PRIME REVIEW ONLINE MECHANICAL ENGINEERING REVIEW MATHEMATICS &BASIC ENGINEERING SCIENCES PRIME'S SUPPLEMENTARY ENHANCERS (ENGINEERING ECONOMICS 02) ENGINEERING ECONOMICS 02 Calculate the 5h year depreciation charge using a fixed percentage method of an asset costing P 1000 having a life expectancy of 5 years and an estimated salvage value of P 400. A. P990 C.F 80 PSEMODULE 10.2 (SOLUTION) A machine initially worth P 50,000 depreciates in value cach year by 20% of its value at the beginning of that year. Find its book value when it is 9 years old. A. P 8,388.61 C.P7.782.42 B. P 5.368.71 D. P6,710.88 B.P 78 Solution k1- Sole-on BV, =50,000(1 -0.2 d, Php 8045 SOk BV, = Php 6.710.89 Alternate Solution: Mode 36 |50% (1-0.2) Ans.D BV96,710.89 o Phplk 400 A machine has an initial cost of P 50,000 and a salvage value of P 10.000 after 10 years. What is the straight line method depreciation d, 4-5ý= 80.45 rate as a percentage of the initial cost? A. 7% C. 9% B.88% D. 10% Ans.C 6. Selutkon FC-SV L A certain copier machine cost P I50,000 with a trade-in value of P 15,000 after making 800,00 copies. Using thedeclining balanced method, what is the book value when the machine had made 300.000 copies? S0,000-10,000 Php 4000 10 FO d/FC 0.08 8% Ans B B. P62.531 BVFC(1 An worth P by 20% of its value at the beginning ofthat year. Comput its book value when it is 19 years old. A. P 850.67 C.P750.45 B. P 520.45 D. P 720.57 equipment initially k =1BV 5,000,2.878x10 (150,000) (1-2.8782 x 10) BVsPhp63,254.48 Aliemate Solution Mode36 50.000(1-0.2)" BV, =Php 720.57 150,000 Alternate Solution Mode 36 800 0015,00 300,000 63,254.48 50k Ans.D 150k(1-0.2) BV, =19 where: k =1- 50,000 depreciates in value each year Setote BV, =FC(1-k C. P 64.896 D. P 63,254 A. P 68,111 d4.000 FC 50,0X0 720.57 Determine the book value at the end of 4 years of a machine costing P 20.000 having a serviceable life of 8 years and a salvage value ofP Ans. D 2000 atthe end of that time, Use SYD method. see 4. 1-000.16745 d, PC(1-1)() d, 1,000(1-0.16745) (0.16745) Altemate Solution Calculator (Mode 36) BV = FC(1-k) D.P84 A. P 6800 A company bought an equipment for P 56,000. Other expen ses including installation amounted to P4,000. The equipment is expected B. P 7250 to have a life of 16 years with a salvage value of 10% ofthe original cost. Determine the book value at the end of 12 years by the straight Salut line method. wbere FC 20,000 DReverse Digits Sum of the digity BV FC-D C. P 20,500 D. P 19,200 A. P 19,500 B. P 18,530 Seleion: : BV. FC-D. > where:D. C. P 620 D. P 7000 D C-SV) SV 8+7+6+5 I+2+3+4+5+6+74R20,000-2,000) D= Php 13,000 L So thus BV 20,000-13,000= Php 7,000.00 12 (56k +4k)-0.1(56k+4k) BV = (Php 56k + Php 4k)- Ans.D 16 BV Php19,500 Alenate Solution Mode 32 0 56k+ 4k =60k 160.1(56k+4k) =6k 3. Calculate the depreciated value after 6 years of a P 10,000 machine having a useful lite of l10 years anda salvage value of 10 % of its originalcost at that time. Use straight-line depreciation. A. P 42000 C. P 4400 B. P 4500 D. P 4600 BV2 1 2 19,500 AnsA Solution. PRIME REVIEW ONLINE MECHANICAL ENGINEERING REVIEW MATHEMATICS &BASIC ENGINEERING SCIENCES PRIME'S SUPPLEMENTARY ENHANCERS (ENGINEERING ECONOMICS 02) D (FC-Sv) BV PC-D, D,10,000-0.1(10,000)] =Php 5,400 At Ist yr BV, = FC-D. D Reverse D1git-(FC -SV) Sum of the digits (9,000-1.000)= Php 1,454.55 2 BV. = FC-D. = 10,000-5,400=Php 4,600 Altemate Solution Mode 32 Then BV FC-D, 9,000-1,454.55 BVPhp7,545.45 Php 10k 1o(10000)0.1) = 1000 Ans.B BV, 6=Php 4,600 Ans D 9. where: D, = 14. An asset is purchased for P 500,000.00. The salvage value in 25 years A company purchased an asset for P 15,000 and plans to keep it for 20 years. If the salvage value is zeo at the end of the 20th year, determine the depreciation in the 4th year? Use SYD. A. P 1214 C.P 1087 B. P 1157 D. P 1206 is P 100,000.00. What is the total depreciation in the first three years using straight-line method? A. P 48,000 B. P 32.000 C.P 24.000 D. P 16,000 Sedit Seluken: d. Reverse Digl(FC SV) D,S00,oo0-100,000)=Php 48,000 Sumof the digits Ahemate Salution Mode 32 -(15,000-0) Php 1214.29 0 500,000 UJEFO 25100,000 Ans.A 10. D 0 - 3 ý = 48,000 issue of 3%. 15 year bond was sold ut 95%. Whatisthe AP1000.000 rate of interesi of this investment? A. 5% 15. A machine costs P 8,000 and an estimated life of 10 years with a salvagevalue of P 500. What is its book value after 8 years? Using C.4% D. 3% B. 2% Seletens iannual net profitL000.000)(0.03) 0.03158 total investment 0.95(1.000,000 Ans.A straight-line method. P 2500 3.158% B. P 2000 Ans. D D. P 4000 D, 10 8,000-500)=Php 6.000 BV, 8.000-6,000 2,000 11. An item is purchased for P 100.000, Annual cost is P 18,000.Using Alterntle Sotution Mode 32 8%interest rate what is the capitalized costfor perpetual service? C.P 532,000 A. P352,000 B. P 235,000 Seletion CcFC+ C. P 3000 D.P 325000 100,000+ 8000 10 500 BV, 8Php 2.000 Php 325,000 0.08 Ans. B Ans. D 12. A machine has an initial cost of P 50.000 and a salvage value of 10,000 after 10 years. What is the book value after 5 years using straight-line depreciation? A.P25,0000 C. P 35,000 D. P 30.000 B. P 15,500 Selutien BV, = FC-D, 