a slightly higher electron energy. Accordingly, metals have good electrical conductivity. The situation is completely dierent with ceramics. Here the valence band is completely lled and, therefore, the electrons cannot absorb any additional energy. The energy jump to the next unlled band is too great for this. The electrons have no other possibility than to stay close to the atomic core. Therefore, ceramics are electrical insulators. The energy gap between the valence band and the next higher band (the so-called conduction band) is not the same for all ceramics. With the so-called semiconductors, such as silicon, it is relatively small. Therefore, a few electrons are still able to jump on this conduction band and conduct some electricity. The resulting current conductivity is nevertheless much lower than that of metals. Figure 2.18: Ashby-diagram: Thermal conductivity vs. specic electrical resistance. Created with the Cambridge Engineering Selector Edu Pack 2008. 28 2 Elastic stiness, atomic bonding and material structure Electrons can transport not only electricity but also heat. For this reason, all metals are also good heat conductors as Figure 2.18 shows. The dierences, however, are considerable. For example, the thermal conductivity of many steels is almost an order of magnitude lower than that of aluminium or copper. That is why you dont burn your ngers when you touch the steel handle of a cooking pot. As Figure 2.18 shows, the reverse conclusion that all electrically insulating materials should also be good thermal insulators is not necessarily correct. This is because the atoms are excited by heat to oscillate. If one heats a material one-sided, atoms there start swinging strongly. Because of the spring-type bonding between the atoms they also excite neighbouring atoms to oscillations and thus heat is transported from one end to the other. This works particularly well with diamond, aluminium nitride and silicon carbide (SiC), so that their thermal conductivity is at the level of aluminium alloys, although their electrical conductivity is lower by many orders of magnitude. With ceramic brakes in expensive cars, consisting of a carbon bre-reinforced SiC matrix, this fact is exploited. The advantages over brake discs made of grey cast iron are the lower weight (the density of SiC is less than half of grey cast iron) and the particularly high temperature resistance of SiC. However, because the manufacturing is complex, such a brake is also quite expensive. 2.2.5 Secondary Bonds Water (H2 O) is a covalently bonded molecule, with both oxygen and hydrogen completely lling their outer electron shells with electrons. Accordingly, one wonders how bonding between water molecules is possible in ice. Obviously, there is no longer a possibility to form covalent bonds between the molecules. In this context, it is important that the oxygen atom attracts electrons more strongly than hydrogen. So oxygen is more electronegative. This results in a charge shift as shown in Figure 2.19. Although the water molecule is electrically neutral (it is not positively or negatively charged), it is an electric dipole. Therefore, dierent H2 O molecules try to arrange themselves in such a way that sides with positive and negative excess charge are directly adjacent (Figure 2.19). This results in an attraction between the molecules, which is called dipole bonding. Table 2.3 shows that the dipole bonds are much weaker than the other three types of bonds. It is also evident that the binding energy between water molecules is comparatively high. This is due to the fact that the electronegative oxygen atom deprives the hydrogen atom of its electron shell (it only has one electron). Therefore, the hydrogen atom can come very close to the oxygen atom of a neighbouring molecule, resulting in a comparatively large binding force. This type of bond is called hydrogen bond. At the moment it is not yet understandable why there is a weak attraction even between molecules that do not have a permanent dipole moment. For example, this weak attraction is the reason why even noble gases are liquid at suciently low temperatures and eventually become solid. So let us imagine, for example, two neighboring argon atoms (Figure 2.20). The electrons around the atoms are on average equally distributed. But at a certain point in time, the left atom just happens to have an excess of electrons on the left side. So for that moment there is an electric dipole and the adjacent atom to the right reacts to this with a charge shift, so that an attractive force is created between 29 2 Elastic stiness, atomic bonding and material structure Figure 2.19: Schematic representation of the dipole bond. r - - + statistically derived dipole + induced dipole Figure 2.20: Schematic representation of the van der Waals bond: The atoms are kept together by time-varying dipole moments, adapted from [4]. the two atoms. This type of dipole bond, which is based on temporal uctuations in the electron distribution, is also called van-der-Waals bond. It is even weaker than the binding based on permanent dipole moments. The dipole bond is mainly responsible for the binding in polymers, as explained in chapter 2.3.3. Since the bond energy is 10 to 100 times lower than that of ionic, covalent and metallic bonds, the low modulus of elasticity of polymers can be understood. A direct correlation between the melting temperature of the materials and the bond strength can also be seen in Table 2.3. This explains why polymers have a low thermal stability and why application temperatures above 100 C are the exception. ° 30 2 Elastic stiness, atomic bonding and material structure Table 2.3: Bonding energy and melting point of dierent materials. type of bond material bonding energy /(eV/atom) ionic covalent metallic dipole bond melting point / NaCl 3.30 801 MgO 5.20 2800 Si 4.70 1410 C (diamond) 7.40 Hg 0.70 > 3550 −39 Al 3.40 660 Fe 4.20 1538 W 8.80 3410 Ar 0.08 Cl2 NH3 H2 O 0.32 0.36 −189 −101 −78 0.52 0 2.3 The structure of the materials By discussing the bond types in chapter 2.2 , the origin of elastic strain and the reason why dierent materials have dierent elastic stinesses could be explained. It also became understandable why metals are good electrical and thermal conductors, whereas ceramics insulate electrically. However, many things are still unclear; for example, why metals but not ceramics can be plastically deformed, why high-strength aluminium alloys can be ten times stronger than pure aluminium, or why elastomers can often be elastically stretched to several times their initial length, whereas the elastic elongation of metals and ceramics is no more than a few tenths of a percent. To understand this, it is now necessary to deal with the structure of materials from a microscopic to a macroscopic scale. It will be shown that the type of bond and the structure of the materials are closely related. 2.3.1 Metals As discussed in chapter 2.2.4, metal atoms have the tendency to surround themselves with as many neighbouring atoms as possible in order to be bound as rmly as possible in the material. This is easy for them because the metallic bond is not directed, in contrast to covalent and ionic bonds. If one imagines the atoms as spheres and reects how to pack them as tightly together as possible, it is easy to see the resulting atomic arrangement. If one places spheres with the same diameter in a plane, the tightest possible packing is achieved by arranging the spheres in rows whereby all spheres touch each other and each row is shifted by half the diameter of a sphere relative to the adjacent one (Figure 2.21). This is exactly how billard balls are arranged at the beginning of the game. Each sphere is surrounded by six nearest neighbours in the plane. To obtain a close-packed arrangement of spheres in three dimensions, such close-packed planes are stacked on top of each other in such a way that the spheres of the following 31 2 Elastic stiness, atomic bonding and material structure Figure 2.21: Close-packed sphere packing of stacking sequence ABC. layer come to rest in the depressions of the preceding layer (Fig. 2.21 ). If the lowest level is called the A level and the second level is called the B level, the atoms of the third level can be placed in the depressions of the B level so that they lie exactly above the A atoms. If one continues this construction principle in thought and stacks the fourth plane on the positions corresponding to the second plane etc., the stacking sequence ABABAB... of the planes follows. However, as shown in Fig. 2.21, the third plane can also be placed in the troughs of the second plane in such a way that it takes up a new position C, which does not coincide with either the rst or the second plane. Continuing this construction principle, the stacking sequence is ABCABCABC... . Both arrangements are closepacked arrangements with a space lling of 74 % of the total volume. A larger lling of the space is not possible with spheres of the same size. Since each atom has not only 6 closest neighbours in the plane but also three in the plane above and below, the total number of closest neighbours is 12. This multitude of nearest neighbours results, as mentioned above, in the fact that the metal atoms are strongly bonded although the metallic bond is not quite as strong as the covalent or ionic bond. Aluminium, copper and nickel are examples of metals that have an atomic arrangement according to the stacking sequence ABCABC. Titanium and magnesium are examples for metals with the stacking sequence ABAB. The metal atoms are thus arranged according to a regular recurring pattern. Therefore, there is not only a short range order, by which the arrangement of atoms in the immediate vicinity is dened, but also a long range order, because also the atomic arrangement in a far distance is exactly dened by the periodic arrangement of the atoms. Whenever such a long range order exists, one speaks of a crystal or a crystalline material. Therefore, metals such as aluminium, nickel or titanium are crystalline materials. In order to be able to describe the respective atomic arrangement in a simple way, socalled unit cells are used. Fig. 2.22(c) shows the one for the tightest sphere packing with stacking sequence ABAB. Here the closest packed A and B planes are easily recognizable. Because the unit cell has the shape of a straight prism with a hexagon as basis, the atomic arrangement is called hexagonal close packed crystal structure. For the edge lengths of the unit cell, a ̸= c applies. Since the atoms are very small, the same applies to the edge 32 2 Elastic stiness, atomic bonding and material structure lengths. They are typically 0.2 nm to 0.6 nm. The unit cell for the stacking sequence ABCABC is shown in Fig. 2.22 (a). Because it is a cube with edge length a, the atomic arrangement is called the cubic close packed crystal structure. Since each cube face has an atom arranged in its center in addition to the corner atoms, one also speaks of a face-centered cubic crystal structure. The closest packed planes are not so easy to see here. Their normal is oriented along the space diagonal of the unit cell. Thus, the closest packed planes lie diagonally in the unit cell as shown in Fig. 2.22(b). Another important structure of metals is the body centered cubic crystal structure (Fig. 2.22 (d)). Its name is derived from the fact that the unit cell is again a cube, where besides the corner atoms an atom is also located in the center of the cube. With a space lling of 68 %, this crystal structure is no longer packed most closely. But the packing density is still very high (compare NaCl structure: 52 % space lling). Apparently, additional covalent bonds come into play, which stabilize this structure in certain metals. Iron is the most important metallic element, which forms this crystal structure at ambient temperature. However, it transforms to the face-centered cubic crystal structure at 911 C. This transformation is of tremendous technological importance. Thanks to it, steels are so important and high-strength steels can be made. If one takes unit cells and links them together in all three directions of space, a crystal, e.g. from aluminium, is created. Hereby, one has to imagine that contact areas between adjacent unit cells merge to one area. Once again, the long range order can be seen in this: If the rst unit cell is placed in space with a certain orientation, the position of all other unit cells is xed. The formation of such crystals occurs in reality during solidication from the liquid or, in special cases, from the gaseous state. Everyone knows about the formation of snow crystals, where each of the snowakes shown in Fig. 2.23 is a single crystal. In Fig. 2.23, the long range order and the resulting unique building principle can be clearly recognized. Also precious stones consist of a single crystal. In technical applications, however, single crystalline materials are the exception. The most important examples are silicon wafers for the semiconductor industry and single crystalline turbine blades in aircraft engines or gas turbines for power generation. In contrast, polycrystalline materials, i.e. materials that consist of many crystals, are the rule. This is so because the solidication of a melt normally produces many small crystal nuclei (Fig. 2.24 (a)), which grow during solidication (Fig. 2.24 (b-e)) until they touch each other and the material completely solidies (Fig. 2.24 (f)). In Fig. 2.24 each square shall represent a unit cell. The dierent crystals, also called crystallites or grains, dier in the position of their unit cells in space. Within a grain the long range order is given. If, however, one crosses the boundary of a grain, the orientation of the unit cell changes in an unpredictable way. Thus, one gets from one grain to another. The border between the grains is called the grain boundary. As Fig. 2.25 shows, the periodicity is disturbed here. Grain boundaries have a thickness of about two elementary cells, i.e. about 1 nm (1 nm = 10−9 m). In contrast, typical grain diameters are 0.01 mm - 0.1 mm. If the surface of a polycrystalline metal is etched with an acid, a preferred attack occurs along the grain boundaries, because the atomic arrangement is disturbed there and the atoms can be attacked more easily by the acid. As Fig. 2.26 (d) illustrates, light rays ° 33 2 Elastic stiness, atomic bonding and material structure A a ne pla C a A eB n pla a a a a (a) Unit cell of the face-centered cubic crystal structure. (b) Closest packed planes in the face-centered cubic crystal structure. plane A a plane B c plane A a a a (c) Hexagonal closest packed crystal structure. (d) Body-centered cubic crystal structure. Figure 2.22: Structure of the metals, adapted from [26]. 34 2 Elastic stiness, atomic bonding and material structure Figure 2.23: Snowakes [21]. (a) (b) (c) (d) (e) (f) Figure 2.24: Schematic representation of nucleation and nucleation growth of crystals during solidication from the molten state, adapted from [22]. 35 2 Elastic stiness, atomic bonding and material structure Figure 2.25: Structure of grain boundaries in metals and ceramics [18]. incident there are therefore scattered and the grain boundaries appear dark when viewed under a light microscope. The light microscopic image of polycrystalline, essentially pure iron is shown in Fig. 2.26 (a) and the grain boundaries are visible as dark lines. Because one is on the microscopic length scale, one also speaks of the microstructure of the material. The microstructure of most technically important materials is not as simple as that of pure iron. For example, the steel C45, which contains 0.45 percent (wt.%) carbon in addition to iron, also contains lamellar iron carbide Fe3 C, which appears black in Fig. 2.26 (b). In so-called nickel-based superalloys, which are used to make turbine blades for aircraft engines, one nds extremely small cube-shaped precipitates in the nickel-rich matrix (Fig. Abb. 2.27). Imagine a large block of a polycrystalline material, e.g. an aluminum block. If tensile specimens are cut from this block in completely dierent directions, in most cases identical values for the E-modulus, the yield strength Rp or the tensile strength Rm result. In this case the properties of the examined material are the same in all directions in space and one refers to this, as already mentioned, as isotropic behaviour. This was not to be expected a priori because if we look at the unit cells in Fig. 2.22 or the spring model in Fig. 2.1, one would rather expect that, for example, the stiness of a crystal should depend on the loading direction, i.e. that the behaviour is anisotropic. However, the crystallites in polycrystals are usually arranged randomly, so that these dierences are averaged out. In contrast, a single crystalline turbine blade actually behaves anisotropically. Its modulus of elasticity in the longitudinal direction of the blade is signicantly smaller than perpendicular to it. 2.3.2 Ceramics The structure of crystalline ceramics is similar to the structure of metals. However, the atoms in ceramics are not arranged in a close-packed structure, and the covalent or ionic bond between the atoms lead to dierent crystal structures than in metals. The unit cell of diamond has already been shown in gure 2.15. Figure 2.28 (a) 36 2 Elastic stiness, atomic bonding and material structure (a) Iron with a carbon content of 0.03 wt.-%. (b) Iron with a carbon content of 0.45 wt.-%. microscope polished and etched surface surface notch grain boundary (c) Grain structure of Al2 O3 . Scanning elec- (d) Image generation at the optical microscope, tron microscope image. The horizontal white adapted from [10]. bar has a length of 1 µm [26]. Figure 2.26: Microstructure of metals and ceramics. shows the unit cell of NaCl. Since the ionic bond predominates here, the atoms are arranged in a way that each atom is neighboured by oppositely charged atoms, whereas equally charged atoms are arranged in a longer distance to each other. In crystalline SiO2 (Quartz), the covalent bond predominates, where every Si atom is neighboured by four oxygen atoms, and every oxygen atom has two bonds with every adjacent Si atom (g. 2.28 (c)). Fig. 2.29 shows the mineral calcite as an example of crystalline ceramics. Each calcite platelet is a single crystal. Fig. 2.26 (c) shows the polycrystalline microstructure of the important technical ceramic Al2 O3 . Due to the etching contrast, the grain boundaries are clearly visible as groves. As with metals, technical ceramics are normally polycrystalline From the above examples, it is apparent that the unit cells of ceramics are much more complicated than those of metals. If a ceramic solidies from the liquid state, it is thus 37 2 Elastic stiness, atomic bonding and material structure Figure 2.27: Microstructure of a nickel base superalloy. much more dicult for the atoms to be arranged in space according to the requirements of the unit cell. This needs much more extensive atomic rearrangements. If there is not enough time for this, the long range order cannot be established and only a short range order occurs. In the example of SiO2 , every Si atom is surrounded by the required number of oxygen atoms. However, this short range order does not repeat periodically, so that there is no long range order (Fig. 2.28 (b)). In contrast to crystalline materials, such materials are called amorphous or glasses. Window glass is an amorphous material that consists mainly of SiO2 . If window glass were to be kept for a long time at several hundred degrees Celsius in a furnace, it would begin to form crystallites, which would then grow until the material is completely polycrystalline. The glass would thereby lose its optical transparency and become opaque, because the grain boundaries would scatter the incident light. This example shows that the crystalline state is the stable condition. The only reason it did not form during solidication is because the time was not enough for that. If we consider the specic volume (i.e. the reciprocal of density) as a function of temperature, important dierences between solidication to a crystalline or amorphous material can be illustrated once again. For this purpose, we assume that the melt solidies into a crystalline solid at the temperature Tm , the melting temperature, if there is sucient time for this to happen. Hereby, the atoms are regularly arranged and, thus, the specic volume decreases sharply during crystalline solidication (Fig. 2.30). If, on the other hand, cooling is rapid so that crystallization does not succeed, the liquid state is initially retained. The atoms coordinate themselves as shown in Fig. 2.28 (b). However, the thermal movement of the atoms is so strong that atomic bonds are constantly broken and reattached. Thus, the atoms are constantly in motion. As the temperature decreases, this movement decreases until it suddenly becomes impossible when a critical temperature, the glass transition temperature Tg , is reached. The melt freezes, so that we can imagine the amorphous state as that of a frozen melt. From what has been said it follows immediately that the glass transition temperature Tg (often also called glass temperature) must be lower than the melting temperature. 38 2 Elastic stiness, atomic bonding and material structure Na+ Si O Cl– 3r 2r r r (a) Crystalline ceramic with predominantly ionic bonding components (NaCl), adapted from [26]. (b) Amorphous structure of a ceramic. Due to the two-dimensional representation only three bonds per silicon atom are shown [3]. Si4+ O2– (c) Crystalline ceramic with covalent bond character (SiO2 ), adapted from [6]. Figure 2.28: Examples of the structure of ceramic materials. 2.3.3 Polymers Structure of the polymer groups The backbones of almost all polymers are carbon chains (Fig. 2.31 (a)), i.e. chains of covalently bonded carbon atoms. Hereby, the tetravalent carbon atoms form two covalent bonds to adjacent carbon atoms along the chain and two covalent bonds to side groups. In the simplest case, the side groups are hydrogen atoms, so that polyethylene results (Table 2.4). However, they can also consist of other atoms (e.g. Cl, F, O) or molecules (e.g. CH3 , OH). The molecular chains have a three-dimensional structure with binding angles of 109 . Of decisive importance for the mechanical behaviour is the fact that the chains are able to rotate along the carbon-carbon bonds (Fig. 2.31 (b)). Due to this ability, they can be either stretched or entangled (Fig. 2.31 (c)). ° 39 2 Elastic stiness, atomic bonding and material structure Table 2.4: Structure and properties of polymers (Tg : glass transition temperature, Tm : melting temperature), adapted from [26]. Name Structural formula Applications Tg / Tm / −25 −15 150 175 −110 −90 125 132 Thermoplastic polymers H CH3 Polypropylene, PP Polyethylene, PE Polystyrene, PS Tubing, bottles, insulation C C H H n H H Tubing, bottles, electrical insulation C C H H n H H C C H Thermal insulation (foam) 74 100 usually amorphous n usually H Polyvinyl chloride, PVC H C Flooring, window frames C 75 105 methacrylate), PMMA (acrylic glass) Transparent H CH3 C phous (210) Cl H n Poly (methyl amor- window-glass (e.g. C windows in planes) 85 165 usually amorphous H C CH3 n O O usually Polycarbonate CH3 O C O Lenses, helmets, CDs, C laminated glass O CH3 142 205 amorphous (220) n Elastomeres Polybutadiene H H H H C C C C H H Tires −108 −75 147 207 n Thermosetting polymers Polyester O I R C O R Fiberglass II n 40 2 Elastic stiness, atomic bonding and material structure Specific volume (1 / density) Figure 2.29: Naturally grown calcite crystals [25]. ous h amorp crysta lline Tg Tm Temperature T Figure 2.30: Volume change due to fast and slow cooling, adapted from [2]. The polymers are formed by polymerization of so-called monomers. This is illustrated in Fig. 2.32 where formation of polyethylen from the monomer ethylene (C2 H4 ) is shown. It is important that ethylene has a double bond. Through addition of a radical former, which contains an unbound, i.e. particularly reactive electron, this double bond is broken as shown in Figure 2.32. This produces again a radical, which in turn reacts with an ethylene molecule. By continuation of this reaction scheme, long polyethylene chains are formed. However, they are not arbitrarily long, since there are also termination reactions. For example, two chains with one unbound electron at each end of the chain can form a covalent bond, in that the two unbound electrons react with each other. The resulting new chain can no longer take part in the polymerization reaction, since 41 2 Elastic stiness, atomic bonding and material structure (a) Structure of a polymer chain. The large spheres correspond to the C-atoms, the small ones can, for example, be H- or Cl-atoms. (b) Rotation possibilities along the carbon chain [10]. (c) Schematic representation of a warped chain molecule [11]. Figure 2.31: General structure of the polymer chains. it does not have any other unbound electron. Typically, the chains are made of 103 to 105 monomers, wherein the C-C bond spacing is 0.15 nm. The chain length is therefore between 0.3µ and 30µ. The fact that the polymers are made up of monomer units that are repeated many times, is symbolized in the structural formulas (Table 2.4) by the addition n. The polymers are divided into three large material groups: The thermoplastic polymers (also called thermoplastics), elastomers and thermosetting polymers (also called thermosets). As they are very dierent in structure and mechanical properties, they are discussed separately in the following sections. 