Grade 11 Mathematics/Investigation 1 NSC Limpopo DoE/Term 1 2025 NATIONAL SENIOR CERTIFICATE GRADE 11 MATHEMATICS INVESTIGATION MARKS : 100 This investigation consists of 10 Pages. Copyright reserved Please turn over Grade 11 Mathematics/Investigation 2 NSC Limpopo DoE/Term 1 2025 INVESTIGATION: DERIVATION OF THE QUADRATIC FORMULA AND ITS SIGNIFICANCE The aim of this investigation is to establish the quadratic formula, allowing us to find solutions to any quadratic equation of the form ax 2 + bx + c = 0 . Let’s start by using the process of completing the square to solve the equation x 2 + 2 x − 8 = 0 . We could solve this equation through factorisation but let’s use completing the square and colour code the terms to follow the process. We can then try to follow the same process to solve ax 2 + bx + c = 0 . This investigation is set out as a fill in the gaps investigation. It is advisable that this paper is used as an answer sheet as well. SECTION A: UNDERSTANDING COMPLETING THE SQUARE [15] 1. Starting with x 2 + 2 x − 8 = 0 , move the constant term to the right-hand side: We can represent this problem visually as the sum of the area of a square with side length x and the area rectangle with side lengths 2 and x, is equal to a square with total area 8: 1.1 Fill in the missing side lengths. Figure 1: Blue (3) Figure 2: Green Figure 3: Orange Equation 1 illustration 1 Splitting the green rectangle down the middle we can place it on either side of the blue rectangle. Copyright reserved Please turn over Grade 11 Mathematics/Investigation 3 NSC Limpopo DoE/Term 1 2025 1.2 Fill in the missing side lengths and areas. (5) Figure 2: Orange Figure 1: Blue & green Equation 1 illustration 2: We can “complete the square” on the left by adding the missing corner. We do this to both sides to balance the equation. 1.3 Fill in the missing area’s. (2) Figure 3: Yellow Figure 1: Blue & green Figure 2: Orange Equation 1 illustration 3: Combining the terms on the right-hand side to form a new square, we now have equivalent squares. Copyright reserved Please turn over 4 NSC Grade 11 Mathematics/Investigation Limpopo DoE/Term 1 2025 1.4 Fill in the missing area for the new rectangle on the right. (2) Figure 2: Grey Figure 1: Blue, green and yellow Equation 1 illustration 4 And hence, ( x + 1) = 9 2 1.5 So, we know the side length x + 1 must be equal to the side length of the grey rectangle which is 3, so a solution is x = . (2) 1.6 If we are looking to solve the equation generally and not just in a concrete case we can also have x + 1 = −3 , and hence our second solution is x = Copyright reserved . (1) Please turn over 5 NSC Grade 11 Mathematics/Investigation Limpopo DoE/Term 1 2025 SECTION B: DEDUCING THE QUADRATIC FORMULA [32] Let’s now repeat this process to deduce the quadratic formula. 2. Starting with ax 2 + bx + c = 0 , divide through by a and move the constant term to the right-hand side: Let’s again represent this problem visually as the sum of the area of a square with side length x and the area of a rectangle with side lengths b and x, is equal to a square with total a area −ac: 2.1 Fill in the missing side lengths and area. Figure 1: Blue (4) Figure 2: Green Figure 3: Orange Equation 2 Illustration 1 Splitting the green rectangle down the middle we can place it on either side of the blue rectangle. Copyright reserved Please turn over Grade 11 Mathematics/Investigation 6 NSC Limpopo DoE/Term 1 2025 2.2 Fill in the missing side lengths and areas. (6) Figure 2: Orange Figure 1: Blue & Green Equation 2 Illustration 2 We can “complete the square” on the left by adding the missing corner. We do this to both sides to balance the equation. 2.3 Fill in the missing areas. (3) Figure 3: Yellow Figure 1: Blue, Green & Yellow Figure 2: Orange Equation 2 Illustration 3: Combining the terms on the right-hand side to form a new square, we now have equivalent squares. 2.4 Fill in the gaps to find a simplified expression for the area of our new grey rectangle: (2) Copyright reserved Please turn over 7 NSC Grade 11 Mathematics/Investigation c b2 − + 2 a 4a =− Limpopo DoE/Term 1 2025 4ac b 2 (make both fractions have the same denominator) + 4a 2 4a 2 b 2 − 4ac = 4a 2 (combine to form a single fraction) 2.5 Does the numerator look familiar? If yes, what is it called? (2) 2.6 Fill in the gap for the area of our new grey rectangle. (1) Figure 2: Grey Figure 1: Blue, Green & Yellow Equation 2 Illustration 4 b b 2 − 4ac And hence, x + = 2a 4a 2 (2) From here let’s rearrange algebraically: (3) 2 a) Take the square roots of both sides, don’t forget to indicate