1) Calculate the voltage across R2 using the voltage divider rule.
Ans: Vx = V*Rx/R1+R2
Rt = R2*R3l/R2+R3l
= 4*13/4+13 = 52/17 = 3.05 Kohm
Now
Vr2 = 12*3.05/1+3.05
= 9.03 V
2) Calculate the current through RL using ohm’s law.
Ans: I=V/RL
= 9.03/13
= 0.694mA
3) Determine the Thevenin equivalent circuit.
Ans:
4) Calculate the current through RL using Thevenin theorem.
Ans: Rth = R1 + R2 + R3
We know that R1 and R2 are connected in parallel and R3 is in series.
Therefore;
Rth = R1*R2/R1+R2 +R3
= 1*4/1+ 4 + 3
= 0.8 + 3 = 3.8 Kohm
Now, to find Vth
I=V/R
= 12/1+4 = 2.4A
Vth = I*4
= 2.4*4 = 9.6 V
= 9.6/3.8+10
= 0.695mA
5) Draw the circuit in EWB software including the Thevenin circuit
and compare your measured current with above calculations by
filling the following table.
Ans:
Current in RL
I [mA]
Ohm’s Law
0.694mA
Thevenin Circuit
0.695mA
software
-695.7micro-amp