m co o. yr ez s. rd rlo co lle ct ed by w w w .p a pe 4PM1 REVISION GUIDE Pearson Edexcel IGCSE Further Pure Mathematics Surds 1. √π π₯ √π = √ππ 2. √π ÷ √π = √ π π 3. √a / √b and √a - √b are conjugate surds. The product of conjugate surds is a rational number. m Indices o. co 1. Am x an = a m + n 2. am / an = am – n 6. π = n√a n ez s. rd ππ m n rlo 1 π π yr 3. (am)n = amn 4. a0 = 1 1 5. a –n = m w .p a pe 7. π π = √a = ( √a) ct w by ed 1. log a + log b = logab π 2. log a – log b = log w Logarithms π co lle 3. a log x y = log x y a 4. log a a = 1 5. logaπ₯ log ππ₯ = log ππ 6. loga1 = 0 1 7. log a b = log π a Binomial theorem co lle ct ed by w w w .p a pe rlo rd s. ez yr o. co m 1. (x + y)n = xn + (nc1 * xn-1 * y)+ (nc2 * xn-2 * y2n)+ ( nc3 xn-3 y3 ) + ( nc4 xn-4 y4 ) ……………………… 2. (r+1)th term = ( ncr xn-r yr ) Quadratic Equation Nature of roots ax2 + bx + c = 0 w .p a pe rlo rd s. ez yr o. co m 1. If b2 – 4ac > 0, roots are real & different / real and distinct and the curve y = ax2 + bx + c will cut the x axis at two real and distinct points lle ct ed by w w 2. If b2 – 4ac < 0, roots are not real/ imaginary / complex and the curve y = ax2 + bx + c will lie entirely above the x axis if a > 0 and entirely below the x axis if a < 0. co # ez yr o. co m 3. If b2 – 4ac = 0, roots are real and equal / repeated / coincident and the curve y = ax2 + bx + c touches the x-axis. rlo rd s. 4. If b2 – 4ac ≥ 0, roots are real. pe Solving Quadratic Inequality by w w w If ππ₯2 + ππ₯ + π > 0, range of values of π₯: π₯ < πΌ, π₯ > π½ If ππ₯2 + ππ₯ + π ≥ 0, range of values of π₯: π₯ ≤ πΌ, π₯ ≥ π½ If ππ₯2 + ππ₯ + π < 0, range of values of π₯: πΌ < π₯ < π½ If ππ₯2 + ππ₯ + π ≤ 0, range of values of π₯: πΌ ≤ π₯ ≤ π½ ed 1. 2. 3. 4. .p a When α and β (α<β) are two roots of ππ₯2 + ππ₯ + π = 0 (a>0) and lle ct α, β co 1. If α and β are two roots of ππ₯2 + ππ₯ + π = 0, π a. πΌ + π½ = − b. πΌπ½ = π π π 2. If two roots of an unknown equation is given and you want to find the equation, follow the following steps: a. Find the sum of the roots. b. Find the product of the root. c. Use the following formula, π₯2 − (π π’π ππ ππππ‘π ) × π₯ + πππππ’ππ‘ ππ ππππ‘π = 0 d. Simplify the equation if needed. 3. ∝2+ π½2 = (πΌ + π½)2 − 2πΌπ½ 4. (πΌ − π½)2 = (πΌ + π½)2 − 4πΌπ½ 5. πΌ3 + π½3 = (πΌ + π½)3 − 3πΌπ½(πΌ + π½) 6. πΌ3 − π½3 = (πΌ − π½)3 + 3πΌπ½(πΌ − π½) ed ct lle co by yr ez s. rd rlo pe .p a w w w m co o. 7. (πΌ + π½)3 = πΌ3 + π½3 + 3πΌπ½(πΌ + π½) Set, Relation and Function co lle ct ed by w w w .p a pe rlo rd s. ez yr o. co m 1. A set is any well-defined collection, list or class of objects. It may be given by either listing its members or defining its properties clearly. 2. A relation is a set of ordered pairs. 3. A function is a relation in which every elements in the domain has a unique image in the range. 4. The range of a function f is the set of values f(x) for the given domain. 5. Two functions f and g can be combined to produce composite functions fg or gf such that fg(x) = f(g(x)) and gf(x) = g(f(x)). In general, fg and gf are different functions. 