42 2 Elastic stiness, atomic bonding and material structure R H H H H R + C C C C H H H H H H H H C C C C H H H H H H H H C C + C C H H H H R R Figure 2.32: Catalytic polymerization of ethylene to polyethylene. The symbol R denotes the free radical former containing a free electron. Thermoplastic polymers As we have seen above, polymer chains are built by covalent bonds. In order for the polymer chains to become a solid material, there must also be bonds between the polymer chains. In the case of polyethylene (PE), only dipole bonds are available for this purpose, because all possibilities to form covalent bonds have already been used up within the chain. This is exactly the characteristic of thermoplastic polymers: They have exclusively dipole bonds between the chains. Polyethylene is therefore a thermoplastic polymer. Because in this case only hydrogen atoms are present as side groups, there is no electronegativity dierence between dierent side groups. So only very weak van der Waals bonds develop. In the case of polyvinyl chloride (PVC), on the other hand, a hydrogen atom is replaced by a chlorine atom (Table 2.4). The latter is much more electronegative so that dipole bonds between the polymer chains form, which are based on permanent dipole moments (Fig. 2.33). Therefore, PVC chains are more strongly bound to each other than polyethylene chains. H C H H C C - H C - Cl H Cl H Dipole interaction + H H H+ H C C C C Cl H Cl H Figure 2.33: Illustration of the dipole interaction on the example of polyvinyl chloride (PVC). The family of thermoplastic polymers is again divided into amorphous and semicrystalline thermoplastics. To understand this dierence, we consider the solidication of a thermoplastic polymer from the molten state. As Table 2.4 shows, polyethylene is in the molten state above 130 C. The temperature is then so high that the weak dipole bonds between the chains are no longer able to keep the chains together. Therefore, the polymer chains can slide freely against each other and a melt is present. However, the viscosity is much higher than that of water or a metal melt, because it is much more ° 43 2 Elastic stiness, atomic bonding and material structure (a) Arrangement of the polymer chains in the crystalline areas. Gray spheres represent C-atoms and red spheres H-atoms [11]. (b) Spherulite structure in polyethylene [26]. (c) Schematic representation of a single spherulite [10]. Figure 2.34: Structure of thermoplastic polymers, adapted from. 44 2 Elastic stiness, atomic bonding and material structure dicult to move long polymer chains past each other than small molecules or single atoms. It is about the same level as honey. If one cools the polymer slowly from the molten state, as shown in Fig. 2.24(a) for the metals, crystallization nuclei are initially formed which grow during solidication. Hereby, the polymer chains arrange themselves in a regular, periodically repetitive form (Fig. 2.34 (a)). Thus, a crystalline structure is created, which can be imagined as built by periodically shifting a unit cell. Starting from the crystallization points, solidication proceeds radially symmetrically outwards. However, it can be seen that the periodic folding of the polymer chains to crystalline areas is quite dicult. Therefore, it does not succeed everywhere and, as shown in Fig. 2.34 (c), sandwich-like packages consisting of crystalline and amorphous regions are formed. In the amorphous regions, the polymer chains are not regularly folded, but are disordered. According to the denition of the amorphous state in chapter 2.3.2, there is no long-range order. If one starts at one end of a polymer chain and runs through the chain to the other end, one notices that the chain folds many times in a crystalline package, then passes through an amorphous region to merge into the next crystalline area again. A chain thus bridges many areas, so that the amorphous and crystalline areas are closely interlinked. This is important to understand the mechanical behavior discussed later on. The radially symmetric solidication does not continue arbitrarily, since the growing crystallization nuclei eventually touch each other. Looking at the solidied polymer at a magnication of about 500 times in the light microscope (Fig. 2.34 (b)), one can see this and the microstructure resembles that of polycrystalline solidied metals. As we have seen, the exact structure is nevertheless very dierent from that of polycrystalline metals. Therefore, one does not speak of individual grains but of spherulites. The slow solidication process discussed above results in a semi-crystalline thermoplastic polymer consisting of crystalline and amorphous areas. If, in contrast, one imagines fast solidication by rapid cooling, the time for a regular folding of the polymer chains is not sucient. Thus, the polymer chains do not crystallize below the melting temperature Tm , but they remain randomly entangled and become more and more immobile as the temperature decreases, until they nally freeze at the glass transition temperature Tg . The viscosity increases to such an extent in a narrow temperature interval around Tg that we perceive this as a transition from a liquid to a solid state. This process is completely analogous to that discussed for ceramics in section 2.3.2. Accordingly, we now have an amorphous thermoplastic polymer, whereby Tg < Tm also applies here. Whether a thermoplastic polymer solidies amorphously or semi-crystalline does not only depend on the solidication rate but also very much on the structure of the polymer chain. Polyethylene is a very simple polymer which can easily fold into crystalline areas. Thus, it is always semi-crystalline at technically usual solidication rates. Hereby, the crystalline portion is between 45% and 80%, depending on the process parameters. On the other hand, polymethyl methacrylate (PMMA), which is also shown in Table 2.4, has much larger side groups, making regular folding very dicult. Under normal technical solidication conditions PMMA is, thus, always amorphous. The mechanical behaviour of thermoplastic polymers is strongly dependent on temperature. This can be illustrated particularly well if the modulus of elasticity is plotted 45 2 Elastic stiness, atomic bonding and material structure E / GPa 1 E / GPa 1 10-3 Glass transition Glass transition energy elastic entropy elastic 10-60 1 amorphous areas: entropy elastic crystalline areas: energy elastic 10-3 viscous 2 10-6 0 3 energy elastic viscous 1 2 Tm (a) Amorphous thermoplastic. E / GPa 1 (b) Semi-crystalline thermoplastic. E / GPa 1 Glass transition Glass transition 10-3 10-3 10-60 3 T/Tg T/Tg energy elastic entropy elastic 1 2 10-6 0 3 energy elastic 1 2 T/Tg 3 T/Tg (c) Elastomer. (d) Thermosets. Figure 2.35: Plot of the modulus of elasticity as a function of temperature, adapted from [26, 9]. as a function of the temperature. For amorphous thermoplastics, the curve shown in Fig. 2.35 (a) is obtained. Below Tg , the modulus of elasticity is several gigapascals. Thus, it is about two orders of magnitude smaller than that of metals and ceramics. This is due to the weak dipole bonds between the polymer chains. They are stretched strongly even at low stresses, so that the polymer stretches strongly elastically even at low stresses. Below the glass transition temperature, many amorphous thermoplastics, such as PMMA or polystyrene, are hard and brittle (i.e. their elongation after fracture determined in a tensile test is low). This is understandable from the idea that the polymer chains freeze below Tg and remain immobile in their positions. Since the glass transition temperature of amorphous thermoplastics is generally signicantly higher than ambient temperature (Table 2.4), this is unfavorable for the majority of technical applications. However, there are also some amorphous thermoplastics which are ductile below Tg . These include, for example, polycarbonate (PC) already mentioned in chapter 1.2. As Table 2.4 shows, polycarbonate has a comparatively complicated structure. As a result, certain areas of the chain are rigid and give strength up to the glass transition temperature, while other areas are already exible well below ambient temperature, thus giving the material ductility and toughness. However, this more favorable material behavior resulting from the more complicated structure leads also to signicantly higher material costs compared to amorphous thermoplastics with a simple structure (Fig. 1.3, 1.4). If the glass transition temperature is reached from low temperatures, then the Young's 46 2 Elastic stiness, atomic bonding and material structure modulus decreases rapidly by several orders of magnitude in this temperature regime (Fig. 2.35). The same applies to the strength. This is understandable, since the dipole bonds break up and the transition to the molten state takes place. Thus, the scope of application of components made of amorphous thermoplastics is below Tg while the softening above Tg is used to produce components. The property to soften at elevated temperatures has given thermoplastics their name. Fig. 2.35 (a) shows another detail: Above Tg the course of the modulus of elasticity has an S-shape, i.e. the decrease of the elastic modulus with temperature slows down at rst and then accelerates again. This is somewhat surprising, because with the transition to the liquid state the elastic stiness should become essentially zero. However, it should be remembered that the polymer chains are still entangled. Like in a ball of wool, the resulting anchoring points between the individual chains lead to a certain residual elastic stiness, although there are no longer any binding forces between the polymer chains. For the purpose of dierentiation, this type of elasticity is referred to as entropy elasticity, which we will look at in more detail in connection with elastomers. In contrast, the elasticity associated with the stretching of atomic bonds is refered to as energy elasticity. Correspondingly, the three areas marked in Fig. 2.35 (a) as energy-elastic, entropy-elastic and viscous result. If one imagines that the same thermoplastic polymer is transformed once into the amorphous and once into the semi-crystalline state by dierent cooling rates, the following dierences result for the semi-crystalline material: Well below T , the mechanical behaviour corresponds largely to that of the amorg phous thermoplastic polymer, i.e. it is generally characterised by brittleness. However, the modulus of elasticity is somewhat higher. This is because the crystalline regions are packed tighter than the amorphous ones. Accordingly, more dipole bonds can be formed between the chains and also the binding forces are stronger due to smaller bond spacing, although the bond type is the same. Ultimately, this is the reason why the crystalline regions only melt at Tm > Tg . When the glass transition temperature is reached, the Young's modulus also decreases (Fig. 2.35 (b)). However, the decrease is much smaller. This is because the amorphous areas soften, but not the crystalline areas. Since the crystalline regions are interlinked by the fact that individual polymer chains link several crystalline regions (see above), they provide for the rigidity and strength of the material, whereas the softened, amorphous areas for ductility. Due to this favourable combination of strength and ductility, partially crystalline thermoplastics are often applied between Tg and Tm . Only when the melting temperature Tm is reached do the crystalline regions also melt. Accordingly, the modulus of elasticity drops rapidly and a viscous melt is formed. Previous considerations have shown that the mechanical behaviour of thermoplastics is strongly dependent on temperature. This is further illustrated in Fig. 2.36, showing the results of tensile tests on the amorphous thermoplastic polyvinyl chloride (PVC). 47 2 Elastic stiness, atomic bonding and material structure Figure 2.36: Temperature and time dependence of mechanical properties on the example of polyvinyl chloride (PVC) [13]. ° ° While the material behaves brittle at -30 C and 25 C, a distinctly ductile behavior can be observed at 40 C and 70 C. At the same time, the strength decreases considerably. If this is compared with the glass transition temperature of PVC, which is approximately 90 C, it becomes apparent that the polymer chains do not freeze completely below Tg . If a suciently high tensile stress is applied, the polymer chains can obviously move past each other at 40 C and thus cause plastic deformation. Ultimately, however, this is understandable: Freezing increases the viscosity by several orders of magnitude. However, if the material is stressed long enough and the temperature is not too low, the viscosity is not high enough to completely prevent the polymer chains from slipping and plastic deformation occurs. This consideration suggests that for thermoplastics, the duration of stress is also a very important factor. If the stress duration is very short, viscous slipping of the polymer chains past each other is not possible. The result should be a brittle material behaviour. If, on the other hand, the stress is applied slowly, sucient time should be allowed for viscous slipping and the polymer should behave ductile. This is conrmed by Fig. 2.36, where tensile test data for PVC at constant temperature (25 C) but dierent speeds of loading are shown. This time dependence of the mechanical behaviour, which already exists at room temperature, is a special feature of polymers (i.e. also of elastomers and thermosets). For metals and ceramics comparable phenomena only occur at signicantly higher temperatures, so that they usually do not have to be taken into account. In order to design a component made of a thermoplastic polymer, a stress-strain curve determined in a tensile test is obviously not sucient due to this time and temperature dependence. That is why a group of so-called isochronous stress-strain curves is often ° ° ° ° ° 48 2 Elastic stiness, atomic bonding and material structure Figure 2.37: Isochronous stress-strain curves of PMMA [26]. used(Fig. 2.37). Each of these curves indicates the stress as a function of strain for a given loading duration. The temperature eect can also be taken into account by dierent scales of the ordinate. The component design is therefore much more complex than when using a metallic or ceramic material, as a much more extensive data set must be used and the component service life must be included as a further parameter. For example, if the component is designed for 100 operating hours, signicantly higher stresses are permissible than is the case with a required service life of 10000 hours. Elastomers Elastomers, i.e. rubber-like polymers, show some remarkable dierences compared to thermoplastics. Firstly, their modulus of elasticity measured at ambient temperature is lower by a factor of 100 (Fig. 2.3). Secondly, elastomers can achieve elastic elongations of several hundred percent. No other material group is capable of this. To understand this, it is helpful to look at the production of elastomers using an example. The starting point is again polymerization from a monomer2 , which in this case has two double bonds (Fig. 2.38). In this case, polymerization produces a polymer chain whose chemical structure corresponds to natural rubber obtained from the rubber tree. To make an elastomer from natural rubber it must be vulcanised. In this process the material is heated by adding sulphur molecules. This occurs, for example, in the form of sulphur dichloride (S2 Cl2 ), which decomposes to Cl2 and S2 molecules in the heat. As shown in Fig. 2.38, the sulphur molecules break the double bond of the polymer and thus cause covalent cross-linking between the individual polymer chains. However, the cross-linking density, i.e. the number of covalent bonds in relation to the number of carbon atoms, is very 2 The exact chemical description is 2-methyl-1,3-butadien. 49 2 Elastic stiness, atomic bonding and material structure low at 10−3 to 10−4 . Only every ten thousandth to one thousandth carbon atom along a polymer chain has a covalent bond to an adjacent chain. Isoprene Polyisoprene CH3 H H CH3 H H H2C C C CH2 Polymerisation C Polyisoprene H CH3 H H C H C C C H C C H H H CH3 H C C C H S H H C Vulcanisation C H CH3 S H C C C H H C H n Figure 2.38: Polymerization of 2-methyl-1,3-butadien followed by vulcanization. This special structure of the elastomers is also noticeable when the elastic modulus is plotted over temperature (Fig. 2.35 (c)). Below Tg , the behavior corresponds to that of an amorphous thermoplastic polymer. The material is hard and brittle. There is no rubber elasticity. When the glass transition temperature is reached and exceeded, the Young's modulus also decreases by several orders of magnitude. However, it stabilizes on this low level and even increases slightly with temperature. In this temperature range above Tg , elastomers are rubber elastic, i.e. that's where their application area is. Above Tg , as with amorphous thermoplastics, all dipole bonds are dissolved. However, in contrast to the thermoplastics, the polymer chains cannot slide freely against each other because they are still connected by the covalent bonds. Therefore, an elastomer is solid above Tg , whereas an amorphous thermoplastic polymer is a viscous liquid. However, the covalent bonds are far apart. Thus, there are relatively long chain segments between these bonds, which are tangled together in the absence of an external load. If, however, an external load is applied, these chain segments stretch (Fig. 2.39) and so does the elastomer. If the load is released again, one might think that the chains simply remain in this stretched state. But this is not the case, because all atoms and molecules oscillate above 0K around their rest position due to the thermal energy. As a result, the molecule chains tangle up again by themselves and the elastomer is returning to its original form. The reason for the reentanglement is that one can imagine much more entangled than stretched states. If one imagines a thousand dice for comparison, the stretched state would correspond to a six on all dice, whereas the tangled state corresponds to any combination of numbers. So because entangled is much more probable than stretched, the molecules entangle themselves again. This eect of nature choosing the more probable, disordered state by itself is described in thermodynamics by entropy. The cause of rubber elasticity is thus nature's endeavour to adopt a state of greatest 50 2 Elastic stiness, atomic bonding and material structure possible entropy (i.e. greatest possible disorder). Therefore, the rubber elasticity of elastomers is also called entropy elasticity. Since the atoms vibrate more and more with increasing temperature, the tendency to assume the disordered state becomes stronger and stronger with increasing temperature. In this respect it is understandable why Youngs modulus rises slightly with temperature above Tg . In the regime of energy elasticity, i.e. below Tg , Youngs modulus, on the other hand, decreases with increasing temperature, because the dipole bonds between polymer chains weaken with increasing temperature. When Tg is reached, the thermal oscillations become so strong that the dipole bonds are no longer able to hold the polymer chains together. We have refered to this as breaking of the dipole bonds. Figure 2.39: Stretching of the chain segments by applying an external load, adapted from [6]. It follows from the above that the glass transition temperature of elastomers must be below room temperature, otherwise one would not be able to make use of the rubberelastic behaviour in most applications. This is achieved by choosing polymer chains with a very simple structure and non-polar side groups (especially H, CH3 ). This results in very weak van der Waals bonds with glass transition temperatures far below room temperature. The Young's modulus in the entropieelastic regime is 0.0001 GPa - 0.1 GPa, depending on the degree of cross-linking. Weak cross-linked elastomers show very high elastic elongations at particularly low elastic rigidity. With increasing cross-linking, the Youngs modulus increases, while the elastic stretchability decreases. The dierence in the elastic behaviour of amorphous thermoplastics, semi-crystalline thermoplastics and elastomers is summarized in Fig. 2.40, using polystyrene as an 51 2 Elastic stiness, atomic bonding and material structure Figure 2.40: Inuence of the degree of crystallization and crosslinking on the shear modulus G using the example of polystyrene, adapted from [19]. example. Polystyrene is normally amorphous, since the phenyl side group shown in Fig. 2.41 leads to limited chain mobility. However, it can also be converted into the semi-crystalline state by cooling particularly slowly from the molten state. Since the aromatic ring has unsaturated double bonds, it can also be crosslinked to form an elastomer (this state is referred to as crosslinked in Fig. 2.40)3 . In case of the amorphous material, the S-shape of the curve above Tg can be seen very clearly, which is the more pronounced the longer the polymer molecules are. In the crosslinked state, however, the Youngs modulus remains almost constant at a low level. In the semi-crystalline state, the Youngs modulus remains at a comparatively high level until melting occurs above 200 C. ° H H C C H H H C C H H C H C C n H C C H C H n Figure 2.41: Simplied (right) and explicit (left) representations of the structural formula of polystyrene with phenyl side group. 3 Technically this is not important, because Tg is well above room temperature Therefore, the rubber elastic state can generally not be used. 52 2 Elastic stiness, atomic bonding and material structure Thermosetting polymers Like elastomers, thermosets have covalent bonds between the polymer chains. However, the density of crosslinks is much higher at 10−2 to 10−1 . This leads to a rigid network of covalent bonds between which the polymer segments can no longer move. For this reason, thermosets behave energy-elastically both above and below Tg and are comparatively brittle. If we examine the Youngss modulus as a function of temperature, the glass transition temperature can be seen from a kink in the curve. The associated decrease in elastic stiness is due to the fact that the dipole bonds can no longer transmit loads. However, as the covalent bonds are still present, the Young's modulus remains at a high level. Since the covalent bonds are very strong, with increasing temperature there is also no melting, but the thermoset burns at several hundred degrees in air. O O O C CH CH C O CH2 CH2 + O n O CH2 O O + O C CH CH C O CH2 CH2 CH2 CH O O CH O C CH CH C O CH2 CH2 O C CH CH C O CH2 CH2 n Figure 2.42: Crosslinking of polyester and phenylethene (solvent). The production of thermosets is shown in Fig. 2.42 on an example. The starting point is a polyester resin. It is highly uid because with 10-20 repeat units the polyester chains are much shorter than those of thermoplastics and they are also dissolved in phenylethene. As already discussed above, the crosslinking reaction is started by adding a radical former (here called hardener). It ensures that the double bonds of the phenylethene and polyester molecules break up, so that free electrons result at these molecules which react with each other. This leads to crosslinks as shown in Fig. 2.42. Hereby, a tightly connected network is formed that does not allow the polymer chains to unraveling, as mentioned above. In mechanical engineering, thermosets are used to produce bre-reinforced polymers. Since the resins have a low viscosity, bre meshes can be well inltrated before the resin is hardened. Although the mechanical properties of such polymer matrix composites are essentially determined by the bres, the matrix also fulls important functions: it xes the bres spatially, enables load transfer onto the bres, protects the bres against buckling under a compressive load and prevents damage of the bres (e.g. by aggressive substances). 