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Class 9 Math Exam Paper - Practice Questions & Solutions

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Math PAPER–CLASS-9th
Time: 2:30 Hr.
Name:
Roll. No:
PAPER OBJECTIVE
Q.1: Choose the correct option and fill up the bubbles.
Sr.
Statements
A
The logarithm of unity to any base is:
If π‘Ž π‘₯ = 𝑛, then
π‘™π‘œπ‘” 𝑒 = π‘€β„Žπ‘’π‘Ÿπ‘’ 𝑒 ≅ 2.718
2 1
(iv) The determinant of matrix 𝐡 = [
] is:
4 7
(v) [√2 0 ] 𝑖𝑠 π‘π‘Žπ‘™π‘™π‘’π‘‘ π‘Ž π‘šπ‘Žπ‘‘π‘Ÿπ‘–π‘₯
0 √2
(vi) πΌπ‘šπ‘Žπ‘”π‘–π‘›π‘Žπ‘Ÿπ‘¦ π‘π‘Žπ‘Ÿπ‘‘ π‘œπ‘“ (−1 + √−2)2 𝑖𝑠:
2 6
(vii) 𝐼𝑓 |
| = 0 , π‘‘β„Žπ‘’π‘› π‘₯ 𝑖𝑠 π‘’π‘žπ‘’π‘Žπ‘™ π‘‘π‘œ:
3 π‘₯
(viii) The vertical line represent in matrix is:
(i)
(ii)
(iii)
(ix)
(x)
(xi)
Date:
Section:
−1
2
25
( ) =
16
The determinant of [π‘Ž] is:
Formula of finding multiplicative inverse of “A”
When square matrix is said to be singular matrix
if |𝐴| =
Which matrix is an additive identity of
(xiii)
2 − 𝑏𝑦 − 2?
𝐴 π‘›π‘œπ‘› π‘‘π‘’π‘Ÿπ‘šπ‘–π‘›π‘Žπ‘‘π‘–π‘›π‘”, π‘›π‘œπ‘› π‘Ÿπ‘’π‘π‘’π‘Ÿπ‘–π‘›π‘” π‘‘π‘’π‘π‘–π‘šπ‘Žπ‘™
(xiv)
represents:
The scalar matrix and identity matrix are
(xv)
75
(12)
B
C
D
1
π‘Ž = π‘™π‘œπ‘”π‘₯ 𝑛
10
π‘₯ = π‘™π‘œπ‘”π‘› π‘Ž
0
π‘Ž = π‘™π‘œπ‘”π‘› π‘₯
0.4343
0
𝑒
π‘₯ = π‘™π‘œπ‘”π‘Ž 𝑛
∞
7
10
8
−7
π‘ˆπ‘›π‘–π‘‘
π‘π‘’π‘Ÿπ‘œ
π‘†π‘π‘Žπ‘™π‘Žπ‘Ÿ
π·π‘–π‘Žπ‘”π‘œπ‘›π‘Žπ‘™
1
−2√2
−1
2√2
6
−9
9
−6
Column
5
4
−π‘Ž
𝐴𝑑𝑗𝐴
𝐴
Row
4
5
1
|𝐴|
𝐴𝑑𝑗
Diagonal
−5
4
π‘Ž
𝐴𝑑𝑗𝐴
−
|𝐴|
None
−4
5
Zero
𝐴𝑑𝑗𝐴
|𝐴|
7
1
0
None
0 0
]
0 0
Natural
numbers
Additive
inverse
1 0
]
0 1
Rational
numbers
0 1
]
1 1
Irrational
numbers
0 1
[
]
1 0
Symmetric
Diagonal
(xii)
[
[
[
1
Prime numbers
Rectangular
*Subjective (Part I)*
2. Write Short Answers of any five parts.
(i)
Define abscissa and ordinate.
(ii)
Multiply: [8 5] [ 2
(iii)
(iv)
(v)
(vi)
(vii)
6
4 −4
(5×2=10)
−5
2]
4
𝐹𝑖𝑛𝑑 π‘‘β„Žπ‘’ π‘šπ‘–π‘‘ π‘π‘œπ‘–π‘›π‘‘ π‘œπ‘“ π‘‘β„Žπ‘’ 𝑙𝑖𝑛𝑒 π‘ π‘’π‘”π‘šπ‘’π‘›π‘‘ π‘—π‘œπ‘–π‘›π‘–π‘›π‘” π‘’π‘Žπ‘β„Ž π‘œπ‘“ π‘‘β„Žπ‘’ π‘π‘œπ‘–π‘›π‘‘π‘ : 𝐴(0,0), 𝐡(0, −5)?