16. The costs of producing a commodity consist of P 45.00 per unit for labor and material cost and P 15.00 per unit for other variable cost. The fixed costper nonth amounts to P 450,000. If the commodity is sokd at P 250.00 each, wbatis the break-even quantity? A. 2345 C. 2368 B. 2632 D. 2224 where:D, 50,000-10,000) D, = Php 20,000 BV, = 50,000-20,000= Php30,000 Alternate Solution Mode 32 2 Expenses Iocome 250x 45x I5x +450,000 x2.368.42 units Ans. 0 50,000 1010,000 BV, =5 = Php 30,000 17. An assel is purchased for P 9,000.00. Its estimated economic life is 10 years alter whichit will be sold forP 1,000.00. Find the depreciation Ans. D 13. An asset is purchased for P 9,000.00. Ius estimated life is 10 years after which it will be sold for P1,000.00. Find the book value during the first year if sum-of-years' digit (SYD) depreciution is used. A. P 8,000.00 C.P6.5(X.00 B. P 7.545.00 Seleo D. P 6,000.00 in the first three years using sum of years digit method. C. P 3,324.32 A. P 3,927.27 D. P 3,743.26 B. P 3,464.35 Sadeio PRIME REVIEW ONLINE MATHEMATICS &BASIC ENGINEERING SCIENCES PRIME'S SUPPLEMENTARY ENHANCERS (ENGINEERINGECONOMICS 02 MECHANICAL ENGINEERING REVIEW Reverse Digit(FC -Sv) D. = Sum of thc digits D. = 0*°(9,000-1,000) 10 ,.0.08" 100,000 P 100.0001+ D, = Php 3927.27 P Php 90,614.93 Ans.A Ans.B 18. issue AP1,000,000.00 of 3.5%, 15 year-bond wassold at 809%. What is the rate of interest of this investment? A. 3.0% C. 2.8% D. 3.52% B. 4.375%6 23. A new machine was installed by a company at a total cost of P 300,000 and projected to have a useful life of 15 years. At the end of its useful life, it is estimated to have a salvage value of P 30,000. Determine the capitalized cost if interest is 18% compounded annually. A. P 320,322.33 C. P 363,321.53 D. P 312,542.02 B. P 324.604.17 Selulion: i annualnet profit (1.000.000 )(0.03)-0.04375 4.375% total investment 0.80(1.000.000) Soluctio Ans. B CC 19. An asset is purchased for P 120.000. Iis estimated life is 10 years, after which it will be sold for P 12,000. Find the depreciation for the second year using the sum of the years digit method. A. P 17,342 C.P 17,673 B. P 17,632 D. P 17,505 Solitiom Reverse Digil(FC d Digits d, =(120.000-12,000) FC+RC-SV Note: FC=RC (1+ i)-1 CC 300,0004300,000-30,000 (1+0.18)-1 CC= Php 324,604.17 Ans. B 24. A company purchases an asset for P 10,000.00 and plans ta keep it for 20 years. If the salvage value is zero at the end of the 20th year, what is the depreciation in the third year? Use sum of the years digits depreciation. d, Php 17,672.73 Ans C A. P 1000.00 B. P 937.00 C. P 857.00 D. P 747.00 Selulian: Reverse Digit(Fc-sv) 20. A factory is running at 80% efficiency with a fixed cost of P 78.000.00, variable cost per unit of P 130,00, selling price per unit of P Digits 416.00, and production capacity of 5000 units. What is the current profit of the factory if all products manufactured are sold. A. P 1,066,000 C. P 1,354,400 D.P 1633,000 B. P 1,042,000 d, 10,000-0)=Php 857.14 Ans.C 25. The corporation purchased a machine for P I million. Freight and Profit Sold- Expenses [(416)(5000)-1 30(5000)](0.8)-78,000 =Php1,066,000 Ans. A Od 21. A company purchases an asset for P 10,000.00 und plans to keep il for 20 years, If the salvage value is zero at the end of 20th year, what is the depreciation in the third year? Use SYD method. A. P 1,000.00 B. P 937.00 D. P 747.00 C.P 857.00 installation charges amounted to 3% of the purchase price. If the machine shall be depreciaied over a period of 8 years with a salvage value of l12 %. Determine the depreciation charged during the Sth year using the sum of the years digit method. A. P 101,107.11 C. P 170,I10.11 B. P 107,1 10.11 D. P 100,711.11 Sali7 d.= Reverse Digit (FC Digits Solilon = 2 Reverse Digil (FC -SV) Sv) E(.0.000)(1.03)-(1.000.000)(1.03)(0.12)] Digits d,=Php 100,711.11 8 Ans. D d, = ( P h p 10k-0) = Php 857.14 - 26. The original cost of a certain piece of equipment is P 150.000 and it is Ans. C 22. A man was offered a certificate with face value of P 10,000 which is bearing interest of 6% per year payable semi-annually and due in 6 a years. Ifhe wants to earn 8% semi-annually, how much must he pay the certificate? A. 100,520.32 C. 98,434.32 B. 0,614.93 D. 96.562.52 Sedu-tiepi depreciated by 10% sinking fund method. What is the annual depreciation charge if the book value of the equipment after 10 years is the same as if it had been depreciated at P14,000.00 each year by straight-line formula A. P8784.36 B. P 6454.54 Sel-t C. P 5645.57 D. P 3484.23 PRIME REVIEW ONLINE MECNANICAL ENGINEERING REVIEW MATHEMATICS &BASICENGINEERING SCIENCES PRIME'S SUPPLEMENTARY ENMANCERS (ENGINEERINGECONOMICS07 30. A man buys a small garden tractor. There will be no maintenance cost AtSLN V the first year as the tractor Is sold with one year's free maintenance - D , , = 150,0K0 -14,000(1o) - Phpt0,0M The second year the maintenance is estimated at $20. In subsequent AtSEM years ofthe maintenance cost will increase $20 per year (that is, 3rd year maintenance will be S40; 4th year maintenance will be $60, and so forth). How much would need to be set aside now at 5% interest to pay the maintenance costs on the tractor for the first six years of R-SV-0i)-»where SV =BV, I50.000-10.0m= 01" -1 ownershipP 0.I A.