"I = 7(7:()
3.
der(?")
((2x1)-(3x1)) -(14x1) -(ax1))
-
((ax3)
+>
(
-
-
-
This
tells
quadratic
and
that
as
curve
that
1)
-
1ax2))
1 5) ( 6)
-
+
-
2
there
though the
it
is
-
invertible
is
a
unique
three
points
4.
LetA
be
the
(?)
marin
[?] (i)
A
=
->
A
=>
m=
".A.[]
()
=
a
=
a
=
".(]
.(i]
fiss I
11
.....(s): ( I
I
~
2
=
2
1.3.2
-
I
S
-
3
-
6
86
-
2
3
-
3
I
TPO-D
[i] "(i)
A
=
I:
-j).1]
-
I
I
= (3) ( 1)
i
+
+
-
-
=(3)
3(3)
4
+
(
1 3)
+
-
-
+
1
+
I
)
:()
:(i):(ii) t
S.
Graphing
the
quadratic
previous
question,
distance
is
does
never
cross
not
the
curve
we
20
eve
can
gotfrom
see
thatthe
therefore,
boundary
the
line
the
ball
·
I
iii)
t
64
D23R
2.
(sign
inversed (
11
....
0
000
I
16
84
2
I
81279
3
I
25664164
I
Ry -> R3 -16R,
I
I
1
D
O
1
00
-
⑧
8-12-14
8127
a
3
25664
16
4
I
I
I
-1S
I
I
-> TPO
R -Rx- 81R,
Ra
Pat Re
/in
->
I I I:
I
7
O
⑧
!
0
-
8
-
12-14
-
I
I
11
0-8-12-14-IS
IS
E
0
essis-
Ds-3 Rs -2S6R,
I
I
00
0
e
-- 8-12-14
·'
I
0
0
D
-
I
8-12-11-1S
0-54-72
-
78
-
88
0.192-240-252-23S
R,
-3
-
IS
000
8
·
a
0
0
4884 IOS
Pay
(sign inverted)
Rs
-2)
I
11
I sign
inversed again so
0
-
0
I
O
0-8-12-14-1S
0
to
11
normall
11.
00
back
I
54-72-78-80
0-192-240-252-ISS
-
8-12-14-IS
O
O
⑧
000
⑧
O
4884
I
10S
TDO
->
Rs-Rs
I
·
I
Ry
-
11
a
o
O
000
0
O
0
-4
I
-
Ry 2 5 Rs
-
I
I
!
0-8-12-14-15
·
sign
I
S
invertedagainso it
but
I
11
0-8-12-14-1S
0
I
a
1
00
0.4-
00
00
det
of
matrin
upper
triangular
is
diagonal
multiplied
the
:.det
1
1x1 -8) xax( a) x
=
-
288
=
this tells
Therefore
that
there
quartic
date
is
a
through
us
unique
the
4.
LetA
be
the
matrix
11
0
I
000
l
!
81
27931
256
64
164
I
-ji):17
ang): (i)
(ii). "I
Using
Matlab
"=
A
11
. 6
-t
a
-2
-
a
-
-
2410
using
MATLAB
A ":
(i]
Eit
3
00
is:
-8
a.
=
am
=
43
=-
-
a
-
=
as
-
S
=
0
10.
11.
Looking
that
line
the
graph
ball
does
at
the
the
interpolation suggests
cross
not
the
boundary
13.
8.6392x10.4
=
a,
a)
a
14.
z
7.7326x10"
=
-
3.5343 x 10'
=
as
=
do
Assuming
my
suggests
the
even
a
g
so
-
4.5800x103
=
MATLAB
as
sense
did
through
calculated
I
if
not
2.2512x10-
=
was
answer
is
-
on
wrong
ball
8.3854x10"
=
0
notmake
interpolation
Powered by TCPDF (www.tcpdf.org)
a
don'tknow
values
4.1474x10-
=
2.5198
I
-
=
ag 6.2070 x10-2
7.3514x10"
-
-9.3056x10a
=
Qc
=
ac
I
a
cross
the
my
the
the
useful
points
as
I
results
11.1
correct
very
a
the
interpolation
line.
The
it
does
recorded.
not
4
Index of comments
11.1
Powered by TCPDF (www.tcpdf.org)
this is probably coherent with your previous answers at Q13.