Uploaded by Ömer Efe Ulusoy

Strength of Materials Homework: Stress & Strain Analysis

advertisement
Ömer
Efe
Ulusoy
11023034
Mukavemet
Ödev
-
-
-
-
-
s
-t
Eda
2
o
en
a
(4)
↑
e
↳
r =
2xdA
r =
006 2x
.
-
d
+
03
+
112
+ el
x
Y
je 4
.
Je posx 103)4
4
+
mrbeus
40X
-
=
H 27-13
rad
eve
.
-dışya
=
"ş valar
post!ea"-cars")
en
=
6 , 85
.
154
= +=
3 +
p
1, 69
=
.
68
103 rad
180. 1 1 69 103
.
1800 JX
-3
X
X=
180
T
1 1 69
.
103
10096
C
Ju = (005X
b
-m
-
eng
x
+
ese3"
-
be
=
1106
I
-
-
10
4 rad
22531 , 7
D
=
1101
.
103 +
1106
1
.
1
"
11.0
=
1 1 11
-
= pox ter
153)
3 = 0
-
+
en3) (03)"
-
"
sempa
en
=
İlk
s"stem"n
güvenl!d!r
-
Anektosun
maruz
kaldığı
maks"mum stes
Impa
t"r Yan"
m
F!z
60 c
=9
=
+
orads
y ac
·ye=
+
aca PoE
+
+
pe
-
Pc
=
-
Ope
-T
o
②
o
PCD
=
Toe-T1
=
0T
-Doe
=T
=
1y
-
T
2T =
=
Ty
10
kN
#5
·
m
De
=
PE
=
De rad
OcD
PDE
+
·
+DE
↳
10-11 - Ta
Tcp
DE
=
04
Ded
+
=
1
-
= 0
T1
756Pa
=
PDE
En
j E c) ben
=
j
=
-
.
1- d
02
·
>
-
0104
10 11) 1 99 -0
-
=
2
11
=
1
-25
.
-
1199 .
Te
5105kN!m
,
-
resent F
d
·
-Tc-2kn!mokn m
.
=
zomm
0
-
~
F = Fl
>
-
Tc =
F
.
Ben
5
0 1 2m
F
g
=
Pp
fud"z
,
=
&
TDE
=
=
6 kr m
.
d
-Da as
rad
Polog5
en
De
TB
ka
fe4o
=As=
Der
,
p + Ped
+
Poe
=
-Top
How 2km =
Esk!m
-
2 + TDE
=
0
2kN-m
E
=
05
t
DE
=
0 , 0204
rad
,
4 18
.
Pa
=
b
-
ac
Pa
=
ac Pc
=
↓
+
0 1 0159
PD
=
-10964
964 180 515
.
↓
+
00805
rad
E
-
·
204N
"
Iy
2
"
-
-
15 1 33
18
133
-
=
-
!
· "
"
:
"
①
-
30195
48 1 9
-
ZFy
= 0
,
Ay + By
23 =0
-
+
By 23kN
Ay
=
[Ma =
=
45
19 20
-
.
6
-
11 By
201
1
By
18133
Ay
=
=
=
4167
10 3 + By
.
=
0
en
s!metr!
⑫
Mz
My
Iz
=
10kN-m
=
17 3k Ne
.
(epreg
=
D
p
.
zests
10-4 mY
1 21
E
=
.
.
=
A
=
Dost 80
-
Iy
=
Poebeeg .
=5
5, 13
-
.
10
6
.
=
Pam
=1 b!se
&
NWOzm
3
=
9 , se
Max Basma
A
⑨
F
63 Mpa
25
,
1 63
mpa
25
=
Max Çekme
tap-taneta
D
=
7624
A
·
·
a
tabots
Download