Bar Bending Schedule for Slabs: Learn One Way & Two Way Slabs Home Civil Engineering 23/01/25, 10:03 AM Bar Bending Schedule for Slabs Bar Bending Schedule for Slabs: One Way Slabs and Two Way Slabs Last Updated on Mar 1, 2023 Download As PDF The Bar Bending Schedule is critical in determining the quantities of reinforcement in a construction. It is recommended to understand the principles of Bar Bending schedule and how to adopt concrete cover for different components of a structure before determining the Bar bending schedule for slabs or steel reinforcement in slabs. It becomes very important in estimating the cost of the project as the cost of reinforcement in a construction project has a major part in determining the total cost. In this article, we will understand the Bar Bending Schedule for Slabs in detail. This article on Bar Bending Schedule for Slabs will help you understand the steps in calculation of bar bending schedule for one way and two way slabs at the site. It would surely increase your preparation for your upcoming SSC JE CE examination, GATE CE examination and RRB JE CE examination. Basic Shapes for Bar Bending Schedule The code of practice includes some fundamental shape codes for bar bending schedules. However, to minimise the misunderstanding and extra labour that comes with extracting the shape from a standard document, it is now typical to sketch the bending shape on the bar bending schedule document. Use the following relation to determine the length of reinforcement bars in a structural drawing: Length of bar= Effective length + Width of support - Concrete cover - Tolerances Crack AAI ATC https://testbook.com/civil-engineering/bar-bending-schedule-for-floor-slab?stay=1 Page 1 of 13 Bar Bending Schedule for Slabs: Learn One Way & Two Way Slabs 23/01/25, 10:03 AM Crack AAI ATC with India’s Best Teachers & Coachings Get 12 Months SuperCoaching @ just ₹11999 ₹5249 Your Total Savings ₹6750 Purchase Now Want to know more about this Super Coaching ? Explore SuperCoaching Now Bar Bending Schedule for Slabs A bar bending schedule is created for floor slabs to demonstrate the quantity, size, and shape of rebars required during construction. This document is critical for pre-contract and post-contract operations. Exams SuperCoaching Test Series Skill Academy The information required to produce the bar bending schedule for the floor slab is taken from the detailed reinforcement drawings. The quantity of steel required is crucial in preparing the bar bending schedule (in kilograms or tonnes). The unit mass and size of the rebars determine this. Pass GetMore Started Slabs are primarily divided into two categories: One-way slabs and Two-way slabs. In a one-way slab, distribution bars are provided in a longer direction (straight bars), while the main bars are provided in a shorter direction (cranked bars). In contrast, the main bars (cranked bars) in the two-way slabs are provided in both directions. The twoway slabs are typically used when the slab's length and width are greater than 4 metres. NEW All-in-One Pass For All Your Exams Get Pass Pro https://testbook.com/civil-engineering/bar-bending-schedule-for-floor-slab?stay=1 Page 2 of 13 Bar Bending Schedule for Slabs: Learn One Way & Two Way Slabs 23/01/25, 10:03 AM Exams Also Includes All Test Series Practice Prev. Year Paper Pro Live Tests Unlimited Test Re-Attempts Bar Bending Schedule for One Way Slabs For understanding the bar bending schedule for one way slabs we can consider an example:- ⾁testbook