PRIVATE TUTORING
(NOTES)
MR SB.
MOKOENA
076 377 6747
075 263 2773
mokoenaselby2@gmail.com
GRADE 10 – 12 ELECTRIC CIRCUITS
SYMBOLS
POTENTIAL
Symbolised by V, measured by
Measure of energy, per unit of
DIFFERENCE
a Voltmeter using the units of
charge, transferred between
Volts (V)
two points in a circuit.
Symbolised by I, measured by a
The rate at which charged
Ammeter using the units of
particles, like electrons, flow
Amperes (A)
through an electrical circuit.
ELECTROMOTIVE
Symbolised by (Emf) measured
Electromotive force is an
FORCE (E)
in Volts. The maximum energy
energy transfer to an electric
per charge.
circuit per unit of electric
ELECTRIC CURRENT
charge, measured in volts.
OTHER EXPLANATIONS
• Potential difference – the work done in moving a charge from a point of low potential
to a point of high potential in an electric field.
• Electric current – the number of charge passing a point in a second.
• Resistance – the ability of a conductor to impede the movement of charge given by
the ratio of the potential difference across a conductor and the current passing through
it. Resistance is measured in ohms (β¦)
• Ohm’s Law – the current through a conductor between two points is directly
proportional to the potential difference across the two points, and, inversely,
proportional to the resistance of the conductor, provided the temperature remains
constant.
• Internal resistance – the extent to which an energy source, like a battery, impedes the
flow of charge within itself.
The potential difference in a circuit is denoted by the letter V. It is defined as the
energy needed to move a charge from one point to another in an electric field. It is
measured in volts (V). Electric current is the movement of charge. The letter, I , is used
as a symbol for electric current. It is defined as the number of charge passing appoint in
a unit time.
OHM’S LAW
The electric current through a conductor
between two points is directly
πΉ=
π½
π°
proportional to the voltage/potential
difference & inversely proportional to
resistance across the two points.
SERIES CIRCUIT
PARALLEL CIRCUIT
RESISTORS IN SERIES
RESISTORS IN SERIES
πΉπ» = πΉπ + πΉπ + πΉπ
(total effective resistance, add all the
resistors)
CURRENT IN SERIES
π°π» = π°π = π°π = π°π
(The current across is the same)
π
π
π −π
+
+ ]
πΉπ πΉπ πΉπ
(total effective resistance, add all the
πΉπ» = [
resistors in fraction inverse form)
CURRENT IN SERIES
π°π» = π°π + π°π + π°π
(The current is divided or shared
POTENTAL DIFFERENCE
π½π» = π½π + π½π + π½π
(Potential Difference is shared across
each resistor from the total)
NB: Series is also called
“Potential/Voltage Divider”
across is the resistors in equivalence to
the ratio)
POTENTAL DIFFERENCE
π½π» = π½π = π½π = π½π
(Potential Difference is the same
across all resistors)
NB: Parallel is also called
“Potential/Voltage Divider”
FORMULAS
πππ = πΌ(π
+ π)
π = ππΌ
π = πΌ2 π
π=
π2
πΌ = π‘ππ‘ππ πππππ‘πππ ππ’πππππ‘
π
= π‘ππ‘ππ ππ₯π‘πππππ πππ ππ π‘ππππ
π = πππ‘πππππ πππ ππ π‘ππππ
NB: If they did not provide
π = πππ€ππ
πΌ = πππππ‘πππ ππ’πππππ‘
π = πππ‘πππ‘πππ ππππππππππ
π
= πππ ππ π‘ππππ
Power is the amount of energy
π = πΆβππππ
πΌ = πππππ‘πππ ππ’πππππ‘
βπ‘ = πβππππ ππ π‘πππ
Electric charge (symbol q,
π
π = πΌβπ‘
internal resistance, or they say it
is negligible - Use zero (0).
transferred or converted per unit
time.
sometimes Q) is a physical
property of matter that causes it
to experience a force when placed
in an electromagnetic field.
π = πΌ2 π
βπ‘
π = π€πππ ππππ
πΌ = πππππ‘πππ ππ’πππππ‘
π
= πππ ππ π‘ππππ
βπ‘ = πβππππ ππ π‘πππ
Work- refers to the energy
transferred when a charge moves
through an electric field
Practice
1. A battery with an emf of 20 V and an internal resistance of 1β¦ is connected
to three resistors as shown below.
Calculate:
a) The current in the 8β¦ resistor ……………………………………………………….. (6)
b) Potential difference across the 5β¦ resistor ……………………………………. (4)
c) Total power supplied by the battery ………………………………………………. (3)
2. Study the circuit below and answer the questions
With Switch S closed the current passing through the 8β¦ is 0,5A
a) State Ohm’s law in Words …………………………………………………………………………….. (2)
b) Calculate the reading on Ammeter π¨π ………………………………………………….......... (4)
c) If device R delivers power of 12 w, calculate reading on Ammeter π¨π ........ (5)
d) Calculate the reading on the voltmeter when switch S is closed. …………….... (3)
MOKOENA SB
076 377 6747 / 065 263 2773
mokoenaselby2@gmail.com