$101.52 B.$164.74 A Php8,784.36 A C. $239.36 D. $284.13 Seltion 7. An engine is expected to have a maintenance cost of P1000 the first year. It is believed that the maintenance cost will increase P 500 per P-Ax-1)d year. Theinterest rate is 6% compounded annually. Over a 10-year pernod. what will be the approximate effective annual maintenance cost? A. P 3011.00 C. P 2450.00 B P3452.00 P o(x-1)($20)| +0.05) D. P 1345.00 P-$239.36 Ans. C Solton A+ (x-1)d 100+(x-){S00) Php 22.161.25 (1+0.06) 31. A manufacturing company buys a machine for $50,000. It estimates the machine's useful life is 20 years and that it can then be sold for $S000. Using straight line depreciation, what is the annual P-P--0+9)"] depreciation charge? 22.161.25 A..S2000 C. $2500 B.$2250 D. $2750 0.06 -(0.06)| A= Php 3,011.00 STT Ans A d(CsV 28. ABC Corporation makes it a policy that for every new equipment purchased. the annual depreciation cost should not exceed 20% of the first cost at any time without salvage value Determinethe length of service life if the depreciation used is the SYD method C. 10 yrs A9yrs 12 yrs D. 19 yrsS Alternate Solution Mode 3 2 o S0.000 20 5.000 $2250 Ans. B Seluton: Since the st depreciation is the greatest d (50,000-5,000) = $2250 then Annual depreciation =0.2 FC 32. Company A has fixed expenses of $15,000 per year and each unit of product hus a SO.002 yariable set. Company B has fixed expenses of Then. $5000 per year and can be produce the same unit of product at a S0.05 variable cost. Atwhat number of units of annual production will Compuny A heve the same overall cost as Company B? Quantity is Rev. digits (FC-SV) e SV =0 Digits nearest t0 n ( n -1C)=0.2 FC A. CER n=9 yTs Ans A 100,000 units C. 300,000 units D. 400,000 units 200.000 units Soltio Epenses, 2Expenses 29. A manufacturer uses 1000 items uniformly throughout the year. The cost to produce the items in-house is Php 2,000.00 for set-up and Php 260.00 per item. Insurance and taxes are estimated as 12% of averuge inventory, and it costs Php 40.00 to store each unit for one complete year. How many of these items should the manufacturer produce at a time? A. 135 item C. 345 items B. 237 items D. 153 items 0.002x + 15.000 = 0.05x +5.000 x = 208,333.33 33. Plan A nequires a S100,000 investment now. Plan B requires an $80,000 investment now and an additional S40,000 invesument later. At 8% interest, what is the breakeven point on the timing of the additional S40,000 later? C.7 ye 3 ycars B. Syeaus Sdton 200,000 units AnsB D. 9 yearss PLAN A unit of time is a year: a = 1000 iten/year Fixed Cost: K = Php 2000.00 Inventory Cost: h y = 40.00,(0.12)Php260.00) Hem- yeur 120 Ans B ilem- year =237 00,000 Php 71.20 item-yeur Plan A Present W = Plan B Present W PLAN B From CFD 40,000 00,(00)= 80,0X)+ 40,000(1+ 0.0 n= 9,01 yrs As. 80,000 PRIMEREVIEW ONLINNE MATHEMATICS &BASIC ENGINEERING SCIENCES PRIME'S SUPPLEMENTARY ENHANCERS(ENGINEERING ECONOMICS 02 MECHANICAL ENGINEERING REVIEW 34. A machine part, operating in a corrosive atmosphere, is made of low carbon steel, costs S350 installed and lasts six years. If the part is treated for corrosion resistance it will cost $700 installed. How long must the treated part last to be as good an investment as the untreated part, if money is worth 7%?| A. 8 years C.14 yearN D.I7 years B. l1 years 38. A manufacturing fim maintains one product assembly line to produce signal generators. Weekly demand for the generators is 35 units. The line operates for 7 hours per day, 5 days per week. What is the maximum production time per unit in hours required of the line to meet the demand? A. C. 3 hours hour B. 0.75 hour D. 2.25 hours Sobuton Seleken: P-0] 7 hrs5 days day wgek 350a07-(1.0) A =$73.43 hr/unit 35 units wgek 700 0.07 (0+007) n=16.27 yrs Ans.D ewpsi 39. A series of year end payments extending over eight years are as 35. An investor is considering buying a 20-year corporate bond. The bond has face value of Si000 and pays 6% interestrate per yearin two semiannual payments. Thus the purchaser of the bond would a receive $30 every 6 months, and in addition he would receive S1000 at the end of 20 years, along with the last $30 interest payment. If the 8% investor though he should receive PS0,000 for the third year, and P40,000 for each year from the fourth worth of these through the 8th payments if the annual interest is 8%. year. Find the equivalent annual A. P44,800.00 B. P30,563.00 annual interest compounded semiannually, the amount he would be willing to pay for the bond is closest to A. $500 B. $600 follows: P10,000 for the first year, P20,.000 for the second year, C. $700 D.