SectionA-A IL4 8mm- Sign Up Now & Daily Live Classes Lx=5000mm| |L/4| Ly=2000mml 12mml Ld| OneWaySlab-- 3000+ Study Quizzes With Tests Material & of a One Detailed Fig.1: Example WayAnalytics Slab PDF + More Benefits Get Free Access Now Ly /Lx = Longer Span/Shorter Span = 5000/2000 = 2.5 > 2 So it is a one way slab. Observations from the above example:One way slab length = 5000 mm. One way slab width = 2000 mm. Main bar = 12 mm @ 150 mm c/c. Distribution bar = 8 mm @ 150 mm c/c. Clear Cover at the top and bottom = 25 mm. Thickness of the slab = 150 mm. Development Length = 40d, where d is the diameter of the bar. Step 1: To Calculate the Number of Bars Number of bars= (Length of Slab/Spacing) + 1 Number of main bars = (Lx /Spacing) + 1 https://testbook.com/civil-engineering/bar-bending-schedule-for-floor-slab?stay=1 Page 3 of 13 Bar Bending Schedule for Slabs: Learn One Way & Two Way Slabs 23/01/25, 10:03 AM Number of main bars = (Lx /Spacing) + 1 = (5000/150) + 1 = 34 Number of distribution bars = (Ly /Spacing) + 1 = (2000/150) + 1 = 14 Step 2: Calculation of cutting length of main bars and distribution bars Cutting length of main bar = Clear span of slab + (2 × Development Length) + Inclined Length - Bend Length Clear span of the slab = 2000 mm Development length = 40d Inclined length = 0.42d 1d is for every 45° bend Where, d = diameter of bar. D = Thickness of slab – Both side clear cover (both top and bottom) – diameter of the bar 150 - (25+25) - 12 = 88 mm Length of main bar = Ly + 2Ld + (1 × 0.42d) − (1d × 4) = 2000 + (2 × 40 × 12) + (2 × 0.42 × 88) − (1 × 12 × 4) = 2838 mm = 2.838 m. 2 2 Weight of main bars = [ d ×L ] × 34 = [ 12 ×2.838 ] × 34 = 86 kg. 162 162 Length of Distribution Bars = Clear span of slab + 2 × Development Length = Lx + 2Ld = 5000 + (2 × 40 × 8) = 5640 mm = 5.64 m 2 2 ×L ×5.64 Weight of distribution bars = [ d162 ] × 14 = [ 8 162 ] × 14 = 31 kg. Step 3: Calculation of Top Bar (Extra Bar) Now, we have to calculate the top bar (extra bar) that is provided at the top of the critical length (L/4) area. Number of top bars = [(Ly /4)/(Spacing) + 1] × 2 = [(2000/4)/(150) + 1] × 2 = 9 Length of extra bar = Ly − (2 × Ly /4) + 2 × 100 [Here 2 × 100 is for https://testbook.com/civil-engineering/bar-bending-schedule-for-floor-slab?stay=1 Page 4 of 13 Bar Bending Schedule for Slabs: Learn One Way & Two Way Slabs 23/01/25, 10:03 AM Length of extra bar = Ly − (2 × Ly /4) + 2 × 100 [Here 2 × 100 is for both side lapping of 100 mm for extra bar] = 2000 – (2 × 2000/4) +200 = 1200 mm = 1.2 m d 2 ×L 82 ×1.2 Weight of extra bar = [ 162 ] × 9 = [ 162 ] × 9 = 4.266 kg Now, total weight of steel required for the bar bending schedule of one way slab = Weight of the main bars + Weight of distribution bars + Weight of extra bars = 86 kg + 31 kg + 4.266 kg = 121.266 kg Bar Bending Schedule for Two Way Slabs For better understanding of the bar bending schedule for two slabs, we can consider below given example:- Fig.2: Example of a Two Way Slab Ly /Lx = Longer Span/Shorter Span = 5000/3000 = 1.66 < 2 So it is a one way slab. Observations from the above example:Length of the longer span = 5000 mm length of the shorter span = 3000 mm Main bar = 12 mm @ 150 mm c/c Distribution bar = 8 mm @ 150 mm c/c Clear cover (Top and bottom) = 25 mm https://testbook.com/civil-engineering/bar-bending-schedule-for-floor-slab?stay=1 Page 5 of 13 Bar Bending Schedule for Slabs: Learn One Way & Two Way Slabs 23/01/25, 10:03 AM Thickness of slab = 200 mm Development length = 40d Where d is