2 4
7 10
1 𝑏
If 2[
] + 3[
]=[
] then find a and b?
−3 π‘Ž
18 1
8 −4
1 −2
Find multiplicative inverse (if it exists) 𝐴 = [
]
3 4
−1 2 1 1
Multiply the matrices:[
][
]
1 3 2 0
Evaluate:
291.3×42.36
3. Write Short Answers of any five parts.
(i)
Define ordered pair.
(5×2=10)
(ii)
(iii)
π‘ˆπ‘ π‘–π‘›π‘” π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘“π‘œπ‘Ÿπ‘šπ‘’π‘™π‘Ž, 𝑓𝑖𝑛𝑑 π‘‘β„Žπ‘’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ 𝑏𝑒𝑑𝑀𝑒𝑒𝑛 π‘‘β„Žπ‘’ π‘π‘œπ‘–π‘›π‘‘π‘ : π‘ˆ(0,2) π‘Žπ‘›π‘‘ 𝑉(−3,0)?
(iv)
Find the multiplicative inverse of the following matrix: 𝐴 = [
(v)
(vi)
Evaluate:
log 512 π‘‘π‘œ π‘‘β„Žπ‘’ π‘π‘Žπ‘ π‘’ 2√2 .
Simplify:
π‘₯ 2 ÷ (π‘₯ 2 )3
(vii)
Use laws of exponents to simplify: [ π‘₯ 4 𝑦 −3 𝑧 0 ]
Evaluate:
(−𝑖)5
2 4
]
−2 1
3
π‘₯ −2 𝑦 −1 𝑧 −4
−3
(5×2=10)
4. Write Short Answers of any five parts.
(i)
Find Multiplicative inverse of the matrix: [√2 0 ]
0 √2
(ii)
Express the following recurring decimal as the rational number π‘ž :
(iii)
Simplify:
(iv)
(v)
(vi)
(vii)
𝐹𝑖𝑛𝑑 π‘‘β„Žπ‘’ π‘£π‘Žπ‘™π‘’π‘’ π‘œπ‘“ π‘₯: π‘™π‘œπ‘”625 5 = 4 π‘₯
Define coordinate axes.
𝐼𝑓 π‘™π‘œπ‘”2 = 0.3010, π‘™π‘œπ‘”3 = 0.4771, log 5 = 0.6990 π‘‘β„Žπ‘’π‘› 𝑓𝑖𝑛𝑑 π‘‘β„Žπ‘’ π‘£π‘Žπ‘™π‘’π‘’ π‘œπ‘“:
Define isosceles triangle.
𝑝
Μ…Μ…Μ…Μ…
0.13
3
52 ÷ (52 )3
1
log 30
*Subjective (Part II)*
Attempt any three Questions. Each Question has 10 marks
3π‘₯ − 2𝑦
5. (a) Solve the linear equations by Cramer’s rule:
5π‘₯ − 2𝑦
3
(10×3=30)
= −6
= −10
0.07921 ×(19.99)2
(b) Use log tables to find the value of: √ (5.79)4 ×0.9474
2
6. (a) π‘†π‘–π‘šπ‘π‘™π‘–π‘“π‘¦ ∢
1
(216) ⁄3 ×(25) ⁄2
√
−3⁄
2
(0.04)
5
7
Use log tables to find the value of: √2.709 × √1.239
4 0
−4 −2
7. (a) If 𝐴 = [
] π‘Žπ‘›π‘‘ 𝐡 = [
] π‘‘β„Žπ‘’π‘› π‘£π‘’π‘Ÿπ‘–π‘“π‘¦ π‘‘β„Žπ‘Žπ‘‘: (𝐴𝐡)−𝟏 = 𝐡 −1 𝐴−𝟏
−1 2
1 −1
(b)
3 −1
(b) 𝐼𝑓 𝐡 = [
] then Prove: 𝐡𝐡 −1 = 𝐼 = 𝐡 −1 𝐡
2 −2
Theorem: The right bisectors of the sides of triangle are concurrent.
Best of Luck
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