53 2 Elastic stiness, atomic bonding and material structure The most important reinforcing bres are listed in Table 2.5. Glass bres are most common because they are the most cost-eective. Particularly high strengths and stinesses can be achieved with carbon bres, while polymer bres (PE-, aramid bres) give the composite particularly high impact strength. It is interesting to note that polymer bres have much greater elastic stiness and strength than normal polymers. This is due to the extreme stretching of the polymer chains along the ber direction, which can be imagined schematically as shown in Fig. 2.43. Accordingly, especially the covalent bonds along the polymer chains are stressed when pulling at a ber. Because these are much stronger than the dipole bonds between the chains, the elastic stiness and strength is much greater. This eect is also exploited, for example, with nylon thread, which is nothing more than a stretched polyamide material. Table 2.5: Properties of reinforcing bres. Material ϱ /(g/cm3 ) E /GPa Rm /MPa A /% 1.8...5.3 Glass bres 2.5...2.6 69...85 1500...4800 Aramid bres 1.4...1.5 65...147 2400...3600 1.5...4.0 0.97 62...175 2200...3500 2.7...4.4 1.75...2.2 140...820 1400...7000 0.2...2.4 Polyethylen bres Carbon bres Figure 2.43: Structure of a polymer bre, consisting of bre bundles [26]. Examples of important polymers Because of the great importance of thermoplastics, some important polymers of this material group are discussed in more detail in this chapter. Important parameters are summarized in Tab. 2.3.3. Fundamentally, one distinguishes between so-called commodity plastics and engineering plastics. The former are inexpensive to produce but have limited mechanical properties, i.e. they are either not very strong or brittle. The four most important representatives of this group are polyethylene, polypropylene, polyvinyl chloride and polystyrene. Together they cover about 85 % of the total market 54 2 Elastic stiness, atomic bonding and material structure for thermoplastics. Their eld of application is mainly outside mechanical engineering (construction, electrical and packaging industry, household goods). But one nds also applications in mechanical engineering. By contrast, engineering plastics such as polyamide, polyoxymethylene or polycarbonate have improved mechanical properties. In the following, important semi-crystalline thermoplastics will be discussed rst, before examples of amorphous thermoplastics are given. Semi-crystalline thermoplastics Polyethylene (PE) As already mentioned, PE is a semi-crystalline thermoplastic which has a high crystalline content due to its simple chain structure. Since the dipole bonds between chains are very weak, the Youngs modulus, the yield strength Rp , the glass transition temperature Tg , and the melting temperature Tm are comparatively low (Table 2.3.3). It is therefore a low strength material, but inexpensive to produce and very easy to form. For this reason, PE products are often used in the household sector (bottles, pipes, containers, etc.) and the construction industry (e.g. drinking water and sewage pipes). An application example in mechanical engineering is the lower engine compartment cover, which is used in newer cars to reduce ow resistance. Likewise, the cups of hip joint implants are partly made of PE, because this material has a very low coecient of friction and is, thus, very suitable as a counterpart to the metallic or ceramic femoral head. In this case, so-called UHMW PE is used (UHMW: ultra high molecular weight), which has an improved wear resistance compared to regular PE due to its extremely long molecular chains4 . This is easy to understand, since with increasing chain length (i.e. increasing entanglement) it becomes more and more dicult to rip a chain out of its surrounding. However, the melt viscosity also increases with increasing chain length, so that processing in the molten state becomes increasingly dicult. A distinction is often made between so-called LD-PE (LD: low density) with a crystalline content of 45 % - 55 % and HD-PE (HD: high density) with a crystalline content of 70 % - 80 %. Since the crystalline areas are more densely packed than the amorphous areas, the density increases with the crystalline portion and due to the stronger and more numerous dipole bonds in the crystalline than the amorphous areas, the strength and elastic stiness are also greater in case of HD-PE. In terms of chain structure, the two variants dier in that the chains in LD-PE are not linear, as we have imagined so far, but individual hydrogen atoms are replaced by short polyethylene side chains (Fig. 2.44). This branched structure of the chain makes regular folding more dicult and consequently the crystalline content decreases. Since the branching also increases the bond spacing, it is understandable why LD-PE also has slightly lower glass transition and melting temperatures. 4 UHMW PE has 1 − 2 · 105 monomer units along a molecular chain, whereas HD-PE and LD-PE have 103 to 104 . 55 2 Elastic stiness, atomic bonding and material structure (a) unbranched (b) branched Figure 2.44: Unbranched and branched polymer chains. Due to the presence of side chains the formation of a crystalline structure is hindered [26]. Polypropylene (PP) This material, which also belongs to the semi-crystalline thermoplastics, is very similar to PE. However, the CH3 side group is much larger than a single hydrogen atom. If the chain wants to rotate along the C-C bonds, this is more dicult, because this large side group has to be rotated as well, which can get caught on neighboring chains more easily. This spatial obstruction leads to less exible chains and thus to higher strength and elastic stiness. For the same reason, the material only softens at higher temperatures, i.e. Tg and Tm increase. (a) isotactic (b) syndiotactic (c) atactic Figure 2.45: Geometric arrangement of side groups using the example of polypropylene (PP). Figure (a) shows the isotactic arrangement in which the CH3 side groups are regularly arranged on the same side, Figure (b) the syndiotactic arrangement with alternating CH3 side groups and Figure (c) the disordered, atactic arrangement [26]. Polypropylene has one CH3 side group per monomer unit. There are basically four dierent positions available for this and a distinction is therefore made between dierent 56 2 Elastic stiness, atomic bonding and material structure arrangement types. If the CH3 group ends at the same position for each monomer unit (Fig. 2.45 (a)), this is referred to as an isotactic arrangement. If, on the other hand, the CH3 group alternates regularly on dierent sides of the carbon chain, the arrangement is called syndiotactic (Fig. 2.45 (b)). If it is completely irregular (Fig. 2.45 (c)), it is called atactic. It is easy to see that the folding to crystalline regions is the easiest in case of the isotactic arrangement and the most dicult for the atactic one. Accordingly, isotactic polypropylene, which is technically the most important, has a crystalline portion of 70 % - 80 %, whereas in an atactic arrangement it is only 50 % - 60 %. The elds of application of PP are similar to those of PE. In mechanical engineering, for example, car bumpers can be made of PP. Polyamide (PA) Like PE and PP, polyamides also have a very simple chain structure and are therefore semi-crystalline. However, the NH-CO group produces hydrogen bonds between the polymer chains, as shown exemplarily in Fig. 2.46. Hereby, the electronegative oxygen produces a negative charge surplus while the likewise electronegative nitrogen atom causes the corresponding hydrogen atom to be positively polarized. Therefore, the binding forces between the polymer chains are much greater than is the case with PE or PP. Accordingly, Tg , Tm and the mechanical properties increase strongly (Table 2.3.3). Since the polyamides are also ductile, they play an important role in mechanical engineering. For example gear wheels, housing parts such as motor covers and cooling fans for automobiles are made of PA. It is often also reinforced with glass bres, which signicantly increases the elastic stiness and strength. Figure 2.46: Molecular structure of PA 6 and PA 66 [12]. CH2 chain segments of dierent lengths can be between the NH-CO groups. This can inuence the density of the hydrogen bonds and, thus, the mechanical and thermal properties. Accordingly, polyamides are designated by the number of carbon atoms between the nitrogen atoms. PA6, for example, has the structural formula [NH-CO(CH2 )5 -]n , PA12 the formula [NH-CO-(CH2 )11 -]n and PA66 has the formula [NH-(CH2 )6 NH-CO-(CH2 )4 -CO-]n . In the latter case, the CO group is located once to the left and 57 2 Elastic stiness, atomic bonding and material structure once to the right of the NH group, which is why the structure may have two CH2 chain segments of dierent lengths. A disadvantage of polyamides is that they tend to absorb water. This is easy to understand, since in both cases the hydrogen bond is the decisive intermolecular bond type and water molecules feel particularly comfortable in polyamides for this reason. The more hydrogen bonds are formed between dissolved water molecules and polymer chains, the less is available for bonding between the polymer chains. In addition, water absorption increases the distance between the polymer chains, which also weakens the bonds. As a result, strength and elastic stiness decrease. Therefore, the mechanical properties of polyamides are dependent on the ambient humidity, which must be taken into account in the component design. Polyoxymethyle (POM) POM also has a very simple monomer unit and, consequently, a high crystalline content of 70 % - 80%. The special feature is that the chain is built by a sequence of carbon and oxygen atoms. In this particular case, relatively strong dipole bonds are formed between the oxygen atoms along the chain and the hydrogen atoms bound to the carbon atom. Therefore, the strength and stiness values are much higher than those of PE or PP (Table 2.3.3). They almost reach the level of polyamides. This is why POM and PA compete with each other and their elds of application are similar. POM has the advantage that it does not tend to absorb water like PA. However, it is less temperature resistant. Amorphous thermoplastics Polymethyl methacrylate (PMMA) This plastic, often referred to as plexiglass, is characterised by a very large side group. Due to the spatial obstruction already described above this impedes chain rotation. Consequently, the polymer chains are relatively sti, so that regular folding to crystalline regions during solidication is not possible. Thus, PMMA is an amorphous thermoplastic polymer. However, due to the relatively high stiness of the polymer chains, the glass transition temperature of about 100 C is also signicantly higher than is the case with the semi-crystalline thermoplastics discussed above. As to be expected, PMMA behaves strong but also comparatively brittle at ambient temperature. Since PMMA is optically transparent and has a very good resistance to ultraviolet radiation, it is used, for example, as glazing in aircrafts. ° Polycarbonate (PC) Polycarbonate has a complex polymer chain structure (Table 2.3.3). In addition to stiening aromatic rings, there are also exible elements (especially the oxygen atoms along the chain), so that not only a major softening occurs when the glass transition temperature of about 140 C is reached, but also a minor softening at about -60 C. If the ° ° 58 2 Elastic stiness, atomic bonding and material structure Youngs modulus is plotted over the temperature, this is noticeable by a small S-shape in the curve. As already discussed, certain chain segments become already exible above -60 C, giving the polymer a high impact strength, whereas the still immobile segments provide strength. This results in superior mechanical properties compared to PMMA, while still maintaining good optical transparency. Consequently, PC is used, for example, to produce headlight glazings for automobiles, CDs and protective helmets. ° Polyethylene terephtalate (PET) PET has a similar chain structure to PC. It therefore belongs those amorphous thermoplastics, which combine good toughness and strength at ambient temperature. Since there are more exible elements along the chain than with PC, the glass transition temperature is somewhat lower than with PC, but processability is easier for the same reason. Beverage bottles are, for example, made from PET. Polyimide (PI) These amorphous thermoplastics are an example of how the stiening of the polymer chain by aromatic rings can be taken to the extreme. Accordingly, polyimides have very high glass transition temperatures and the highest possible operating temperatures of up to 250 C among all thermoplastics. However, polyimides are also particularly dicult to process. Components made from these materials are therefore very expensive. ° 59 H n H C methylene (POM) C (PS) H H Polystyrene H H Polyoxy- H C (PA) C H O n n (CH2)x H n H O C C (PP) Polyamide H CH3 Polypropylene N C C (PE) H H formula Structural- Polyethylene Name n 74 110 −18 −8 44 56 −25 −15 −110 −90 ∗ / Tg 160 184 210 220 150 175 125 132 / Tm 140 115 110 103 97 λ / W/mK 20 3 · 10 21 3.3 · 1020 1.4 · 10 1.5 · 1019 3 · 1023 3.3 · 1022 3 · 1024 3.3 · 1022 76 202 144 149 122 180 126 198 0.12 0.13 1025 1027 90 153 Amorphous thermoplastic polymers 0.22 0.35 0.23 0.25 0.11 0.17 0.40 0.44 1.2 2.6 2.5 5 2.6 3.2 0.9 1.6 0.6 0.9 E / GPa −6 /K α / 10 ρe / µΩ cm Semi-crystalline thermoplastic polymers / Tmax 29 56 49 72 50 95 21 37 18 29 / MPa Rp bridge Engineering Selector Edu Pack 2008, Engineered Materials Handbook, Vol. 2, ASM International. 36 57 60 90 90 165 28 41 21 45 / MPa Rm 1.2 3.6 10 75 30 100 100 600 200 800 / % A sion, E : Young's modulus, Rp : Yield strength, Rm : Tensile strength, A: Strtain to rupture, ρ: Density), References: Cam- maximum service temperature, λ: Thermal conductivity, ρe : Specic electrical resistivity, α: Coecient of thermal expan- Table 2.6: Characteristic properties of some important polymers. (Tg : Glass transition temperature, Tm : Melting temperature, Tmax : ρ 3 1040 1050 1390 1430 1120 1140 890 910 939 960 / kg/m Polyester Polybutadiene (PET) thalate -tereph- Polyethylee (PC) carbonate Poly- (PMMA) methacrylate Polymethyl- (PVC) chloride Polyvinyl- Name C R O C C H H O C n II H C H n n H H n O C C H O O C O R O C C H H H I CH3 O C C H C CH3 n O O C H CH3 CH3 O C C Cl H n H H formula Structural- 147 207 −108 −75 68 80 142 205 85 165 75 105 Tg / Tm / 150 120 87 144 57 70 / Tmax λ 3 · 1021 3.3 · 1020 1020 1021 3 · 1024 3.3 · 1023 1020 1022 1020 1022 0.29 0.3 3 · 10 19 3.3 · 1018 Thermosetting polymers 0.2 0.22 99 180 130 150 115 119 120 137 72 162 100 150 2.1 4.4 0.001 0.0021 2.8 4.1 2 2, 4 2.2 3.8 2.1 4.1 E / GPa −6 /K α / 10 ρe / µΩ cm Elastomers 0.14 0.15 0.19 0.22 0.08 0.25 0.15 0.29 / W/mK Rp 33 40 1.5 7 57 62 59 70 54 72 35 52 / MPa Rm 41 90 1.5 7 57 72 60 72 54 80 41 65 / MPa A 2 2.6 500 550 30 300 70 150 2 10 12 80 / % ρ 1040 1400 910 940 1290 1400 1140 1210 1160 1220 1300 1580 / kg/m 3 3 Strength and phase diagrams Please note: To understand chapters 3.3.3 and 3.3.4, it is helpful to be familiar with phase diagrams (Chapter 3.4). This is absolutely necessary for Chapter 3.3.5. It is therefore recommended that after Chapter 3.3.2, you rst familiarize yourself with Chapter 3.4 before working on Chapters 3.3.3 - 3.3.5. 3.1 The ideal strength In chapter 2 we have seen that the elastic stiness of materials, which is an important property in the construction and design of components, is decisively dependent on the structure of the materials and the atomic bonds. Because the atoms in ceramics and metals are more strongly bound than in polymers, the former have a higher Youngs modulus than polymers. Designs must also meet strength criteria. They are generally required to only deform elastically, but not plastically. With the yield strength Rp and the tensile strength Rm determined in the tensile test, important characteristic values have already been introduced and discussed in connection with the polymers. Here, too, it turned out that strength and structure of the materials are closely related. For example, polyamides are much stronger than polyethylene due to stronger dipole bonds. HD-PE is stronger than LD-PE due to a larger crystalline fraction. It also became clear that plastic deformation of polymers is caused by the mutual sliding of the polymer chains, i.e. a mechanism that is fundamentally dierent from the mechanism of elastic deformation. Analogous dependencies can also be found in metals and ceramics. However, aspects come into play here that were not yet accessible. For this reason, the questions of what determines the strength of metals, what causes plastic deformation when the yield strength is exceeded and how the strength of metals can be raised are now discussed in chapters 3.2 and 3.3. A thought experiment is helpful as an introduction to this topic. Here the question is asked of how strong a material should be, i.e. what tensile stress it should withstand before it breaks. If we look at Fig. 2.12, we could arrive at a simple answer: As the stress increases, the atomic bonds are increasingly loaded and the atoms are deected from their equilibrium distance. If this deection is about 1.25 times the equilibrium distance, the restoring force that tries to move the atoms back to their original position, reaches a maximum. If this force is exceeded, the bonds break apart. Therefore, the material cannot withstand a higher load without rupturing. From σ = E ·ε and ε ≈ 0.25, the ideal strength ideal σideal ≈ E/4 follows. More precise calculations with real atomic potentials result in approximately E/10. Accordingly, a steel or zirconia ceramic with a Youngs modulus of ≈ 200,000 MPa each should have a tensile strength of about 20,000 MPa. However, simple deep-drawing steels only reach values of about 300 MPa and also the strength of high-strength steels is 62 3 Strength and phase diagrams no more than 2,000 MPa. The compressive strength of zirconia is 4,000 MPa (Abb. 3.2). Yet, under a tensile load, the strength is considerably lower and the ceramic breaks at an elongation of about 0.5 %, instead of the expected 25 %. Metals, on the other hand, do achieve rupture elongations of 25 %, but by plastic and not elastic deformation. Polymers which usually have Youngs moduli of a few gigapascals, should have tensile strength values of a few hundred megapascals, which are, however, not achieved in reality. These examples show that there may be something wrong with the above consideration. A central assumption was that all atoms are loaded equally and failure occurs when all atomic bonds are loaded at the same time with the maximum possible value. However, this idea is obviously not right. For example, if we consider plastic deformation of polymers by slipping of polymer chains past each other it is not necessary for the slipping chain to overcome all dipole bonds to adjacent chains at the same time to move a little bit. Rather, initially only a short segment of a polymer chain moves and this displacement then propagates through the chain, so that nally the whole chain has moved. So only few bonds are overcome at the same time. Thus, it is understandable that the plastic deformation of polymers begins far below the theoretical strength. This plastic deformation is ultimately responsible for failure, so that the tensile strength Rm is also far below the theoretically expected value. This fact can be illustrated once again with an analogue, the carpet trick. For this, imagine a very large carpet that is to be moved a little. If one wanted to move it in one piece, the eort would be very high, because the frictional forces would have to be overcome over the entire surface. If, on the other hand, one lifts the carpet only on one location (i.e. the bonds are only released locally there), this fold can be pushed through much easier, so that in the nal eect the whole carpet is moved a little (Fig. 3.1). Accordingly, the polymer chain is not moved as a whole, but shifted segment by segment. Hereby, the shifting propagates through the entire chain. Just as the displacement of the carpet is permanent, so is the displacement of the polymer chain: When the load is relieved, it does not move back. Thus, a plastic deformation results. Figure 3.1: Analogy to the sliding of polymer chains: Movement of a carpet, adapted from [4]. 63 3 Strength and phase diagrams Also with metals, the carpet trick is the reason why the ideal strength is far from being achieved. Here, certain crystal defects, so-called dislocations, are responsible. They are discussed in the next chapter. 3.2 Dislocations in crystals In chapter 2.3 crystals were dened as periodically built structures, which result by periodic arrangement of the unit cell in all three dimensions. However, this perfect order is not maintained during solidication from the melt. Often half-planes are formed (Fig. 3.2), which end in the crystal. They are called edge dislocations. The perfect crystal order is disturbed where the inserted half-plane ends. Therefore, a dislocation is a onedimensional, i.e. line-type, defect while a grain boundary is a two-dimensional defect. Consequently, a dislocation is represented by a so-called dislocation line. In case of an edge dislocation, it runs along the end of the inserted half-plane as illustrated in Fig. 3.5 (a). (a) Crystal containing a half-plane. (b) Perfect crystal. Figure 3.2: Edge dislocation and denition of the Burgers vector, adapted from [14]. If a shear stress is applied to the crystal (Fig. 3.3) and if the edge dislocation is moved from left to right through the crystal, the upper half of the crystal is shifted by the vector b relative to the lower half of the crystal. One calls b the Burgers vector of the dislocation. As shown in Fig. 3.2 (a), the size and direction of the Burgers vector can be recognized by moving along a line around the dislocation line and doing the same number of steps down/up and right/left. One will notice that the line is not closed. The vector needed to close the line is the burger vector. Characteristic of edge dislocations is that the Burgers vector is oriented perpendicular to the dislocation line. Fig. 3.3 illustrates that even in the case of plastic deformation of metals the carpet 64 3 Strength and phase diagrams (a) (b) Figure 3.3: Movement of an edge dislocation through a crystal, adapted from [4, 26]. trick is used. To displace two crystal halves permanently past each other, not all bonds have to be released at the same time (and reestablished after the displacement). Instead, this only occurs at the position of the dislocation. Hereby, the dislocation moves by the Burgers vector b. By repeating this movement many times, the crystal halves nally slide past each other. The resulting deformation is plastic, because dislocations do not move back on unloading. Because of this carpet trick, plastic deformation occurs at stresses ≪ E/10. As Fig. 3.2 shows, the atoms near the dislocation line are displaced from their equilibrium position. Where a half-plane is inserted, the atoms are pushed together, i.e. the atomic bonds are compressed. Accordingly, there is a compressive stress. But where the half-plane is missing, the atomic spacing is too big. The atomic bonds are stretched and there is a tensile stress. Therefore, a dislocation is surrounded by a distortion eld which increases the energy of the crystal. Since the displacement of atoms in the vicinity of the dislocation is proportional to the Burgers vector b and the force for the displacement of an atom is proportional to G · b (Fig. 2.12), the stored energy per unit length of a dislocation must obviously be proportional to G · b2 . In fact, one nds for this so-called line tension T of the dislocation. 65 3 Strength and phase diagrams T ≈ T b Gb2 . 2 (3.1) line tension length of the Burgers vector Eq. 3.1 shows that energy is required to produce a dislocation. Because nature tries to minimize this energy expense, which increases with b2 , the crystal lattice only contains dislocations with the smallest possible burger vector. A further condition for b is apparent from Fig. 3.3. The Burgers vector must be a translation vector that translates the crystal lattice into itself. Therefore, it must start at one atomic position and end at another. Otherwise, dislocation motion would displace atoms to positions that are not allowed in the crystal lattice. In the face-centered cubic crystal lattice the smallest possible distance between atoms is that between a corner atom of the unit cell and an atom arranged in the middle of a side-face. Correspondingly, only burgers vectors exist which connect a corner atom with an atom arranged in the middle of a side-face. Such a burger vector is shown in Fig. 3.4 (a). For the same reason, burger vectors in the body centered cubic crystal lattice always connect a corner atom of the unit cell with the atom arranged in the centre of the unit cell, as shown in Fig. 3.4 (b). Plastic deformation always occurs by motion of dislocations with these burger vectors. Also, the dislocations only move along certain planes. These so-called slip planes are always the closest packed planes in the respective crystal lattice (i.e. the planes that have the most atoms per area) because dislocation motion is easiest along these planes. Fig. 3.4 shows one slip plane for the face-centered cubic (a) and body centered cubic (b) crystal lattice. Lattice constants, i.e. the edge lengths of the unit cells, and burgers vectors are listed in Table 3.1 for some metals. Table 3.1: Lattice constants and Burgers vectors of some metals. Metal Structure Lattice constant Fe bcc 2.87 × 10 2.48 × 10 W bcc 3.17 × 10 2.74 × 10 −10 −10 −10 Burgers vector −10 −10 −10 Al fcc 4.05 × 10 2.86 × 10 Ni fcc 3.52 × 10 2.48 × 10 −10 −10 Dislocations in ceramics have larger burger vectors, because the crystals are more complicated. This is associated with a higher line tension. Accordingly, greater forces are required to move dislocations through the crystal lattice. In addition, the dislocation movement is made more dicult by covalent bonds. Therefore, dislocation motion in ceramics is virtually immobile at ambient temperature. This explains why ceramics fail in a brittle manner and are not plastically deformable like metals. In addition to the edge dislocation shown in Fig. 3.5 (a), where b is perpendicular to the dislocation line, so-called screw dislocations also occur (Fig. 3.5 right). As with a 66 3 Strength and phase diagrams (a) Face-centered cubic crystal structure with slip plane and Burgers vector. (b) Body centered cubic crystal structure with slip plane and Burgers vector. Figure 3.4: Representation of a slip plane and a Burgers vector, adapted from [26]. spiral staircase, the planes are displace parallel to the dislocation line. Consequently, the Burgers vector b is oriented parallel to the dislocation line. Figure 3.6 shows schematically the slip process when a screw dislocation moves through the crystal. (a) Edge dislocation (b) Screw dislocation Figure 3.5: Comparison of the two basic types of dislocations. The drawn straight lines indicate the course of the dislocation lines. 67 3 Strength and phase diagrams Figure 3.6: Slip process when moving a screw dislocation through the crystal. 