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AP Calculus AB Exam Review - Practice Problems

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AP Calculus AB
Name ________________________________________________
Semester Exam Review
1.
1
Let 𝑓𝑓 −5 = 0, 𝑓𝑓 ′ −5 = −10, 𝑔𝑔 −5 = 1, and 𝑔𝑔′ −5 = − 5
𝑓𝑓 π‘₯π‘₯
(A)
(C)
2.
(A)
(C)
3.
(A)
(C)
4.
(A)
(C)
5.
(A)
(C)
Find β„Ž′ (−5) if β„Ž π‘₯π‘₯ = 𝑔𝑔 π‘₯π‘₯
10
−10
(B)
(D)
−2
50
Find an equation of the tangent line to the graph of 𝑓𝑓 πœƒπœƒ = tan πœƒπœƒ at the point
(B)
4π‘₯π‘₯ − 4𝑦𝑦 = πœ‹πœ‹ − 4
(D)
Find the limit.
π‘₯π‘₯ 2 + 11π‘₯π‘₯ + 28
lim
π‘₯π‘₯→−4
π‘₯π‘₯ + 4
(B)
4 2 π‘₯π‘₯ − 4𝑦𝑦 = πœ‹πœ‹ − 4
0
3
π‘₯π‘₯ + β„Ž 3 − π‘₯π‘₯ 3
equals
lim
β„Ž→0
β„Ž
3π‘₯π‘₯ 2
0
π‘₯π‘₯ 3 − 8
lim
equals
π‘₯π‘₯→2 π‘₯π‘₯ − 2
0
0
16
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(D)
(B)
(D)
(B)
(D)
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4π‘₯π‘₯ − 2𝑦𝑦 = πœ‹πœ‹ − 2
𝑦𝑦 = π‘₯π‘₯
0
Does not exist
π‘₯π‘₯ 3
3π‘₯π‘₯ 2 β„Ž
4
12
πœ‹πœ‹
,1
4
6.
lim +
π‘₯π‘₯→−7
(A)
(C)
7.
(A)
(C)
8.
(A)
(C)
9.
(A)
(C)
10.
(A)
(C)
−1
π‘₯π‘₯ + 7
equals
π‘₯π‘₯ + 7
(B)
(D)
0
Find the limit.
π‘₯π‘₯ + 9 − 3
lim
π‘₯π‘₯→0
π‘₯π‘₯
(B)
∞
(D)
1
3π‘₯π‘₯ + sin π‘₯π‘₯
π‘₯π‘₯→0
π‘₯π‘₯
1
∞
0
1
6
lim
(B)
4
(D)
1
3π‘₯π‘₯ 2 + 10π‘₯π‘₯ − 8
equals
π‘₯π‘₯→−4 π‘₯π‘₯ 2 + π‘₯π‘₯ − 12
3
0
lim
−
2
14
3
(B)
(D)
14
3
∞
π‘₯π‘₯−3
At which value(s) of π‘₯π‘₯ is 𝑓𝑓 π‘₯π‘₯ = π‘₯π‘₯ 2−2π‘₯π‘₯ −8 discontinuous?
3
−4, −2, 3, 4
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(B)
(D)
−2, 3,4
−2, 4
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11.
(A)
(C)
12.
(A)
(B)
(C)
(D)
13.
Determine the value of 𝑐𝑐 so that 𝑓𝑓 π‘₯π‘₯ is continuous on the entire real number line when
π‘₯π‘₯ − 2, ; π‘₯π‘₯ ≤ 5
𝑓𝑓 π‘₯π‘₯ = οΏ½
𝑐𝑐𝑐𝑐 − 3 ; π‘₯π‘₯ > 5
(B)
0
5
6
(D)
(C)
14.
(A)
(C)
1
Which of the following statements is not true of 𝑓𝑓 π‘₯π‘₯ = π‘₯π‘₯ 2 − 49 ?
𝑓𝑓 is continuous on the interval (−∞, −7]
𝑓𝑓 is continuous on the interval [−7, 7]
𝑓𝑓 is continuous at π‘₯π‘₯ = 14
𝑓𝑓 is continuous on the interval [7, ∞)
Find the limit: lim
π‘₯π‘₯→1
(A)
6
5
5
π‘₯π‘₯ − 1 2
0
1
(B)
(D)
6π‘₯π‘₯ 2 − 13π‘₯π‘₯ − 5
equals
π‘₯π‘₯→−∞ 4π‘₯π‘₯ 2 + 19π‘₯π‘₯ − 63
−∞
∞
lim
0
3
2
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(B)
(D)
2
3
5
63
Flamingo Math.com
15.
