Worksheet 21 - Induction, Faraday's Law Q1: A circular loop of radius 0.1 m is rotating in a uniform magnetic field of 0.2 T. Find the magnetic flux (in mWb) through the loop when the plane of the loop and the magnetic field vector are at an angle of 30.0°. (mWb = 10 -3 T.m2) Answer: 3.14 ∅ = π΅π΄ cos π = 0.2(π(0.1)2 ) cos(90 + 30) = 3.14 πππ Q2: A 11 loop coil of area 0.29 m2 is in a 0.047 T uniform magnetic field oriented so that the maximum flux goes through the coil. The coil is then rotated so that the flux through it goes to zero in 0.40 s. The average emf (in volts) induced in the coil during the 0.40 s is Answer: 0.37 π= π π΅ π΄ 11(0.047)(0.29) = = 0.37 π π 0.4 Q3: A conducting loop of wire has an area of 180 cm 2 and a resistance of 22 Ω. There is a magnetic field of 200 T perpendicular to the loop. At what rate must this field be reduced (in T/s) to induce a current of 0.10 A in the loop? Answer:122.2 πΌ= π ππ΄ ππ΅ =− ( ) π π ππ‘ ππ΅ −πΌ π 0.1(22) ( )= =− = −122.2 π/π ππ‘ ππ΄ 180 × 10−4 Q4: A uniform magnetic field is applied perpendicular to the plane of a 90-turn circular coil with a radius of 6.0 cm and a resistance of 0.8 Ω. If the magnetic field increases from 0.2 T to 2.1 T in 0.30 s, what is the emf (in V) induced in that coil? Answer: 6.45 π= βπ΅ 2.1 − 0.2 ππ΄ = (π(0.06)2 )(90) = 6.45 π βπ 0.3 Q5: A circular coil of radius r = 5 cm and resistance R = 0.3 Ω is placed in a uniform magnetic field perpendicular to the plane of the coil. The magnitude of the field changes with time according to B = 0.6 e -0.1 t T. What is the magnitude of the current (in mA) induced in the coil at the time t = 3.5 s? Answer: 1.11 πΌ= π ππ΄ ππ΅ =− ( ) π π ππ‘ π(0.05)2 πΌ=− (−0.1(0.6)π −0.1(3.5) ) = 1.11 ππ΄ 0.3 Q6: You are designing a generator with a maximum emf 9.0 V. If the generator coil has 200 turns and a cross-sectional area of 0.060 m2, what would be the frequency (in Hz) of the generator in a magnetic field of 0.035 T? Answer: 3.41 πΈπππ₯ = π π΄ π΅ π = π π΄ π΅ (2π π) π= πΈπππ₯ 9 = = 3.41 π»π§ π π΄ π΅ (2π) 200 (0.06) (0.035) (2π) Q7: A 46-turn circular coil (radius = 6.0 cm, total resistance = 0.12 Ω) is placed in a uniform magnetic field directed perpendicular to the plane of the coil. The magnitude of the magnetic field varies with time as given by B = 40 sin(7π t) mT where t is measured in s. What is the magnitude of the induced current (in A) in the coil at 0.12 s? πΌ= Answer: 3.34 (Use Radians while solving) πΌ=− π ππ΄ ππ΅ =− ( ) π π ππ‘ (46)π(0.06)2 (7π(40) cos(7π(0.12)) × 10−3 ) = 3.34 π΄ 0.12 Q8: In the arrangement shown, a conducting bar of negligible resistance slides along horizontal, parallel, frictionless conducting rails connected as shown to a 2.0-Ω resistor. A uniform 1.5-T magnetic field is perpendicular to the plane of the paper. If L = 70 cm, at what rate is thermal energy (in Watt) being generated in the resistor at the instant the speed of the bar is equal to 4.3 m/s? π= π 2 (π΅ππ£)2 (1.5(0.7)(4.3))2 = = = 10.19 π π π 2 Answer: 10.19 Q9: A circular wire ring is situated above a long straight wire, as shown in the figure. The straight wire has a current I flowing to the right, and this current is decreasing at a constant rate. Which of the following statements is true? a) There is an induced current in the wire ring, directed in a counterclockwise orientation. b) There is no induced current in the wire ring. c) There is an induced current in the wire ring, directed in clockwise orientation. Q10: In the figure, a bar magnet moves away from the solenoid. The direction of the induced current through the resistor R is a) from b to a. b) The direction of current will keep changing. c) No current is induced. d) from a to b. Q11: A square loop of wire moves with a constant speed v from a field-free region into a region of uniform B field, as shown. Which of the five graphs correctly shows the induced current i in the loop as a function of time t? IV ο· III II I V