3.2.1 Forces between dislocations Dislocations distort the crystal lattice and are therefore surrounded by a stress eld. At the location of the inserted half-plane of an eddge dislocation, the crystal lattice is compressed resulting in compressive stresses. Where the inserted half plane is missing, the crystal is widened. So there are tensile stresses. Due to these stress elds, dislocations exert forces on each other. If two dislocations with the same sign, i.e. the inserted half plane points in the same direction, are positioned on the same slip plane, they repel each other (Fig. 3.7). In contrast, dislocations with inverse sign attract each other. If they are positioned on the same slip plane, they annihilate each other. Figure 3.7: Interaction between dislocations. A frequently required quantity is the force F , which is exerted on a dislocation by an external shear stress. Let the crystal shown in Fig. 3.8 be represented by the dimensions l1 and l2 . Then, external work τ · l1 · l2 · b is expended when the upper crystal half slips by the Burgers vector b. Herby, τ · l1 · l2 is the external force acting on the slip plane and b the resulting displacement. The displacement is caused by the movement of an edge dislocation of length l1 over the distance l2 . If F is the force on the dislocation, 68 3 Strength and phase diagrams Figure 3.8: Illustration of a crystal loaded by a shear stress τ which slides by Burger's vector b [15]. then the expended work is F · l2 . Equating both terms leads to: (3.2) F =τ ·l·b . l length of the edge dislocation 3.3 Measures to increase strength In Section 3.2 it became clear that dislocations are the carriers of plastic deformation in metals. The movement of dislocations is associated with the breaking and reestablishment of bonds at the location of the dislocation core. Therefore, a critical shear stress τ0 must be exceeded to enable dislocation motion through the crystal. The strength of pure metals, which is approx. 1 MPa to 10 MPa, results from that. If one wants to further increase the strength of metals, that is, their resistance to plastic deformation, measures must be taken, to further hinder the movement of dislocations. These are discussed in the following. 3.3.1 Work hardening The simplest strengthening method is work hardening (also refered to as strain hardening). This is based on the fact that metallic materials become stronger when they are plastically deformed. This increase in strength with increasing plastic deformation can also be seen from the stress-strain curve: If one unloads a plastically deformed material and loads it again, the yield strength (ReL or Rp0,2 ) rises to the previously achieved stress level. The reason for the increasing strength is that the dislocation density has greatly increased due to plastic deformation. Because of that, the dislocations get more and more entangled, thus making dislocation motion more and more dicult (see Fig. 3.9). The strength increases with the square root of the dislocation density ρ. Accordingly, the increase in strength due to work hardening ∆σwh compared to the imaginary dislocation-free state σ0 (which does not occur in reality) is: 69 3 Strength and phase diagrams ∆σwh = const · ∆σwh ρ √ (3.3) ρ. Strength increase due to work hardening ∆σ = σ1 - σ0 dislocation density Figure 3.9: A dislocation (gray) moves through a eld of obstacles caused by other dislocations, adapted from [26]. In Fig. 3.10, the yield strength Rp0,2 , the tensile strength Rm and the elongation at fracture A is plotted for a copper alloy containing 30 % nickel as a function of the degree of rolling. The degree of rolling indicates how much the thickness of a sheet is reduced by plastic deformation during rolling. A considerable increase in strength with increasing degree of rolling is clearly visible. Since such forming processes are easy to realize and often part of the manufacturing process, work hardening is a particularly simple measure to increase strength. This is a particular advantage. However, an important disadvantage is also evident in Fig. 3.10: The elongation at fracture, i.e. ductility, of the material decreases drastically due to work hardening. This shows that strain hardening is a cost-eective way to increase the strength of relatively soft materials with high ductility The resulting loss of ductility can often be accepted. High-strength materials, on the other hand, already exhibit a relatively low elongation at fracture. In this case, there is no chance of achieving an additional strengthening contribution through work hardening. 3.3.2 Strengthening by grain size reduction In reality, crystalline materials do not consist of one crystal with one orientation, but of many crystals with dierent orientations. Since dislocations are bound to their slip planes (this corresponds to the closest packed plane of the unit cell, see section 2.3.1), they cannot easily pass from one grain to the neighbouring grain. Therefore, grain boundaries act as obstacles where dislocations accumulate (Fig. 3.11(a)) and this strengthening mechanism is, thus, also referred to as grain boundary strengthening. The ner the grain, the more grain boundaries, i.e. obstacles, stand in the way of the dislocations and the stronger the material. Correspondingly, strengthening by grain size reduction results. 70 3 Strength and phase diagrams Figure 3.10: Strength and strain to rupture of a copper alloy containing 30% nickel as a function of the degree of rolling, adapted from [6]. As more and more dislocations accumulate at a grain boundary, they can exert such a high stress on the neighbouring grain that it in turn emits dislocations from the grain boundary and the deformation is propagated through the metal (Fig. 3.11(b)). Empirically, there is an increase in strength ∆σgsr compared to an imaginary reference material with innite grain size according to the so-called Hall-Petch relation: k ∆σgsr = √ . d ∆σgsr k d (3.4) Strengthening by grain size reduction Hall-Petch-constant (also called kHP ) grain size (diameter) Typical values for the Hall-Petch constant are: Steel N 19 mm 3/2 Aluminium N 3.5 mm 3/2 Copper N 5.5 mm 3/2 As can be seen from the Hall-Petch constants mentioned above, the increase in strength by grain size reduction, especially in the case of metals with face-centered cubic crystal structure, is rather small. However, strengthening by grain size reduction has a signicant advantage: while the elongation at fracture decreases with all other strengthening 71 3 Strength and phase diagrams Slip plane Grain 2 Slip plane Grain 1 (a) Dislocations pile up in grain 1 and are blocked at the grain boundary. Slip plane Grain 1 (b) Increasing dislocation pile up leads eventually to dislocation motion in grain 2 along a dierent slip plane. Figure 3.11: : Dislocations in grain 1 accumulate at a grain boundary due to the applied shear stress and eventually cause dislocation movement in grain 2 on a dierent slip plane, adapted from [26]. measures, it increases with this measure. For this reason, the aim is to use materials with the smallest possible grain size. Grain sizes between 0.01 mm and 0.1 mm are typical. 3.3.3 Solid solution strengthening A good way to increase the strength of metals is to contaminate them with other elements. The alloyed elements go into solution in the solid, similar to how sugar dissolves in water. Now that the crystal is made of a mixture of several elements, one speaks of a solid solution and solid solution strengthening. Aluminium strengthened by magnesium is a technically relevant example. As the Al-Mg phase diagram (Fig. 3.12) shows, approx. 1 % magnesium is soluble in aluminium at room temperature. In practice, however, up to 5 % magnesium will remain in solid solution if cooled quickly from elevated temperature (e.g. 400 C), as the driving force for the formation of the equilibrium phase Al3 Mg2 is not sucient. The magnesium atom with an atomic radius r of 0.16 nm is approx. 10% larger than the aluminium atom (r = 0.143 nm) and, therefore, distorts the lattice locally. Similar to the interaction between two dislocations, a dislocation feels this distortion eld. Thus, an additional force is required to move the dislocation past the dissolved magnesium atoms. This increases the yield strength Rp0,2 with the magnesium content by up to 100 MPa as shown in Fig. 3.13. Fig. 3.13 shows that Rp0,2 increases approximately with the square root of the concentration c of the dissolved element. Correspondingly, the general rule for the increase in strength due to solid solution strenghtening ∆σsss compared to the non solid solution strengthened material (c=0) is: ° ∆σsss = const · ∆σsss c √ (3.5) c, Strength increase by solid solution strengthening Concentration of the dissolved element 72 3 Strength and phase diagrams Figure 3.12: Binary Al-Mg phase diagram, adapted from [24]. Figure 3.13: Yield strength Rp0,2 of aluminium as a function of the dissolved magnesium content, adapted from [1]. 73 3 Strength and phase diagrams Hereby, c is the concentration of the alloyed element. In the case under consideration, magnesium atoms replace the aluminum atoms in the host lattice. This is called substitutional solid solution strengthening (Fig. 3.14(a)). The situation is quite dierent when carbon is added to iron (steel = iron alloyed with carbon). Since the carbon atom (r = 0.077 nm) is much smaller than the iron atom (r = 0.124 nm), it is placed in the interstices, i.e. the gaps between the host atoms. This is known as interstitial solid solution hardening (Fig. 3.14(b)). Since the carbon atom does not t exactly into these interstices, this again leads to lattice distortion and, thus, to an increase in strength. As an interstitially dissolved atom, carbon is already relatively easily mobile in the host lattice at ambient temperature. Since it is somewhat too large, it tends to move to the area of the dislocation core where the bonds are stretched, thus, taking up an energetically favourable position. At ambient temperature, a few days are required for the carbon atoms to travel the distance to the dislocations. The dislocations are now locked by the carbon atoms and a relatively high level of stress is required before dislocations can be torn o from the carbon atoms. This causes the upper yield strength ReH shown in Fig. 3.15. Once dislocations have been torn o, they are already mobile at a lower stress, the lower yield strength ReL . This special feature of steels leads to inhomogeneous deformation. It produces so-called Lüders bands, also refered to as slip bands or stretcher strain marks. When deep-drawing sheet metal these stretcher strain marks disturb the surface nish. To avoid this, sheets can rst be rolled to mobilize all dislocations and then deep-drawn. (a) Substitutional solid solution. (b) Interstitial solid solution. Figure 3.14: Dierent types of solid solutions in a crystal. 3.3.4 Particle strengthening If a solid solution, consisting of the host atoms A and the dissolved atoms B, is cooled down, it may happen that the B atoms can no longer be completely dissolved. Precipitation of B-rich particles then occurs. This is illustrated in Fig. 3.16. While Fig. 3.16 a shows a solid solution in which the solute atoms (bright) are randomly distributed on the sites of the host lattice, Fig. 3.16 b, c show two examples of precipitates in a crystal 74 3 Strength and phase diagrams Figure 3.15: Technical stress-strain-diagram of steel. lattice. In Fig. 3.16 b, all lattice planes of the matrix continue in the particle and vice versa. Then one speaks of coherent particles. This situation can occur when the crystal structures are very similar. In the case shown here, they are even identical, so that matrix and precipitate particles dier only because of their dierent compositions. In Fig. 3.16 c, on the other hand, the two crystal structures are so dierent that no lattice plane of the matrix is continued in the particle and vice versa. Then one speaks of incoherent particles. Something analogous to the case described here happens when you dissolve a lot of sugar in hot water and then let it cool down. At some point, the sugar molecules are no longer completely soluble and sugar crystals precipitate out. The temperature at which the solute is just soluble is called the solvus temperature or solubility limit. (a) Solid solution. (b) Coherent precipitate (c) Incoherent precipitate. Figure 3.16: Comparison between solid solution and dierent precipitates in a crystal lattice. As the example of Al-Mg in section 3.3.3 has already shown, it is necessary to fall below the solubility limit in order to form precipitates. Under certain circumstances, however, this still does not happen. To understand this, it is necessary to look more closely at the energetic conditions involved in the formation of precipitates. Two terms need to be considered. First, we imagine that a solid solution is cooled below the solubility limit. 75 3 Strength and phase diagrams Then, the transformation of the volume V from the state of disequilibrium (supersaturated solid solution) to the equilibrium state (solid solution with reduced concentration of dissolved atoms plus precipitates) is associated with a decrease in free enthalpy. This is what nature strives for. If ∆Gv is the free enthalpy dierence between the nal state and the initial state, then ∆Gv < 0 applies. The absolute value of ∆Gv is greater, the greater the supercooling below the solubility limit is. For spherical particle with radius r, the following applies: 4 ∆Gv = πr3 ∆gv , 3 ∆Gv r ∆gv (3.6) Dierence in free enthalpy Particle radius specic change in free enthalpy ∆gv represents the change in free enthalpy related to the precipitated volume. At the same time, an interface is created due to the formation of a particle (Figure 3.16). This is associated with an increase in free enthalpy. For a spherical particle, the following holds: (3.7) ∆Gs = 4πr2 γs . ∆Gs γs Dierence in free enthalpy Specic interphase energy The specic interfacial energy γs is typically between 0.2 J/m2 and 2 J/m2 . It is particularly low for coherent particles, but particularly high for incoherent particles. This can be easily understood from Fig. 3.16 b, c. All atoms of a precipitate particle would like to nd conditions as it is the case for the atoms inside the particle. In the case of an incoherent particle, on the one hand, an atom directly at the interface with the matrix "notices" that both the chemical composition and the coordination with nearest neighbors are not as it would be desirable. Accordingly, the formation of interface is very unfavorable. A large interfacial energy is generated. In the case of coherent precipitation, on the other hand, the coordination with nearest neighbors ts at the interface. Only the chemical composition does not match. Consequently, the interfacial energy is signicantly lower. Comparing Eq. 3.6 with Eq. 3.7, it is obvious that ∆Gv is proportional to r3 , whereas ∆Gs increases with r2 . Since the quadratic term predominates for small particle radii, an initial expenditure of free enthalpy is necessary to form a particle. This is shown in Fig. 3.17, where besides ∆Gv and ∆Gs also the total change of the free enthalpy ∆G with 4 ∆G = ∆Gv + ∆Gs = πr3 ∆gv + 4πr2 γs 3 76 (3.8) 3 Strength and phase diagrams Free enthalpy Effort for interface Total energy (Critical radius) Particle radius r Gain from chem. bonds Figure 3.17: Energy balance during precipitation of a particle, after [20, 26]. is shown. Thus, a critical radius r⋆ results, which must be reached before the precipitate continues to grow with a decrease in free enthalpy. Since r* occurs at the maximum of the curve, the following applies: d∆G = 0 = 4πr⋆2 ∆gv + 8πr⋆ γs dr (3.9) i. e. r∗ = − r∗ 2γs . ∆gv (3.10) Critical radius According to eq. 3.10, r⋆ becomes smaller, the larger the absolute value of ∆gv is and the smaller γs is. The negative sign results because ∆gv is negative. An important result of this observation is that precipitates do not form immediately despite the existence of a thermodynamic driving force (∆Gv < 0), because the free enthalpy rst increases until r⋆ is reached. At this point, one may ask how precipitates can be formed at all, if ∆G increases rst. This is due to the fact that the atoms can move in the crystal lattice. Responsible for this is another type of defect in the crystal lattice, namely unoccupied lattice sites, which are called vacancies (Fig. 3.18). In this context, it is important to realize that the atoms in the crystal lattice are not at rest but vibrate, and the higher the temperature, the stronger the vibration. The amplitude of oscillation varies from oscillation to oscillation. In Fig. 3.18, top left, the 77 3 Strength and phase diagrams atom marked with an arrow has such a large amplitude at the time under consideration that the atom overcomes the bonding forces to the neighboring atoms and jumps into the neighboring vacancy. The vacancy and the atom have changed places and moved. In the next moment (top right image), the same happens for an atom dissolved in the host lattice (blue) and then again for host atoms (bottom row of images). These processes will be discussed in more detail in Chapter 4.1. At this point, it is sucient to realize that atoms can change places in the crystal lattice and that this occurs more frequently the higher the temperature is. This change of places causes a random movement of the atoms in the crystal lattice, which is called diusion. As a result, it happens by chance that a precipitate particle with the critical radius r⋆ forms and then continues to grow because this is now energetically favorable. Figure 3.18: Crystal lattice consisting of host atoms (black), dissolved atom (blue) and a vacany. Due to lattice vibrations, atoms can move into a void. As the example shows, this can also lead to the movement of the dissolved atoms in the crystal lattice. We now imagine an aluminum alloy consisting of aluminum and 4 % Cu. As illustrated by the phase diagram shown in Fig. 3.19, the solubility limit for this alloy is 500 C. At a temperature T ≥ 500 C, the copper content is completely soluble and a solid solution is present. Below 500 C, ∆gv is negative. Thus, there is a thermodynamic driving force for the formation of precipitates, in this case CuAl2 . As mentioned, the precipitates nevertheless do not form immediately, because the energy hill must rst be climbed. The question now is how long this takes. First, it is clear that no particles can form at 500 C and above because ∆gv is zero at 500 C and positive above. Below 500 C, on the other hand, ∆gv is negative and becomes more negative as the temperature decreases. It is then only a matter of time before precipitates form. Let us rst imagine a relatively high temperature a little below 500 C. Because the solubility limit is only slightly undershot, the absolute value of ∆gv is small and thus r⋆ is very large. Therefore, it takes a very long time for a particle with critical radius r⋆ to be formed by random change of the atom positions, even though the velocity at which the atoms change their places, in ° ° ° ° ° ° 78 ° 3 Strength and phase diagrams the following referred to as place change velocity, is large to the high temperature. This is shown in Fig. 3.20. The curves labeled 1 and 99 respectively indicate the time after which 1 % and 99 % of the precipitable volume of CuAl2 has formed at a given temperature. The two curves thus represent approximately the beginning and the end of the precipitation process. Also plotted is the solubility limit above which CuAl2 can never form. T,°C single phase (Al-solid solution) 700 600 Liquid + Al-solid solution 500 400 300 two phase (Al- solid solution + CuAl2-solid solution) 200 100 0 0 4 8 12 16 20 24 28 32 36 40 weight-% Cu Figure 3.19: Binary phase diagram for the system aluminium-copper (adapted from [26]). The alloy Al-4Cu is marked. If we next imagine a low temperature, e.g. room temperature, then the absolute value of ∆gv is large and r⋆ is very small. However, it takes a very long time for the precipitation process even in this case, because now the place change velocity of the atoms is extremely low. On the other hand, as Fig. 3.20 shows, the precipitation process is fastest at intermediate temperatures because then the place change velocity is relatively large and r⋆ is relatively small. Thus, the precipitation process is not extremely retarded because neither r⋆ is huge nor is the place change velocity extremely small. Accordingly, Fig. 3.20 shows a curve which has the shape of a nose. Such diagrams are called time-temperature-transformation diagrams (TTT diagrams for short), because they give information about phase transformations (here the formation of CuAl2 precipitates) as a function of temperature and time. TTT diagrams thus indicate the rate at which phase transformations take place. The outstanding feature of particle strengthening is that particularly large increases in strength can be achieved by this method. However, this requires very small precipitates with diameters that are typically a few to a few tens of nanometers. Accordingly, the next question is how such small diameters can be realized. In this context, two parameters are important: First, the number of particles with radius r⋆ that form per unit time in a volume under consideration, hereafter referred to as the nucleation rate. Second, the growth rate of these particles. Initially, we imagine that the nucleation rate is small and 79 3 Strength and phase diagrams Figure 3.20: Time-temperature transformation diagram for the formation of CuAl2 in Al-4Cu, after [2]. The two red curves indicate the beginning and the end of the precipitation process. Also plotted (see blue curve) are the heat treatment steps in particle strenghtening, consisting of solution heat treatment, quenching and precipitation heat treatment. the growth rate is large. So it takes a long time to form a particle that can continue to grow on its own. It then grows rapidly because the growth rate is large. In the case of CuAl2 precipitates in the aluminum solid solution, the area surrounding a particle is depleted of Cu, because this element accumulates in the particle. As a result, it is no longer possible to form further CuAl2 particles in the neighborhood of this particle, because there is no longer sucient copper for this. After some time, another particle may form at a great distance, which then also grows rapidly and prevents further particle formation in its vicinity. So it is clear that in this case few, large particles are formed, which is undesirable. Now let us imagine the opposite. Let the nucleation rate be large and the growth rate be small. Then very many particles are formed in a short time, but they grow only slowly. Before they can grow to any appreciable extent, other particles have already formed in their neighborhood, so that, as desired, the precipitated particle volume consists of many small particles. Thus, a large nucleation rate coupled with a low growth rate is desirable. Of course, one can wish for many things. The question is what can be achieved in reality. For this purpose, one must be clear about what both variables depend on. The smaller r⋆ is, the higher is the nucleation rate, because the easier it is to form a growing particle. Because random place changes of the atoms are required for this, the nucleation rate also increases with the place change velocity of 80 3 Strength and phase diagrams the atoms. Likewise, particle growth increases with the place change velocity, because it is these place changes that, in the example of the CuAl2 particles, allow copper to be transported to the particle. Thus, if the place change velocity is increased, this has a desirable and an undesirable eect. These two eects cancel each other out, so that the place change velocity has no inuence and r⋆ remains as the only relevant variable. The smaller r* is, the ner the precipitates are. Thus, to ensure ecient particle strengthening, we need a small r⋆ . Based on this observation, the question arises how to ensure a small critical radius. This is shown by Eq. 3.10. Obviously, the specic interfacial energy γs must be small for this purpose. Therefore, not all particles of a second phase, which precipitate in a matrix, are suitable for particle strengthening, but only coherent ones, because for them γs is small. Particle strengthening is therefore possible, for example, only for very specic aluminum alloys and not for others. As the above example shows, Cu-containing aluminum alloys obviously belong to the former group. Additionally, the critical particle radius becomes the smaller the more negative ∆gv is, i.e. the lower the temperature is. Therefore, the lower the temperature at which the precipitation reaction takes place, the smaller the precipitated particles become. Thus, one could conclude that it is best to simply wait at room temperature until the CuAl2 particles have precipitated out in our example. However, Fig. 3.20 shows that this is not too good an idea, because the precipitation process would start only after a waiting time of about 8000 hours (i.e., almost a year) and would be completed only after many years. The premise is therefore to choose a temperature that is as low as possible, but also as high as necessary, so that the precipitation process takes place in a technically reasonable period of time. As Fig. 3.20 shows, temperatures around 150 C are a reasonable choice for the Al-Cu alloy under consideration. From what has been learned, the following sequence of temperature control must be followed during particle strengthening. First, the material must be heat treated in a single-phase eld to dissolve particles formed in an uncontrolled manner and to achieve an initial single-phase state. In Fig. 3.20, approx. 