(A)
(C)
16.
(A)
(C)
17.
(A)
(C)
18.
(A)
(C)
19.
(A)
(C)
π‘₯π‘₯−2
Find all vertical asymptotes of the graph of 𝑓𝑓 π‘₯π‘₯ = π‘₯π‘₯ 2−3π‘₯π‘₯ −10
(B)
π‘₯π‘₯ = −2, π‘₯π‘₯ = 5
(D)
𝑦𝑦 = 0
𝑦𝑦 = 1
π‘₯π‘₯ = 2, 𝑦𝑦 = 5
If 𝑓𝑓 2 = 3 and 𝑓𝑓 ′ 2 = −1, find an equation of the tangent line when π‘₯π‘₯ = 2.
(B)
𝑦𝑦 = 2(π‘₯π‘₯ + 1) + 3
𝑦𝑦 = −1 π‘₯π‘₯ − 2 + 3
𝑦𝑦 = 3 π‘₯π‘₯ + 1 + 2
(D)
𝑦𝑦 = 2 π‘₯π‘₯ − 2 − 1
(B)
12π‘₯π‘₯ 3 − 18π‘₯π‘₯ 2 + 3
Find 𝑓𝑓 ′ π‘₯π‘₯ : 𝑓𝑓 π‘₯π‘₯ = 3π‘₯π‘₯ 4 − 6π‘₯π‘₯ 3 + 3π‘₯π‘₯ − 2
3π‘₯π‘₯ 3 − 6π‘₯π‘₯ 2 + 3
3π‘₯π‘₯ 4 − 6π‘₯π‘₯ 3 + 3π‘₯π‘₯
Find 𝑓𝑓 ′ π‘₯π‘₯ : 𝑓𝑓 π‘₯π‘₯ =
(D)
12π‘₯π‘₯ 3 − 18π‘₯π‘₯ 2 + 3π‘₯π‘₯ − 2
π‘₯π‘₯ 2 − 4π‘₯π‘₯
π‘₯π‘₯
3π‘₯π‘₯ − 4
2π‘₯π‘₯ 1/2
2π‘₯π‘₯ − 4
1
2 π‘₯π‘₯
(B)
2π‘₯π‘₯ − 4
π‘₯π‘₯
(D)
π‘₯π‘₯ 3/2 − 4π‘₯π‘₯1/2
(B)
−5 sin π‘₯π‘₯ − 3 cos π‘₯π‘₯ + 4
𝑑𝑑𝑑𝑑
Find 𝑑𝑑𝑑𝑑 : 𝑦𝑦 = 5 cos π‘₯π‘₯ − 3 sin π‘₯π‘₯ + 4π‘₯π‘₯
5 sin π‘₯π‘₯ − 3 cos π‘₯π‘₯ + 4
−5 sin π‘₯π‘₯ − 3 cos π‘₯π‘₯
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(D)
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−5 cos π‘₯π‘₯ + 3 sin π‘₯π‘₯
20.
(A)
(C)
21.
(A)
(C)
22.
(A)
(C)
23.
(A)
Find an equation for the tangent line to the graph of 𝑓𝑓 π‘₯π‘₯ = 2π‘₯π‘₯ 2 − 2π‘₯π‘₯ + 3 at the point
where π‘₯π‘₯ = 1.
(B)
𝑦𝑦 = 2π‘₯π‘₯ − 2
𝑦𝑦 = 4π‘₯π‘₯ 2 − 6π‘₯π‘₯ + 2
(D)
(B)
252 ft/sec
(D)
264 ft/sec
24 ft/sec
240 ft/sec
The velocity function for an object is given by 𝑠𝑠 ′ 𝑑𝑑 = −15𝑑𝑑 2 + 8, where 𝑠𝑠 is measured in feet and
𝑑𝑑 is measured in seconds. What is the instantaneous velocity when 𝑑𝑑 = 3?