$800 C. P35.650.00 D. P33,563.85 Se TU FOR M10,000 20.000 40k 40k 4Dk 40k 40k 50,000 8 0.080.000) P-1,0001 EUAC 0.08 EUAC P=10,000(1+0.08) +20,000(1+0.08)+50,000(1+0.08) P S802.07 400001-(1+0.08) (1+0.08) a.08 D P Php 192,880 36. Consíder a deposit of P600.00 to be paid buck in one yeur by P700.00. What are the conditions on the rate ofinterest, 1% per year compounded annually, such that the net present worth of the investmentis positive. Assume i 20 A. 0sic16 7% C. 125%si<143% B. 0si<14 3% D. 16.7% sis100% Seltion PEUA[-(+0 380A1-(1+0.08) CEBU Ans.D 0.08 EVAC=Php33,563.85 40. A machine has been purchased and instaled at a total cost of P18.000.00. The machine will be retired at the end of 5 years, at which time it isexpected to have a serap value of P2,000.00 based on curent rices. The machine will then be replaced with an exact P F{1+i 600=700(1+i) i = 0.1667 Then, determining EUAC duplicate. The company plans to establish a reserve funds to accumulate the capital needed to replace the machine. If an average 1667% Thus, 0% Si s16.67% annual rate ot unflatton of 3% in anticipated, how mucbh capital must be Ans. A accumulated? A PI5,030.00 C. P13,382.00 B. Pl8.548.39 D. P15,386.00 37. The cost C of a product is a function of the quantity x of the product: C)=x-4000x+ 50. Findthequantityfor which the cost is F P(l+f) minimum. 3000 B. 2000 A. Selon C(x)=x*-4000x +50 C(x)= 2x-4000 =0 x 2000 units Ans. C. 000 D. 1500 where: P =18000-2000 Php 16,000 Subst. P: F=l6,000(1+0.03) Php 18,548.385 PRIME REVIEWONLINE MECHANICAL ENGINEERING REVIEW MATHEMATICS &BASIC ENGINEERING SCIENCESs PRIME'S SUPPLEMENTARY ENHANCERS (ENGINEERING ECONOMICS 02 41. What uniform annual amount should be deposited cach year in order to accumulate P100,0XX0.00 at the end of the 5h annual deposit if money -(0"] >where:P =F(1+i) eams 10% interests? So: F(l+1)"-1-(1+"] C.PI8494.45 A. P15,708.83 B. P17.943.45 D. Pl6.379.75 18.000(1+0.1s) = 0.15 A Selaien: F[a- 1+0.15)"| Php3,919.54 ADS. B 46. What is the present worth of the two PI00 payments at the end of the third year and fourth year? The annual interest rate is 8%. A PI53 C. P162 D. P127 B. P160 100.000[0-010.10L A = Php 16,379.75 Ans. D Selulie 42 An asset is purchased for P1 20,000.00. Its estimated life is 10 years. after which it will be sold for P12.000.00. Find the depreciation for the second year using the sum-of-the-ycars-digit method: A. P19,000 C. P18,200 B. P17.673 D. P18,400 = PA 100 AlternateSolution: P=100(1+0.08)+100%i+0.008)= Php152.89 100 An.A Solelion: d =Reverse Digit 0.08) 1008)' Php152.89 P -SVv) 47. A manufacturer of sports equipment produces tennis rackets for which there is a demand of 200 per month. The production set cost for each lot of racket us P300.00. In addition, the inventory carrying cost for Digits -(120,000-12,000) each racket is P24.00 peryear. Using the Economic Order Quantity (EOQ) model, which is the best production batch size for the rackets? C. 173 units A. 245 units D. 346 units B71 units EFOR d. = Php 17,672.73 Ans. B Settion 43. A fim borrows P2000 for 6 years at 8%. At the end of 6 years, it renews the loan for the amount due plus P2000 more for 2 years at 8%. What is the lump sum due? C. P5,254.00 D. P6,03500 A. P6,135.00 B. P5,280.00 EOQ-2ak-2(200/month)(Php 300 h Ans.A = 245 units V(Php24/year)(1yr/12months) 48. What is the maximum profit when the profit-versus-production function is as given below? P is profit and x is unit of production. P 200,000-x- Seluion: to the 8th power From CFD: A. 285,000 LumpSum 2,00(1+0.08)+2,000(1+0.08) C. 250,000 D. 305,000 B. 200,000 = Php 6,034.6 Seluion Ans D P200.000-x1 44. The purchase of a motor for P6000 and a generator for P4000 will allow a company to produce its own energy. The configuration can be assembled for PS00. The service will operate for 1600 hours per year 1-(.1 dx for 10 years. The maintenance cost is P300 per year, and costto operate is P0.85 per hour for fuel and related cost, Using siraight line depreciation, what is the annual cost for the operation2 There is P400 salvage value for the system at the end of 10 years. C. P2630 A. P2710 D. P2670 B. P2480 X0.3713 At x= 0.3713 P 199,999.46» Php200,000 Ans.B 49. A man was offered a certificate with a face value of P 100,000 which of 6% per year payable semi-annually an due in 6 years. If he wants to earn 8% semi-annually, how much must he pay the is bearing Solutier: certilicate? By SLM Mode 3,2 x(yr -8)(*+1)" -0 y(Price) 0 6,000+4,000+S00 0 400 AC shift 15 2 A. P 90,615 C. P 96,322 B. P93,322 D.P 102,334 Sotuon 1010 the value of B So, the annualcost is EUAC=1010 300+0.85(1600) = Php 2670 Ans.D P100.00 1+ 45. In five years, P18,000 will be needed to pay lor a building renovation. In order to generate this sum, a sinking fund consisting ofthree annual P Php 90,614.93 payments is established now. For tax purposes, no further payments will be made after three years. What payments are necessary if money is worth 15% per annum? A. P2870 C. PS100 B. P3919 D. P2670 AnA Php 100,000 0.06 10.08 PRIME REVIEW ONLINE MATHEMATICS &BASIC ENGINEERING SCIENCES PRIME'S SUPPLEMENTARY ENHANCERS (ENGINEERING ECONOMICS 02 MECHANICAL ENGINEERING REVIEW 50. A certain office cquipment has a first cost of P 20.000 and has a Converting the mode of compounding salvage value of P 1000 at the end of 10 years. Determine the total 010- depreciation at the end ofthe 6th year using sinking fund method at 3% interest A. P 10,720 B. P11420 0.09569 C.P 12.340 D. P 10.520 From PW: Seluton: FC-SV-0+i-1 A 100,000 0.09569 20,0-1,00 0.03 003)"-i 12 A= Php 