530 C was chosen for this purpose (see starting point of the blue curve). After this, the material must be quenched. The quenching rate must be high enough to pass the "nose" in the TTT diagram, as shown in Fig. 3.20 by the blue curve, so that the single-phase state is maintained. If one were to cool more slowly than shown in Fig. 3.20, the precipitation process would begin at high temperatures, resulting in large particles. Then, the material is heat treated at a temperature that, as mentioned, is chosen as low as possible but as high as necessary. This heat treatment step is called precipitation heat treatment. In summary, there are three steps: ° ° Solution heat treatment Quenching Precipitation heat treatment Finally, a subtlety in the TTT diagrams should be pointed out. In Fig. 3.20, on the one hand, a cooling curve is drawn in which the temperature changes continuously 81 3 Strength and phase diagrams with time. On the other hand, the temperature does not change with time during the precipitation heat treatment. Of course, the temperature-time history has an eect on the time at which phase transformations occur. Thus, it makes a dierence whether one cools continuously from a certain temperature (about 530 C in Fig. 3.20) and observes when a phase transformation occurs as a function of the cooling rate, or whether one sets (very quickly) a certain temperature, keeps it constant, and then determines the time at which the phase transformation occurs. In practice, both temperature control methods are commonly used. Therefore, there are so-called continuous TTT diagrams, which are based on experiments with continuous cooling, and isothermal TTT diagrams, which are based on isothermal heat treatments. However, the dierences are mostly small and irrelevant for qualitative considerations, as they are in the foreground here. For this reason, no distinction is generally made here between these two types of diagrams. If you want to have exact information, however, you have to use the TTT diagram applicable to the respective case. Due to the logarithmic time scale, it is always the case that continuous cooling curves in the TTT diagram are convexly curved and, hence, always reach the nose above the nose tip. Because the phase transformation in the temperature range above the nose tip is slower the higher the temperature, the continuous TTT diagram above the nose tip shifts to somewhat larger times compared to the isothermal one. For example, isothermal holding at 400 C would result in faster precipitation of CuAl2 particles than cooling from 530 C to 400 C. This situation is illustrated in Fig. 3.21. There, the red lines indicate the beginning and end of the precipitation process of CuAl2 particles for isothermal heat treatment, and the green lines for continuous cooling. It can be seen that the green curves above the nose tip are shifted to the right to longer times. Below the nose tip the eects reverse, because below the nose tip phase transformations are slower the lower the temperature. Accordingly, the two green curves below the nose tip shift forward relative to the red ones. The green, dotted line indicates that here the precipitation process comes to a standstill during cooling because diusion is now too slow. Unlike the green solid lines, the precipitated volume of CuAl2 particles is not constant along the dotted line. Rather, it changes from one percent of the precipitable volume on the far left to 99 % on the far right. In the middle, at the position of the number 50, it is 50 %. In Fig. 3.21, two continuous cooling curves are also shown in green with dashed lines. If one follows the continuous cooling curve 2 , the precipitation process starts at approx. 450 C and ends at approx. 400 C. The precipitable content of CuAl2 has now been completely formed. If one follows the continuous cooling curve 1 , the precipitation process starts at approx. 400 C. However, the second curve, which shows that the entire precipitable CuAl2 volume has now been formed, is never reached. Rather, the green, dotted line is intersected at about 260 C. As already mentioned, the precipitation process comes to a halt here and the number 50 indicates that half of the precipitable volume of CuAl2 particles has formed at this point. Finally, a possible misinterpretation when interpreting cooling curves on the basis of isothermal TTT diagrams must be pointed out. For this purpose, we once again consider the cooling curve 2 . The beginning and end of the precipitation process are described ° ° ° ° ° ° O ° ° O 82 O 3 Strength and phase diagrams qualitatively correctly using the red curves for the isothermal diagram. Only slightly too high temperatures result, for example approx. 430 C instead of approx. 400 C for the end of the precipitation process. The red curves are intersected by the cooling curve again at approx. 250 C and approx. 150 C. However, this is meaningless. It would be a misinterpretation to conclude that CuAl2 dissolves again between 250 C and about 150 C. As the phase diagram shows (Fig. 3.19), CuAl2 is thermodynamically stable below 500 C for the alloy Al-4Cu considered here. Once formed, it therefore does not dissolve on cooling. ° ° ° ° ° ° ° Figure 3.21: Isothermal (red lines) and continuous (green lines) TTT diagram of the alloy Al4Cu, after [2]. Green, dashed lines show two cooling curves with dierent cooling rates. 3.3.5 Combined measures to increase strength: the quenching and tempering of steels In the case of steels, there is a technologically very important process for achieving a favorable combination of strength and ductility, known as quenching and tempering. Due to the outstanding importance of quenching and tempering, this chapter will take a closer look at the processes involved. We will see that several hardening mechanisms interact in this process, i.e. the resulting increase in strength is made up of various contributions from the individual mechanisms discussed in sections 3.3.1 to 3.3.4. To get started, we look at the iron-carbon phase diagram (Fig. 3.36) and set ourselves the goal of realizing particle strengthening by precipitating Fe3 C particles in the αphase. If we proceed according to the procedure worked out in chapter 3.3.4, we rst 83 3 Strength and phase diagrams have to transform the steel into the single-phase state by heat treatment in the α single phase eld. According to Fig. 3.36, the maximum carbon solubility in the α-phase is 0.02 %. It is reached at 723 C. Thus, in order to heat treat in the α single phase eld, we must choose a steel with a carbon content not exceeding this value. After solution heat treatment, the steel is quenched and precipitation heat treated, e.g. at 300 C. If we were now to measure the strength, the disappointment would be great, because the increase in strength would be very small. This is due to the low solubility of carbon in the α-phase. As can be seen immediately from the lever rule, this leads to a very low volume fraction of precipitated Fe3 C particles and therefore to a small increase in strength. Looking at the Fe-C phase diagram again, one can come up with another idea. Since the γ -phase can dissolve much more carbon than the α-phase, one could choose a steel with a higher carbon content (e.g. 0.8 %) and set a single-phase condition by solution heat treatment in the γ single phase eld, e.g. at 1000 C. The material is then quenched. Fig. 3.22 shows the corresponding TTT diagram on the left. It can be seen that the nose in the TTT diagram can be avoided when the steel is quenched out of the γ phase eld in about one second (see step 1 to 2 in Fig. 3.22). In this case, too few atomic place changes take place, i.e., diusion is too slow. Therefore, α-phase and Fe3 C cannot form by a transformation that requires diusion. Thus, one would expect single phase γ to continue to exist after quenching. However, this is not the case, because the γ -phase nds another way to transform into the α-phase without requiring atomic place changes (for which there is not enough time). Such phase transformations (here from the γ -phase into the α-phase), which take place without the atoms changing places, are called martensitic transformations. In contrast, phase transformations that require place change processes (i.e. diusion) are called diusion-controlled. Because martensitic transformations do not require diusion, they cannot be suppressed by rapid quenching. They always take place when a thermodynamic driving force is present. This is also illustrated in Fig. 3.22. On the basis of the horizontal line marked Ms at approx. 230 C, it can be seen that the martensitic transformation of the steel shown with 0.8 % carbon starts at approx. 230 C, even at extremely rapid cooling rates. The only prerequisite is that one passes the nose in the TTT diagram, as shown by the cooling curve marked with 1 in Fig. 3.22, so that a diusion-controlled transformation has not already taken place beforehand. Ms stands for martensite start temperature. Thus, the martensitic transformation starts at this temperature. M50 and M90 , on the other hand, denote the temperatures where 50 % or 90 %, respectively, of the γ -phase is martensitically transformed. Mf indicates the martensite nish temperature, where 100 % is transformed into martensite. With increasing carbon content, the martensitic transformation temperatures are reduced because carbon stabilizes the austenite with respect to the ferrite (see g. 3.36). At 0.8 % carbon content, Mf is at room temperature. Thus, the austenite is barely transformed completely into martensite. At higher carbon content, this would no longer be possible. During the martensitic transformation, the atoms within the austenitic crystal reorient themselves slightly so that the face-centered cubic structure becomes body-centered cubic. This so-called displacive transformation can best be illustrated by comparing the ° ° ° O O ° O 84 ° 3 Strength and phase diagrams Temp., °C 723° 3 1 1s 2 1 min 1h 1a 0,8 Figure 3.22: Schematic TTT diagram of an eutectoid steel with a carbon content of 0.8 wt.-% (left) with corresponding phase diagram (right), after [27]. elementary cells of the face-centered cubic γ -phase and the body-centered cubic α-phase sketched in Fig. 3.23. If we look at two adjacent unit cells of the face-centered cubic structure, it is clear that there is a distorted body-centered cubic unit cell between two unit cells, which is compressed along two axes and stretched along the third axis. A slight displacement of the atoms in such a distorted cell can transform the crystal into a cubic body-centered one without the need for atomic place changes. The transformation is therefore diusionless. It begins at numerous sites within a crystal and spreads from there almost at the speed of sound. The movement of the atoms is coordinated, whereby the atoms always rearrange themselves around the area that has already been transformed. Also, the orientation of the new crystal lattice is not arbitrary, but depends on that of the old crystal lattice. The new α-crystals grow in a roughly lenticular shape. In a metallographic cross sectional cut through such a structure, typical so-called martensite needles can be observed (Fig. 3.24). Because very many martensite needles form in an austenite grain, a very ne structure is created. Not least because the body-centered cubic lattice is somewhat less densely packed than the face-centered cubic lattice, considerable internal stresses and local plastic deformation occur during martensitic transformation. The latter causes a high dislocation density in the martensitic microstructure. In addition, a high carbon content is now forcibly dissolved in the α-phase. This leads to an extreme distortion of the crystal lattice and thus to an unusually strong solid solution strengthening, which increases strongly with 85 0, 355nm 3 Strength and phase diagrams 1 nm 0, 25 0, 355nm (a) Two face-centered cubic cells from the γ -phase (austenite). (b) Tetragonal cell from (a). (c) Martensite cell Figure 3.23: Illustration of the martensitic transformation from the γ -phase to the α-phase. Hereby, the face-centered cubic unit cell is compressed in one direction and elongated in the others [26]. Figure 3.24: Micrograph of a quenched steel containing 0.6 % carbon. Martensite needles can be seen. [26]. the carbon content. Finally, the martensite needles are very ne, so that a ne-grained structure with corresponding strengthening by grain size reduction is present here. Thus, solid solution strengthening, work hardening and strengthening by grain size reduction interact here, with the former mechanism having by far the greatest strengthening eect. Above a carbon content of about 0.2 %, this results in an extremely strong and hard, but also very brittle material state. In this state, the material has no useful properties due to its brittleness. Therefore, a heat treatment is carried out, which is called tempering (see Fig. 3.22 Step 3 ). Depending on the application, temperatures between 150 C and 600 C are typical. In this process, part of the lattice distortion is removed by precipitation of nely distributed carbide particles (Fe3 C). This results in a very ne microstructure overall (nely distributed martensite needles, nely distributed precipitates), which leads to a very favourable combination of strength and ductility. Naturally, the strength decreases with increasing tempering temperature, whereas the ductility increases. Steels with this favourable combination of properties are called quenched and tempered steels. It is important to note that not every steel is suitable for such heat treatment. In addition to a sucient carbon content (see above), a homogeneous dis- ° ° O 86 3 Strength and phase diagrams tribution of carbon in the structure is particularly necessary. If this were not the case, strong uctuations in the properties of the material would result. At places of locally increased carbon concentration, the material would be disproportionately strong and not very ductile, while at places with too low carbon content, the result would be too low strength with high ductility. This would not be acceptable for practical use. The possibility of hardening and tempering steels is decisive for the special importance of steels in mechanical engineering. This is only possible because iron has two dierent phases (α and γ ) and the phase existing at higher temperatures has a much greater carbon solubility. If this were not the case, steels would not be as important as they are today. Finally, the TTT diagram of Fig. 3.22 should be considered again. There, on the right, the designations coarse pearlite, ne pearlite and bainite are given for the microstructure transformed by diusion, whereby it is sucient here to imagine bainite as particularly ne perlite. In analogy to particle strengthening, where the precipitated particles become ner and ner with decreasing precipitation temperature, here the pearlitic microstructure becomes ner and ner (i.e. the α- and Fe3 C-lamellae become narrower and narrower), the lower the temperature for the diusion-controlled transformation is. The beginning and end of the diusion-controlled transformation is depicted by two solid lines. The dashed one indicates an intermediate state. 3.4 Phase diagrams For the description of solid solutions and precipitates (sections 3.3.3 and 3.3.4) the Al-Mg phase diagram (Fig. 3.12) has already been mentioned. In the following, phase diagrams are explained in more general terms. 3.4.1 Solubility, states of aggregation, Gibbs phase rule The term phase can be illustrated by the dierent behaviour solutions in the liquid state (Fig. 3.25). If alcohol is added to water, the alcohol dissolves. The composition is the same everywhere in the liquid, so there is only one liquid phase. If, on the other hand, oil and water are mixed, the oil does not dissolve, and there are two phases. Common salt dissolves in water. At high concentrations, the solubility limit is exceeded, and salt is precipitated as a solid phase from the supersaturated solution. In general, a phase is matter of spatially constant physical state (e.g. state of aggregation, crystal structure). The phase diagram shows which phases are stable at a given composition, temperature T and pressure p. Gibbs' phase rule gives a correlation between the number of the equilibrium phases P , the number of degrees of freedom f and the number of components n of a system: (3.11) f =n−P +2 . Hereby are: 87 3 Strength and phase diagrams (a) States of aggregation of water. (b) Water and alcohol. (c) Water and salt. (d) Water and oil. Figure 3.25: Phases and solubility, adapted from [6]. f n P number of the degrees of freedom number of components number of equilibrium phases Degrees of freedom are freely selectable system variables (e.g. composition of phases, temperature, pressure). Examples of components are elements or stable chemical compounds (molecules). For pure elements or water as a molecule n = 1 holds and the composition does not change. The three states of aggregation (solid, liquid and gaseous) represent possible phases. In the corresponding single-phase regions (P = 1) in the phase diagram of water (p-T diagram, Fig. 3.26) there are two degrees of freedom (f = 2) according to the phase rule, i.e. pressure and temperature can be changed without leaving the region. Along the lines that dene the areas of existence of the phases, two phases are in equilibrium (P = 2). This results in a degree of freedom (f = 1), i.e. one system quantity (e.g. pressure) can be specied and, thus, the other system quantity (temperature) is xed. 88 3 Strength and phase diagrams Pressure p At the triple point all three phases are in equilibrium (P = 3) and all system variables are xed (f = 0). Liquid Solid (Ice) 1 bar Vapour TSm T3 TS Temperature T Figure 3.26: Schematic phase diagram of water. The meaning of the symbols is as follows: TSm - melting temperature, T3 - triple point, TS - boiling temperature If one considers materials in mechanical engineering, such as steels, only the solid and liquid states of aggregation are of interest. Since the phase boundaries between solid and liquid substances depend only to a small extent on pressure and applications usually take place at 1 bar, the pressure is generally xed so that one degree of freedom is already consumed. Thus, the phase rule can be written as follows: (3.12) f = n − P + 1 (p = const.). For a pure metal (n = 1) at the melting point the following applies: (i) two phases are stable (solid and liquid, P = 2); (ii) there is no longer a freely selectable system variable, i.e. the number of degrees of freedom is f = 0. 3.4.2 Binary systems and microstructure formation Systems of two substances consist of two components (n=2; e.g. Cu-Ni, Fig. 3.27). If one xes the pressure, which is always assumed in the following, the temperature and the compositions of the phases are the remaining degrees of freedom. In the phase diagrams, the temperature T is plotted on the ordinate and the concentration c of the added element (in weight-% or atom-%) on the abscissa. Binary phase diagrams with complete miscibility Fig. 3.27 shows the binary phase diagram for the copper-nickel system. On the left and right ends of the diagram there are 100 % copper and 100 % nickel, respectively. From 89 3 Strength and phase diagrams Figure 3.27: Binary phase diagram for the copper-nickel system. L: melt; α: solid, adapted from [7]. left to right, the nickel content increases, which lowers the copper content. The sum of both concentrations is always 100 %. The phase diagram for copper and nickel is particularly simple because in the solid state there is only one phase (α). Therefore, there is a complete miscibility between the two metals. If one starts on the left end of the phase diagram, pure copper with a face-centered cubic crystal structure exists. If one moves then to the right, more and more nickel is dissolved in the face-centered cubic crystal until one nally arrives at pure nickel, which is also face-centered cubic. Requirements for complete miscibility are the same crystal structure of the components and an identical or only slightly dierent atomic radius r. Basically, such a phase diagram can be divided into three regions: a single-phase region of the melt (L = liquid), which is delimited by the so-called liquidus line, a single-phase region of the solid solution (α), which is delimited by the so called solidus line, and the lenticular, two-phase region enclosed by the solidus and liquidus line. This region is two-phase, since both liquid melt (L) and solid solution (α) are present. For a certain temperature, the concentrations of both phases are given by so-called tie-lines. These are horizontal lines (i.e. lines at a certain temperature) extending over the entire twophase eld, with the end points of the tie-lines giving the respective concentrations. In Fig. 3.27 this is exemplary shown for T=1300 C. The end point of the tie-line on the liquidus line denotes the concentration of the melt (cliq ) and the end point at the solidus line the concentration of the solid solution (csol ), which is in equilibrium with the melt. ° 90 3 Strength and phase diagrams If the Gibbs phase rule is applied to the two-phase region, the degree of freedom is f = 2 − 2 + 1 = 1. For example, one can freely choose the temperature. Then, the compositions of the two phases are determined by the corresponding tie-line. It is also possible to freely select the concentration of a phase, e.g. the concentration cliq shown in Fig. 3.27. Then, the position of the tie-line is dened, i.e. temperature and concentration of the second phase are xed. Further examples for complete miscibility are silverpalladium (face-centered cubic; rAg = 0.145 nm; rPd = 0.138 nm)) or molybdenumtungsten (body centered cubic; rMo = 0.136 nm; rW = 0.137 nm). Figure 3.28: Equilibrium solidication by slow cooling of a copper-nickel alloy. a and b stand for the length of the lever arms, explanation see text, adapted from [7]. Let us now consider the cooling of a Cu-Ni melt containing 40 wt.% nickel (Fig. 3.28). At a temperature above 1280 C, only the melt is present. When cooling down to 1280 C the two-phase eld is reached. The rst crystals precipitate and oat in the melt. According to the associated tie-line, they have a nickel concentration of 52 %, i.e. they are enriched with the higher melting element nickel. With further cooling, the proportion of the solid solution increases, whereby the composition of the melt and solid solution changes. Both phases become poorer in nickel. When the solidus temperature is reached, the last melt solidies and the copper alloy containing 40 wt.% nickel is completely solidied. It is now a single-phase solid solution. ° ° Lever rule The previous example has shown that the proportions of melt and solid solution change while the two-phase eld (α+L) is passed through during solidication. How large these proportions are at a certain temperature can be calculated using the so-called lever rule, which is explained using the Cu-Ni system presented here. According to Fig. 3.28 the following is dened: c(Ni) concentration of nickel in the alloy (gross concentration) cliq(Ni) concentration of nickel in the melt csol(Ni) concentration of nickel in the solid Furthermore, the masses are dened as: 91 3 Strength and phase diagrams mliq msol m = msol +mliq mass of the liquid phase mass of the solid phase entire mass Since the mass of nickel must be preserved, the following applies: csol(Ni) · msol + cliq(Ni) · mliq = c(Ni) · m = c(Ni) · (msol + mliq ). (3.13) Rearrangement results in: (csol(Ni) − c(Ni) ) · msol = (c(Ni) − cliq(Ni) ) · mliq . ° (3.14) If we inspect the example in Fig. 3.28 (tie-line at approx. 1260 C), the tie-line can be interpreted as a seesaw, which is supported at the gross concentration (c(Ni) =0.4). The length of the lever arms a and b of this seesaw result as: Lever arm a Lever arm b = c(Ni) − cliq(Ni) = csol(Ni) − c(Ni) And the length of tie-line is: Tie-line length a + b = csol(Ni) -cliq(Ni) Similar to the equilibrium of moments in mechanics, the lever rule says (eq. 3.14), that the product of the right lever arm length b with the mass of the phase at the right hand side (msol ) must be as large as the product of the left lever arm length a with the mass of the left phase (mliq ). When solidication begins, the lever arm (c(Ni) − cliq(Ni) ) is very short. Correspondingly, the mass of the melt is large. The opposite is true at the end of the solidication. Adding the term (c(Ni) − cliq(Ni) ) · msol on both sides of eq. 3.14, results in: (csol(Ni) − c(Ni) ) · msol + (c(Ni) − cliq(Ni) ) · msol = (c(Ni) − cliq(Ni) ) · mliq + (c(Ni) − cliq(Ni) ) · msol (3.15) msol · [(csol(Ni) − c(Ni) ) + (c(Ni) − cliq(Ni) )] = (c(Ni) − cliq(Ni) ) · m (3.16) (c(Ni) − cliq(Ni) ) msol = m (csol(Ni) − cliq(Ni) ) (3.17) And in analogy: 92 3 Strength and phase diagrams (csol(Ni) − c(Ni) ) mliq = m (csol(Ni) − cliq(Ni) ) (3.18) This relation says that the mass fraction of one phase (msol /m respectively mliq /m) is given by the ratio between the length of the opposite lever arm (a respectively b) and the total length a+b. This calculation of the phase fractions can be used in any twophase area. For example, it can also be used to determine the proportion of precipitates during precipitation hardening. Non-equilibrium solidication with complete miscibility In the case of very slow cooling, concentration dierences in the solid state are compensated by diusion, i.e. the movement of atoms in the solid. In this way, the Ni concentration of the solid solution formed in Fig. 3.28 changes from 52 % to 40 % and at the end of solidication a homogeneous solid solution is obtained (Fig. 3.28) which has the same concentration everywhere. As shown in Fig. 3.29, the conditions for rapid cooling (non-equilibrium solidication) are dierent. At rst, crystals precipitate again with a nickel concentration of 52 %. After further cooling the equilibrium concentration of nickel in the solid is 46 % and the already solidied material should actually release nickel by diusion in order to reach this equilibrium concentration. However, as the solidication is fast, this does not occur. Only the newly solidied material is deposited with this concentration at the previously solidied one. Say, the resulting average nickel concentration in the solid is 51 %. After further cooling to the solidus temperature the equilibrium concentration of nickel is 40 % and say the average is 48 %. Under equilibrium conditions, solidication would be now fully completed. Here, however, this is not yet the case, because the average concentration of the solid does not yet correspond to the gross concentration of 40 %. Accordingly, the solidication process continues until the average nickel concentration in the solid material has reached 40 %. Thus, in the case of rapid cooling the solidication interval is given by the thin dash-dotted line in Fig. 3.29. Due to this non-equilibrium solidication, concentration dierences are formed within the solidied solid solution. They are referred to as segregation. Figure 3.29: Non-equilibrium solidication through rapid cooling of a copper-nickel alloy, adapted from [7]. 