Solve the following systems Using (I) Row reduced Echelon Form (II) Jauss-Jordan Elimination and (III) by determining the inverse of the matrix of coefficients and then using matrix multiplication. For the matrices π΄π΄ and π΅π΅ below, verify (check) the following properties. Take ππ = 3 I- Determinants: i- π΄π΄π΄π΄ = π΄π΄ π΅π΅ ii- π΄π΄π‘π‘ = π΄π΄ iii- πππ΄π΄3×3 = ππ 3 π΄π΄ iv- πΌπΌ = 1 v- 0 = 0 vi- π΄π΄ + π΅π΅ ≠ π΄π΄ + π΅π΅ i- (π΄π΄π΄π΄)−1 = π΅π΅−1 π΄π΄−1 1 −1 −1 ii-(ππππ) = π΄π΄ ππ v-(π΄π΄ + π΅π΅)−1 ≠ π΄π΄−1 + π΅π΅ −1 iii- (π΄π΄−1 )−1 = π΄π΄ II- Inversions: π‘π‘ )−1 = (π΄π΄−1 )π‘π‘ iv- (π΄π΄ vi- π΄π΄−1 1 = π΄π΄ , π΄π΄ ≠ 0 For π§π§1 and π§π§2 below, verify (check) the following properties. π§π§1 = −ππ + 3, III- Complex Numbers: π§π§2 = 4 − 2ππ π§π§1 +π§π§1 i- π π π π (π§π§1 ) = 2 π§π§1 −π§π§1 ii- πΌπΌπΌπΌ(π§π§1 ) = 2ππ vii- π§π§οΏ½1 = π§π§1 viii- π§π§οΏ½1 = π§π§1 iv- π§π§1 οΏ½ π§π§2 = π§π§οΏ½1 οΏ½ π§π§οΏ½2 v- π§π§1 π§π§2 π§π§1 = , (π§π§2 ≠ 0) π§π§2 iii- π§π§1 − π§π§2 = π§π§οΏ½1 − π§π§οΏ½2 vi- π§π§1 π§π§2 π§π§1 = , (π§π§2 ≠ 0) π§π§2 ix- Sketch (Draw) π§π§1 , π§π§2 , π§π§οΏ½1 and π§π§οΏ½2 on the Cartesian or Argand plane.