Math 244: MATLAB Assignment 1
Name:
RUID:
Date:
clear;
close all;
clc;
1.
% Define variables and computations here
x = 6;
y = 5;
sol1 = x*y
sol1 =
30
sol2 = (x^2) + (y^2)
sol2 =
61
sol3 = x/(3*y)
sol3 =
0.4000
2.
% Display commands here
disp(['The number x is ' num2str(x) '.']);
The number x is 6.
disp(['The number y is ' num2str(y) '.'])
The number y is 5.
disp(['The number xy is ' num2str(x*y) '.'])
The number xy is 30.
3.
% Generates a random number between 1 and 100
randNum = randi(100, 1)
randNum =
98
1
% Write the if statements here
if mod(randNum,2) == 0
disp(['The number ' num2str(randNum) ' is even.'])
else
disp(['The number ' num2str(randNum) ' is odd.'])
end
The number 98 is even.
4.
% Define a vector that will contain the Fibonacci numbers
fib = zeros(1,20);
% Initial conditions
fib(1,1) = 1;
fib(1,2) = 1;
% Write the for loop here
for i=3:length(fib)
fib(1,i) = fib(1,i-2) + fib(1,i-1);
end
% Display the vector
disp(fib)
1
1
2
3
5
5.
xVals = linspace(0, 3, 1000);
% Define the functions f and g
f = sin(xVals);
g = xVals - 1;
% Plot the graph of f
hold on
plot(xVals, f, 'blue')
hold off
2
8
13
21
34
figure();
% Plot the graph of g
hold on
plot(xVals, g, 'red')
hold off
figure();
% Plot the graph of f and g together
hold on
plot(xVals, f, 'blue')
3
plot(xVals, g, 'red')
hold off
figure();
6.
% Define function and use quiver244 here.
f = @(t,y)(t-(y.^2));
quiver244(f,0,5,-3,10,'blue')
4
figure();
disp('With all three starting points (y(0)=3, y(0)=0, & y(0)=8), y approaches the
same value, however, they take different paths. For example, y(0)=3 & y(0)=8 take
l/u-shaped paths, whereas y(0)=0 takes an s-shaped path.')
With all three starting points (y(0)=3, y(0)=0, & y(0)=8), y approaches the same value, however, they take different
7.
% Code for sample plots here
f = @(t,y)(t-(y.^2));
hold on
samplePlots244(f,0,5,-3,10,0,3,'blue')
samplePlots244(f,0,5,-3,10,0,0,'red')
samplePlots244(f,0,5,-3,10,0,8,'green')
hold off
5
disp('Yes, these graphs do support my thoughts in the previous part. Both the green
and blue graphs have a sort of l/u-shaped curve, whereas the red graph is closer to
being s-shaped')
Yes, these graphs do support my thoughts in the previous part. Both the green and blue graphs have a sort of l/u-sha
6