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BJT Circuit Analysis: Homework Assignment

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Pann Su
Homework : BJT
Khine
B6642259
ot 12V
10
.
= Re
14
loki
·
C :
i ha
=
Vout
W
VBB-Pe ·
&
-
"CE sat
O
=
IV
.
,
=
=
↑
0
=
BE sat
.
6V
,
B
=
50
VBB =?
Vce
=
12
=
FcRe
In
=>
12-s
=
e
12-001
=
B
=
E
at
.
9 mA
=
E
:
KVL
11
ku
↑
=
Apply
=
D:
11
=
gm
30
Ep
VBB-10hR (1)
:.
.
VBB
.
VBE sat
=
=
o
,
10 h (0 238 m) +
=
.
=
"BB
0 238 mA
=
=
2
2
.
.
38 + 0
98V
.
6
0
.
6
10
.
16 .
1
:
=
50 +
5h(Ip + 1) + Vce
V
cf + 54 Ec
Va + 5kIc
50
=
Vcz + 10k ]c
Yc2 + 10/2
If
If
50
=
-
-
=
0
C
5k(Ip
+
-
BB
54(20MA)
=
I,
.
Vg
=
Fc
=
0
=c
0
=>
=
Ve
=
49
.
=
4 994153 A
.
9V
I
=
"Ea
4998
:
=
B
4.19x
=
↑
49 9
=
-
Ec
VE
T
At the intersection point ,
(b)
c
[c
5kIp-5hIc
50
=
5hIc
+
IC
=
,
F
=
419x
20 M
3 mA
=
8V
20MA
-
cogos
=
20
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