839.2 A = Pbp1657.38 At 6th yr Ans. D D. 1+i-i- 0.03 +003-1=Php10,720.61 Ans.A 54. A local firm is establishing a sinking fund for the purpose of be redeemed at 110% on June 21, 2004. It is bought on June 21, 2001 to yield 4% S1. AP 1000, 6% bond pays dividend semi-annualy and will accumulating a sufficient capital to retire its outstanding bonds at maturity. The bonds are redeemable in 10 years, and their maturity value is P150.000.00. How much should be deposited each year ifthe interest. Find the price of the bond. A. 1,144.81 C. 1,432.332 B. 1,129.42 D.1,042.12 fund pays interest at the rate of 3%? Selufion Selu-tion EFOR150.0F-0-.009)"- (0.06 1000 0.04 2 2 D.P16,848.87 B. P13,084.58 P-0]Ri P. 150,000 C.P14.094.85 A. P12,547.14 A=Php 13084.58 (100-(0.1000)12 B P= Php 1,144.81 Ans.A 52. You need P4000 per year for four years to go to college. Your father invested PSO00 in 7% account for your education when you were born. with P4000 at the end of your 17, , 19th and 20 birthday, how much money will be left in the account at the end of the Ifyou draw 18 21 year? A. P2500 B. P3400 Saladan C. P1700 D. P4000A 55. A machine cast P20,000.00 today and has an estimated scrap value of P2,000.00 after 8 yeurs. Inflation is 8% per year is 8%. How much money needs to be set aside each year to replace theFQE machine with an identical model 8 years from now? A. P2,990.00 C.P3,920.00 B. P3,290.00 D.P3,610.00 2000 Solet 1 4000 2 2 3 2p2 20,000 CEBU 20,000-2,000(1+0.08) A1-(1+0.08) 0.08 A=Php 3292.27 Ans. B FromCFD, At21 so(1007- +0.0n)-1(007= Then, At 21, x = Php 1700 Ans. C 53. Mr. Ayala borrows PI00.000.00 at 10% effective annaual interest. He must pay back the loan over 30 years with uniform monthly payments due on the first day of each monh. What does Mr. Ayala pay each month? A. P870.00 C. P878.00 B. P846.00 D. P839.00 Setukon S6. A machine is under consideration for investment. The cost of the machine is P25,000.00. Each year it operates, the machine will generate a savings of P15,000.00. Given an effective annual interest is payback period, in years, on the rate of investment in the machine? 18%. whut the discounted A.1.75 years C.L.67 ycars B. 3.17 years D.2.16 years P-0"] 25,000 1-(1+0.18)" 0.18 n=2.155yTs Ans.D PRIME REVIEW ONLINE MATHEMATICS &BASIC ENGINEERING SCIENCES MECHANICAL ENGINEERING REVIEW PRIME'S SUPPIEMENTARY ENHANCERS (ENGINEERING ECONOMICS 02) 57. A businessman wishes to earn 7% on his capital after payment of taxes. If the income from an available investment will be taxed at an average rate of 42%, what minimum rate of retum, before payment of taxes, must the investment offer to be justified? A. 12.1% C.11.1% D.12.7% B. 10.7% Selti. Since the Ist depreciation is the greatest then. d Annual depreciation = 0.2 FC Then Rev. digilS(FC-SV) @SV =0 2 Digits n nn+1C)=0.2 FC Let x >invested 0.07x =(1-042)x i 2 i =0.121 » 12.1% n=9 yrs Ans. A 58. Ans. A The maintenance cost for sewing machine this year is expected to be P S00. The cost will increase P S0 each year for the subsequent 9 a years. The interest is 8 % compounded annually. Whatis the approximate present worth of maintenance for the machine over the full 10-year period? . P4.700 C.P 5,30%0 B. P 4,300 D. P5,500. Selutien: 62. A deposit of P1000 is made in a bank account that pays 8% interest compounded annually. Approximately how much money will be in the account after 10 years? A.P2,160 (1+i) D. PL925 Selution F P(1+i=1000(1+0.08) F P-Ar1)a] C. PI860 B.P2.345 Php 2158.92 Ans.A 500+50(x-1) 63. A machine costing P 480,000 has a life expectancy of 12 years with a salvage value of 10% of the first cost. What is the book value after five 10.08) P Php 4.653.88 years using the declining balance method? Ans. A B. P 174,322 A. P 183,892 59. A machine costing P 45,000 is estimated to have a book value of P 4,350 when retired at the end of 6 years. Depreciation cost is computed using a constant percentage ofthe declining book value. What is the annual rate of depreciation in %? A. 33.25% B. 35.25% Saleion BV FC-D, =FC(1-k where C. 32.25% D. 34.25% 0.10FC 0.1746 FC BV, 480,000(1-0.1746) = Php183,896.97 Setution k C. P 152,758 D. P 166,342 Ans. A 43500.3225 45000 l 64. A macinehas an initial cost of P 50,000 and a salvage value of P10,000.00 after 10 years. What is the book value after 5 years using Aternate Sohrion: Mode 3 6 straight line depreciation? A P 35,000.00 0 45,000 6 4350 B. P 15.500.00 ACShift 1 5 2 .67745 the value of B k=l-B 0.3225 D. P 30,000.00 Setution CE Ans. C esks 60. An equipment costs P 10,000 with a salvage value of P 500 at the end BV, = FC -D, where: D 50,000-10,000) Php 20,000 BV, S0.000-20,000 = Php 30,000 of 10 years. Calculate the annual depreciation cost by sinking fund method at4 % interes A. P 791.26 C. P 950.00 D. P 845.332 B. P 971.12 Aluetnate Solutso Mode 32 Selution: BV, 5 Php 30.000 C-SVui)-] 10,.000-500 +0.04)- A Php 791.26 Ans. A 61. Acompany makes it a policy that for any new equipment purchased, the annual depreciation cost should not exceed 20% of the first cost at any time with no salvage value. Determine the length of service life necessary if the depreciation used is the SYD method A. 