93 3 Strength and phase diagrams Binary phase diagrams with limited miscibility If the solubility of the components in the solid state is limited, miscibility gaps occur, i.e. there are T -c areas in which two solid phases coexist. An example of this is the eutectic system, which is described below on the example of the Pb-Sn phase diagram (Figs. 3.30 to 3.33). In the medium concentration range lies the two-phase eld ((α + β)), which reaches up to the solidus line. A small quantity of tin is soluble in the α-Pbphase and up to a tin content of 2 wt.% a single-phase solid solution is formed from the melt during solidication (Fig. 3.30). Alloys with a tin content between 2 and 19 wt.% solidify rst to a single-phase solid solution, but if the solution falls below the solvus line, the second phase is precipitated (Fig. 3.31). This behaviour is utilized for precipitation strengthening (chapter 3.3.4). Figure 3.30: Solidication of a Pb-2 wt.% Sn alloy, adapted from [7]. For Sn contents between 19 wt.% and 61.9 wt.%, solidication begins, as before, with the precipitation of the α-phase (Fig. 3.32). At 183 C, however, the eutectic reaction now takes place, in which the residual melt, having a Sn content of 61.9%, solidies into two solid phases. A Pb-Sn melt with eutectic composition (61.9 wt.% Sn) solidies at a certain temperature (the so-called eutectic temperature) completely (without solidication interval), and there are two solid phases after solidication. Therefore, three phases are in equilibrium at the eutectic temperature (melt + 2 solid phases, P = 3). According to the phase rule (eq. 3.12), the number of degrees of freedom is f = 0. The two-phase eutectic microstructure (Fig. 3.33) is characterized by a lamellar arrangement of the two phases. Elements which are hardly soluble in the solid state generally stabilize the more tol- ° 94 3 Strength and phase diagrams Figure 3.31: Solidication of a Pb-10 wt.% Sn alloy, adapted from[7]. Figure 3.32: Solidication of a Pb-30 wt.% Sn alloy, adapted from [7]. erant melt and lower the liquidus temperature. This is exploited for solder materials, which often have a composition close to eutectic. In addition to the eutectic solidication, which follows the reaction scheme L ↔ α + β , there is another reaction, the so-called peritectic solidication, in which three phases are in equilibrium, i.e. the number of degrees of freedom is zero. This is shown in Fig. 3.34 on example of the Ni-Re phase diagram. If an alloy with a rhenium content of 60% is imagined, it begins to solidify at 2481 C, forming the β -phase (= Re-rich solid solution). At the peritectic temperature of 1620 C, the residual melt solidies by reacting with the β -phase to form the α-phase (= Ni rich solid solution). The reaction scheme is now L + β ↔ α. Phase diagrams often consist of a sequence of peritectic and eutectic reactions. An example is the phase diagram for nickel and aluminium shown in Fig. 3.35. On the Al rich side, one can see a eutectic reactionL ↔ α + δ at 639.9 C. The phase α stands for the Al-rich solid solution. Because the solubility for nickel is very low, the expansion ° ° ° 95 3 Strength and phase diagrams Figure 3.33: Solidication of a Pb-61,9 wt.% Sn alloy, adapted from [7]. Figure 3.34: Binary phase diagram of the Ni-Re system, adapted from [23]. 96 3 Strength and phase diagrams of this single-phase eld is also very small and can hardly be seen in the diagram. At 854 C, a peritectic reaction is present. Here, the melt reacts with the ε-phase to the δ -phase (reaction scheme: L + ε ↔ δ ). While the ε-phase exists from about 57 % to 61 % nickel, the range of existence of the δ -phase is so narrow that it only appears as a line in the diagram. A further peritectic reaction occurs at 1133 C (reaction scheme: L + β ↔ ε). At high nickel contents (to the right of the β -phase) a peritectic reaction (reaction scheme: L + β ↔ γ ') and a eutectic reaction (reaction scheme: L ↔ γ ' +γ ) occur. In addition, at 700 C the β -phase reacts with the γ '-phase under formation of the η -phase (reaction scheme: β + γ ′ ↔ η ). Since only solid phases are involved, one is not talking of a peritectic reaction but a peritectoid reaction. The so-called nickel-based superalloys are based on this phase diagram. With the help of the alloying element aluminium, the Ni-rich solid solution (γ -phase) is precipitation strengthened by the γ 'phase, resulting in outstanding strength at operating temperatures up to about 1000 C. ° ° ° ° Figure 3.35: Binary phase diagram of the Al-Ni system, adapted from [24] . 3.4.3 The Iron-Carbon Diagram The iron-carbon diagram is the most important phase diagram in engineering because steel, as an alloy of iron and carbon, is based on this diagram and, with an annual world production of about 1.6 billion tons, is the most frequently used material in mechanical engineering. Accordingly, the iron-carbon diagram (Fe-C diagram for short) will be discussed in more detail here. In Fig. 3.36 it is shown up to a carbon content of about 6.6 %. According to the diagram, the melting temperature of pure iron is 1536 C. At this temperature, the melt (denoted by the symbol L for liquid) solidies into solid iron with a cubic body-centered crystal structure. This rst solid phase is called ° 97 3 Strength and phase diagrams ° the δ phase. At a temperature of 1392 C, a transformation of the crystal structure from the body-centered cubic to the face-centered cubic takes place. This face-centered cubic modication of the iron is called the γ phase or austenite. If one cools further, the face-centered cubic lattice transforms again into the body-centered cubic lattice at 911 C. The resulting phase is called α-phase or ferrite. The respective lattice structures have already been presented in Chap. 2.3 (Fig. 2.22 on page 34). ° Figure 3.36: Metastable iron-carbon diagram. If carbon is now added to the iron, it is dissolved within certain limits in the α, γ or δ phase. Solid solutions are formed. It is noticeable that the γ phase can dissolve much more carbon than the α phase. In the γ phase, up to 2.06 % carbon is soluble at 1147 C, whereas in the α phase a maximum of 0.02 % at 723 C is soluble. As already mentioned in section 3.3.5, the existence of these two phases with their enormous dierence in solubility for carbon is the decisive reason why the mechanical properties of the steels can be adjusted within wide limits depending on the application (see Chap. 3.3.5). In Fig. 3.36, three reactions can be seen in which three phases are in equilibrium, i.e. the number of degrees of freedom is zero. First, a so-called peritectic reaction occurs at 1493 C (top left in the diagram). Here, melt L and δ phase transform according to the reaction L + δ ↔ γ into the γ phase. However, this reaction is not important for understanding the steels. Secondly, a so-called eutectoid transformation takes place at 723 C. In this process, the γ phase with a carbon concentration of about 0.8 % decomposes into the α phase and the iron carbide Fe3 C, which is also called cementite, ° ° ° 98 ° 3 Strength and phase diagrams according to the reaction γ ↔ α + Fe3 C. A eutectoid reaction diers from a eutectic reaction by the fact that here, a solid phase (instead of a liquid phase) decomposes into two solid phases. Third, a eutectic reaction occurs at 1147 C where melt with a carbon concentration of 4.3 % transforms according to the reaction L ↔ γ + Fe3 C into γ phase and Fe3 C. According to the phase diagram, the solidication of the melt ends with this reaction when the carbon content is more than 2.06 %. At lower contents, solidication occurs either via the peritectic reaction described above or by the melt transforming directly into the γ phase when passing through the two-phase eld L + γ . Steels are all Fe-C alloys with a carbon content of not more than 2.06 %, whereas Fe-C alloys above 2.06 % C are called cast iron. In steels, the carbon always precipitates as iron carbide Fe3 C, whereas in cast irons both Fe3 C and graphite can form. In the rst case, one speaks of white cast iron. In the second, technically more important case, which generally requires the addition of graphite-stabilising elements (especially silicon), one speaks of grey cast iron. Surprisingly, graphite is slightly more thermodynamically stable than Fe3 C, although precipitation of graphite occurs only under special circumstances due to kinetic inhibition. As Fig. 3.37 shows, the phase boundary lines shift slightly when graphite forms instead of Fe3 C. These changes are shown by the blue dashed lines. They occur only where carbon / Fe3 C are involved in the phase formation. Where this is not the case, the phase diagram remains unchanged and the black lines continue to apply. The relevant diagram for steels with formation of Fe3 C is therefore the metastable diagram (solid lines in Fig. 3.37), whereas the diagram with the changes according to the blue dashed lines is the stable one. In the following we restrict ourselves to the steels, i.e. carbon contents not exceeding 2.06 %. In accordance with our considerations above, we assume that the γ phase has formed after solidication of the melt, and we now follow the microstructural transformations during slow cooling from the γ single-phase eld to room temperature. We progressively move from low carbon contents to higher ones. Fig. 3.38 represents a section of the Fe-C diagram in which a composition containing 0.3 % carbon is plotted. When the line GS is intersected (here: 820 C), the transformation from austenite to ferrite begins. The transformation temperature has lowered due to the addition of carbon compared to pure iron. Point 2 shows the microstructure just below the GS line. The rst α crystallites have formed along the γ grain boundaries. In principle, the α phase can also precipitate in the grain interior. However, the grain boundaries are preferred here because they represent favourable nucleation sites for the α-phase. Since ferrite cannot dissolve as much carbon as austenite, the remaining austenite is enriched with carbon by diusion processes. With further cooling, the proportion of ferrite increases and the γ phase accumulates even more carbon (point 3 in Fig. 3.38). At 723 C the γ -phase has nally reached eutectoid composition with 0.8 % C. It now decomposes eutectoid as described above with the formation of a lamellar structure consisting of ferrite and Fe3 C. This phase mixture has been given the name pearlite due to its pearlescent sheen under the light microscope. The nal microstructure (Fig. 3.38, right) consists of ferrite (light) and pearlite (dark), the lamellae can be seen under higher magnication. The microstructure is therefore also called a ferritic-pearlitic microstructure. It is also important to note that in the eutectoid reaction, the carbon must split between the α ° ° ° 99 (Temperature in °C) 3 Strength and phase diagrams (Austenite) (Ferrite) Carbon content in wt.-% Metastable system Stable system Figure 3.37: Comparison between metastable (solid lines) und stable (blue dashed lines) ironcarbon diagram. phase and the cementite (Fe3 C). This happens by diusion and takes time. If it is not available, other transformation processes take place, which are described in chapter 3.3.5. If we increase the carbon content to 0.8 %, as shown in Fig. 3.39, it is noticeable that no transformation interval is passed through during cooling where α-phase and γ -phase coexist. Above 723 C the single phase region of austenite is present. When the PSK line is reached at 723 C, the austenite disintegrates lamellar into ferrite and cementite (Fe3 C) and a pearlitic microstructure is formed (see Fig. 3.39, right). The process of pearlite formation is like that discussed above for the steel containing 0.3 % carbon. If the carbon concentration is greater than 0.8 %, the phase transformation occurs as shown in Fig. 3.40 for a concentration of 1.1 %. Again, we start by looking at the single phase region of austenite (γ ) at about 900 C. Cooling slowly from this temperature, the SE line is intersected at 825 C. The γ solid solution is now no longer able to absorb the entire carbon content and cementite (Fe3 C) precipitates on the austenite grain boundaries. This is similar to the discussed α precipitation for the steel containing 0.3 % carbon, but there the C content increased in the γ phase, while here it decreases. Finally, the γ phase reaches the point S at 723 C and the remaining austenite decomposes to pearlite (ferrite + cementite). A typical microstructure consisting of cementite along the former austenite grain boundaries (light) and pearlite is shown in Fig. 3.40 on the right. ° ° ° ° ° 100 3 Strength and phase diagrams 1100 E γ γ (Austenite) 1000 γ γ γ γ+Fe 3C γ γ G 900 γ γ 1 Temperature, °C α 800 γ 2 700 γ S P 3 γ γ K 4 (a) Ferritic-pearlitic microstructure α (Ferrite) 600 Perlit Fe 3C α α 500 20µm α+Fe 3C 400 (b) Magnification of ferritic-pearlitic microstructure from (a) 0 1,0 1,0 2,0 Carbon content, wt.-% Figure 3.38: Solidication of a steel with 0.3 wt.-% C. Right: Optical micrographs of a ferriticpearlitic microstructure, after [10]. 101 3 Strength and phase diagrams 1100 E γ (Austenite) 1000 γ+Fe 3C G 900 Temperature, °C γ 800 γ 1 γ γ S P 700 K 2 α α (Ferr ite) 600 Fe 3C 500 α+Fe 3C 400 0 1,0 1,0 2,0 Pearlitic microstructure Carbon content, wt.-% Figure 3.39: Solidication of a eutektoid steel, 0.8 wt.-% C. Right: Optical micrograph of a pearlitic microstructure, after [10]. 102 3 Strength and phase diagrams 1100 γ+Fe 3C γ (Austenite) 1000 γ γ γ 900 γ 1 γ γ 800 2 γ Fe 3C α+γ K 3 700 Perlit Temperature, °C γ α (Ferr ite) 600 Fe 3C α Fe 3C 500 α+Fe 3C 400 Pearlitic microstructure with cementite (light) on the grain boundaries 0 1,0 1,0 2,0 Carbon content, wt.-% Figure 3.40: Solidication of a hypereutectoid steel, 1.1 wt.-% C. Right: Optical micrograph of a hypereutectoid microstructure, after [10]. 103 4 Processes at High Temperatures In the previous chapters, we have already encountered processes at high temperatures. We have seen that atoms can migrate in the crystal lattice because there are vacancies in the crystal lattice, but this only happens to a signicant extent at high temperatures. This allows, for example, to smooth out segregations occuring during solidication (see chapter 3.4.2) or to form precipitates (see chapter 3.3.4). These important processes at high temperatures will be considered in more detail in this chapter. First, chapter 4.1 explains why vacancies form in the crystal lattice and why their concentration increases drastically with temperature. Then, in chapter 4.2, we will discuss the laws governing diusion in the crystal lattice, which is based on vacancy migration. Finally, chapters 4.3 and 4.4 discuss the recrystallization and recovery processes that take place at high temperatures. 4.1 Vacancies As already mentioned, vacancies are places in the crystal lattice which are not occupied by atoms. Fig. 3.18 shows such a vacancy. It is created when an atom is removed from its place in the lattice. Since the atom has bonding forces to its neighbouring atoms, an energy must be expended to remove the atom. This energy expenditure is called the vacancy formation energy Qb . Despite this energy expenditure, vacancies form because this increases entropy. For example, if one imagines a crystal lattice with N sites, where all sites are occupied by the same atoms (e.g., Fe), there are no distinguishable arrangements, i.e., the number of distinguishable arrangements is one. If, on the other hand, one adds a vacancy, there are N distinguishable arrangements, because the vacancy can reside in N dierent places. Accordingly, the entropy increases. The entropy increase due to the insertion of a vacancy in the above example can be easily calculated. In general, the entropy S is (4.1) S = kB · ln(W ) + b where kB is the Boltzmann constant and b is an arbitrary constant. W is the probability of the considered state, dened by the number of distinguishable realization possibilities for this state (in this context one speaks of the number of so-called microstates). The entropy of a state is therefore larger, the more distinguishable realization possibilities there are for a state. If the situation in which all N lattice sites are occupied by atoms is state 1, then W1 = 1, because there is only one distinguishable realization possibility. For the state 2 with one vacancy, on the other hand, there are N distinguishable realization possibilities, i.e. W2 = N . Thus, the entropy change ∆S when inserting a vacancy results in 104 4 Processes at High Temperatures W 2 ∆S = kB · ln = kB · ln(N ) W1 (4.2) Following this example, the question is now how many vacancies form in the crystal lattice in thermodynamic equilibrium. Here we can assume constant volume in a good approximation and therefore use the free energy F as the relevant thermodynamic quantity with the help of which we can answer this question. It holds: (4.3) F = U − TS U: T: S: internal energy temperature entropy Let the energy of the crystal with N lattice sites, all occupied by the atomic species A (no vacancies), be U0 . For the case that n lattice sites are occupied by vacancies, the probability W is given by W = ln N! n! · (N − n)! (4.4) In accordance with the above example, W = 1 if there is no vacancy, i.e. for n = 0 (note: 0! = 1). If there is a vacancy (n = 1), W = N . One way to understand the formula in general is as follows: For each distinguishable arrangement of the n vacancies and (N −n) atoms on the N places, there would be further n! arrangements, if the n vacancies would be distinguishable among themselves, respectively (N − n)! further arrangements, if the (N − n) atoms would be distinguishable. Accordingly, for each distinguishable arrangement there would be n!(N − n)! additional arrangements, if vacancies and atoms were distinguishable. In this case, all objects would be distinguishable and the number of possible arrangements on N places is then N ! The number of possible arrangements for the case of indistinguishability at hand here multiplied by n!(N − n)! must therefore be N ! Converted, this results in the quotient in equation 4.4. With the help of this probability W , the entropy results to S = kB · ln N! n! · (N − n)! (4.5) where the arbitrarily constant b was set to zero for simplicity. Since n vacancies increase the internal energy by nQb , the free energy is given by F (n) = U0 + n · Qb − kB T · ln N! n! · (N − n)! 105 (4.6) 4 Processes at High Temperatures In thermodynamic equilibrium, F (n) is minimal, i.e. following holds dF (n) dn = 0. For dFdn(n) , the dF (n) d N! d = Qb −kB T · ln = Qb −kB T · ln(N !)−ln(n!)−ln(N −n)! dn dn n! · (N − n)! dn (4.7) With the approximation ln(x!) ≈ xln(x) for not too small numerical values x, the derivative results to d d ln(N !) − ln(n!) − ln(N − n)! = N ln(N ) − nln(n) − (N − n)ln(N − n) dn dn (4.8) N −n N −n = 0 − ln(n) − 1 + ln(N − n) − · (−1) = −ln(n) + ln(N − n) = ln N −n n and thus N −n dF (n) = Qb − kB T · ln dn n (4.9) n Because of n ≪ N , N n−n ≈ N = cV results, where cV is the vacancy concentration. dS Thus, the entropy change dn is given by the term kB ln c1V . Because of cV < 1, dS dn is always positive. Thus, under the condition n ≪ N used here, the entropy increases steadily with increasing vacancy concentration. However, dS dn becomes smaller and smaller with increasing vacancy concentration. Thus, the increase in entropy with each additional vacancy becomes smaller and smaller. In contrast, the increase in the energy of the crystal lattice with each new vacancy is constant, namely Qb . The equilibrium concentration of vacancies is reached when the increase in the energy of the crystal lattice with each new vacancy equals the increase in entropy with each additional vacancy multiplied by the temperature. If the temperature increases, this equilibrium is reached at a smaller value of dS dn , i.e., a larger vacancy concentration. This qualitative observation can be conrmed on the basis of the equilibrium condition dFdn(n) = 0 as follows. 0= dF = Qb + kB T · ln(cV ) dn (4.10) Rearranging equation 4.10 leads to ln(cV ) = − Qb kB T (4.11) respectively 106 4 Processes at High Temperatures Q b cV = exp − kB T (4.12) ° For example, Qb for copper is 1.6 · 10−19 J. Copper melts at 1083 C, i.e. 1356 K. Accordingly, using the above equation and kB = 1.38·10−23 J/K, the vacancy concentration is 6.5 · 10−18 at room temperature and 1.9 · 10−4 at the melting temperature. This illustrates the drastic increase in vacancy concentration with temperature. For all metals, the vacancy concentration is about 0.0001 when the melting temperature is reached, i.e. about every ten thousandth lattice site is occupied by a vacancy. If the crystal lattice is heated, the atoms start to vibrate. Hereby, it can happen that an atom absorbs so much energy that it jumps from its place in the lattice to a neighboring vacancy (see Fig. 3.18). If we look at the vacancy, it jumps in the opposite direction. In the following, we consider the processes from the point of view of the vacancy. Since the vacancy occupies a lattice site before and after the jump, the energy of the vacancy before and after the jump is identical. In between, however, the vacancy is in an energetically unfavorable state. Thus, as Fig. 4.1 shows, the vacancy must overcome an energy mountain before it moves from its original equilibrium position at location x1 to the next equilibrium position at location x2 . The magnitude of the energy required for this is called the migration energy of the vacancy Qw (Fig. 4.1). As mentioned, this migration succeeds from time to time only because the atoms oscillate and thus occasionally have a sucient amount of energy in the right direction so that the atom or vacancy can overcome the energy mountain. Related to one oscillation, the probability that the will migrate by overcoming the energy mountain is given vacancy Qw by the term exp − kB T . On the one hand, the probability is the larger the higher the temperature is. Thus, as the temperature increases, not only does the number of vacancies increase dramatically. The vacancies also move much more frequently. On the other hand, the probability of vacancy migration increases with decreasing migration energy Qw . Figure 4.1: Energy of a vacancy as a function of the spatial coordinate x. If the vacancy is located at a lattice position (coordinates x1 and x2 ), its energy is minimal. If the vacancy moves from lattice site to lattice site, it is in an energetically less favorable state in between. It has to expend the migration energy Qw in order to overcome the energy mountain located between the equilibrium positions. 107 4 Processes at High Temperatures The chapter started with the statement that a vacancy is formed when one removes an atom from its lattice site. One may wonder at this point what has become of the atom that was previously present at the site of the newly formed vacancy. The answer is that dislocations and grain boundaries are sources and sinks for atoms and vacancies, respectively. Thus, they can absorb atoms while emitting vacancies or absorb vacancies while emitting atoms. In this way, the crystal lattice is able to adjust the vacancy concentration as the temperature changes to match the thermodynamic requirement given in Equation 4.12. Fig. 4.2 shows the process of vacancy absorption or emission using the example of an edge dislocation. In the left image, three vacancies can be seen next to the edge dislocation. One of the vacancies moves towards the edge dislocation and replaces an atom there. This changes the position of the edge dislocation (see middle image). It no longer ends in its original slip plane, which is horizontal in Fig. 4.2, but one level higher. This movement of the dislocation from one slip plane to another is called climbing of the dislocation. In the case considered here, one vacancy has disappeared because there are only two vacancies left in the middle image. This process is repeated from the middle image to the right one, so that there is only one vacancy left on the right and the dislocation has climbed up one level again. Because vacancies have disappeared in this example, the dislocation acted as a vacancy sink. But one can also read the image sequence from right to left. Then, the edge dislocation climbs down and creates vacancies. So in this case, the dislocation acts as a vacancy source. Figure 4.2: Absorption or emission of vacancies at an edge dislocation (the symbol ⊥ indicates the location of the dislocation line, see Fig. 3.6) [26]. 