Get all Chapter’s Instant download by email at etutorsource@gmail.com Answers to Study Questions Chapter 1: Animals and Environments: Function on the Ecological Stage 1. There is a chance that a calcium atom or carbon atom that was once part of Caesar’s or Cleopatra’s body is now part of your body. Part of the reason is that most calcium and carbon atoms that were parts of these rulers’ bodies did not go to their graves with them. Explain both statements. (If you enjoy quantifying processes, also see Question 11.) Answer: Animals exchange atoms with their environments throughout their lives. Thus, over the decades of Caesar’s life, numerous atoms that were part of his body had returned to the environment. Because of this process, the number of atoms in the environment that were once part of Caesar’s body far exceed the number in his body at his death, raising the likelihood that some atoms that were once his are still among us. 2. Animals do not keep all their detoxification enzymes in a constant state of readiness. Thus they depend on phenotypic plasticity to adapt to changing hazards. An example is provided by the enzyme alcohol dehydrogenase, which breaks down ethyl alcohol. People who do not drink alcoholic beverages have little alcohol dehydrogenase. Expression of the enzyme increases when people drink alcohol, but full expression requires many days, meaning that people are incompletely defended against alcohol’s effects when they first start drinking after a period of not drinking. Consider, also, that muscles atrophy when not used, rather than being maintained always in a fully developed state. Propose reasons why animals depend on phenotypic plasticity, instead of maintaining all their systems in a maximum state of readiness at all times. Answer: Maintaining proteins costs energy; thus, unused capacities are not cost-free. Protein molecules occupy space in cells, and dissolved proteins add to the total solute concentrations of intracellular fluids. In terms of hypotheses we can offer to explain the phenomena described, failure to maintain proteins at all times may be a means of (i) avoiding unnecessary energy costs or (ii) keeping cell contents or concentrations below acceptable maxima. 3. Whereas the larvae of a particular species of marine crab are bright orange, the adults of the species are white. An expert on the crabs was asked, “Why are the two different life stages different in color?” She replied, “The larvae accumulate orange-colored carotenoid pigments, but the adults do not.” Did she recognize all the significant meanings in the question asked? Explain. Answer: No. While recognizing the question of mechanism, she did not recognize the question of origins: Why did larvae evolve orange coloration? Do larvae gain an advantage by being orange? Do adults benefit by being white? Get all Chapter’s Instant download by email at etutorsource@gmail.com © 2016 Sinauer Associates, Inc. Get all Chapter’s Instant download by email at etutorsource@gmail.com 4. Referring to Figure 1.11, do plains zebras, warthogs, and greater kudus have normal or exceptional gestation lengths? Justify your position in each case. Answer: The line in Figure 1.9 shows the statistically expected gestation length at each body weight. Of course, to compare any particular species with what is expected for animals of its weight, statistical tests would need to be carried out. Based on visual inspection, however, the zebras have exceptionally long gestation lengths, because they plot far above the line of expected gestation length. Compared to the length that is statistically expected for their body weight, warthogs have a far shorter gestation. Greater kudus plot on the line of expectation and therefore have a normal, or expected, gestation length. 5. At least three hemoglobin alleles in human populations alter hemoglobin structure in such a way as to impair the transport of O2 by the blood but enhance resistance of red blood cells to parasitization by malaria parasites. Explain how such alleles exemplify pleiotropy, and discuss whether such alleles could lead to nonadaptive evolution of blood O2 transport in certain situations. Answer: Each allele of this sort causes an individual to exhibit two distinct, seemingly unrelated traits: impaired O2 transport and improved malaria resistance. In an environment where people are likely to get malaria, these alleles could be favored by natural selection during evolution because of their benefits for malaria resistance. High frequencies of the alleles would lead to high frequencies of impaired O2 transport. 6. What are some of the microclimates that a mouse might find in your professor’s home? Answer: The microclimate in the space inside one of my professor’s shoes will likely be more humid than elsewhere in the house. If my professor opens windows, the surfaces just inside the windows will experience more wind than most parts of the house. If a secluded part of the attic is occupied by several families of mice, the CO2 concentration in the air there might be especially high. 7. Figure 1.16 seems at first to be simply a description of the physical and chemical properties of a lake. Outline how living organisms participate in determining the physical and chemical (i.e., temperature and O2) patterns. Consider organisms living both in the lake and on the land surrounding the lake. Consider also a research report that shows that dense populations of algae sometimes change the temperature structure of lakes by raising the thermocline and thereby increasing