Ch1 Homework A (Principles Based Problems) 15 questions Course Info Instructor Name Student Name Question 1 of 15 A eukaryotic cell contains many compartmentalized organelles that organize its interior. Each organelle is a discrete unit enclosed by a membrane and has a specialized function. Other structures, such as ribosomes or the cytoskeleton, are not enclosed by a membrane. The generalized animal cell shown is colored so that the features can easily be distinguished from each other. Label each structure with its function. Choose the best answer for each structure. Answer Bank storage of genetic information protein transport out of cell protein synthesis cellular respiration; ATP synthesis membrane synthesis; protein modification © Macmillan Learning Question 2 of 15 How does the surface‑to‑volume ratio affect the rate of cellular metabolism? Metabolic rate is limited by surface area. The rate of metabolism is maximized when volume is maximized. Larger surface‑to‑volume ratios equate to slower metabolic rates. The rate of metabolism does not depend on the surface‑to‑volume ratio. The spherical bacterium Neisseria gonorrhoeae is responsible for the disease gonorrhea. Calculate the surface‑to‑volume ratio, given that the diameter of the bacterium is is 4 3 𝜋𝑟 . 3 0.5 𝜇m. Note that the surface area of a sphere is 4𝜋𝑟2 and the volume of a sphere 𝑆 : 𝑉 µm−1 How many times greater is the surface‑to‑volume ratio of Neisseria gonorrhoeae compared to that of a globular amoeba, a large eukaryotic cell with a diameter of 150 𝜇m? times greater: © Macmillan Learning Question 3 of 15 Complete the table, which illustrates the energy sources and carbon sources for various metabolic strategies. Then, complete the sentences. Answer Bank chemoautotroph photoheterotroph chemoheterotroph bear photoautotroph dandelion must obtain at least some carbon from organic materials. include organisms that can use sunlight to generate energy. can fix atmospheric carbon dioxide. © Macmillan Learning Question 4 of 15 Which statements identify differences between proteomics and genomics? Genomics starts at the DNA level and makes inferences about the product, whereas proteomics begins with the product. Microarrays are used for the analysis of DNA in genomics, but cannot be utilized in proteomics. Proteomics involves the study of genes, whereas genomics involves the study of proteins. Mass spectrometry is a technique that is used in proteomics, but not in genomics. Genomics is used to identify the entire human genome, whereas proteomics is only used to identify specific proteins in organisms. © Macmillan Learning Question 5 of 15 Assume you have a crude lysate sample that you obtained from mechanically homogenizing E. coli cells. You centrifuged the supernatant from the sample at a medium speed supernatant at high speed (80,000 𝑔) for 1 h. (20,000 𝑔) for 20 min, collected the supernatant, and then centrifuged the What procedure should you follow to isolate the ribosomes from this sample? Layer the from the high‑speed centrifugation over medium. Centrifuge at a very high speed (150,000 g) for 3 h and collect the © Macmillan Learning Question 6 of 15 Ibuprofen is an over‑the‑counter drug that blocks a class of prostaglandins that cause inflammation and pain. Ibuprofen is available as a racemic mixture of (R)‑ibuprofen and (S)‑ibuprofen. In living organisms, an isomerase catalyzes the chiral inversion of the (R)‑enantiomer to the (S)‑enantiomer. The reverse reaction does not occur at an appreciable rate. In the figure, sites a, b, and c represent binding sites in the isomerase enzyme that converts the (R)‑enantiomer to the (S)‑enantiomer. All three sites recognize the corresponding functional groups of the (R)‑enantiomer of ibuprofen. However, sites a and c do not recognize the corresponding functional groups of the (S)‑enantiomer of ibuprofen. Place the substituent groups to represent the (R)‑enantiomer and the (S)‑enantiomer. Answer Bank CH3 The (S)‑enantiomer of ibuprofen is H COO − 100 times more efficacious for pain relief than is the (R)‑enantiomer. Drug companies sometimes make enantiomerically pure versions of drugs that were previously sold as racemic mixes, such as esomeprazole (Nexium) and escitalopram (Lexapro). Since (S)‑ibuprofen is more effective, why do drug companies not sell enantiomerically pure (S)‑ibuprofen? The presence of the (R)‑enantiomer prevents chiral inversion, and inactivation, of the (S)‑enantiomer. The conversion molecule binds the (S)‑enantiomer and keeps it out of circulation. It is unnecessary because an enzyme converts the less effective enantiomer to the effective enantiomer. It is unnecessary because both enantiomers relieve pain at equal levels in a racemic mixture. © Macmillan Learning Question 7 of 15 Three important biomolecules are depicted in their ionized forms at physiological pH. You may need to reference a table (https://sites.google.com/site/chempendix/amino-acids) of amino acid