MATH IN FOCUS WITH RAJA NADEEM AMIN 03215862394 O & A Level campus Trigonometric Functions Q1 (N 2004/P1) The function π(π₯) = 5sin2 π₯ + 3 cos2 π₯ is defined for the domain 0 ≤ π₯ ≤ π. (i) Express π(π₯) in the form π + π sin2 π₯, stating the values of ‘a’ and ‘b’. (ii) Hence find the values of x for which π(π₯) = 7π πππ₯. (iii) State the range of π(π₯). Q2 (J2005/P1/Q7) A function f is defined by (π₯) = 3 − 2π πππ₯ , for 00 ≤ x ≤3600 . (i) Find the range of π. (ii) Sketch the graph of π¦ = π(π₯) A function g is defined by π(π₯) = 3 – 2π πππ₯, for 00 ≤ x ≤A0 , where A is a constant. (iii) State the largest value of A for which g has an inverse. (iv) When A has this value, obtain an expression, in terms of x, for g-1(x). Q3. (J2006/P1/Q2) [1] [2] π ππ 2π₯ + 3 πππ 2π₯ = 0, Solve the equation for 00 ≤ π₯ ≤ 1800 . Q4. [2] [2] [4] (J2007/P1/Q8) The function f is defined by π(π₯) = π + ππππ 2π₯, for 00 ≤ x ≤ π. It is given that π π(0) = −1 and π ( 2 ) = 7 (i) (ii) (iii) Q5. Find the values of a and b. Find the x coordinates of the points where the curve π¦ = π(π₯) intersects the x-axis. Sketch the graph of π¦ = π(π₯). (J2007/P1/Q3) 1−tan2 π₯ Prove the identity 1+tan2 π₯ ≡ 1 − 2 sin2 π₯. [3] [3] [2] [4] MATH IN FOCUS WITH RAJA NADEEM AMIN 03215862394 Q6.(j2008/P1/Q2) (i) Show that the equation 2 tan2 π πππ π = 3 can be written in the form Q7. 2 cos 2 π + 3 πππ π − 2 = 0. [2] (ii) Hence solve the equation 2 tan2 π πππ π = 3, for 00 ≤ π ≤ 3600 . [3] (J2009/P1/Q4) The diagram shows the graph of π¦ = π π ππ(ππ₯) + π for 0 ≤ π₯ ≤ 2π. (i) Find the values of a, b and c. (ii) Find the smallest value of x in the interval 0 ≤ π₯ ≤ 2πο for which π¦ = 0. Q8. [3] [3] (J2009/P1/Q1) π πππ₯ π πππ₯ Prove the identity 1−π πππ₯ − 1+π πππ₯ ≡ 2 tan2 π₯ Q9. [3] (J2010/P1/Q1) The acute angle x radians is such that tan x = k, where k is a positive constant. Express, in terms of k, (i) π‘ππ(π − π₯), [1] π Q10. (ii) π‘ππ ( 2 – π₯), [1] (iii) sin x. [2] (J2010/P1/Q5) The function π is such that π(π₯) = 2 sin2 π₯ − 3 πππ 2π₯ for 0 ≤ π₯ ≤ π. (i) (ii) (iii) Express π(π₯) in the form π + π cos 2 π₯, stating the values of a and b. State the greatest and least values of π(π₯). Solve the equation (π₯) + 1 = 0 . [2] [2] [3] MATH IN FOCUS WITH RAJA NADEEM AMIN 03215862394 Q11. (J2011/P1/Q5) πππ π (i) Prove the identity π‘πππ( (ii) Hence solve the equation π‘πππ( Q12. 1 ≡ 1 + π πππ 1−π πππ ) πππ π 1−π πππ ) [3] = 4 for 00 ≤ π ≤ 3600 (J2012/P11/Q1) Solve the equation π ππ 2π₯ = 2 πππ 2π₯, for 00 ≤ π₯ ≤ 1800 . Q13. [3] [4] (J2012/P11/Q7) (a) The first two terms of an arithmetic progression are 1 and cos 2 π₯ respectively. Show that the sum of the first ten terms can be expressed in the form π – ππ ππ2 π₯, where a and b are constants to be found. [3] 1 (b) The first two terms of a geometric progression are 1 and 3 tan2 π respectively, where π 0 < π < 2. Q14. (i) Find the set of values of π for which the progression is convergent. (ii) Find the exact value of the sum to infinity when π = 6 . π [2] [2] (J2012/P12/Q5) (i) Prove the identity [2] 1 1 