the diameter of the bar. For Section A-A Step 1: Calculation of number of main bars and distribution bars that are required in slab Number of bars = Length of slab/spacing + 1 Total number of bars = Ly /150 + 1 = 4000/150 +1 = 27 Total number of main bars = 14 Total number of distribution bars = 13 Step 2: Calculation of cutting length ( for main bars and distribution bars) Cutting length of main bar = Clear span of slab + (2 × Development Length) + Inclined Length - Bend Length Clear span of the two way slab = 5000 mm Development length = 40d Inclined length = 0.42d 1d is for every 45° bend Where, d is the diameter of the bar. D = Thickness of the slab - Both side clear cover (top & bottom) diameter of the bar 200 - (25+25) - 12 = 138 mm. Cutting length of main bar = Lx + 2Ld + (2 × 0.42d) − (1d × 4) = 5000 + (2 × 40 × 12) + (2 × 0.42 × 138) − (1 × 12 × 4) = 6028 mm = 6.02 m. For 14 bars, the total length of the main bars becomes = 6.02 × 14 = 84.28 m. Weight of main bars = [ 2 d 2 ×L ×84.28 ] = [ 12 162 ] = 75 kg. 162 Cutting length of Distribution Bars = Clear span of slab + 2 × Development Length = Lx + 2Ld https://testbook.com/civil-engineering/bar-bending-schedule-for-floor-slab?stay=1 Page 6 of 13 Bar Bending Schedule for Slabs: Learn One Way & Two Way Slabs 23/01/25, 10:03 AM = 5000 + (2 × 40 × 8) = 5640 mm = 5.64 m For 13 bars, the total length of the distribution bars becomes = 5.64 × 13 = 73.32 m. Weight of distribution bars = [ 2 d 2 ×L ] = [ 8 ×73.32 ] = 29 kg. 162 162 Step 3: Calculation of Top Bar (Extra Bar) Now, we have to calculate the top bar (extra bar) that is provided at the top of the critical length (L/4) area. Number of top bars = [(Ly /4)/(Spacing) + 1] × 2 = [(4000/4)/(150) + 1] × 2 = 16 Length of extra bar = Lx − (2 × Lx /4) + 2 × 100 [Here 2 × 100 is for both side lapping of 100 mm for extra bar] = 5000 – (2 × 5000/4) +200 = 2700 mm = 2.7 m Total length of extra bar = 2.7 × 16 = 43.8 m. d 2 ×L Weight of extra bar = [ 162 ] = [ 82 ×43.2 ] = 17 kg 162 Total weight of steel required for Section A-A = Weight of the main bars + Weight of distribution bars + Weight of extra bars = 75 kg + 29 kg + 17 kg = 121 kg For Section B-B Step 1: Calculation of number of main bars and distribution bars that are required in slab Number of bars = Length of slab/spacing + 1 Total number of bars = Lx /150 + 1 = 5000/150 +1 = 35 Total number of main bars = 18 Total number of distribution bars = 17 Step 2: Calculation of cutting length ( for main bars and distribution bars) Cutting length of main bar = Clear span of slab + (2 × Development Length) + Inclined Length - Bend Length Clear span of the two way slab = 4000 mm Development length = 40d Inclined length = 0.42d https://testbook.com/civil-engineering/bar-bending-schedule-for-floor-slab?stay=1 Page 7 of 13 Bar Bending Schedule for Slabs: Learn One Way & Two Way Slabs 23/01/25, 10:03 AM 1d is for every 45° bend Where d is the diameter of the bar. D = Thickness of the slab - Both side clear cover (top & bottom) diameter of the bar 200 - (25+25) - 12 = 138 mm. Cutting length of main bar = Ly + 2Ld + (2 × 0.42d) − (1d × 4) = 4000 + (2 × 40 × 12) + (2 × 0.42 × 138) − (1 × 12 × 4) = 5028 mm = 5.02 m. For 18 bars, the total length of the main bars becomes = 5.02 × 18 = 90.36 m. Weight of main bars = [ d 2 ×L 122 ×90.36 ] = [ ] = 80 kg. 162 162 Cutting length of Distribution Bars = Clear span of slab + 2 × Development Length = Ly + 2Ld = 4000 + (2 × 40 × 8) = 4640 mm = 4.64 m For 17 bars, the total length of the