9 years C. 10 years B. 12 years D. 19 years Solutomi C.P 25,000.00 x oso,000 1o10.000 Ans. D 65. A producthas a current selling price of P 325. If its selling price is expected to decline at the rate of 10% per annum because of absolescence, what will be its selling price four years hence? A. P 213.23 C. P 210.21 D. P 209.54 B.P221.42 Seleiems BV, = FC(1-k) Ans.A BV, = 325(1-0.1)' = Php 213.2325 PRIME REVIEW ONLINE MECHANICAL ENGINEERING REVIEW 66 MATHEMATICS &BASIC ENGINEERING SCIENCES PRIME'S SUPPLEMENTARY ENHANCERS (ENGINEERING ECONOMICS 02 A machine costing P 480,O00 has a life expectancy of 12 years with a salvage vaBlue of 10% of the first cost. What is the book value after ive years using the decining balance method? C.P152,7S8 A. P 183,892 D.P 214,785 B.P196432 70. For some interest rate i and some number of interest perids n, the unilorm series capital recovery factor is 0.0854 and the sinking fund factor is 0.0404. The interest rate i must be C. 6% A. 3 4% B. 4 4% D. 8% Soletion Selulior = BV. = RC(1-A) BV, = C - D. USCRF-SFF =0.0854-0.0404 where i=0.0450 O.10FC -0.1746 Ans. B BV, = 4$0,000(1-0.1746) = Php183.,896.97 71. A man buys a small garden tractor. There will be no maintenance cost the first year as the tractor is sold with one year's free maintenance The second year the maintenance is estimated at $20. In subsequent AnsA 67. The fist cost of equipment is P 100,000 and estimated to have a book value of P 30,000 when retired at the end of 10 years. Detemine the annual rate of deprecation using a constant percentage declining balanced method. A. I1.34% C. 10.33% B. 10.21% D. 10.56% Sola~ien: years the maintenance cost will increase $20 per year (that is, 3d year maintenance will be S40; 4th year maintenance will be S60, and so forth). How much would need to be set aside now at 5% interest to pay the maintenance costs on the tractor for the first six years of ownership? C. $239.36 A. $101.52 B. $164.74 D. $284.13 Seloi eni 30.000-0.1134 kl-100.000 P-A- Alternate Solution Mode 36 0 100.000 P-0(-520) 10 30.000 +0.05 P $239.36 k = 1-B =0.1134 Ans. A AnsC 68. A company bought an equipment for P56.000. Otherexpenses including installation amounted to P 4,000. The equipment is expected to have a life of 16 years with a salvage value of 10% of the original cost. Detenmine the book value at the end of 12 years by sinking fünd method at 12% interest. A. P 28,500 C.P28,500 B. P 27,530 72. A manufacturing company buys a machine for S50,000. It estimates the machine's useful life is 20 years and that it can be sold for $5000. Using straight line depreciation. what is the annual depreciation charge? C. $2500 A.$2000 B. $2250 D.$2750 D.P29,520 Sduteni d(FC-Sv)=50.000-5,00) BVFC Dn Determining annual dep. d $2250 FC-SV fa+i"-1 AlternateSalation- (Php56k+ 4k)-(0.10)(Php 56k + 4k) 20126 CEBU 0 50,000 20 5.000 A = Pbp 1263.06 B $2250 BV12-C-DPi2 BV2 Php(5ok 4k) 00.12)| BV2 Php 29,518.38 Ans D 69. The maintenance cost of a machine this year is expected to be P 1000. The cost will increase P200 each year for the subsequent 9 years. The interest is 15% compounded annually. What is the approximate present worth of maintenance for the machine over the ful 10 years? C. P8,414.67 A. P 4,818.67 D. P4,418.76 B. P 4,481.76 13. Company A has fixed expenses of SI5.000 per year and each unit of product has a $0.002 variable cost. Company B has fixed expenses of $5000 per year and can produce the same unit of product at a $0.05 variable cast. At what number of units of annual production will Company A have the same overall cost as Company B? Quanity is nearest to A. 100,000 units B. 200,000 units C. 300,000 units D. 400,000 units Sealian 2Expenses, - Expenses Slo P-A(a1)a P-21iy 1000 200(x -1) (1+0.15) P Php 8414.66 As C Mode 32 0.002x+ 15,000) =0.05x + 5,000 x 208,333.33 units As. PRIME REVIEW ONLINE MECHANICAL ENGINEERING REVIEW MATHEMATICS & BASIC ENGINEERING SCIENCES PRIME'S SUPPLEMENTARY ENHANCERS (ENGINEERING ECONOMICS 02 74. Plan A requires a Php5,000,000 investment now. 78. A bank charges 1 h per month on the unpaid balance for purchases Plan B requires an Php 4,000,000 investment now and an additional Php 2.000,000 investment later. At 8% interest, what is thhe breakeven point on the timing of the additional $40,000 later? A. 3 years C. 7 years B. 5 years D.9 ycaN made with its credit card. This is equivalent to what effective annual interest rate? A. 1.5% C. 18% D. 19.5% B. 12% Seltlon Seleton i,(1+-1 PLAN A i,= (1+0.015)"-1 i, 0.19562 = 19.562% Ans.D 5,000,000 79. A man purchased a car with a cash price of P350,000. He was able to Plan A Present W = Plan B Present W negotiate with the selker to allow him to pay only a down payment of 20% and the balance payable in equal 48 end of the month installment at 1.5% interest per month. On the day he paid the 20h installment. he 5,000.000= 4,000,000+ 2,000,000 (1+0.08) PAN B n 9.01 yTs decided to pay theremaining balance. How much is the monthly Ans. D 2,000,000 payment and what is the remaining balance that he paid? C. P186034.30 A. P187030.20 B. P186927.25 4,000,000 75. A newbuildingis being considered to housesome equipment. The new buiding will reduce maintenance costs by S00 per year for the first ten years, and $3000 per year thereafter. Based on a 50-year D. P 195986.26 Seltion From CFD analysis period, what buiking construction cost can be justified? The P justified construction costis closest to if the interest is 9.5% 250.000=(3so.0o0)(0.2)+ 0.015 -(+0015) A. $30.000 B. $50.000 C. S90,000 D. $140,000 214 AT6000 3.000r, 0 . 