(B)
−15 ft/sec
(D)
−37 ft/sec
−135 ft/sec
−127 ft/sec
An object is thrown straight down from a 225-foot-tall building with an initial velocity of
46 feet per second. The position function for the movement described is
𝑠𝑠 𝑑𝑑 = −16𝑑𝑑 2 − 46𝑑𝑑 + 225
𝑠𝑠 𝑑𝑑 = 16𝑑𝑑 2 − 46𝑑𝑑 + 225
24.
Differentiate: 𝑦𝑦 = π‘₯π‘₯ 2
(C)
𝑦𝑦 = 2π‘₯π‘₯ + 1
The position function for an object is given by 𝑠𝑠 𝑑𝑑 = 6𝑑𝑑 2 + 240 𝑑𝑑, where 𝑠𝑠 is measured in feet
and 𝑑𝑑 is measured in seconds. Find the velocity of the object when 𝑑𝑑 = 2 seconds.
(C)
(A)
𝑦𝑦 = 4π‘₯π‘₯ 2 − 6π‘₯π‘₯ + 5
(B)
(D)
𝑠𝑠 𝑑𝑑 = −9.8𝑑𝑑 2 + 46𝑑𝑑 + 225
𝑠𝑠 𝑑𝑑 = 9.8𝑑𝑑 2 − 46𝑑𝑑 + 225
5π‘₯π‘₯
+1
5
2π‘₯π‘₯
5
1 + π‘₯π‘₯ 2
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(B)
(D)
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5(1 − π‘₯π‘₯ 2 )
1 + π‘₯π‘₯ 2 2
5π‘₯π‘₯ 2 − 5
1 + π‘₯π‘₯ 2 3
25.
(A)
(C)
26.
(A)
(C)
27.
(A)
(C)
28.
(A)
(C)
Differentiate: 𝑓𝑓 π‘₯π‘₯ = π‘₯π‘₯ 3 + 3 cot π‘₯π‘₯
3π‘₯π‘₯ 2 + 3 cot π‘₯π‘₯
3π‘₯π‘₯ 2 − 3 csc 2 π‘₯π‘₯
(D)
3π‘₯π‘₯ 2 + 3 csc 2 π‘₯π‘₯
3π‘₯π‘₯ − 3 csc 2 π‘₯π‘₯
Find 𝑓𝑓 ′ (π‘₯π‘₯) for 𝑓𝑓 π‘₯π‘₯ = 2π‘₯π‘₯ 2 + 5 7
7 4π‘₯π‘₯ 6
Find the derivative: 𝑓𝑓 π‘₯π‘₯ = sec
4π‘₯π‘₯ 7
(B)
7 2π‘₯π‘₯ 2 + 5 6
(D)
28π‘₯π‘₯ 2π‘₯π‘₯ 2 + 5 6
(B)
sec
π‘₯π‘₯
2
1
π‘₯π‘₯
π‘₯π‘₯
sec
tan
2
2
2
1
π‘₯π‘₯
π‘₯π‘₯
tan
− sec
2
2
2
(D)
−
π‘₯π‘₯
π‘₯π‘₯
tan
2
2
1
π‘₯π‘₯
csc 2
2
2
Differentiate: 𝑦𝑦 = sin2 𝑑𝑑 − cos2 𝑑𝑑
2 sin(2𝑑𝑑)
−4 sin 𝑑𝑑 cos 𝑑𝑑
29.
Find 𝑓𝑓 ′′ (π‘₯π‘₯) if 𝑓𝑓 π‘₯π‘₯ = sin π‘₯π‘₯ 2
(A)
2(cos π‘₯π‘₯ 2 − 2π‘₯π‘₯ 2 sin π‘₯π‘₯ 2 )
(C)
(B)
2π‘₯π‘₯ cos π‘₯π‘₯ 2
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(B)
(D)
(B)
(D)
4 sin 𝑑𝑑 cos 𝑑𝑑
1
−4π‘₯π‘₯ sin π‘₯π‘₯ 2
2(cos π‘₯π‘₯ 2 − π‘₯π‘₯ sin π‘₯π‘₯ 2 )
Flamingo Math.com
30.
(A)
(C)
31.
(A)
(C)
32.
(A)
(C)
33.
(A)
(C)
34.