there are two answers ________________ b) Simplify the fraction by recalling x = y x y _______________________ Copyright reserved Please turn over Grade 11 Mathematics/Investigation 8 NSC Limpopo DoE/Term 1 2025 c) Isolate the x on the left by moving the other term to the right ___________________________ d) Write the right-hand side as a single fraction _______________________ If you have followed the steps correctly you have established quadratic formula, i.e. for a quadratic equation of the form ax 2 + bx + c = 0 , solutions are: 2.7 x = −b b 2 − 4ac 2a (2) Further questions to ponder: 3. Who was the first person to establish this formula and when? (2) 4. Are there other ways to establish the formula? (5) SECTION C: SIGNIFICANCE OF THE QUADRATIC FORMULA [3] The quadratic formula defines the points ( x;0 ) on the parabolic graph, where the parabola y = ax2 + bx + c crosses the x -axis and it can be separated into two terms, x= −b b 2 − 4ac 2a x=− b b 2 − 4ac 2a 2a The first term − b describes the (i) 2a b 2 − 4ac , gives the (ii) 2a , the line x = − b . The second term 2a the roots are away from the axis of symmetry. If the parabola’s vertex is on the x -axis, then the corresponding equation has a single repeated root on the line of symmetry, and this distance term is zero, algebraically, the (iii) commonly known as b 2 − 4ac = 0 . (3) GRAND TOTAL: 100 MARKS Copyright reserved Please turn over Grade 11 Mathematics/Investigation Level 1 (1x) Criteria Section A: Understanding Completing the Square [36 Marks] Missing side lengths (1.1 & 1.2) No attempt to fill inside lengths. (0 correct) Missing areas (1.2-1.6) Incorrect areas with significant errors. (0 correct) 9 Limpopo DoE/Term 1 2025 NSC 9 No understanding of balancing the equation and adding missing corners. (0 correct) Section B: Deducing the Quadratic Formula [52 Marks] Completing the square (1.3-1.4) Level 2 (2x) Level 3 (3x) Most side lengths completed correctly. (1-2 correct) Some areas calculated correctly but with noticeable errors. (1-3 correct) All side lengths accurately identified and completed with clear understanding (3-5 correct). Partial completion of the square with some understanding of balancing both sides. (1 correct) All correct completion of square and correct addition of missing corners. (2-3 correct) Most areas are correctly calculated and logical reasoning shown. (4-5 correct) LDoE/Term 1 2025 Level 4 (4x) Max Marks /x4 All areas are calculated correctly with detailed explanations of process. (6 and both conclusion values correct). /x3 /x4 Fill-in side lengths and areas (2.1 & 2.2) No side lengths identified. (0 correct) 3 side lengths completed correctly/with minor errors. 5 side lengths are completed correctly with some gaps. All side lengths are completed accurately and systematically. /x3 Completing the square visually (2.3 & 2.4) No attempt to visually represent the square or add missing corners. (0 correct) One correct understanding of completing the square visually but lacks clarity or accuracy. Most visual representations and additions are correct with minor errors. (2-3 correct) Clear and accurate visual representation with logical reasoning (4-5 correct). /x3 Familiarity of the numerator (2.5) No attempt/response to the familiarity of the numerator. (0 correct) Attempted to respond to familiarity of the numerator with yes only. (1 correct) Conclusion/algebraic rearrangements (2.6 & 2.7) No understanding of algebraic rearrangements. (0 correct) 1-2 correct rearrangement attempted but with errors. Attempted to respond to familiarity of the numerator with yes and named it. (2 correct) Most algebraic steps are correct with some inaccuracies. (3-4 correct) Most algebraic steps are correct with some inaccuracies. (5-8 correct) /x3 Historical and alternative methods (3 & 4) No attempt to answer historical and alternative method questions. (0 correct) 1-2 correct response with limited explanation or accuracy. 3-4 correct responses correct with some gaps in detail. 5-7 correct responses correct with some gaps in detail. /x1 one interpretation of terms with noticeable gaps or errors. (1 correct) Two terms are interpreted correctly with minor errors. (2 correct) Both terms are interpreted correctly as well as the discriminant. (3 correct) /x3 /x4 Section C: Significance of the Quadratic Formula [12 Marks] Interpretation of terms (i-iii) Incorrect interpretation of terms and their significance. (0 correct) Total Copyright reserved /100 Please turn over Grade 11 Mathematics/Investigation Copyright reserved 10 Limpopo DoE/Term 1 2025 NSC Please turn over