distribution bars becomes = 4.64 × 17 = 78.88 m. d 2 ×L Weight of distribution bars = [ 162 ] = [ 82 ×78.88 ] = 31 kg. 162 Step 3: Calculation of Top Bar (Extra Bar) Now, we have to calculate the top bar (extra bar) that is provided at the top of the critical length (L/4) area. Number of top bars = [(Lx /4)/(Spacing) + 1] × 2 = [(5000/4)/(150) + 1] × 2 = 18 Length of extra bar = Ly − (2 × Ly /4) + 2 × 100 [Here 2 × 100 is for both side lapping of 100 mm for extra bar] = 4000 – (2 × 4000/4) +200 = 2200 mm = 2.2 m Total length of extra bar = 2.2 × 18 = 39.6 m. 2 2 Weight of extra bar = [ d ×L ] = [ 8 ×39.6 ] = 16 kg 162 162 Total weight of steel required for Section B-B = Weight of the main bars + Weight of distribution bars + Weight of extra bars = 80 kg + 31 kg + 16 kg = 127 kg Total weight of steel required for the Two Way Slab = Total weight of https://testbook.com/civil-engineering/bar-bending-schedule-for-floor-slab?stay=1 Page 8 of 13 Bar Bending Schedule for Slabs: Learn One Way & Two Way Slabs 23/01/25, 10:03 AM Total weight of steel required for the Two Way Slab = Total weight of steel for Section A-A + Total weight of steel for Section B-B = 121 kg + 127 kg = 248 kg. Difference Between One-Way Slabs and Two-Way Slabs The differences between the one way slabs and two way slabs are as follows:One-way Slab Two-way Slab Ly /Lx ≥ 2 Ly /Lx < 2 Loads are carried along a single direction. Loads are carried along both the directions. Slab bends only in one direction along its shorter span Slab bends in both directions. A shorter span of main bars is offered to support the bending moment. The main bars are offered in both directions to support the bending moment. One way slabs are supported on both sides by beams. Two way slabs are supported by beams on all the sides. Practical examples of one way slabs are chajjas. Slabs constructed in both small and high rise buildings are examples of two way slabs. This was all about the Bar Bending Schedule for slabs explained with an example each for one way slab and two way slab. This article is important for determining the amount of steel for floor slabs at the construction site. It will enhance your preparation for various Civil Engineering recruitment exams. You can avail the AE/JE Civil Coaching and GATE CE Coaching to crack https://testbook.com/civil-engineering/bar-bending-schedule-for-floor-slab?stay=1 Page 9 of 13 Bar Bending Schedule for Slabs: Learn One Way & Two Way Slabs 23/01/25, 10:03 AM You can avail the AE/JE Civil Coaching and GATE CE Coaching to crack various technical recruitments for Civil Engineers. You can also check out the Testbook app for accessing comprehensive study material, affordable online courses, SSC JE Civil previous years papers, AE/JE Civil Mock Tests and free SSC JE Civil Mock Tests to amplify your preparation More Articles for Civil Engineering Soil Exploration Quality Control of Concrete Laminates Roof Trusses Plate Girders Soil Compaction Varnishes Valuation Of Building Sheet Pile Walls Design of Columns Bar Bending Schedule for Slabs FAQs IS Standard for bar bending schedule? What is the rate for 1 tonne bar bending? What is RCC slab code? What is the formula of bending strength? What is the maximum spacing of bars in slab? https://testbook.com/civil-engineering/bar-bending-schedule-for-floor-slab?stay=1 Page 10 of 13 Bar Bending Schedule for Slabs: Learn One Way & Two Way Slabs 23/01/25, 10:03 AM What is the maximum spacing of bars in slab? 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