Linear circuit analysis
“Lab: 1 report”
Submitted by:
NC Muhammad Soban
NC Warsaan Naveed
Captain Asim Javed
GC Muhammad Saifullah
Course:
BEIS-4
“Lab 1”
Task: Find the total current (Itotal) of the circuit:
Solution:

Given that:
V=5V
R1=10kΩ
R2=1kΩ
R3=1kΩ

To find total current, we need to calculate equivalent resistance of this circuit and then
use Ohm’s law:
V=IR => I=V/R

As R2 and R3 connected in parallel so its equivalent resistance is:
1/R23 = 1/R2 + 1/R3
1/R23 = 1/1 + 1/1
1/R23 = 1 + 1
1/R23 = 2
R23 = 1/2
R23 = 0.5kΩ

Now R1 and R23 are in series so its equivalent resistance is:
Req = R1 + R23
Req = 10 + 0.5
Req = 10.5kΩ

Using Ohm’s law i.e. V=IR:
Itotal = V/Req
Itotal = 5/10.5
Itotal = 0.476 mA
The total current is: 0.476 mA
Picture of circuit:
Measurement of current:
1.
2.
3.
4.
5.
Current is always measured in series with the circuit components.
Disconnect the circuit at the point where you need to measure the current.
It creates an open loop at the measurement location.
Connect the ammeter in series at the break point.
Connect the positive terminal of the ammeter to the load, and the negative terminal of
the ammeter to the negative terminal of the battery.
6. Turn on the power supply to restore the current flow through the circuit.
7. Observe the current reading displayed on the ammeter. This value represents the
current flowing through the circuit at the measurement point.
Verification using proteus: