ME 470 Final Project Analysis: Velocity Analysis
Due February 7, 2024
4 bar linkage
Chosen Values Table
Link Length
Link 1
d=8”
Link 2
a=5”
Link 3
b=8”
Link 4
c=6”
Input
rin = 5”
Output
rout = 3”
ω2
-50 rad/s
Drawing:
Determine 𝜔3 , 𝜔4 , 𝑎𝑛𝑑 𝑚𝐴 at all possible values of 𝜃2 .
Assume rin = a = 5” and rout = c/2 = 6/2 = 3”.
ω3
ω4
mA
𝑚𝐴 = |
𝜔3 =
𝑎𝜔2 sin(𝜃4 − 𝜃2 )
𝑏 sin(𝜃3 − 𝜃4 )
𝜔4 =
𝑎𝜔2 sin(𝜃2 − 𝜃3 )
𝑐 sin(𝜃4 − 𝜃3 )
𝜔𝑖𝑛 𝑟𝑖𝑛
𝑐 sin(𝜃4 − 𝜃3 ) 𝑟𝑖𝑛
|=|
(
)|
𝜔𝑜𝑢𝑡 𝑟𝑜𝑢𝑡
𝑎 sin(𝜃2 − 𝜃3 ) 𝑟𝑜𝑢𝑡
Only graph to a maximum
y-axis value of 20.
Crank Slider linkage
Chosen Value Table
Link 2 Link 3
Link Length a=1.4”
b=4”
Link 4
c=1”
rin
1.4”
2
5 rad/s
Determine 𝜔3 , 𝑑̇, 𝑎𝑛𝑑 𝑚𝐴 at all possible values of 𝜃2 .
𝑎𝜔2 cos 𝜃2
𝜔3 =
𝑏 cos 𝜃3
𝑑̇ = −𝑎𝜔2 sin 𝜃2 + 𝑏𝜔3 sin 𝜃3
𝜔𝑖𝑛 𝑟𝑖𝑛
|
𝑑̇
Only graph to a maximum
y-axis value of 20.
𝑚𝐴 = |
ME 470 Final Project Analysis: Velocity Analysis
Due February 7, 2024
4 bar linkage
Crank Slider linkage
Notice how omega 4 and mA are related.
When omega 4 is near zero, mA is very high.
When omega 4 is a higher value (either
positive or negative), mA is low. This is not
due to omega 2, but to changing transmission
angle values.
Notice how VB (Slider velocity) and mA are
related. When VB is near zero, mA is very
high. When VB is a higher value (either
positive or negative), mA is low. This is not
due to omega 2, but to changing transmission
angle values.