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Acero Flexión en Zapata - Cálculo

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Datos
P = 640.0 kN
fy=420 Mpa
M = 80.0kN-m
f'c=21 Mpa
h = 40.0 cm
r = 7.5 cm
d=32.5 cm
kgf
CJadm
= 3. O -cm
-2
Elaborado por: lng. Honald Gabriel Soto: +505-7785-2230
Cálculo del vuelo de la zapata
1.80 m - 0.30 m
= 0.75 m
2
Cálculo de la excentricidad producto de la demanda
M
80.0 kN - m
e = -p = 640.0 kN = 0.125 m
Chequeo de la excentricidad
L 1.80 m
e < - = - - = 0.30 m
- 6
6
Ok!
Esfuerzos transmitidos al suelo
P
[
O'máx = - - - 1
Lx Ly
*
O'máx =
m]
kN
[
6 * 0.125
+ -6e] = - - 640.0
----- * 1 +---Lx
(1.80 m) * (1.80 m)
1.80 m
kgf
279.835 kPa = 2. 854--2
cm
P
[
6e]
640.0 kN
[
6 * 0.125
O'mín = Lx * Ly 1 - Lx = (1.80 m) * (1.80 m) * 1 1.80 m
m]
kgf
O'mín = 115.226 kPa = 1.175-2
cm
Chequeo del esfuerzo máximo
kgf
kgf
2.854 - 2 < 3.0 - 2
cm
cm
Ok!
Elaborado por: lng. Honald Gabriel Soto: +505-7785-2230
Cálculo de CTa y CTm
L-V
L
kgf
kgf
2.854 - 2 - 1.175 - 2
<Je =
max
mm (L - V) =
cm
cm (1.80 m - 0.75 m)
L
1.80 m
kgf
<Je= O. 979-cm 2
(J
,
-
(J
,
kgf
kgf
O"m = O"mín + <Je = 1.175-2 + 0.979-2
cm
cm
kgf
O"m
= 2. 154--2
cm
Elaborado por: lng. Honald Gabriel Soto: +505-7785-2230
Resultantes
1
F1 = 2 * V * ( CJ máx -
CJ m) * L
1
(
kgf
kgf)
F1 = 2 * 75 cm* 2.854 cm 2 - 2.154 cm 2 * 180 cm
F1 = 4,725.00 kgf
kgf
F2 = 75 cm* 2.154--2 * 180 cm
cm
F2 = 29,079.00 kgf
Elaborado por: lng. Honald Gabriel Soto: +505-7785-2230
Momento de diseño
Mu= F1 •
G•v) + G•v)
F2 •
Mu = 4,725.00 kgf •
(! •
75 cm) + 29,079.00 kgf •
G•
75 cm)
Mu = 1,326,712.50 kgf - cm
Mu = 130,106,051.381 N - mm
Mu
130,106,051.381 N - mm
0bd 2
0.90 * 1,800 mm* (325 mm) 2
Mu
(Z)bd 2 = O. 76 MPa
Elaborado por: lng. Honald Gabriel Soto: +505-7785-2230
Tabla B.8 /2 = 420 MPa·
p
Amn por
tem¡,eratura
y contracción
P m1n por
flexión
0.00 18
0.00 19
0.0020
0.002 1
0.0022
0.0023
0.0024
0.0025
0.0026
0.0027
0.0028
0.0029
0.0030
0.003 1
0.0032
0.0033
0.0034
0.0035
0.0036
0.0037
0.0038
J: = 2 1 MPa. nidades del I
k͡,
</Jbd 2
0.740
0.780
0.820
0.860
0.900
0.940
0.980
1. 0 19
1.059
1.098
1. 137
1.1 76
l. 2 16
1.255
1.293
1. 332
1. 37 1
1.409
1.448
1.486
l. 525
p
0.0048
0.0049
0.0050
0.005 1
0.0052
0.0053
0.0054
0.0055
0.0056
0.0057
0.0058
0.0059
0.0060
0.006 1
0.0062
0.0063
0.0064
0.0065
0.0066
0.0067
0.0068
k͡,
<J>bd 2
1.902
1.939
1.976
2.0 13
2.050
2.087
2. 124
2.16 1
2.197
2.233
2.270
2.306
2.342
2.378
2.4 14
2.450
2.486
2.52 1
2.557
2.592
2.628
p
0.0078
0.0079
0.0080
0.008 1
0.0082
0.0083
0.0084
0.0085
0.0086
0.0087
0.0088
0.0089
0.0090
0.009 1
0.0092
0.0093
0.0094
0.0095
0.0096
0.0097
0.0098
k͡,
<J>bd 2
2.975
3.0 10
3.044
3.078
3.11 2
3. 146
3.1 79
3.2 13
3.247
3.280
3.3 13
3.347
3.380
3.4 13
3.446
3.479
3.5 11
3.544
3.577
3.609
3.64 1
p
0.0 107
0.0108
0.0109
O.O! 10
O.O! 11
0.011 2
O.O! 13
0.011 4
0.0 11 5
O.O! 16
O.O! 17
0.0 11 8
0.011 9
0.0 120
0.0 12 1
0.0122
0.0123
0.0 124
0.0 125
0.0126
0.0127
k͡,
<J>bd 2
3.928
3.960
3.99 1
4.022
4.053
4.084
4.11 5
4.1 46
4 .177
4.207
4.238
4 .268
4.298
4 .328
4.359
4 .389
4 .4 18
4 .448
4.478
4.508
4.537
A 5 = pbd = 0.0033 * (180 cm)* (32.5 cm)= 19. 31 cm 2
19.31 cm 2 ➔ 165 cm
1.98 cm 2 ➔ S cm
165 cm* 1.98 cm 2
S=-------19.31 cm 2
S = 16.92 cm
Usar varillas de #5@ 16 cm
Elaborado por: lng. Honald Gabriel Soto: +505-7785-2230
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