structures. Guanosine triphosphate (GTP) is an energy‑rich nucleotide that serves as a precursor to RNA. Methionine enkephalin is an endogenous compound in the human brain, sometimes called the brain's own opiate. Phosphatidylcholine is a component of many membranes. Classify the chemical consituents that are part of each molecule. Guanosine triphosphate (GTP) Methionine enkephalin Phosphatidylcholine Answer Bank glycerol one phosphate three phosphoryl groups palmitate guanine methionine choline α‑D‑ribose two glycines phenylalanine © Macmillan Learning Question 8 of 15 Researchers isolated an unknown substance, X, from rabbit muscle. They determined its structure from the following observations and experiments. (a) Qualitative analysis showed that X was composed entirely of C, H, and O. A weighed sample of X was completely oxidized, H2 O and CO2 produced were measured. This quantitative analysis revealed that X contained 40.00% C, 6.71% H, and 53.29% O by weight. and the (b) The molecular mass of X, as determined by mass spectrometry, was 90.00 atomic mass units (u). (c) Infrared spectroscopy showed that X contained one double bond. (d) X dissolved readily in water, and the solution demonstrated optical activity when tested in a polarimeter. (e) The aqueous solution of X is acidic. What is the empirical formula of X? What is the structure of X? © Macmillan Learning Question 9 of 15 Use the diagram which represents a spontaneous reaction to answer the questions. Is the reaction endothermic or exothermic? exothermic endothermic What is the activation energy of the reaction? activation energy: kJ/mol © Macmillan Learning Question 10 of 15 The diagram represents a spontaneous reaction. Use the diagram to answer the questions. Is the reaction endothermic or exothermic? endothermic exothermic What is the activation energy of the reaction? 𝐸a = kJ/mol © Macmillan Learning Question 11 of 15 Each beaker contains two types of particles, represented as different colors. Arrange the three beakers and their contents in order of increasing entropy. Greatest entropy Least entropy Answer Bank © Macmillan Learning Question 12 of 15 Which of the reactions are spontaneous (favorable)? C(s) + H2 O(l) ⟶ CO(g) + H2 (g) Δ𝐺 = 90.8 kJ/mol AgCl(s) ⟶ Ag+ (aq) + Cl− (aq) Δ𝐺 = 55.6 kJ/mol 2 H2 O(g) ⟶ 2 H2 (g) + O2 (g) Δ𝐺 = 457 kJ/mol 2 Mg(s) + O2 (g) ⟶ 2 MgO(s) Δ𝐺 = −1137 kJ/mol CH4 (g) + 2 O2 (g) ⟶ CO2 (g) + 2 H2 O(l) Δ𝐺 = −820 kJ/mol NH3 (g) + HCl(g) ⟶ NH4 Cl(s) Δ𝐺 = −91.1 kJ/mol © Macmillan Learning Question 13 of 15 For the reaction 2 NH3 (g) − ↽⇀ − 3 H2 (g) + N2 (g) the equilibrium concentrations were found to be [NH3 ] = 0.250 M, [H2 ] = 0.360 M, and [N2 ] = 0.800 M. What is the equilibrium constant for this reaction? 𝐾 eq = © Macmillan Learning Question 14 of 15 Suppose that the gene for a protein 500 amino acids in length undergoes a mutation. If the mutation causes the synthesis of a mutant protein in which just one of the 500 amino acids is incorrect, the protein may lose its biological function. How can a small change in a protein’s sequence inactivate the protein? The active site may base pair incorrectly with the complementary DNA strand. The catalytic site of the protein may be malformed, preventing complementary fit. RNA may not recognize the altered DNA sequence, and bases may pair incorrectly. It may alter the shape of the protein’s molecular chaperone, preventing proper protein folding. The resulting protein may fold incorrectly and may not attain its native conformation. © Macmillan Learning Question 15 of 15 Tardigrades, also called water bears or moss piglets, are small animals that can grow to about 0.5 mm in length. Terrestrial tardigrades typically live in the moist environments of mosses and lichens. Some of these species are capable of surviving extreme conditions. Some tardigrades can enter a reversible state called cryptobiosis, typically triggered by water loss, in which metabolism completely stops. In this state, various tardigrade species have withstood dehydration, extreme temperatures from −200 °C to +150 °C, pressures from 6000 atm to a vacuum, anoxic conditions, and the radiation of space. When conditions become hospitable, and when water is available, the animal becomes active again. Photo credit: Schokraie E, Warnken U, Hotz-Wagenblatt A, Grohme MA, Hengherr S, Förster F, et al. (2012) Comparative proteome analysis of Milnesium tardigradum in early embryonic state versus adults in active and anhydrobiotic state. PLoS ONE 7(9): e45682. https://doi.org/10.1371/journal.pone.0045682 (http://) Do tardigrades in an ametabolic state meet the definition of life? No, metabolism and energy use are prerequisites for life. No, entropy will increase without energy input from normal body function. Yes, biochemical mechanisms exist for restoring the normal state. Yes, an animal in a cryptobiotic state can still reproduce by spores. Yes, DNA replication and maintenance still takes place. © Macmillan Learning