6. The absolute value of x, written as |x|, is defined as x if x > 0 |x| = 0 if x = 0 -x if x < 0 Circular Measure 1. ∏ radian = 1800 2. For a sector of a circle enclosed by two radii that subtend an angle of θ radians at the centre, the arc length s is given by s=rθ and the area of the sector A is given by 1 A = π2 θ 2 co lle ct ed by w w w .p a pe rlo rd s. ez yr o. co m where r is the radius of the circle. co lle ct ed by w w w .p a pe rlo rd s. ez yr o. co m Trigonometry πππ 1. Sin θ = βπ¦π ππj 2. Cos θ = βπ¦π πππ 3. Tan θ = ππj 1 4. Sec x = cos π₯ 1 5. Cosec x = sin π₯ 1 6. Cot x = tan π₯ cos π₯ 7. Cot x = sin π₯ 8. Sin2 + cos2 x = 1 9. sec2 x - tan2 x =1 10. cosec2 - cot2 x = 1 11. Sec2 x = 1 + tan2 x 12. Sin(A + B) = sin A cos B + cos A sin B 13. Cos(A+B) = cos A cos B – sin A sin B tan π΄ + tan π΅ 14. Tan (A+B) = 1 − tan π΄ tan π΅ 15. Sin 2A = 2 sin A cos A 16. Cos 2A = cos2 A – sin2 A = 1 -2sin2 A = 2 cos2 A -1 2 tan π΄ 17. Tan 2A = 1−tan2 π΄ sin π΄ co lle ct ed by w w w .p a pe rlo rd s. ez yr o. co m 18. Tan A = cos π΄ Arithmetic Progression (A.P) 1. Nth term = a + (n-1)d π 2. Sn = {2π + (π − 1)π 2 co yr ez s. ,r<1 # -1 < r < 1 or |r| < 1. The series is convergent. It has sum to infinity. .p a π rd 1−π ,r>1 rlo 3. Sn = π−1 π (1−ππ) pe 2. Sn = o. 1. Nth term = arn-1 π (ππ−1) m Geometric Progression (G.P) w 1. Sα = 1−π co lle ct ed by w w Otherwise the series is divergent. It has does not have sum to infinity. Co – ordinate Geometry 1. The distance between two points A(x1 , y1) and B(x2 , y2)π¦is √{(π₯2 − π₯1) + (π¦2 − π¦1)} 2−π¦1 2. The gradient of the line joining A(x y ) and B(x y ) is 1, 1 2, 2 π₯2−π₯1 3. The coordinates of the mid-point of the line joining A(x1 , y1) and B(x2 , y2) are π¦ +π¦ π₯1 + π₯2 ) , ( 1 2) . 2 2 ( yr ez s. π+π pe rlo π= (π × π₯1) + (π × π₯2) π+π (π × π¦1) + (π × π¦2) rd π= o. co m 4. Finding coordinates when a point divides a line internally. co lle ct ed by w w w .p a 5. The equation of the straight line having a gradient m and passing through the point (x1, y2) is given by : y – y1 = m (x – x1). 6. Two lines are parallel if their gradients are equal. 7. Two lines are perpendicular to each other if the product of their gradients is -1. Differentiation 1. For a curve π¦ = π(π₯) represents the gradient of the tangent to the curve at any point π₯. ππ¦ 2. If π¦ = ππ₯π, then = πππ₯π−1, where π and n are constants. 3. π (π’ + π£) = ππ₯ ππ’ ππ₯ ππ£ + ππ₯ ππ₯ 4. If π¦ is a function of π’, and π’ us a function of π₯, then 5. If y, π’ and v are functions of π₯ and π¦ = π’π£, then ππ¦ ππ¦ = ππ₯ =π’ ππ₯ ππ¦ × ππ’ ππ’ ππ£ ππ₯ ππ’ ππ₯ ππ₯ +π£ ππ£ π£ππ’− π’ π’ ππ₯ (quotient rule). ππ₯ o. yr ez (cos π₯) = − sin π₯ (tan π₯) = sec2 π₯ s. 9. ππ₯ π (sin π₯) = cos π₯ rd 8. π ππ₯ π 15. 16. 17. 