4.2 Diusion Diusion is the movement of particles occurring without external inuences, in this case the movement of atoms or vacancies in the crystal lattice. As already explained, diusion is necessary, for example, in order to compensate for concentration dierences or to be able to form precipitates. We now imagine that we observe a certain volume over a certain time and note how many vacancies change places. The larger the number Z of these events, the faster the vacancies move in the crystal lattice, so the greater the diusion rate. On the one hand, Z is the greater the more vacancies there are in the lattice, i.e., the greater their concentration cv . On the other hand, the more frequently a vacancy moves from one lattice site to another, the greater Z is. Thus, the diusion Qb rate increases with the vacancy concentration cv = exp − kB T and the rate a vacancy 108 4 Processes at High Temperatures changes places, which is proportional to exp − kQBwT . If, for example, the concentration of vacancies and the rate a vacancy changes places were both increased by a factor of 10, the number of place changes in a given time would increase by a factor of 100. Thus, there is a multiplicative relationship and we can state: Q Q Q +Q w w b b Diffusion rate ∼ exp − · exp − = exp − . kB T kB T kB T (4.13) We now imagine a solid solution consisting of the host atoms and the atoms dissolved in the host lattice. Let the concentration of the dissolved atoms be the same everywhere. In this case, diusion can only be recognized by a random motion of the atoms in the crystal lattice. This changes if there is a concentration gradient in the solid solution, e.g. due to a non-equilibrium solidication. Such a situation is shown in Fig. 4.3. In this case, a solid solution with complete miscibility of the two elements, namely the gray atoms and the red atoms, is assumed, as is the case, for example, with copper and nickel (compare with Fig. 3.27). On the far left only the gray atoms are present, on the far right only the red atoms. As Fig. 4.3 shows, the concentration c of the gray dc atoms decreases from left to right. The concentration gradient dx is negative because c decreases in the positive x-direction. If we now look at the area drawn in blue, there are more gray atoms to the left of it than to the right. The motion of the atoms is also in this case random. But because there are more gray atoms to the left of the blue area than to the right of it, on average more gray atoms move from left to right through this area than vice versa. As the arrows show, in the case of Fig. 4.3, four gray atoms move from left to right through the blue area but only three from right to left when all atoms change places once across the area. In this way, there is a total ow J of one gray atom from left to right (for the red atoms it is the other way around). J is dened as the number of gray atoms moving from left to right across the area under consideration per unit time. Naturally, the larger the area A under consideration is, the larger is J . J To eliminate this relationship, we dene the current density j = A . Thus, the current density j indicates the number of gray atoms moving from left to right per area and time unit. Accordingly, its unit is m12 s . The greater the concentration gradient and the diusion velocity, the greater the current density. Accordingly, with the proportionality factor D0 we obtain Q + Q dc Q dc dc w b j = −D0 · exp − = −D0 · exp − = −D kB T dx kB T dx dx (4.14) This relationship is called Fick's rst law after its discoverer. The negative sign results dc from the above example: While dx is negative, the current density is positive because it points in the positive x-direction. The parameter D is called diusion coecient. It contains the so called diusion constant D0 and in the exponential term the so called 2 activation energy for diusion Q = Qb + Qw . D and thus also D0 have the unit ms . The concentration is the number of atoms per volume. Accordingly, the concentration gradient has the unit m14 . The e-function is dimensionless (numerator and denominator 109 4 Processes at High Temperatures have the unit of one energy). As required, this results in the unit of the current density on the right side, i.e. m12 s . Figure 4.3: Emergence of a diusion current in a concentration gradient, after [5]. Table 4.1 gives some values for D0 and the activation energy for diusion Q′. Here, Q′ does not refer to an atom as before, but to a mole of atoms. The unit of Q′ is therefore J ′ 23 gives the number mol . Thus, Q = Q · L, where Avogadro's number L = 6.022 · 10 of atoms per mole. Considering that for the ideal gas constant R = kB L holds, the diusion coecient can be written as follows Q Q′ D = D0 · exp − = D0 · exp − kB T RT (4.15) The temperature-dependent diusion coecients resulting from Table 4.1 are shown in Fig. 4.4. The following becomes clear: Dierent elements diuse at dierent rates in a given host lattice. In iron, for example, Cr diuses particularly slowly and carbon particularly quickly. The latter is due to the fact that carbon is interstitially dissolved. While a substitution atom, such as chromium, can only change its place if one of the rarely occurring vacancies is present at a neighboring lattice site, an interstitially dissolved atom can do so if a neighboring interstitial site is unoccupied, which is almost always the case. For this reason, interstitially dissolved atoms diuse as a basic principle faster than substitutional atoms. This has an important technical consequence in connection with the hardening of steels. As can be seen from Fig. 3.22, a simple steel containing essentially only carbon as an alloying element must be cooled very rapidly to get past the "nose" in the TTT diagram in order to harden the steel 110 4 Processes at High Temperatures by the martensitic transformation. These high cooling rates are necessary because carbon diuses very quickly. Thus, it is easy to partition carbon between the αphase and Fe3 C by diusion, and the diusion controlled transformation is fast. While suciently fast cooling rates to prevent diusion controlled transformation can be realized in thin-walled components, this is not possible inside thick-walled components. This phenomenon is referred to as insucient hardenability, because hardening by the martensitic transformation does not reach the interior of the component. One way out is to use slower-diusing alloying elements, such as Cr. These must also be partitioned between the α-phase and the carbide by diusion. Because they diuse more slowly, considerably more time is required for this. Accordingly, the nose in the TTT diagram shifts to the right to longer times, so that lower cooling rates, which can also be realized for thick-walled components, are sucient for the martensitic transformation to take place. Hardenability is thus improved. In dierent host lattices, the atoms diuse at dierent rates. For example, it is noticeable that diusion is much slower in iron than in aluminum. This is because the iron atoms are more strongly bonded in the crystal lattice than the aluminum atoms (see Table 2.3). This makes the formation and migration of vacancies, and thus diusion, more dicult. The stronger bonding also causes iron to melt later than aluminum (see Table 2.3). Thus, there is a tendency for the rate of diusion at a given temperature to decrease as the melting temperature (i.e. the bond strength) increases. Consequently, iron must be annealed at a higher temperature than aluminum, for example, to compensate for concentration dierences. The diusion rate depends on the crystal lattice. This is particularly well seen in the fact that the diusion rate in iron changes abruptly at the transformation temperature from α-Fe to γ -Fe. In the fcc γ -Fe it is obviously much lower than in the bcc α-Fe. This is because the face-centered cubic crystal lattice is more densely packed than the body-centered cubic one. This makes vacancy migration more dicult because there is less space available for atomic motion. In addition, the denser packing leads to more nearest neighbors. As a result, an iron atom is more tightly bound in the fcc lattice than in the bcc lattice. Accordingly, the formation energy for vacancies Qb is larger in the fcc lattice, which also slows down diusion. The atoms dissolved in the host lattice, such as C or Cr in iron, are also called impurity atoms. If we consider their diusion, we therefore speak of impurity diusion. If, on the other hand, we consider the diusion of the host atoms themselves, i.e. in this example the diusion of the iron atoms, we speak of self-diusion. At this point, one may ask how one can observe self-diusion. To do this, one uses an isotope of the host element and observes its motion. The example in Fig. 4.3 shows a concentration gradient pointing only in the direction dc dc dc of the x-axis. In general, the concentration gradient has components dx , dy , dz in the direction of all three coordinate axes. This results in components jx , jy , jz of the current 111 4 Processes at High Temperatures ′ Table 4.1: Diusion constants D0 and activation energies Q for diusion of dierent elements in dierent host lattices. Sources: [16] for Cr in Fe; [10] for all other data. 2 kJ Q′ [ mol ] C D0 [ ms ] 2.8 · 10−4 6.2 · 10−7 Cr 3.0 343 Fe 5.0 · 10−5 2.3 · 10−5 2.3 · 10−4 284 Matrix Diusing element α-Fe α-Fe α-Fe γ -Fe γ -Fe Fe Al Al C 251 80 148 144 Figure 4.4: Diusion coecient D of dierent elements in dierent host lattices as a function of 1/T (T : temperature). density. Thus, generalized, the current density is a vector with these three components. Accordingly we can write jx dc/dx jy = −D · dc/dy jz dc/dz (4.16) d/dx j = −D · d/dy c = −D · grad c d/dz (4.17) or 112 4 Processes at High Temperatures where grad c is the concentration gradient and the underscore symbolizes that the current density (like the velocity) is a vector. For example, if we consider segregation due to non-equilibrium solidication, we are interested in how long it takes for concentration dierences to be equalized by diusion. In other words, we are interested in how the concentration at a location changes over time. This information can be derived from Fick's rst law. For now, we again restrict ourselves to the one-dimensional case and consider the volume shown in Fig. 4.5 with area A and thickness dx. We imagine that we observe the ow of foreign atoms B in a concentration gradient. We note that on the left side B atoms ow into the volume with current density j(x) and on the right side they ow out with current density j(x + dx) ̸= j(x). Accordingly, j(x) · A gives the number of atoms owing into the volume per unit time, whereas j(x+dx)·A shows how many atoms ow out per unit time. Consequently, the change in the number of B atoms per unit time in the volume under consideration is (4.18) − A · j(x + dx) − A · j(x) Figure 4.5: Diusion current density j through a thin-walled cuboid of cross-sectional area A and thickness dx changing with spatial coordinate x. In the case shown, j(x + dx) and j(x) are positive because they point in the positive direction of the x-coordinate. For example, if j(x + dx) is larger than j(x), as shown in Fig. 4.5, the number of B atoms in the volume under consideration decreases. This proves that the minus sign in Equation 4.18 is necessary. Dividing equation 4.18 by the volume A · dx gives the change in the number of B atoms per unit time and volume, i.e. the change in concentration with time ∂c∂tB : ∂cB A · j(x + dx) − A · j(x) j(x + dx) − j(x) ∂j =− =− =− ∂t A · dx dx ∂x 113 (4.19) 4 Processes at High Temperatures Whereas previously the concentration gradient was assumed to be invariant with time, c and j are now quantities dependent on location and time. Therefore, Eq. 4.19 contains partial derivatives, represented by the symbol ∂ . If we now use the right term of Fick's rst law (Eq. 4.14) for j and generalize ∂c∂tB to ∂c ∂t , we obtain Fick's second law ∂ ∂c ∂2c ∂c =− −D =D 2 ∂t ∂x ∂x ∂x (4.20) It can be seen that the concentration at a given location always changes over time when the second derivative of the concentration with respect to the location is not zero, i.e. when the concentration gradient changes with the location. A constant concentration gradient, as in Fig. 4.3, does not lead to this. This fact is also easy to understand with the help of Fig. 4.5. If the concentration gradient were constant there, j(x + dx) = j(x) would follow from Eq. 4.14 and the concentration would not change in the considered volume. Obviously, however, there is a situation in Fig. 4.5 where the concentration gradient on the left side of the cuboid is smaller in magnitude than on the right and therefore fewer B atoms ow into the volume than out of it. Extending the relationship shown in Eq. 4.20 to the general three-dimensional case is straightforward. In general, not only along the x-coordinate dierent atomic currents will ow into and out of a volume element. This will also happen along the y and z coordinates, and this will change in an analogous way the concentration of the atomic species under consideration. If we imagine, for example, that along the x-coordinate 5 atoms less ow into the considered volume element than ow out, but along the yand z-coordinate 4 and 2, respectively, more ow in than ow out, the total change is −5 + 4 + 2 = 1. Thus, all contributions have to be added, resulting in the following relation for the three-dimensional case: ∂2c ∂c ∂2c ∂2c =D + + ∂t ∂x2 ∂y 2 ∂z 2 (4.21) An important example that can be considered with the help of Fick's second law is the carburization of so-called case-hardened steels. Case-hardened steels are characterized by a low carbon concentration. Typical values are between 0.1 % and 0.2 %. In case hardening, the steel is heated in a furnace to such a high temperature that it is in the γ single phase eld and the carbon solubility is correspondingly high, e.g. to 950 C. In addition, the steel is exposed to a carburizing atmosphere. This can be achieved, for example, by introducing carbon monoxide and hydrogen. The reaction CO + H2 −→ H2 O + C creates the desired carburizing atmosphere with a certain constant carbon concentration in the gas. This also establishes a certain constant carbon concentration cs on the steel surface. Starting from the surface, the carbon now diuses into the steel and a surface layer with increased carbon content is formed. The steel is then quenched and subsequently tempered at a relatively low temperature, e.g. 180 . The high carbon content in the surface layer coupled with the low tempering temperature results in a hard and wear-resistant surface layer. Because the steel continues to have a low carbon content ° ° 114 4 Processes at High Temperatures in its interior, a ductile but also strong material state is produced there despite the low tempering temperature. This combination of properties is ideal for components, such as gears, whose surfaces are subject to wear. We now take a closer look at the carburization process with the aid of Fick's second law. As already mentioned, a certain constant carbon concentration cs is established on the steel surface. Starting from the steel surface, which is at the spatial coordinate x = 0, the carbon now diuses into the steel. For x > 0, we are in the steel, which we imagine to be innitely extended. This assumption is generally well fullled, because the penetration depth of the carbon is generally small compared to the steel dimensions. Thus, c(x = 0) = cs for all times t ≥ 0 and c(x) = c0 for t = 0 and x > 0 holds. Here, c0 is the carbon concentration of the not yet case-hardened steel. What is sought is the carbon concentration c(x, t) in the steel for arbitrary time and location. As solution, which satises Fick's second law and the given boundary conditions, one obtains: x c(x, t) − c0 = 1 − erf √ cs − c0 2 Dt (4.22) with Gaussian error function 2 erf(z) = √ π Z z (4.23) exp −y 2 dy 0 The quotient on the left side of Eq. 4.22 gives the dierence between searched concentration c(x, t) and initial concentration c0 , related to the concentration dierence cs − c0 initially prevailing everywhere. For example, if the value of the quotient is 0.1, the concentration at the considered location and time increases by 10 % of the initial dierence. It is noteworthy that c(x, t) depends only on the quantity √xt . For example, c(x1 , t1 ) = c(2x1 , 4t1 ) is therefore valid. Thus, at twice the distance, four times the time is required until a certain concentration of the atomic species under consideration (here: carbon) is reached. The resulting temporal and spatial variation of c(x, t) is shown in Fig. 4.6. The course of the Gaussian error function is shown in Fig. 4.7. In our example, let cs = 0.01 (i.e. 1 %) and c0 = 0.001. To ensure sucient wear resistance over the lifetime of the component, we require a carburized surface zone of at least 0.2 mm thickness, which should have a carbon content of at least 0.5 %. Insertion into Equation 4.22 gives the value 0.50 for the quotient on the left-hand side. Accordingly, √ √ erf(x/(2 √Dt) = 0.5 must hold. This is satised to a good approximation for x/(2 Dt) = 0.5 or x/ Dt = 1. The thickness of the carburized boundary layer is thus x≈ √ (4.24) Dt This formula is often used to estimate the distance atoms travel by diusion. For economic reasons, we limit the carburization process in our example to a duration of one hour, i.e. t = 3600 s. Logarithmizing equation 4.24 we obtain 115 4 Processes at High Temperatures Figure 4.6: Concentration c(x, t) calculated with equation 4.22 depending on the local coordi- ° nate x and time t. Values used: T = 950 C, diusion coecient D for carbon in γ -Fe according to Tab. 4.1, cs = 0.01, c0 = 0.001. Figure 4.7: Gaussian error function erf(z) in dependence of the parameter z . Q′ 1 ln(D0 ) − + ln(t) 2 RT (4.25) Q′ R · ln(D0 ) + ln(t) − 2ln(x) (4.26) ln(x) = i.e. T = ° Using the values from Table 4.1 for D0 and Q′ , 951 C results as annealing temperature in order to obtain the required surface layer thickness of 0.2 mm after one hour. This 116 4 Processes at High Temperatures is also shown by the blue curve in Fig. 4.6, which was calculated for almost identical parameters (T = 950 C instead of 951 C). Now, for example, one could still aim to realize a thicker surface layer by annealing longer. Therefore, instead of one hour, four hours shall be annealed in the furnace. Inserting this new annealing time in Eq. 4.24 gives a resulting surface layer thickness of 0.4 mm (compare also with the orange curve in Fig. 4.6). This result could have been obtained without recalculation, because we have √ already seen that c(x, t) depends only on the parameter x/ t. Thus, for a given value of c(x, t) (here: 0.5 %), the surface layer thickness x doubles for a quadrupled annealing time t. Thus, if one wanted to increase the surface layer thickness tenfold to 2 mm, one would need 100 hours instead of one hour. This shows why such surface layers are limited in practice to a few tenths of a millimetre. ° ° 4.3 Recrystallization In chapter 3.3.2, the special importance of strengthening by grain size reduction became apparent, which leads to an increase in strength without loss of ductility. Therefore, this strengthening method, i. e. a particularly small grain size, is highly desirable. First of all, the solidication conditions have an inuence on the grain size. However, solidication does not lead to grain sizes of about 10 micrometers and smaller that are desired for pronounced strengthening by grain size reduction. If one wants to achieve such a ne grain size, the method of recrystallization, leading to the formation of new grains, must be used. This is the subject of this chapter. First, let us imagine a metal that has been strongly deformed. As explained in section 3.3.1 and shown schematically in Fig. 4.8 (a), this leads to a high dislocation density of up to 1016 m−2 . According to section 3.2, dislocations distort the crystal lattice and thus increase the energy stored in the crystal. The high dislocation density has thus created an energetically unfavourable state. If it were possible to reduce the dislocation density, the material could be converted to a more energetically favourable state. One way to accomplish this is by recrystallization. As Fig. 4.8 (b) illustrates, individual grains reform in this process. This happens analogous to the formation of precipitates by a nucleation and growth process. However, here we do not have particles of a second phase. Instead, grains are formed which exactly correspond to the already existing grains of the host lattice with respect to composition and crystal structure. These newly formed grains grow as atoms from the neighboring, highly deformed grains migrate across the grain boundaries and are incorporated into the new grains. The growth process of the new grains is not defect-free and therefore dislocations also occur in the newly formed grains. However, their dislocation density of about 1012 m−2 is much lower than that in the highly deformed grains. Consequently, recrystallization leads to a more energetically favourable state. In particle hardening, the goal was to produce small precipitates. To understand how this can be achieved, it was necessary to look at the energy contributions in this process. Here, the goal is to form grains that are as small as possible. Accordingly, it is also necessary here to be clear about the energy contributions. There are many analogies to particle strengthening. Here, too, for example, it is necessary to form as many nuclei as 117 4 Processes at High Temperatures (a) Initial situation with a high dislocation density due to plastic deformation (the symbol ⊥ indicates the location of the dislocation line, see g. 3.6). (b) Formation of a new grain (blue) with reduced dislocation density by recrystallization. Figure 4.8: Schematic representation of the recrystallization of a polycrystalline metal. possible, because the nuclei formed grow until all the grains of high dislocation density have been replaced. Accordingly, the more nuclei formed, the smaller is the grain size after recrystallization is complete. Let ρ1 be the dislocation density of the deformed grains and ρ2 that of the newly formed ones with ρ2 < ρ1 . According to Section 3.2, the energy stored per unit length of a dislocation line is given by the line tension T . Because the dislocation density gives the dislocation line length per volume, the product T · ρ gives the energy stored per volume (T · ρ = (energy/length) (length/volume)). If we think of the newly formed grain simplied as a sphere with radius r, the dislocation density in this spherical volume has changed from ρ1 to ρ2 . The associated change in free enthalpy is therefore1 4 ∆Gv = πr3 · T · (ρ2 − ρ1 ) < 0 3 (4.27) Again, the analogy to equation 3.6 is obvious. However, the causes of the driving forces are dierent. Here, the reduction of dislocation density leads to an energetically 1 For those with a good knowledge of thermodynamics: Strictly speaking, the term 43 πr3 T (ρ2 − ρ1 ) only indicates the energy change U of the crystal lattice. As said, however, no other phase is formed here but grains of the same crystal structure and composition are formed. Therefore, in contrast to particle strengthening, the entropy change ∆S is negligible. Because of ∆G = ∆H −T ∆S, ∆G ≈ ∆H (H : enthalpy) follows here rst of all. Furthermore, because recrystallization does not lead to any appreciable volume change (because of identical crystal structure, the packing density of the atoms is unchanged before and after recrystallization) and thus the work of volume change is negligible, it also follows ∆H ≈ ∆U , thus also ∆G ≈ ∆U . Consequently, it is irrelevant here whether one considers the change in energy U or in free enthalpy G. To make the analogy to particle strengthening clear, we stay here with ∆G. 118 4 Processes at High Temperatures more favorable state, whereas in particle strengthening the chemical disequilibrium is decisive. Since both cases involve a volume term (i.e., a term proportional to the converted volume), the same symbol ∆Gv is used here. As in the case of particle strengthening, the formation of the new grain creates an interface. In the case of a particle of a dierent phase, we call it a phase boundary; here we refer to it as a grain boundary. The associated increase in free enthalpy is given by Eq. 3.7 as follows (4.28) ∆Gs = 4πr2 γs (γs : specic interfacial energy of the grain boundary). Accordingly, an energy balance completely analogous to that shown in Fig. 3.17 results2 . Thus, a nucleation barrier must be overcome here as well. From 4 ∆G = ∆Gv + ∆Gs = πr3 · T · (ρ2 − ρ1 ) + 4πr2 γs 3 (4.29) follows the condition for the maximum of ∆G, at which r corresponds to the critical radius r⋆ : d∆G = 0 = 4π(r⋆ )2 · T · (ρ2 − ρ1 ) + 8πr⋆ γs dr (4.30) This leads to the critical radius r⋆ = 2γs 2γs ≈ T (ρ1 − ρ2 ) T ρ1 (4.31) Because ρ2 ≪ ρ1 applies in general, the expression on the right-hand side can be further simplied as indicated. Thus, the larger the dislocation density generated by deformation, the smaller is r⋆ . The result obtained here for r⋆ is analogous to that of Section 3.3.4. However, the denominator in the above equation depends on the dislocation density and not on the driving force due to a phase transformation. As in particle strengthening, the smaller r⋆ is, the greater is the nucleation rate of new grains. Thus, the greater the dislocation density before recrystallization, the ner the grains afterwards. The existence of a nucleation barrier has another important consequence: as in particle strengthening, recrystallization does not take place immediately but with a time delay. This is illustrated in Fig. 4.9 by the example of a nickel alloy deformed at room 2 As Fig. 4.8 (b) shows, the new grains are generally formed at the grain boundaries of existing grains. Strictly speaking, one would have to take into account that not only new grain boundaries are formed, but also that previously existing ones are removed. For reasons of simplication, this is neglected here, especially since more new interface is formed than old interface is removed, so that the statement that an energy expense occurs here is correct. 119 4 Processes at High Temperatures temperature to a nominal strain of -0.7 (in a rolling process, this corresponds to a thickness reduction of 70 %). The higher the temperature, the earlier recrystallization begins, because the atomic motion becomes faster and faster with increasing temperature and thus less and less time is required until a critical nucleus is formed. In contrast to the formation of precipitates, this trend toward higher temperatures continues on and on because the denominator in the above equation does not decrease with increasing temperature, whereas this is the case for the denominator of Eq. 3.10. It is true that the onset of recrystallization depends not only on temperature but also on dislocation density, because r⋆ changes with dislocation density. However, referring to the absolute temperature scale in Kelvin, it is a rule of thumb that one should reach at least 40 % of the melting temperature of the metal in question in order to start the recrystallization process in a reasonable period of time. For nickel with a melting temperature of 1726 K, this is approx. 