Homework
Ia R a = 1Ω
IT
Determine:
If
Vs =
R f = Et
Id
100Ω
200V
I T , If , Ia ,Pf ,Pa ,PE ,PV
rv
~
E=
197V
Show that
1
:
200
-
IfRf
200 =
If
mech 2 :
0
=
If (100)
=
IfRf-IcRa-197
2 (100)
-
Fall)
-
=
0
S
=
IGRf
=
22(100)
=
400W
=
FaRa
Pf
197 = 0
Ia = 3 A
2 A
Pa
2
=
KCL :
It
=
Fat If
PE
I + = 3 + 2 = 5A
9W
=
I V
,
=
=
IT Vvs
32(1)
=
=
PVs
~
PV = Pf + Pa + PE
P = I2R
Mech
~
3(197)
591W
PVs Pf + Pa + PE
=
# + Vs = 400+ 9 +591
5 (200) =
1000
1000
2000
=
S
Homework
Q
P
jΩ
1Ω
I
I1
P2
4Ω
P
,
(1) Determine I, I1, I2, and Vo
I2
4Ω
Vi =
rmS
10∠0 V

Q
Q
j6Ω
,
(2) Show that power given by the
source equals power consumed by
the load
Vo
2
j6Ω
f = 50Hz
=
k
Riz
+
R = 1+j
1
R
,
=
Rz
V = IR
4 + j6
,
1010° = [(3 + 4j)
.
=
.
-
6j
T
2(538
Pi
Pi
=
-
1
1
57538
T
6j)(2+ 3j)
.
3j
RI
,
-
=
-
-
T
-
z
2
=
~
=
R2
=
(1 2
4
-i
--
5
=
(2) (10) cos (53 %
=
12
=
1
-
530
[2
=
I r = 4
P
Pz = [2 = 1(4) = 4
Pi
12
=
=
=
P + p + P2
,
12
, 2
-
.
1
.
6j)(2 + 3j)
4 + 6j
P =
,
R
T
R2
-
4 + 6j
IVCOS (53 %
w
R12
I
=
3
1
1+ j + 2 +
R+ = 3 + 4j
(1 2
.
T
I = 1 2- 1
Y
=
(3) Draw phasor diagram of I, I1, I2,
and Vo
2 + 3j
=
R+ =
4 + j6
=
I
R(2
3
4
-
=
I , Re
=3
IUsin 533
Qi = 16 VAR
-
7 2 +0
=
.
7
=
5j
Q =
Vo
j)(4 6)
+
.
4j
21 (3 183
.
.
Q =
12x2 22(1)
=
=
4 VAR
Q = Q2 = = 2x) = 12(6) = 6 VAR
Q
=
Q + 01 + Q2
16
=
16
;