0 9 5 L ( + 0 . 0 9 5 ) ao 0.095 1-+0.095) 10.095) P S50.071.52 Ans money have to be invested before it wil double in value? A. 59 months C. 70 months D. 76 months B. 62 months F P(1+i) 2P P(1+i 2P=P(+0.0i) n 69.66 months Alternate Solution: ( Rule of 72 72 rule months 77. A department store charges one and one-half percent interest per month on credit purchases. This is equiyalent to a nominal annual interest rate of A. 1.5 percent C. 18.0 D. 19.6 I5.0 Selu-kon: .i.m i, =(0.015)(12) =0.18 a 18% D. 199,008.23 Salidon F[0- 4.000,00= 0.15)- A=Php 197.008.25 81. An oil well which could produce a net income of P5,000,000.00 per year for 25 years is being considered to be purchased by group of businessmen. If the returm on investment is targeted to be 20% out of the netincome and asinking fund at 18% interest is to be established to recover the investment, how much must be paid to the oil well? A. P73,921,184.58 B. P72.867,170.54 C. P73,985,239.55 D. P67,895.179.70 70 months Ans.C Ans.C 80. In anticipation of a much bigger volume of business after 10 years, a fabrication company purchased an adjacent lot for its expansion program where it hopes to put up a building projected to cost P4.000,000.00 when it will be constructed 10 years after. To provide for the reguired capita expense,it plans to put up-a sinking fund for the purpose. How much must the company deposit each year if interest to be eamed is computed at 15%? C. 197,008.25 A. P198,009.30 CEBUAns.C Sellon (0.015)-1 FPhp186921.24 Ans. B B. P197,007.45 76. How many months at an interest rate of l percent per month does , APhp 8225 Balance350.000(1-0.2)(1+0015 Sdton 12 DP+Annual payments Solfiom 15,000,000 0.18 1+-I (1+0.18)-1 As.A = Php 73,921,184.58 PRIME REVIEW ONLINE MECHANICAL ENGINEERING REVIEW 82 A unit of welding machine cost P45,00X with an estimated life of 5 years. Its salvage value is P2,500 find its deprecation using Straight line method MATHEMATICS & BASIC ENGINEERING SCIENCES PRIME'S SUPPLEMENTARY ENHANCERS (ENGINEERING ECONGMICS 02 86. A steel drum manufacturer incurs a yearly fixed operating cost of $200,000. Each drum manufactured costs Si60 to produce and selk for $200 What is the manufacture's break-even sales volume in drums per Assuming that n will deposit the money to a bank giving 8.5%. Solve year? 100X) C. 1250 B. 25(X) D. 5000 A. for the deprviation. A. P8700: P7692.50 B. P8500: P6494.55 C. P8500 P7172.54 Sele Break even D. P7834 P6794,45 2 Income =2Expenses Using SLM 200x 160x + 200,000 C-SV_45.000-25000 -Php 8500 Mode: x5000units Ans.D 32 0 45.000 87. 5 2.500 five B-Php 8500 By Sinking Fund order to meet demand' A. 0.75 hour B. 2.25 hours FC-SV 01+i"-1 45,000-2500=0.085 (+0.08s)-I week. What is C. I hour D. 5 hours Solufiom A = Php 7172.54 Ans. C 83 A manufacturing firm maintains one product assembly line to produce signal generators. Weekly demand for the generators is 35 units, and the line operates for seven hours per day. days per the maximum production time per unit, in hours, required of the line in 7 hrs5 days day wgek , If you obtain a loan of PIM at the rate of 12% in order to build a house, how much umust you pay monthlyto amornize the loan within a period of ten years? A. P14.980.60 C. P14,974.50 B. P13.785.56 D. P13,994.64 compoundedannualy 1 s units wek hr/unit Ans. C 88. Tops Corporation's gross margin is 45% of sales. Operating expenses such as sales and administration are 15% of sales. Tops is in a 40% tax bracket. What percent of sales is their profit after taxes? Changing the mode of compounding 0% C. 5% B.18% D. 24% o12- Sales=(1-0.4)(0.45-0. 15) 0.11386 0.18 P 18% Ans. E 89 1.000,0)= 0.11386 12 A = Php13,994.72 Ans.D A company purchased for a cash price of P500,000.00 a machine which is esuunated to have a salvage value of PS0,000.00 at the end of its 10 yeat ecunomie life. How much yearly deposit must the company deposit un a siæking fund hat will pay l18% interest, compounded yearly, to accumulate the needed fund to purchase a new machine at the end of the 10th year economic life of the machine it purchased if a new machine will cost 75% mmore by that time. 84. A bank pays one percent interest on savings accounts four times a year. The effective annual interest rale is C. 3.96% A. 1.00% D. 4.06% B. 1.04% A. P35,078.60 C. P35,085.64 B. P40,080.67 D. P35,074.58 Sale.kon 3y SEM ola-bon = (1+0.01) -1 -sV- = 0.0460 = 4.6% "- (500.000)(75)-50,000 = 0.18 +0.1s)" - Ans. D A =Php 35,074.58 85. Whal interest rate, compounded quaterly, is equivalent to a 9.31% effecive interest rate? A. 2.25% C. 4.66% B. 2.33% D. 9.00% Ans. D 0. A car dealer acdvertise the sale of a car model for a cash price of P280,000.00. Ii purchased on installment, the required down pay ment is 15% and balunce payable in 18 cqual