(A)
(C)
𝑑𝑑𝑑𝑑
Find 𝑑𝑑𝑑𝑑 for 2π‘₯π‘₯ 2 + π‘₯π‘₯π‘₯π‘₯ + 3𝑦𝑦 2 = 0
−4π‘₯π‘₯ − 𝑦𝑦
6𝑦𝑦
4π‘₯π‘₯ + 𝑦𝑦 + 6𝑦𝑦
(B)
(D)
− 4π‘₯π‘₯ + 𝑦𝑦
π‘₯π‘₯ + 6𝑦𝑦
4π‘₯π‘₯ + 6𝑦𝑦
−π‘₯π‘₯
𝑑𝑑𝑑𝑑
Find 𝑑𝑑𝑑𝑑, then evaluate the derivative at the point 0, 2 : 5x 2 − 3xy + y = 2.
−2
0
(B)
(D)
−
6
5
4
The volume of a cube is changing at the rate of 18 cubic centimeters per second. How fast is the
edge of the cube expanding when each edge is 3 centimeters?
2
cm/sec
3
3
9 cm/sec
(B)
(D)
3 cm/sec
3
18 cm/sec
A spherical balloon is inflated at the rate of 16 cubic feet per minute. How fast is the radius of the
balloon changing at the instant the radius is 2 feet?
4πœ‹πœ‹ ft/min
1
ft/min
πœ‹πœ‹
(B)
(D)
32πœ‹πœ‹
ft/min
3
2πœ‹πœ‹ ft/min
The absolute maximum of 𝑓𝑓 π‘₯π‘₯ = 5 − 6π‘₯π‘₯ 2 − 2π‘₯π‘₯ 3 on [−3, 1] equals
5
1
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(B)
(D)
Flamingo Math.com
−3
3
35.
(A)
(C)
36.
(A)
(C)
37.
(A)
(C)
38.
(A)
(C)
39.
(A)
(C)
𝑓𝑓 π‘₯π‘₯ = 6π‘₯π‘₯ 2 − 9π‘₯π‘₯ + 5 has a local minimum at
π‘₯π‘₯ =
π‘₯π‘₯ =
1
2
3
4
(B)
(D)
π‘₯π‘₯ = 1
π‘₯π‘₯ =
3
2
The set of all critical numbers of 𝑓𝑓 π‘₯π‘₯ = π‘₯π‘₯ 2 − π‘₯π‘₯ − 2 1/3 equals
{−1, 2}
{0, 2}
(B)
(D)
{0, −1}
1
−1, 2 , 2
The set of all numbers 𝑐𝑐 in (0, 4) satisfying the conclusion of the Mean Value Theorem for the
function 𝑓𝑓 π‘₯π‘₯ = 3π‘₯π‘₯ 2 − 12π‘₯π‘₯ + 11 on the interval [0, 4] equals
{2}
{1, 3}
(B)
(D)
{1}
{1, 2}
The set of all numbers 𝑐𝑐 in (0, 4) satisfying the conclusion of Rolle’s Theorem for the function
𝑓𝑓 π‘₯π‘₯ = 3π‘₯π‘₯ 2 − 12π‘₯π‘₯ + 11 on the interval [0, 4] equals
{1}
{3}
(B)
(D)
{2}
{1, 2}
Find all the points of inflection of the graph of the function 𝑓𝑓 π‘₯π‘₯ = π‘₯π‘₯ 3 − 3π‘₯π‘₯ 2 − π‘₯π‘₯ + 7
(0,0) and (1, 4)
(1, 4)
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(B)
(D)
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(0,0)
(2, 1)
40.
Find all the interval(s) on which the graph of the function 𝑓𝑓 π‘₯π‘₯ = π‘₯π‘₯ 4 − 4π‘₯π‘₯ 3 + 2 is concave
downward.
(A)
(C)
41.
(A)
(D)
(0, 2) and (2, ∞)
(−∞, 0) and (0, 2)
(0, 2)
Let 𝑓𝑓 be a continuous function whose derivative is given by 𝑓𝑓 ′ π‘₯π‘₯
= οΏ½1
For what values of π‘₯π‘₯ does the graph of 𝑓𝑓 have a point of inflection?
(B)
0 only
(C)
42.