π‘πππ₯ + ≡ π‘πππ₯ π πππ₯πππ π₯ (ii) Solve the equation for 0 ≤ π₯ ≤ 1800 . Q15. (i) (ii) (iii) 1 = 1 + 3π‘πππ₯ π πππ₯πππ π₯ [4] The function f is such that π(π₯) = π – π πππ π₯ for 00 ≤ x ≤3600, where a and b are positive constants. The maximum value of π(π₯) is 10 and the minimum value is -2. Find the value of a and b. Solve the equation π(π₯) = 0. Sketch the graph of π¦ = π(π₯). [3] [3] [2] MATH IN FOCUS WITH RAJA NADEEM AMIN 03215862394 Q16. (J2014/P11/Q1) The diagram shows part of the graph of y = a + bsin x. State the values of the constants a and b. [2] Q17. (J2015/P11/8) π₯ The function π: π₯ → 5 + 3 cos (2) is defined for 0 ≤ π₯ ≤ 2π (i) (ii) (iii) (iv) Q18. Solve the equationπ(π₯) = 7, giving your answer correct to 2 decimal places. Sketch the graph of π¦ = π(π₯). Explain why f has an inverse. Obtain an expression for π −1 (π₯). [3] [2] [1] [3] (J2016/P11/Q11) π π The function f is defined by π βΆ π₯ → 4 π ππ π₯ − 1 for – 2 ≤ π₯ ≤ 2 . (i) (ii) (iii) (iv) Q19. State the range of f. [2] Find the coordinates of the points at which the curve π¦ = π(π₯) intersects the coordinate axes.[3] Sketch the graph of π¦ = π(π₯). [2] −1 −1 Obtain an expression for π (π₯), stating both the domain and range of π . [4] (J2017/P11/Q3) (a) Prove the identity 1+πππ π π πππ (b) Hence solve the equation π πππ 2 + 1+πππ π ≡ π πππ 1+πππ π π πππ π πππ [3] 3 + 1+πππ π = π πππ for 0 ≤ π ≤ 360 [3] MATH IN FOCUS WITH RAJA NADEEM AMIN 03215862394 Q20. (J2017/P11/Q3) The equation of a curve is π¦ = 2 πππ π₯. (i) Sketch the graph of π¦ = 2 πππ π₯ for −π ≤ π₯ ≤ π, stating the coordinates of the point of intersection with the y-axis. [2] π Points P and Q lie on the curve and have x-coordinates of 3 and π respectively. (ii) Find the length of ππ correct to 1 decimal place. [2] The line through π and π meets the π₯ − ππ₯ππ at π»(β, 0) and the π¦ − ππ₯ππ at πΎ(0, π). 5π (iii) Show that β = 9 and find the value of π. Q21. [3] (J2017/P12/Q3) (i) Prove the identity 2 1 1−π πππ (πππ π − π‘ππ π) ≡ 1+π πππ (ii) [3] Hence solve the equation 2 1 1 (πππ π − π‘ππ π) = 2 for 00 ≤ π ≤ 3600 Q22. Q23. [3] (J2017/P13/Q5) 2π πππ+πππ π (i) Show that the equation π πππ+πππ π = 2π‘πππ may be expressed as cos 2 π = 2 sin2 π (ii) (ii) Hence solve the equation π πππ+πππ π = 2π‘πππ for 00 < π < 1800 . 2π πππ+πππ π Prove the identity (i) (ii) (iii) (iv) (v) (vi) (vii) (viii) 1 − cos 2 π₯ ≡ sin2 π₯ (1 − sin2 π)π‘πππ ≡ πππ ππ πππ 1 sin2 π cos2 π − sin2 π ≡ 1 1 tan2 π ≡ cos2 π − 1 sin2 π −3 cos2 π+1 sin2 π−cos2 π 1 1 cos2 π ≡2 1 + sin2 π ≡ cos2 π sin2 π πππ π 1 π‘πππ + π πππ ≡ π ππππππ π 1 1+π πππ 1 2 + 1−π πππ ≡ cos2 π [3] [3] MATH IN FOCUS WITH RAJA NADEEM AMIN 03215862394 1−tan2 π₯ (ix) Prove the identity 1+tan2 π₯ ≡ 1 − 2 sin2 π₯ (x) Prove the identity πππ π₯ + 1+π πππ₯ ≡ πππ π₯ (xi) Prove the identity 1−π πππ₯ − 1+π πππ₯ ≡ 2 tan2 π₯ (xii) Prove the identity 1+π πππ₯ πππ π₯ π πππ₯ π πππ₯ 2 ( 1+πππ π (xiii) Prove the identity (xiv) Prove the identity π‘πππ( + π πππ π πππ 1+πππ π πππ π 1−π πππ ) ≡ 2 1 1 − π πππ − π‘ππ π) ≡ πππ π 1 + π πππ 2 π πππ 1 ≡ 1 + π πππ