Math PAPER–CLASS-9th Time: 2:30 Hr. Name: Roll. No: PAPER OBJECTIVE Q.1: Choose the correct option and fill up the bubbles. Sr. Statements A The logarithm of unity to any base is: If π π₯ = π, then πππ π = π€βπππ π ≅ 2.718 2 1 (iv) The determinant of matrix π΅ = [ ] is: 4 7 (v) [√2 0 ] ππ ππππππ π πππ‘πππ₯ 0 √2 (vi) πΌππππππππ¦ ππππ‘ ππ (−1 + √−2)2 ππ : 2 6 (vii) πΌπ | | = 0 , π‘βππ π₯ ππ πππ’ππ π‘π: 3 π₯ (viii) The vertical line represent in matrix is: (i) (ii) (iii) (ix) (x) (xi) Date: Section: −1 2 25 ( ) = 16 The determinant of [π] is: Formula of finding multiplicative inverse of “A” When square matrix is said to be singular matrix if |π΄| = Which matrix is an additive identity of (xiii) 2 − ππ¦ − 2? π΄ πππ π‘πππππππ‘πππ, πππ ππππ’ππππ πππππππ (xiv) represents: The scalar matrix and identity matrix are (xv) 75 (12) B C D 1 π = ππππ₯ π 10 π₯ = ππππ π 0 π = ππππ π₯ 0.4343 0 π π₯ = ππππ π ∞ 7 10 8 −7 ππππ‘ ππππ ππππππ π·πππππππ 1 −2√2 −1 2√2 6 −9 9 −6 Column 5 4 −π π΄πππ΄ π΄ Row 4 5 1 |π΄| π΄ππ Diagonal −5 4 π π΄πππ΄ − |π΄| None −4 5 Zero π΄πππ΄ |π΄| 7 1 0 None 0 0 ] 0 0 Natural numbers Additive inverse 1 0 ] 0 1 Rational numbers 0 1 ] 1 1 Irrational numbers 0 1 [ ] 1 0 Symmetric Diagonal (xii) [ [ [ 1 Prime numbers Rectangular *Subjective (Part I)* 2. Write Short Answers of any five parts. (i) Define abscissa and ordinate. (ii) Multiply: [8 5] [ 2 (iii) (iv) (v) (vi) (vii) 6 4 −4 (5×2=10) −5 2] 4 πΉπππ π‘βπ πππ πππππ‘ ππ π‘βπ ππππ π ππππππ‘ πππππππ πππβ ππ π‘βπ πππππ‘π : π΄(0,0), π΅(0, −5)? 2 4 7 10 1 π If 2[ ] + 3[ ]=[ ] then find a and b? −3 π 18 1 8 −4 1 −2 Find multiplicative inverse (if it exists) π΄ = [ ] 3 4 −1 2 1 1 Multiply the matrices:[ ][ ] 1 3 2 0 Evaluate: 291.3×42.36 3. Write Short Answers of any five parts. (i) Define ordered pair. (5×2=10) (ii) (iii) ππ πππ πππ π‘ππππ πππππ’ππ, ππππ π‘βπ πππ π‘ππππ πππ‘π€πππ π‘βπ πππππ‘π : π(0,2) πππ π(−3,0)? (iv) Find the multiplicative inverse of the following matrix: π΄ = [ (v) (vi) Evaluate: log 512 π‘π π‘βπ πππ π 2√2 . Simplify: π₯ 2 ÷ (π₯ 2 )3 (vii) Use laws of exponents to simplify: [ π₯ 4 π¦ −3 π§ 0 ] Evaluate: (−π)5 2 4 ] −2 1 3 π₯ −2 π¦ −1 π§ −4 −3 (5×2=10) 4. Write Short Answers of any five parts. (i) Find Multiplicative inverse of the matrix: [√2 0 ] 0 √2 (ii) Express the following recurring decimal as the rational number π : (iii) Simplify: (iv) (v) (vi) (vii) πΉπππ π‘βπ π£πππ’π ππ π₯: πππ625 5 = 4 π₯ Define coordinate axes. πΌπ πππ2 = 0.3010, πππ3 = 0.4771, log 5 = 0.6990 π‘βππ ππππ π‘βπ π£πππ’π ππ: Define isosceles triangle. π Μ Μ Μ Μ 0.13 3 52 ÷ (52 )3 1 log 30 *Subjective (Part II)* Attempt any three Questions. Each Question has 10 marks 3π₯ − 2π¦ 5. (a) Solve the linear equations by Cramer’s rule: 5π₯ − 2π¦ 3 (10×3=30) = −6 = −10 0.07921 ×(19.99)2 (b) Use log tables to find the value of: √ (5.79)4 ×0.9474 2 6. (a) ππππππππ¦ βΆ 1 (216) ⁄3 ×(25) ⁄2 √ −3⁄ 2 (0.04) 5 7 Use log tables to find the value of: √2.709 × √1.239 4 0 −4 −2 7. (a) If π΄ = [ ] πππ π΅ = [ ] π‘βππ π£πππππ¦ π‘βππ‘: (π΄π΅)−π = π΅ −1 π΄−π −1 2 1 −1 (b) 3 −1 (b) πΌπ π΅ = [ ] then Prove: π΅π΅ −1 = πΌ = π΅ −1 π΅ 2 −2 Theorem: The right bisectors of the sides of triangle are concurrent. Best of Luck