18. ππ₯ π ππ₯ π ππ₯ π ππ₯ π ππ₯ pe .p a w w w (π sin ππ₯) = ππ cos ππ₯ by ππ₯ π (tanπ π₯) = π tanπ−1 π₯ (sec2 π₯) (π cos ππ₯) = −ππ sin ππ₯ ed 14. ππ₯ π (cosπ π₯) = π cosπ−1 π₯ (− sin π₯) (π tan ππ₯) = ππ sec2 ππ₯ ct 13. ππ₯ π (sinπ π₯) = π sinπ−1 π₯ (πππ π₯) [sin(ππ₯ + π)] = π cos(ππ₯ + π) lle 12. ππ₯ π co 11. π rlo Other formulae 10. co The following are true only when π₯ is in radians: 7. (product rule). m ππ¦ 6. If π¦, π’ and π£ are functions of π₯ and π¦ = , then = ππ₯ π£2 ππ₯ π£ (chain rule). [cos(ππ₯ + π)] = −π sin(ππ₯ + π) [tan(ππ₯ + π)] = π sec2(ππ₯ + π) Application of Differentiation 19. Stationary points or turning points of a function π¦ = π(π₯) occur when 20. The second derivative ( (a) If π2π¦ ππ₯2 π2π¦ π 2π¦ ππ₯ 2 ππ¦ ππ₯ = 0. ) determines the nature of the stationery points: is negative, the stationery point is a maximum point. (b) If ππ₯2 is positive, the stationary point is a minimum point. π2π¦ (c) If ππ₯2 is zero, the nature of the stationery point depends on how the value of ππ¦ ππ₯ changes near the stationary point: ππ¦ (i) if the sign ππ₯ does not change before and after the turning point, the point is a point of inflexion. ππ¦ (ii) if the value of ππ₯ changes from positive to negative after the turning point, the point is a maximum point. (iii) if the value of ππ¦ changes from negative to positive after the turning point, the point is a ππ₯ co m minimum point. 21. To sketch a curve, note (i) the points where π₯ = 0 or π¦ = 0 (ii) the nature and position of the stationary points (iii) the direction of the curve as π₯ and π¦ approach infinity. (iv) the interval on which the gradient is positive or negative. yr o. Further Applications of Differentiation ez 22. If π¦ = π(π₯) and πΏπ₯ and πΏπ¦ are small increments in π₯ and π¦ respectively, then πΏπ¦ = ππ¦ × πΏπ₯ ππ₯ π2π by ππ‘ and acceleration π is given by ππ‘ or ππ‘2. rd ππ£ rlo ππ s. 23. If the displacement of a body is given by π = π(π‘), where π‘ is the time, then velocity v is given .p a pe 24. When a body is instantaneously at rest, its velocity is zero. ππ¦ 25. If a curve is given by π¦ = π(π₯), then the gradient of the tangent to the curve is given and the 1 w gradient of the normal is − ππ¦ . co lle ct ed by w w ππ₯ ππ₯ Integration 1. J ππ₯π ππ₯ = ππ₯π+1 π+1 2. J (ππ₯ + π)πππ₯ = 3. 4. 5. 6. +π π ≠ −1 (ππ₯+π)^(π+1) (π+1)π +π J cos π₯ ππ₯ = sin π₯ + π J sin π₯ ππ₯ = −πππ π₯ + π J sec2 π₯ ππ₯ = tan π₯ + π 1 J cos ππ₯ ππ₯ = sin ππ₯ + π π 1 7. J sin ππ₯ ππ₯ = − cos ππ₯ + π 1 9. J cos(ππ₯ + π) ππ₯ = π m π π tan ππ₯ + π co 1 sin(ππ₯ + π) + π o. 8. J sec2 ππ₯ ππ₯ = 1 π ez π 1 tan(ππ₯ + π) + π s. 11. J sec2(ππ₯ + π) ππ₯ = yr 10. J sin(ππ₯ + π) ππ₯ = − cos(ππ₯ + π) + π rd 12. The area bounded by the curve π¦ = π(π₯), the π₯-axis and the lines π₯ = π and π₯ = π is given by π lle ct ed by w w w .p a pe rlo ∫π π¦ ππ₯. π ∫π π₯ ππ¦. co 13. The area bounded by the curve π₯ = π(π¦), the π¦-axis and the lines π¦ = π and π¦ = π is given by π 14. Area between π(π₯) and π(π₯) = ∫π |π(π₯) − π(π₯)| ππ₯ 15. When the area bounded by π¦ = π(π₯), the π₯-axis and the lines π₯ = π and π₯ = π is rotated π through 360o about the π₯-axis, the volume of solid of revolution is given by π ∫π π¦2 ππ₯. 