(B)
(−∞, 0) and (2, ∞)
(D)
4 only
0 and 2 only
Let 𝑓𝑓 be a function that is differentiable on the open interval (π‘Žπ‘Ž, 𝑏𝑏). If 𝑓𝑓 has a relative minimum
at 𝑐𝑐, 𝑓𝑓 𝑐𝑐 and π‘Žπ‘Ž < 𝑐𝑐 < 𝑏𝑏, which of the following must be true?
II. 𝑓𝑓 ′′ 𝑐𝑐 must exist
III. If 𝑓𝑓 ′′ (𝑐𝑐) exists, the 𝑓𝑓 ′′ 𝑐𝑐 > 0
(A)
(C)
(B)
I only
(C)
(A)
π‘₯π‘₯ + 3 ; π‘₯π‘₯ > 2
2 only
I. 𝑓𝑓 ′ 𝑐𝑐 = 0
43.
2
π‘₯π‘₯ 2 ; π‘₯π‘₯ ≤ 2
(D)
III only
4
οΏ½
2
𝑑𝑑
3𝑑𝑑 2 + 2𝑑𝑑 − 1
𝑑𝑑𝑑𝑑
12
46
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II only
I and II only
𝑑𝑑𝑑𝑑 =
(B)
(D)
Flamingo Math.com
40
55
44.
(A)
(C)
45.
(A)
(C)
46.
4
If ∫0 π‘₯π‘₯ 2 − 6π‘₯π‘₯ + 9 𝑑𝑑𝑑𝑑 is approximated by 4 inscribed rectangles of equal width on the x-axis,
then the approximation is
(B)
4
5
(D)
6
10
π‘₯π‘₯ 2
𝑑𝑑
οΏ½ [cos(𝑑𝑑 3 )] 𝑑𝑑𝑑𝑑 =
𝑑𝑑𝑑𝑑
0
− sin π‘₯π‘₯ 6
cos π‘₯π‘₯ 6
(B)
2π‘₯π‘₯ cos(π‘₯π‘₯ 3 )
2π‘₯π‘₯ cos(π‘₯π‘₯ 6 )
(D)
Choose the correct statement, given that
5
5
0
2
οΏ½ 𝑓𝑓 π‘₯π‘₯ 𝑑𝑑𝑑𝑑 = 7 and οΏ½ 𝑓𝑓 π‘₯π‘₯ 𝑑𝑑𝑑𝑑 = −1
(A)
(C)
2
οΏ½ 𝑓𝑓 π‘₯π‘₯ 𝑑𝑑𝑑𝑑 = 6
(B)
οΏ½ 𝑓𝑓 π‘₯π‘₯ 𝑑𝑑𝑑𝑑 = 8
(D)
0
0
(A)
(C)
οΏ½ 𝑓𝑓 π‘₯π‘₯ 𝑑𝑑𝑑𝑑 = −1
5
2
οΏ½ 𝑓𝑓 π‘₯π‘₯ 𝑑𝑑𝑑𝑑 = 8
0
2
47.
2
Use the Fundamental Theorem of Calculus to evaluate the integral:
1
οΏ½ 1 − 2π‘₯π‘₯ 𝑑𝑑𝑑𝑑
−2
6
−6
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(B)
(D)
Flamingo Math.com
−2
2
48.
(A)
(C)
49.
(A)
(C)
50.
(A)
(C)
Evaluate the definite integral.
1
οΏ½(3 − 2π‘₯π‘₯) 𝑑𝑑𝑑𝑑
−2
−12
−3
Evaluate the integral:
π‘₯π‘₯ 4 − π‘₯π‘₯ 3
οΏ½
𝑑𝑑𝑑𝑑
π‘₯π‘₯ 2
2π‘₯π‘₯ − 1 + 𝐢𝐢
π‘₯π‘₯ 3
π‘₯π‘₯ 2
−
+ 𝐢𝐢
3
2
(B)
12
15
2
(D)
(B)
(D)
2π‘₯π‘₯ 3 − 3π‘₯π‘₯ 2 + 𝐢𝐢
3
20
4π‘₯π‘₯ 2 − 5π‘₯π‘₯ + 𝐢𝐢
Two equal rectangular lots are to be made by fencing in a rectangular lot and putting a fence
across the middle. If each lot is to contain 1875 square feet, what size lots require the minimum
amount of fence?
60 feet by 35 feet
50 feet by 50 feet
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(B)
(D)
Flamingo Math.com
50 feet by 37.5 feet
52 feet by 36 feet
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