the thickness of the deep, cold layer; how could algal populations do this, and what could be the consequences for deep-water animals? Answer: Living organisms often affect the pattern of O2 concentration in a lake. For example, if there are lots of fish in a lake, the fish use O2 at a high rate and may lower O2 concentration at all depths. If organisms living around the lake, such as trees along the shores, add lots of organic matter to the lake (e.g., falling leaves), bacteria using the organic matter as food may tend to deplete O2. In the case of high algal growth in the lake, the high concentration of algal cells may block penetration of sunlight, meaning the sun does not warm the water at as great depths as usual, raising the thermocline. Get all Chapter’s Instant download by email at etutorsource@gmail.com © 2016 Sinauer Associates, Inc. Get all Chapter’s Instant download by email at etutorsource@gmail.com 8. Do you agree with François Jacob that evolution is more like tinkering than engineering? Explain. Answer: Yes. In air-breathing fish there is no rhyme or reason to the location where the air-breathing organ evolved. Sometimes the gill cavity is the site of air-breathing, sometimes it’s the intestines, etc. The fish seem to have improvised like a tinkerer would. Also, why would there be 30 different molecules that act as luciferins during bioluminescence if evolution occurred as though an engineer were in charge? 9. Explain how the comparative method, knockout animals, and geographical patterns of gene frequencies might be used to assess whether a trait is adaptive. As much as possible, mention pros and cons of each approach. Answer: In the comparative method, you look – for example – to see if all animals evolved in deserts have similar characteristics beneficial to desert life. A problem with this method is that there are no absolute rules regarding which animal species should or should not be included in a comparison. In using knockout animals, you engineer animals to lack functional copies of a gene and look at how they are inferior by comparison to normal animals. A problem with this method is that physiological systems other than those controlled by the gene may cover up for deficiencies. In using geographical patterns, if you find, for example, that the frequency of an allele varies systemically from low to high latitude, you will have good reason to believe that the allele helps with some challenge that varies with latitude. Determining which challenge, however, may be difficult. 10. Certain species of animals tolerate body temperatures of 50°C, but the vast majority do not. Some species can go through their life cycles at very high altitudes, but most cannot. What are the potential reasons that certain exceptional species have evolved to live in environments that are so physically or chemically extreme as to be lethal for most animals? How could you test some of the ideas you propose? Answer: If a species can evolve to live where most organisms cannot, it may avoid predation or disease, because predators or pathogens cannot live there. Another hypothesis is that if a species can evolve to live where most organisms cannot live, it may be able to get most of the food there. To test this last idea, if a herbivore species lives over a range of habitats that are non-extreme and extreme, you could carry out measurements to see if the percentage of vegetable matter it eats is greater in the extreme parts of its range that in the non-extreme parts where competitors are better able to live. 11. Using the set of data that follows, calculate how many of the molecules of O2 that were used in aerobic catabolism by Julius Caesar are in each liter of atmospheric air today. All values given are expressed at Standard Conditions of Temperature and Pressure (see Appendix C) and therefore can be legitimately compared. Average rate of O2 consumption of a human male during ordinary daily activities: 25 L/h. Number of years after his birth when Caesar was mortally stabbed near the Roman Forum: 56 years. Number of liters of O2 per mole: 22.4 L/mol. Number of moles of O2 in Earth’s atmosphere: 3.7 1019 mol. Number of molecules per mole: 6 1023 molecules/mol. Get all Chapter’s Instant download by email at etutorsource@gmail.com © 2016 Sinauer Associates, Inc. Get all Chapter’s Instant download by email at etutorsource@gmail.com Amount of O2 per liter of air at sea level (20°C): 195 mL/L. Be prepared to be surprised! Of course, criticize the calculations if you feel they deserve criticism. Answer: First estimate the total liters of O2 Caesar consumed in his lifetime: 25 L O2/h 24 h/day 365 day/year 56 years = 12,264,000 L O2 Then calculate the moles of O2 he used in his lifetime: 12,264,000 L mol/22.4 L = 547,500 mol Then calculate the fraction of atmospheric O2 that Caesar processed: 547,500 mol/3.7 1019 mol = 1.5 10‾14 If a liter of air contains 0.195 L O2, then it contains 0.195/22.4 mol O2 = 0.00871 mol O2. Accordingly, it contains 0.00871 (6 1023) = 5.2 1021 molecules of O2. If each liter of air contains 5.2 1021 molecules of O2, and if Caesar processed 1.5 10‾14 of those, then the liter contains 7.8 107 molecules that were in Caesar’s cells and participated in his metabolism. Get all Chapter’s Instant download by email at etutorsource@gmail.com © 2016 Sinauer Associates, Inc. We Don’t reply in this website, you need to contact by email for all chapters Instant download. Just send email and get all chapters download. 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