Natalie Baker
Problem I
(b) tetrahedral
(a) octahedral
(i) Tin
Trea (9 ,
Tirr
=
0
,
1
Han Eur Tin
+
,
,
%
,
,9
1
,
1 ,
0
,
+
,
1)
<
Crea )
Ang
1
1
,
1
,
,
1
, 1, 1 ,
, ,)
%
=
:
Fred (3
,
+
T
i
0 , 1, 1 ,
:
,
,
,
0,
0,2
,
6
,
0
,
0
,
2,
0)
Tirr-Tiu Tau
,
,
allowed
z
,
0
,
0,2,
6
,
0
,
0
,
2
,
0)
,
0,2
X Y :z
,
1
,
Cred (3
:
,
0,
%,
Yes X Y z reducible
,
0)
1,
1)
Ta
Yes X Y z allowed
,
0,
reducible
Sirr-Ta
,
,
Ti + Ta
=
,
(iv) A
0
,
=
yes
Tig
E
<
Tirr-TintTau
,
1)
,
fred (6
Tirr
+
yes X y
,
,
(iii)T
0
:
Trea /6
1)
yes X Y z allowed
(iii) Tu Eg
(iv) En i
-
:
,
,
1.
firr Ta
not X Y , z allowed
Cred (6
,
,
,
,
1
,
1
Yes X Y z allowed
:
,
+
=
Tirr Air
no
0
,
,
Tirr A2 E T Ta
Tzu
:
Tres (9
(ii) Da
(ii) Azu
:
,
allowed
yes X % z
,
(i) T. To
Tag
:
,
,
(c)
(d)
(1) En Eg
Crea (4
0
:
,
,
4
0
,
,
0, 4
0, 4 ,
,
0,
0)
(i) En < Eg
free (4 1
,
,
0 , 4,
Tirr Dia Dan Biu Bau
Tirr Aiu Azu-Eu
,z reducible
Yes
yes X y z reducible
+
=
+
(ii) Han
Fred- (1
,
1
,
1
,
,
,
(ii) Azu
Aig
<
+
=
,
% , , , ,,
,
11)
Eg
:
Frea (2 ,
:
Tirr Azu
Tirr
yes z reducible
no , not X
=
,
(iii) Big Bag
fred) 1
1
,
:
1
,
1
,
%
,
1
,
1
,
1
,
1
,
1)
,
0,
,
En
:
Crea 2,
0
,
, 2,
no , not X, ,z reducible
yes Xy reducible
>
Crea (2
,
(iv) Han
0
,
,
0, 2
,
0,
2
0
,
,
0)
Frea) 1
yes X y reducible
no not X
,
1,
,
Sirr Air
,
,
0)
Ang
Pirr Eu
=
i
,
Bag
0, 2
0)
,
Tirr-En
(iv) En
,
y z reducible
Sirr-Hag
y
2, 1
Eg
(iii) Alg
,
+, 0
1
,
:
,
,
y z reducible
,
,
1)
Problem 2
Problem 3
Microstates -n
(a) P(l)
neutral Ti [Ar] 303452
:
(a)
conc
10 !
=
6 ! (10-6) !
Pi(ID [Ar] 3 d
:
210
(b)d" = D
=> 37
(b) neutral Fe [Ar] 3 d752
:
Fe(V) [Ar]3d3
multiplicity- (2s 1)(2L D 25
+
+
=
:
(C) GS
=> F
(C)
*
neutral Ni [Ar]3d +s?
:
NiCID [Ar] 3dS
:
=>
37
(d) neutral Mn [Ar]3d4s
?
:
Mn(II) [Ar]3d
:
= SD
(e) neutral Co [Ar]3d* 4s
:
>
CoLID [Ar] 3d
:
=>
(f) neutral Fe [Ar]3d4s
?
:
Fell) [Ar]3de
:
=> SD
:
"Tag 5- 2
,
multiplicity (2s D (2) 1) 15
-
+
=
+
=
Problem 4
Problem 5
Ang" (trg)" (eg)
(b)Tig
(teg)" (eg)3
(C) ·Tay
(tag)"leg)
(a) (SFE
(a)
=
(6x
-
4Dq)
+
(2
+
(Dq)
=-
12Dg
<
<
(b) (SFE (5
=
(c) CSFE
:
x
(4x
-
-
1Dg) (3 GDg)
4Dg)
+
=
=
(4
+
=
2Dg
GDg) ODg
=