NATIONAL
SENIOR CERTIFICATE
GRADE 10
PHYSICAL SCIENCES (P1)
COMMON TEST
SEPTEMBER 2019
MARKING GUIDELINES
TIME:
2 Hours
MARKS: 150
These marking guidelines consists of 12 pages.
Physical Sciences P1
2
Grade 10 - NSC
Common Test September 2019
QUESTION 1
1.1
B üü
(2)
1.2
Büü
(2)
1.3
Aüü
(2)
1.4
B üü
(2)
1.5
Aüü
(2)
1.6
C üü
(2)
1.7
D üü
(2)
1.8
D üü
(2)
1.9
B üü
(2)
1.10
A üü
(2)
(20)
QUESTION 2
2.1
Difference in position in space üü
OR
Change in position in space üü
2.2
2.2.1 Bü
C
7cm
ü
5cm
A
(2)
Dü
3cm
(3)
2.2.2
A
D
ü
1cm
(1)
2.2.3 300 m ü
2.2.4 20 mü
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(1)
east ü
(2)
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Physical Sciences P1
2.2.5
3
Grade 10 - NSC
Å POSITIVE MARKING FROM 2.2.2
v=
Δx
Δt
=
20 ü
150
ü
ü
= 0,13 m × s-1 eastü
2.3
2.3.1
Common Test September 2019
v=
D
ü
Δt
550 = 2200 ü
ý
Δt þ
ü
(3)
Δt = 4h
2.3.2
(4)
D
v=
Δt
500=
1100
Δt ü
Δt = 2,2h
ü
2.3.3
(2)
for the rest of the trip :
D = (2 200 - 1 100) = 1 100 km
Δt = (4 - 2,20 ) = 1,8 h
v=
=
D
Δt
1100ü
1,80
ü
= 611,11 km ×h-1 ü
(3)
[21]
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Physical Sciences P1
4
Grade 10 - NSC
Common Test September 2019
QUESTION 3
3.1
Its velocity is constant ü
(1)
3.2
The gradient / slope (for BCD) is the same. ü
OR
The gradient is constant ü
(1)
3.3
The train is now moving opposite to its original direction ü
OR
It is moving northwards ü
(1)
3.4.1
a =gradient ü OR a =
Δy
Δx
0 - 45 ü
= 20 - 5 ý ü
þ
=- 3m×s -2
(3)
a=3m×s - 2 northwards ü
3.4.2
a=
=
0 - (- 30)
ü
45 - 30
30
15
= 2m×s -2 northwards ü
3.5
3.5.1
(2)
ü
ï
ï
OR
ïý EITHER ONE ü
æ1
ö
æ1
ö
= (1´b) + b ´ h
+
b´h ï
ç
÷
ç
÷
è2
ø
è2
ø ïþ
ü æ1
ü ö æ 1
ü
ö
= (5´45)+ ´15´45 +
´25´[- 30]
÷
ç
÷ ç
è2
ø è2
ø
Δx =area under the graph
= 225
+ 337,50
ü
=187,50m
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+ (- 375 )
ü
southwards
(6)
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Physical Sciences P1
5
Grade 10 - NSC
Common Test September 2019
3.5.2 D= 225 + 337.50 + 375
= 937,50mü
3.6
(1)
POSITIVE MARKING FROM 3.4.1 AND 3.4.2
2
a
(m × s-2 )
30
45
Δt(s)
0
ü
ü
Correct labels and units on both axes
Horizontal line where a=0m.s-2 and Δt =5s
ü
Horizontal line where a=- 3m.s-2 and Δt =5 - 30s
Horizontal line where a= 2m.s- 2 and Δt = 30 - 45s
ü
(4)
[19]
QUESTION 4
4.1
4.2
4.3
The velocity decreases ü by 2.5 m.s-1 every second ü
ü
72000müý
-1
3600s = 20m.s
ü þ
OPTION 1
Distance = spree x time ü
= 20.0,4 ü
= 8m ü
(2)
(2)
OPTION 2
1
2
Dx = vi Dt + .a.Dt ü
2
= 20.0,4 + 0 ü
=8m ü
OPTION 3
æv +v ö
Dx = f i Dt ü
ç
÷
ç 2 ÷
è
ø
20 + 20
=
.0,4 ü
2
= 8m ü
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Physical Sciences P1
6
Grade 10 - NSC
Common Test September 2019
v f = v + aDt ü
i
4.4
ü
ü
0 = 20 + (- 2,5)Δt
Δt = 8s
Δttotal = (0,5 + 8 )
4.5
= 8,50 sü
OPTION 1
vf
2
(4)
2
= vi + 2aDx ü
2
(0) = (20)2 + 2 (- 2,5)Δx ü
Δx = 80 m ü
\motor car will stop ü
ü
Since it comes to a halt within (80 + 8
hich is less than 100m)
)m (w
[POSITIVE MARKING FROM 4.3]
OPTION 2
1
Δy =v Δt+ a Δt2 ü
i
2
1
2
= 20(8)+ (- 2,50)(8) ü
2
=80m ü
\motor car will stop ü
Since it covers (80 + 8)mü (which is less than 100m)
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(5)
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Physical Sciences P1
7
Grade 10 - NSC
Common Test September 2019
QUESTION 5
5.1
5.2
5.3
The energy of an object due to its position in the gravitational field ü