700 K. Figure 4.9: Annealing times tStart , tF inish to the start and end of recrystallization, respectively, as a function of temperature for a cold-worked nickel alloy (after [17, p. 85]). In summary, the steps to achieve the smallest possible grain size by recrystallization can be summarized as follows: Introduction of a high dislocation density by as much plastic deformation as possible. Annealing at elevated temperature to recrystallize the material completely within a technically reasonable period of time. Since much greater plastic deformation can be achieved under compressive stress than 120 4 Processes at High Temperatures under tensile stress before the material fails, forming under pressure such as rolling or forging is normally used for the rst step. 4.4 Recovery As was pointed out in chapter 4.1, moving vacancies can be absorbed by dislocations. The dislocations thus leave their original slip plane and end up on another one. We have called this process climbing. It can only occur at elevated temperatures, because only then do vacancies migrate to a signicant extent. In Fig. 3.7, it became clear that two edge dislocations with their half-planes can unite to form a perfect crystal plane. The two dislocations originally present have then disappeared. They have annihilated each other. The prerequisite is not only that the two half-planes point in opposite directions. The two dislocation lines must also lie on exactly the same slip plane. If this is not the case, the two half-planes cannot unite to form a complete plane and the dislocations with their respective dislocation lines remain. This dislocation annihilation is extremely rare at room temperature because it is very unlikely that two oppositely oriented dislocations share the same slip plane. At elevated temperatures, however, the dislocations can help themselves because they are able to climb. This allows them to leave their original slip planes and reach the same plane. Once this is achieved, annihilation takes place. In this process, the dislocations move towards each other by climbing and gliding because attractive forces prevail, i.e. the dislocations attract each other. This process of dislocation annihilation, which is called recovery, reduces the dislocation density. Thus, there are two processes by which dislocation density can be reduced at elevated temperature: recovery and recrystallization. In contrast to recrystallization, recovery begins at somewhat lower temperatures (rule of thumb: from about 30 % of the melting temperature, based on the absolute temperature scale). If one wants to produce a grain as ne as possible by recrystallization, recovery is undesirable, because part of the originally existing dislocation density is thereby reduced before recrystallization begins. Because no nucleation barrier has to be overcome for recovery to take place, recovery begins immediately at elevated temperature. Thus, it is inevitable that the dislocation density is somewhat reduced before recrystallization begins. On the other hand, recovery can also be useful. For example, if a metal was strongly plastically deformed and, thus, its deformation capability largely exhausted, the deformation capability can at least be partially regained by recovery. The metal thus partially recovers from the previous exertion of cold forming. The strength decreases in the process because work hardening is reduced. 121 5 Oxidation and corrosion Materials are surrounded by media that can lead to material attack on the surface. If, for example, an iron rod is held in a ame, it tends to scale, i.e. a layer of iron oxide is formed, which often akes o during cooling and leads to consumption of the material. This type of attack is called oxidation because it is caused by oxygen in the air. Our experience shows that this type of attack requires high temperatures. In contrast, the rusting of a steel car body sheet, for example, already takes place at ambient temperature. The main dierence is that the attack is not caused by atmospheric oxygen alone but also by contact with an electrically conductive liquid, the electrolyte. This process is called corrosion. Both processes will be discussed below. It will be explained why oxidation processes only occur at much higher temperatures than corrosion processes. The economic loss through corrosion/oxidation damage is very signicant. About 2% of the annual production of steel is lost through rust every year. For the Federal Republic of Germany this means a steel loss of about 0.9Mt/a or 30 kg/s. Therefore, it is not surprising that about 2500 to 5000e per inhabitant are spent annually on corrosion protection measures. 5.1 Oxidation All materials that can form a covalent or ionic bond with oxygen under an energy gain are at risk of oxidation in air. Considering the energy conversion during the reaction (5.1) Material + Oxygen −→ Oxide it can be seen that all metals except gold tend to oxidize (Fig. 5.1), negative values correspond to energy gain). This is why gold is the only metal that occurs in the earth's crust in elemental form. With the exception of PTFE, polymers also tend to oxidize. They burn under formation of CO2 and H2 O. The reason for the stability of PTFE is that the electrons of carbon are already bound by the extremely electronegative uorine. Nitride and carbide ceramics also tend to oxidize, since the oxidation products (oxide plus CO2 or NOx )) are more energetically stable. Only oxide ceramics remain as engineering materials that are resistant to oxidation. This raises the question why, in our experience, oxidation at ambient temperature in dry air does not play a role, although the oxidation reaction should take place from an energy point of view. To answer this question, it is necessary to consider the reaction kinetics. It has already become clear from the example of the scaling of iron that an oxide layer forms during the reaction with oxygen. This separates the reaction partners. 122 5 Oxidation and corrosion Resistant against oxidation Vulnerable for oxidation Energy [kJ/mol] SiC Diamond Al2O3 SiO2 (no reaction) Ceramics Magnesium Aluminium Titanium Chromium Zinc Tungsten Iron Nickel Copper Platinum Gold Metals Wood CFRP GFRP other Polymers PTFE Polymers Composites Figure 5.1: Formation energy for oxides. Further oxidation can only occur to the extent that oxygen ions or metal ions can diuse through the layer (Fig. 5.2). Since diusion processes are very slow at ambient temperature, even a few nanometers of oxide layer thickness are sucient to separate the reactants and to prevent oxidation. (a) Metal ions diuse faster than oxygen ions. (b) Oxygen ions diuse faster than metal ions. Figure 5.2: Kinetics of oxidation using the example of a metallic material. If a material is to be resistant to oxidation at high temperatures the following is required from the oxide layer: Low diusion coecient (i.e. generally high melting point); Low electrical conductivity; Firm adhesion to the base material. 123 5 Oxidation and corrosion When comparing the melting points of important oxides (Tab. 5.1), it can be seen why Al2 O3 , Cr2 O3 and SiO2 protect very eciently, whereas FeO and Cu2 O are less eective. Al2 O3 has the additional advantage of a very low electrical conductivity (109 times lower than FeO). Therefore, it is not surprising that virtually all metals used at high temperatures are alloyed with Cr, Al and, in rare cases, silicon. Ceramics for high temperature applications are either oxide-based (e.g. Al2 O3 ) or silicon-based (SiC, Si3 N4 ). In the latter case, it is the formation of a SiO2 top layer that protects against oxidation. Table 5.1: Melting temperatures of important oxides. Material Melting temperatures / FeO 1369 Cu2 O Cr2 O3 Al2 O3 SiO2 1235 2266 2072 1702 Tab. 5.2 summarizes the temperature limits for important engineering materials. It is clear that the oxidation resistance increases steadily with the Cr+Al+Si content. This is understandable, since alloys generally do not form pure surface layers, but rather mixed oxides, e.g. (FeO + Cr2 O3 ), and as the content of Cr, Al, Si increases, the proportion of the less protective oxide is reduced. Unfortunately, refractory metals such as tungsten (Tm = 3422 C) form extremely unstable oxides. For this reason, they have not yet gained any practical signicance in high-temperature applications, although their mechanical strength is exceptionally high. Polymers, whose main components are C and H, do not form a protective oxide layer. As a result, they usually decompose above 250 C. ° ° Table 5.2: Temperature resistance of some engineering materials. Material Oxidation resistant up to / Alloy steels 500 (1 5 % Cr) High temperature steels 650 Heat resistant steels 1100 Ni-Cr-alloys 950 (ca. 15 20 % Cr) Ni-Cr-Al-alloys 1100 (ca. 15 20 % Cr + 5 % Al) SiC, Si3 N4 1300 124 5 Oxidation and corrosion 5.2 Corrosion 5.2.1 Fundamentals In the previous chapter it became clear that high temperatures are necessary for the oxidation of materials, because diusion of ions and electrons through oxide layers is required. Consequently, alloyed steels are suciently resistant to dry air up to 500 C (Table 5.2). If, on the other hand, they are simultaneously exposed to moisture or wetness, the attack can take on dramatic proportions even at room temperature. As Fig. 5.3 shows, the attack of iron by oxygen containing water is very similar to oxidation. ° Figure 5.3: Reaction scheme for the corrosion of metal in water. Also here an oxidation of the metal takes place by giving o electrons Fe −→ Fe2+ + 2e− , (5.2) as well as a reduction reaction under absorption of electrons O2 + 2H2 O + 4e− −→ 4OH− (5.3) However, if the liquid is electrically conductive, i.e. an electrolyte, it can dissolve the charged metal ions and move them away from the metal/electrolyte interface. This means that no protective surface layer is formed on the metal so that the attack can take place even at low temperatures. This corresponds to our experience of rusting steel. First the iron ions go into solution. If the water evaporates, their solubility limit is reached and loose rust is deposited on the metal, which, however, does not form a protective surface layer. Simplied, it can be understood as 4Fe(OH)2 (compare with Fig. 5.3). Fig. 5.3 also shows that the two partial reactions according to eq. 5.2, 5.3 can take place at dierent locations. This is because the electrons in the conductive metal can move easily. Lateron, it becomes clear that this has important consequences for corrosion protection. 4Fe(OH)2 + O2 + 2H2 O −→ 4Fe(OH)3 −→ 2Fe2 O3 + 6H2 O , 125 (5.4) 5 Oxidation and corrosion In summary, the following requirements are necessary for corrosion attack: The presence of a conductive medium; The presence of an oxidizing agent (in water this is the dissolved oxygen); A good solubility of the oxidation product in the corrosion medium. In addition to the reduction reaction in water containing oxygen, as shown in eq. 5.3, corrosion in acids according to 2H+ + 2e− −→ H2 (5.5) often plays an important role. As with oxidation, the driving forces of the reactions (eq. 5.2- 5.5) shall be analysed in the following. The following thought experiment is used for this purpose: A metal plate Me is immersed in an electrolyte containing the same metal as cation. Depending on the oxidation tendency of the metal, a certain amount of positively charged metal ions is dissolved in the electrolyte during immersion. As the electrolyte becomes increasingly positively charged and the metal sheet increasingly negatively charged, the metal ions are increasingly attracted to the metal surface and the reverse reduction reaction leading to metal deposition is accelerated (Fig. 5.4). After a short time, an electrical potential is established so that the two partial reactions are in equilibrium. If this potential is measured against a reference, the tendency of the metal to release electrons, i.e. to oxidize, can be quantied. It is the greater the more negative the potential of the metal plate is. Figure 5.4: On the driving force of corrosion. 126 5 Oxidation and corrosion As a reference, a second half cell, the standard hydrogen electrode, is used. Its reaction is according to eq. 5.5 (Fig. 5.5). Thereby, the H+ -concentration is arbitrarily set to 1 mol/l (pH=0), the H2 -pressure is set to 1 bar and the potential to 0V. The voltage dierence between both half cells is measured by a voltmeter. Negative voltage means that an electron pressure towards the reference electrode exists. In analogy to the energy scale in Fig. 5.1, Fig. 5.6 shows voltages. An important result is, that only the noble metals Au, Pt, Ag are resistant against corrosion in aqueous media and acids. Figure 5.5: Measurement of the voltage dierence between two half cells. 1: Measuring electrode, 2,3: counter platinum electrode, 4 electrolyte (pH=0), 5 electrolyte bridge, 6 voltmeter, 7 ne-pored glass frits 5.2.2 Kinetics of corrosion According to Fig. 5.6, it would be expected that the corrosion in water containing oxygen would proceed faster than in acids. However, this contradicts the experience that a millimetre thick iron sheet dissolves in an acid (e.g. HCl) within a few hours. If, on the other hand, the same sheet is held in water containing oxygen, the corrosion loss is less than one millimetre per year. The cause is immediately apparent from Fig. 5.7. Whereas in acid corrosion the positive H+ ions are drawn to the negatively charged metal sheet by the electrostatic forces, the O2 molecule uncharged. It diuses in the aqueous solution and meets the metal sheet only randomly. Another important aspect is shown in Table 5.3. Here the corrosion rates of dierent materials in agricultural and industrial air are compared. First of all, it is noticeable that the less noble materials zinc and aluminium have lower removal rates than steel. As with oxidation, this is due to the formation of relatively dense oxide/hydroxide layers which inhibit corrosion. These layers can be unstable against further substances in the corrosive medium. For example, zinc hydroxide layers are attacked by SO2 (component of industrial air). A steel plate, containing a zinc coating of 40 µm (hot dip galvanizing), is protected outside of industrial areas for about 25 years. However, in industrial areas 127 5 Oxidation and corrosion Figure 5.6: Standard electrode potentials. (a) Metal in Acid. (b) Metal in oxygenated water. Figure 5.7: Representation of the corrosion of metals in acid and oxygenated water. 128 5 Oxidation and corrosion the protective eect can be reduced to a few years. Table 5.3: Material loss due to atmospheric corrosion. Material In industrial air / µm/a In country air / µm/a Aluminium 0,7 0,05 Steel 40 170 10 65 Copper 1,3 0,5 Zinc 3 22 1 2 A very important and aggressive component of aqueous solutions is the Cl− -ion (in seawater, through road salt on roads). It is able to attack many layers, such as Al2 O3 . Therefore, aluminium is at risk of corrosion in seawater or in contact with road salt, whereas it is very stable in the absence of Cl− -ions (Table 5.3). 5.2.3 Corrosion protection measures It is often unavoidable to use metallic materials in media that present a risk of corrosion. It is therefore extremely important to take measures which reduce the corrosion attack to the extent permissible for the planned component life. There are three main possibilities: Selection of suitable materials; Application of a protective coating; Corrosion-resistant design. These possibilities will be discussed in the following. Application of a protective coating A very common measure is the galvanizing of steel. Hereby, the kinetic inhibition of the atmospheric corrosion of zinc (Table 5.3) is utilized. Typical layer thicknesses are 5 to 50 µm. This results in a corrosion protection that can last for several decades outside industrial areas. However, in industrial areas the protective eect may be only a few years. Comparable processes are also phosphating of steel and the anodizing of aluminium. In anodizing, aluminium is immersed in an electrolyte and additionally positively polarised. This leads to the formation of a relatively thick Al2 O3 top layer, protecting the base material. Coating processes have the advantage that they are cost-eective. Their disadvantage is that their protective eect is limited in case of local damage (no self-healing eect). Coatings which are less noble than the base material (e.g. Zn on Fe) are preferable. In case of small damages, the oxidation reaction still occurs by dissolving zinc. As electrons are pressed from the less noble zinc into the more noble iron, a negative polarization of the iron occurs. This suppresses the oxidation of the iron and at the iron surface almost exclusively the reduction reaction takes place (Fig. 5.8 (b)). 129 5 Oxidation and corrosion (a) Noble coating. (b) Non-noble coating. Figure 5.8: Corrosion attack in case of noble and non-noble coatings. In the case of damage to more noble coatings (e.g. Cu, Fig. 5.8 (a)), the entire surface is available for the reduction reaction so that a large amount of oxygen can be converted. The electrons required for this must be made available by oxidation of the exposed metal. The metal dissolution is therefore highly localized and accelerated, so that a deep corrosion hole can form. Selection of suitable materials The most important element for increasing the corrosion resistance of steels is Cr. As already discussed in chapter 5.1, it forms a dense Cr2O3 layer which is relatively resistant to aggressive media. Steels with a chromium content of at least 10.5% are therefore designated as stainless steels in accordance with DIN EN 10020 (further requirement: Ccontent < 1.2%). Strictly speaking, however, this only applies to atmospheric corrosion. In aggressive media, such as sea water, corrosion phenomena can nevertheless occur. A very common steel is the so-called 18-8 or V2A steel (18 Cr, 8 Ni). Cutlery, for example, is made of this material. Since nickel has a much lower tendency to form chlorides than iron, Ni-Cr alloys provide even better corrosion resistance. However, this is achieved at considerably higher costs (cf. Fig. 1.3). A very important aspect in the selection of corrosion resistant materials is to avoid microstructural inhomogeneities. They always reduce the corrosion resistance locally. This is caused by the formation of so-called local cells, whereby the reduction reaction takes place spatially separated on the surface of the noble microstructural components. If the area ratio between noble and less noble microstructural components is large, very high local corrosion rates result (analogy: failure of noble coatings). For this reason, precipitation strengthened alloys generally have worse corrosion resistance than solid solution strengthened alloys. Solid solution strengthened Al-Mg alloys, for example, are signicantly more corrosion resistant than precipitation strengthened Al-Cu-Mg alloys. Another important example of the occurrence of local cells is the intercrystalline corrosion of stainless 18-8 Cr-Ni steels under certain conditions (Fig. 5.9). If the carbon content is well above 0.03% and the material is heated to temperatures between 600 C and 800 C, as is the case for example during welding, chromium-containing carbides (Cr23 C6 ) are precipitated under these conditions (Fig. 5.10). As a result, the regions around grain boundaries become depleted in chromium. If the chromium content falls ° ° 130 5 Oxidation and corrosion below approx. 12%, the passivity is lost locally and the steel is attacked locally. The conditions under which this phenomenon occurs can be read from the so-called sensitization diagram (Fig. 5.11). (a) Initial stage. (b) Final stage. Figure 5.9: Grain decay in a 18-8 Cr Ni-Steel. Figure 5.10: Schematic representation of the microstructural causes of grain decay. Shown in Fig. 5.11 is the range, dependent on time, temperature and carbon content, in which the material is sensitized, i.e. susceptible to intergranular corrosion. Fig. 5.11 131 5 Oxidation and corrosion is similar to the time-temperature diagram discussed in section 3.3.5. This is not surprising, as it is the formation of (Cr23 C6 ) particles at the grain boundaries that is responsible for the sensitization. However, the upper branch of the curves does not run horizontally, as is the case with the TTT-diagrams. This is due to the fact that Cr diuses from the grain interior to the depleted grain boundary areas at suciently high temperatures so that the Cr content increases again over time. Figure 5.11: Sensitization diagram (18-8 Cr-Ni steel). Accordingly, the sensitization is lost again if the annealing time is sucient, as can be seen from the falling upper curve branch of the curves. The section of the associated phase diagram inserted in Fig. 5.11 shows the relevant phase elds (γ and γ + Cr23 C6 ). Measures to counteract the sensitization are: Reduction of the carbon content below 0.03% Adding elements having a higher anity for carbon than chromium. As a result, special carbides of these elements are formed and the chromium remains in solution. Suitable carbide formers are titanium and niobium. Corrosion protection by design It has already become clear that pairs of dierent metals under corrosion attack are always unfavourable, since the more noble metal provides additional surface for the reduction reaction. Particularly unfavourable are situations in which the area of the more noble material is large compared to the area of the less noble material. So it would be a bad idea to x a copper rain gutter with a steel nail. Also the connection of steel pipes with copper pipes can lead to contact corrosion, also called galvanic corrosion. However, this is not a problem with closed water circuits (central heating), as no oxygen is supplied. If pairings of dierent metals are unavoidable, the following aspects should be considered under corrosive conditions: 132 5 Oxidation and corrosion Combine metals which are as close as possible with respect to their standard electrode potentials; The area of the more noble metal should be small compared to the area of the less noble metal (area rule); If the above points are not fullled, the contact points should be isolated. In the case of corrosion in oxygen-containing water, areas with dicult access to oxygen (e.g. at crevices caused by the design) are also particularly at risk. This is particularly true for corrosion-resistant materials (e.g. stainless steels) which would be protected by a stable surface layer under normal conditions. Because of the impeded oxygen access, the crevice initially depletes oxygen. As a result, only metal dissolution takes place in the crevice, but no oxygen is available to maintain the protective oxide layer (Fig. 5.12). Figure 5.12: Corrosion and degradation of the protective layer in the crevice due to lack of oxygen. Therefore, the protective layer increasingly dissolves, resulting in the formation of an active local element (metal oxidation in the crevice; oxygen reduction at contact surfaces outside the crevice). This results in another important rule: Crevices due to the design should be avoided in contact with corrosive media. Examples of good and bad design solutions are given in the following gures. Figures 5.13 to 5.15 give examples of how to avoid crevices and contact corrosion in welded, riveted and bolted connections. 5.2.4 Degradation of polymers Strictly speaking, corrosion is the electrochemical attack of a material. Since electron transport in the solid and electrolyte is a necessary part of the corrosion reaction, polymers are immune against electrochemical attack as they are electrical insulators. However, polymers are not resistant to purely chemical attack by aggressive substances. This will be discussed in the following. An essential feature of polymers, making these materials sensitive to chemical attack, is their relatively open structure (not most densely 133 5 Oxidation and corrosion Figure 5.13: Comparison of welded designs regarding crevice corrosion. Figure 5.14: Comparison of riveted joints regarding crevice corrosion (equal materials). Figure 5.15: Comparison of bolted connections with regard to contact and crevice corrosion. The situation shown on the left is unfavourable even though insulating material is used, because its application leads to crevices. This is avoided on the right hand side. 134 5 Oxidation and corrosion packed). This allows molecules (water, alcohol etc.) to penetrate into polymers and lead to chemical change. Due to dierent packing densities, amorphous thermoplastics are generally more susceptible than partially crystalline thermoplastics. Damage is caused by the reaction of the penetrated substance with the bonds of the polymer. Since the carbon-carbon bond is very stable, it is not attacked. In thermoplastics, the points of attack are rather the dipole bonds. The rule of thumb is that substances which are polar themselves (alcohols, acetone etc.) interact with these dipole bonds and, thus, lead to chemical attack. Therefore, polymers are generally sensitive to polar substances (Fig. 5.16), but more resistant to non-polar substances (e.g. fats). Figure 5.16: Breaking of dipol bonds in PMMA by methanol. Chemical decomposition can also be caused by UV radiation or prolonged exposure to heat. One example is the decomposition of PVC. Thereby, C-H and C-Cl bonds are broken. The released radicals react to form HCl, which is released. 135 5 Oxidation and corrosion Acknowledgement This script was translated from its German version with the help of DeepL Translate, the translator in Microsoft Word, and the dictionary LEO. 136 Bibliography [1] F. M. Ashby and D. R. H. Jones. Engineering Materials 1 - An Introduction to their Properties and Applications. Pergamon Press, 2. edition, 1980. Engineering Materials 2 - An introduction to microstructures, processing and design. Pergamon Press, 1. edition, 1986. [2] F. M. Ashby and D. R. H. Jones. Engineering Materials 2 - An introduction to microstructures, processing and design. Elsevier Butterworth-Heinemann, 2. edition, [3] F. M. Ashby and D. R. H. Jones. 1998. [4] F. M. Ashby and D. R. H. 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