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270 m
0 m (no movement)
270 m
If BC=3 minutes and DO=270 m
Speed of the tractor over time interval BC= 270 m/ 3 x 60 secconds
270 m/ 180 s = 1.5 m/ seccond
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1.5 m/ seccond
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3 m/s
Acceleration= vf-vi/t
3 m - 0 m/ 20 secconds
Acceleration= 3m/20 secconds= 0.15 m/ s2
0.15 m/s2
AB= 16 s
Speed= 3m/s
Total distance travelled= 16x3= 48m
48 m
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BC= 14s
Speed= 3m/s
Total distance travelled= 14x3= 42m
42 m
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increasing
constant
constant
zero
increasing
constant
Time interval OA
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Acceleration: vf-vi/t
OD=30m/s
OA=200s
30m - 0m/ 200s= 0.15m/ s2
0.15m/s2
Deceleration= vf-vi/t
OD= 30m/s
BC= 300s
0m - 30m/ 300= -0.10m/ s
-0.10m/ s2
Avarage speed=
30 x 300= 9000
deceleration= -0.10m/s2
30/0.10= 300
1+2+3+4+...+300(-0.1)= -4515
9000-4515= 4485
4485/300= 14.95m/s
14.95m/s
30m x 300s/ 2= 4500
14.95 x 300= 4485m (estimated to 4500 m)
4500 m
Time interval AB
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