Math PAPER–CLASS-9th
Time: 2:30 Hr.
Name:
Roll. No:
PAPER OBJECTIVE
Q.1: Choose the correct option and fill up the bubbles.
Sr.
Statements
A
The logarithm of unity to any base is:
If π π₯ = π, then
πππ π = π€βπππ π ≅ 2.718
2 1
(iv) The determinant of matrix π΅ = [
] is:
4 7
(v) [√2 0 ] ππ ππππππ π πππ‘πππ₯
0 √2
(vi) πΌππππππππ¦ ππππ‘ ππ (−1 + √−2)2 ππ :
2 6
(vii) πΌπ |
| = 0 , π‘βππ π₯ ππ πππ’ππ π‘π:
3 π₯
(viii) The vertical line represent in matrix is:
(i)
(ii)
(iii)
(ix)
(x)
(xi)
Date:
Section:
−1
2
25
( ) =
16
The determinant of [π] is:
Formula of finding multiplicative inverse of “A”
When square matrix is said to be singular matrix
if |π΄| =
Which matrix is an additive identity of
(xiii)
2 − ππ¦ − 2?
π΄ πππ π‘πππππππ‘πππ, πππ ππππ’ππππ πππππππ
(xiv)
represents:
The scalar matrix and identity matrix are
(xv)
75
(12)
B
C
D
1
π = ππππ₯ π
10
π₯ = ππππ π
0
π = ππππ π₯
0.4343
0
π
π₯ = ππππ π
∞
7
10
8
−7
ππππ‘
ππππ
ππππππ
π·πππππππ
1
−2√2
−1
2√2
6
−9
9
−6
Column
5
4
−π
π΄πππ΄
π΄
Row
4
5
1
|π΄|
π΄ππ
Diagonal
−5
4
π
π΄πππ΄
−
|π΄|
None
−4
5
Zero
π΄πππ΄
|π΄|
7
1
0
None
0 0
]
0 0
Natural
numbers
Additive
inverse
1 0
]
0 1
Rational
numbers
0 1
]
1 1
Irrational
numbers
0 1
[
]
1 0
Symmetric
Diagonal
(xii)
[
[
[
1
Prime numbers
Rectangular
*Subjective (Part I)*
2. Write Short Answers of any five parts.
(i)
Define abscissa and ordinate.
(ii)
Multiply: [8 5] [ 2
(iii)
(iv)
(v)
(vi)
(vii)
6
4 −4
(5×2=10)
−5
2]
4
πΉπππ π‘βπ πππ πππππ‘ ππ π‘βπ ππππ π ππππππ‘ πππππππ πππβ ππ π‘βπ πππππ‘π : π΄(0,0), π΅(0, −5)?
2 4
7 10
1 π
If 2[
] + 3[
]=[
] then find a and b?
−3 π
18 1
8 −4
1 −2
Find multiplicative inverse (if it exists) π΄ = [
]
3 4
−1 2 1 1
Multiply the matrices:[
][
]
1 3 2 0
Evaluate:
291.3×42.36
3. Write Short Answers of any five parts.
(i)
Define ordered pair.
(5×2=10)
(ii)
(iii)
ππ πππ πππ π‘ππππ πππππ’ππ, ππππ π‘βπ πππ π‘ππππ πππ‘π€πππ π‘βπ πππππ‘π : π(0,2) πππ π(−3,0)?
(iv)
Find the multiplicative inverse of the following matrix: π΄ = [
(v)
(vi)
Evaluate:
log 512 π‘π π‘βπ πππ π 2√2 .
Simplify:
π₯ 2 ÷ (π₯ 2 )3
(vii)
Use laws of exponents to simplify: [ π₯ 4 π¦ −3 π§ 0 ]
Evaluate:
(−π)5
2 4
]
−2 1
3
π₯ −2 π¦ −1 π§ −4
−3
(5×2=10)
4. Write Short Answers of any five parts.
(i)
Find Multiplicative inverse of the matrix: [√2 0 ]
0 √2
(ii)
Express the following recurring decimal as the rational number π :
(iii)
Simplify:
(iv)
(v)
(vi)
(vii)
πΉπππ π‘βπ π£πππ’π ππ π₯: πππ625 5 = 4 π₯
Define coordinate axes.
πΌπ πππ2 = 0.3010, πππ3 = 0.4771, log 5 = 0.6990 π‘βππ ππππ π‘βπ π£πππ’π ππ:
Define isosceles triangle.
π
Μ
Μ
Μ
Μ
0.13
3
52 ÷ (52 )3
1
log 30
*Subjective (Part II)*
Attempt any three Questions. Each Question has 10 marks
3π₯ − 2π¦
5. (a) Solve the linear equations by Cramer’s rule:
5π₯ − 2π¦
3
(10×3=30)
= −6
= −10
0.07921 ×(19.99)2
(b) Use log tables to find the value of: √ (5.79)4 ×0.9474
2
6. (a) ππππππππ¦ βΆ
1
(216) ⁄3 ×(25) ⁄2
√
−3⁄
2
(0.04)
5
7
Use log tables to find the value of: √2.709 × √1.239
4 0
−4 −2
7. (a) If π΄ = [
] πππ π΅ = [
] π‘βππ π£πππππ¦ π‘βππ‘: (π΄π΅)−π = π΅ −1 π΄−π
−1 2
1 −1
(b)
3 −1
(b) πΌπ π΅ = [
] then Prove: π΅π΅ −1 = πΌ = π΅ −1 π΅
2 −2
Theorem: The right bisectors of the sides of triangle are concurrent.
Best of Luck