16. When the area bounded by π¦ = π(π₯), the π¦-axis and the lines π¦ = π and π¦ = π is rotated π through 360o about the π¦-axis, the volume of solid of revolution is given by π ∫π π₯2 ππ¦. co lle ct ed by w w w .p a pe rlo rd s. ez yr o. co m 17. If the velocity v of a particle is given as a function of time t, i.e. π£ = π(π‘), then ∫ π(π‘) ππ‘ will give the expression for the distance covered. 18. If the acceleration α of a particle is given as function of time t, i.e. α=f(t), then ∫ π(π‘) ππ‘ will give the expression for the velocity. Vector 1. A vector quantity possesses both magnitude and direction. The vector −→ has a 0π΄ magnitude or modulus |−→| and its direction is from O to A. 0π΄ 2. If a fixed point O is taken as a origin, the vector −→ is known as the position vector of A 0π΄ m π΄π΅ πQ s. 6. ez yr o. 5. co 3. 4. with references to O. Two vectors are equal if they have the same magnitude and direction. Vector addition: If two vectors acting at a point are represented both in magnitude and direction by the adjacent sides of a parallelogram, then their sum is represented both in magnitude and direction by the diagonal of the parallelogram through the point. a = b β |a| = |b| and a is parallel to b. ha = kb β |ha| =|hb| and a is parallel to b. or, h = k = 0 if a is not parallel to b. If −→ = ha + kb and −→ = ma + nb, where h, k, m and n are constants, and a is not parallel πQ rlo π΄π΅ rd to b, then −→ = −→ → β = m and k = n. .p a pe 7. If the position vectors of A and B relative to an origin O are a and b respectively, the (π+π) position vector of the mid point (M) of AB is −→= π = . 0π co lle ct ed by w w w 8. The scalar product of two vectors a and b is given by a-b = |a||b| cos θ where θ is the angle between the two vectors. 9. Commutative law: a x b = b x a 10. Distributive law: a(b+c) = a x b + a x c 11. If a = x1i + y1j and b = x2i + y2j, then a x b = x1x2 + y1y2 2 Binomial Expansion 1. π! = π(π − 1)(π − 2)(π − 3) … • eg: 4! = 4 * 3 * 2 * 1 = 24 π! 2. (π−2)! = π(π−1)(π−2) = π(π − 1) (π−2) 3. ππ1 = π 4. ππ2 = 5. ππ3 = 2! π(π−1)(π−2)(π−3) 3! (π + π₯)π = ππ + ππ 1 * ππ−1 * π₯ + ππ 2 * ππ−2 * π₯2 + ππ 3 * ππ−3 * π₯3 + … m 6. π(π−1) 2! yr 1 2 ez {4(1 + )} s. π₯2 1 1 β’ = 42 * (1 + π₯2 2 4 1 π₯2 2 β’ = 2 (1 + ) lle ct ed by w w w 4 co rd 4 ) rlo (4 + π₯2 )2 = pe 1 8. 3! [In above formula the value of ‘a’ must be ‘1’ ] .p a • o. co • [Note: Above formula cannot be used when ‘n’ is negative or in fraction] π(π−1) 2 π(π−1)(π−2) 3 7. (π + π₯)π = 1 + ππ₯ + π₯ + π₯ + … Graph Sketching π¦ = −π₯ π¦=π₯+1 π¦ = −π₯ + 1 co π¦ = π₯2 + 1 lle ct ed by w w w .p a pe rlo rd s. ez yr o. co m π¦=π₯ π¦ = π₯2 - 1 π¦ = (π₯ + 1)2 m π¦ = π₯2 by w w w .p a pe rlo rd s. ez yr o. co π¦ = (π₯ − 1)2 co lle ct ed π = π π₯ ; π¦ = π−π₯; π¦ = − π−π₯; π¦ = − ππ₯ π = ππ₯ + 1 π¦ = − π₯3 by w w w .p a pe rlo rd s. ez yr o. π¦ = π₯3 co m π¦ = ππ₯ - 1 co lle ct ed π¦ = π₯3 + 1 π¦ = π₯3 - 1 π¦ = −π₯3 − 1 π = (π₯ + 1)3 π = (π₯ - 1)3 co lle ct π¦ = (π₯ + 1)(π₯ + 4)(π₯ − 2) ed by w w w .p a pe rlo rd s. ez yr o. co m π¦ = −π₯3 + 1 π¦ = (π₯ − 1)(π₯ − 3)(−π₯ + 2) ed ct lle co by yr ez s. rd rlo pe .p a w w w m co o.