relative to some reference point ü
(2)
Ep = mgh ü OR U=mgh
= 45 x 9,8 x 1,15 ü
= 507,15 J ü
(3)
In an isolated system ü the total mechanical energy remains constant ü
(2)
5.4
Mechanical Energy on Ground = Mechanical Energy at Apple "ü EITHER ONE
ý
(Ep + Ek)
= (Ep + Ek)
ground
at Apple
þ
ü
1
= 507,15 + (45 )v2 = (45´9,8´2,50)+ 0
2
ü
v = 5,14m×s-1
5.5
5.6
ü
ü
(4)
Initial movement is not linear ü
OR
Motion is “pendulum-like” ü
OR
He is about to swing in an arc ü
(1)
Greater than ü
Ep would decrease ü While Ek increases ü Since Mechanical Energy has to
remain constant ü Therefore when Ek increase then (v) must also increase ü
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(5)
[17]
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Physical Sciences P1
8
Grade 10 - NSC
Common Test September 2019
QUESTION 6
6.1
When two waves occupy the same space at the same time,ü the resulting
amplitude is the algebraic sum of the amplitudes of two waves ü
(2)
6.2
20mm ü
(1)
6.3
Constructive ü
(1)
6.4
They are moving in opposite directions ü
(1)
6.5.1
f=
1
T
1
=
1,4
= 0,71Hz
6.5.2
ü
ü
(3)
ÅPOSITIVE MARKING FROM 6.5.1
0,12
l=
= 0,06
2
ü
v = f ´λ
= 0,71 ´ 0,06
= 0,04 m × s-1 ü
(3)
[11]
QUESTION 7
7.1 Does the frequency of the note decrease as the wavelength increases?üü
OR
Any question which mentions the two variables (frequency and wavelength) üü
(2)
7.2 Temperature ü (of the surrounding air)
(1)
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Physical Sciences P1
9
Grade 10 - NSC
Common Test September 2019
üü
ü
Plotting all 3 points correctly
Straight line graph passing through the origin
0
0,05
7.3
(3)
Frequency (Hz)
100
80
60
40
20
0,10
0,20
0,15
1
wavelength
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0,25
0,30
(m-1)
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Physical Sciences P1
7.4
gradient =
10
Grade 10 - NSC
84 - 44
ü
0,25 - 0,13
ü
Common Test September 2019
= 333,33 ü
OR
Any other suitable co-ordinates
(3)
7.5 Speed ü (of sound)
(1)
[10]
QUESTION 8
8.1
8.2.1
A packet of energy üü of light
E=
hc
λ
(2)
ü
(6,63´10-34 )(3´108 ) ü
=
(1 ´10-13 ) ü
=1,99´10-12 J
ü
8.2.2 Source 2 ü
It has a greater amount of energy compared to that of source 1 ü
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(4)
(2)
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Physical Sciences P1
11
Grade 10 - NSC
Common Test September 2019
QUESTION 9
9.1
A substance that is strongly attracted by magnets üü
OR
A substance that is easily magnetized üü
(2)
9.2
üü Pattern
ü
direction
(3)
[5]
QUESTION 10
10.1
Q
n=
ü
Qe
40 =
Q
- 1,6 ´10 19
(2)
Q = - 6,40 ´10-18Cü
10.2
Charge quantization ü
(1)
10.3
X to Y ü
(1)
10.4
Å= POSITIVE MARKING FROM10.1
Q+Q
Q= 1 2 2 ü
- 6,40´10-18 + (0 )
ü
=
2
=- 3,20´10-18C ü
(
10.5
)
Conservation of charge ü
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(1)
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Physical Sciences P1
12
Grade 10 - NSC
Common Test September 2019
QUESTION 11
11.1 The voltage measured across the terminals of the battery ü
when charges are flowing in the circuit ü
11.2 V = W ü
(2)
Q
3´10 4 ýüï ü
2,5´103 ï
þ
=
(3)
=12V ü
11.3
Q
I=
ü
Δt
=
3,24
ü
2
=1,62A
11.4
11.5
ü
(3)
0,97A ü
1
=
1
(1)
+
1
ü
R1 R2
1
1
= +
6
4
ü
\R9 = 2.40Ω
RP
\RT =RP +RR
7,40 = 2,40 +R
R = 5Ω
R
11.6
R
ü
(5)
Zero ü
(1)
[15]
TOTAL MARKS:
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