monthly installnents at an nterest rate of 1.5% per month. How much will be the required -1 0om-(O.0XX) AnsD = 9% nonthly payuwents? A.PI5,186.70 C.PI5,185.78 B. PI5,200.87 D. Pl6,187.75 PRIME REVIEW ONLINE MECHANICAL ENGINEERING REVIEW MATHEMATICS &BASIC ENGINEERING SCIENCES PRIME'S SUPPLEMENTARY ENHANCERS (ENGINEERING ECONOMICS 02 Selelion: The service has an infinite life, capitalized cost: Sdton CapCost (Brand B) =initial Cost Car price = DP + Anual payments A 3.500+0, 000(1-0.87)= Php 29.500.00 280,000 0.15(280,.000)+ o.015 1-(1+0.015)" 0.10 A = Php 15,185.78 Ans.C AnsC 91. A small building can be reroofed for Php 30,000 (aluminum) or Php 96. The heat loss from bare steam pipes costs a hotel manager Pbp 20,000 annually. Two brands of insulation are available. Brand A will cost Php 6,000 and will reduce o8ses by 93%. Brand B wil cost Php 3500 and wil 175,000 (shingles). The estimated lives are 50 years and 15 years respectively. If the interest rate is 10%, what is the cquivalent uniform annual cost for aluminum? A. Php 30,258.00 C. Php 35,098.00 D. Php 20,675.00 B. Php 23,0O8.00 reduce losses by 87%. Which insulation is economically superior if the interest rate is 10% ? A. Brand A C. both are superior D. insufficient data for comparison B. Brand B Selelen The service has an infinite life, capitalized cost EUAC 1 0 " - 1 300,000 Cap Cost (Brand A)= 6,000 O.100.10)" EUAC =Php 30,258aluminum 20,000(1-0.93) Php 20,000.00 0.10 Cap Cost (Brand B) =3,500+ Ans.A = Php 29.500.00 10 Brand A is superior for it needs lesser Cap Cost 92. be reroofed for A smallbuilding can 175.00 (shingles). The estimated lives are 50 yearsand15years, respectively. If the interest rate is 10%. what isthe equivalent unifom annual cost for shingles? A. Php 30,258.00 Php 30,000 (aluminum) or Php 97 The total estimated costs of producing 240 and 360 units are Php cost? is 4000 respectively. C. Php 7.50 unit A. Php 5.00/unit D. Php 10.00/unit B. Php 7.00/unit 34000and Php C.Php 35.098.00 D. Php 20.675.00 B. Php 23,008.00 Ans. A What the incremental Seluton A110 incremental cost= 4000-34O0600 120 =175,000 360-240 L 01 0 1 . 1 0 5 I 5 , 0 0 0 Php 5.00/ unit Ans. A EUAC Php 23,008shingles Ans. B 98. The totalestimated costs of producing 240 and 360 units are Php 3400 and Php 4000respectively. Whatis the is the fixed cost? 93. An item is purchased for Php 5,000,000. Amualcosts are Php 900,000. Using 8%, what is the capitalized costof perpetual service? A. Php 14.71/unit B. Php 12.345.000.00 C. Php 2,200.00 /unit D. Php 4.500.00 /unit B. Php 5.00/ unit C Php 12,645,000.00 A. Php 16, 250,000.00 D. Php 1.450,000.00 Selotian incremental cost The service has an infinite life; capitalized cost: Fited Cost=Php 3400 (Php 5.00/unit 240 units)= Php P 2,200 Cap Cost (Brand A)= initial Cost + 5,000.00+ 4000-3400 Php 5.00/umit 360-240 120 n6RPhp16.250,000 CEBU Ans.C 99. A production onder for200 units is received. The item is made on a Ans.A 94. The heat loss from bare stean pipes costs a hotel manager Php 20.000 annually. Two brands of insulationare avaitable. Brand A will cost Php 6,000 and will reduce losses by 93%. Brand B will cost Php 3500 and will reduce losses by 87%. What ure the capitalized conts of perpetual service for brand A if the interest rate is 10% 7 A. Pbp 16.000.00 C. Php 30,000.00 B. Php 20,000.00 D. Php 42,000.00 machine that has a Php 1,000.00 set-up., an output of six items per hour, and a daily fixed cost of Php 5000. The variable item cost is $1.00. What is the highest price the company could afford to buy the item for, instead of producingthe item itself? A. Php 186.78 c. Php 183.50 B. Php 159.25 D. Php 120.50 Working hours in a day is assumed to be 8 hours. Stion: The service has an infinite life; capitalized cos Cap Cost initial Cost = 6,000+ 200units time requreu (6nit l hrX&hrs/ day) 4,17 dayss + A Cost per em= piN0+4.17(Php5000)+ 200(Php50) 20,000(1-095)Php 20,001K) 0.10 200 Php 159.25 Ans. B Ans. B 95. The from bare steam pipes costs manager Php annually. Two brands of insulation ure avaikable. BrandA will cost Php heal loss a hotel 20,000 6,000 and will reduce losses by 93%. Brand B will cost Php 3500 and will reduce losses by 87%. What are thecapitalized costs of perpetual service for brand B if the interest rate is 10% 7 A. Php 16,0KO.00 C. Pbp 29,.500.0K) B. Php 20,000.00 D. Plhp 42,000.00 PRIME REVIEW ONLINE MECHANICAL ENGINEERING REVIEW MATHEMATICS& BASICENGINEERINGSCIENCES PRIME'S SUPPLEMENTARY ENHANCERS (ENGINEERING ECONOMICS 02 100. A public works project has an initial cost of Php 1.000,000 benefits with a present worth of Php 1.500,000 and disbenefits with a present worth of Php 300,000. What is the benefits cost ratio and the excess of benefits over costs? A. 2.0 and Php 5,000,000.00 C. 1.7 and Php 300,000.00 B. 1.2 and Php 1,000,000.00 D. 1.2 and Php 200,000.00 Seloten: B1SO0,000-300,000 = 1.2 c 1.000,000 B-C Phpl,500,000-Php300,000-Phpl,000,0 = Php200.000.00 Ans. D Please log-on to www.primereviewcenter.com for the enhancement of Elements(Terms) in Mathematics & Basic Engineering Sciences, Power &Industrial Plant Engineering and Machine Design. NG717 TUTE FOR RMECA 90 CEBU EERING