Chapter 8 Normal Distributions ■ sketch normal curves to illustrate distributions or probabilities ■ use a normal distribution to model a continuous random variable Continuous Random Variables • A continuous variable is a variable that can assume any value on a continuum (can assume an uncountable number of values) thickness of an item time required to complete a task temperature of a solution height, in inches Continuous Random Variables We talk about the probability of the random variable assuming a value within a given interval, NOT on a given particular value When X is a discrete random variable, we can represent 𝑷(𝑿 = 𝒓). When X is a continuous random variable, we can represent 𝑷(𝒂 ≤ 𝑿 ≤ 𝒃). Properties of Normal Distributions Normal distribution • A continuous probability distribution for a random variable, x. • The most important continuous probability distribution in statistics. • The graph of a normal distribution is called the normal curve. x © 2012 Pearson Education, Inc. All rights reserved. 4 of 105 Properties of Normal Distributions 1. The mean, median, and mode are equal. 2. The normal curve is bell-shaped and is symmetric about the mean. 3. The total area under the normal curve is equal to 1. 4. The normal curve approaches, but never touches, the x-axis as it extends farther and farther away from the mean. Total area = 1 μ © 2012 Pearson Education, Inc. All rights reserved. x 5 of 105 Properties of Normal Distributions 5. Between μ – σ and μ + σ (in the center of the curve), the graph curves downward. The graph curves upward to the left of μ – σ and to the right of μ + σ. The points at which the curve changes from curving upward to curving downward are called the inflection points. μ – 3σ μ – 2σ μ–σ © 2012 Pearson Education, Inc. All rights reserved. μ μ+σ μ + 2σ μ + 3σ 6 of 105 Means and Standard Deviations • A normal distribution can have any mean and any positive standard deviation. • The mean gives the location of the line of symmetry. • The standard deviation describes the spread of the data. μ = 3.5 σ = 1.5 © 2012 Pearson Education, Inc. All rights reserved. μ = 3.5 σ = 0.7 μ = 1.5 σ = 0.7 7 of 105 The mean gives the location of the line of symmetry. The standard deviation describes the spread of the data. Example: Understanding Mean and Standard Deviation 1. Which normal curve has the greater mean? Solution: Curve A has the greater mean (The line of symmetry of curve A occurs at x = 15. The line of symmetry of curve B occurs at x = 12.) © 2012 Pearson Education, Inc. All rights reserved. 9 of 105 Example: Understanding Mean and Standard Deviation 2. Which curve has the greater standard deviation? Solution: Curve B has the greater standard deviation (Curve B is more spread out than curve A.) © 2012 Pearson Education, Inc. All rights reserved. 10 of 105 Example: Interpreting Graphs The scaled test scores for the New York State Grade 8 Mathematics Test are normally distributed. The normal curve shown below represents this distribution. What is the mean test score? Estimate the standard deviation. Because the inflection points Solution: Because a normal curve is symmetric about the mean, you can estimate that μ ≈ 675. © 2012 Pearson Education, Inc. All rights reserved. are one standard deviation from the mean, you can estimate that σ ≈ 35. 11 of 105 Do Exercise 8A page 191-192 • Answer numbers 1a-f, 2a, 6 Homework (A4) Page 199 • Answer 8B numbers 1 a-f, 2 a-f QUESTIONS? Standard Normal Distribution A normal distribution with a mean of 0 and a standard deviation of 1. Area = 1 –3 –2 –1 z 0 1 2 3 • Any x-value can be transformed into a z-score by using the formula Value Mean x z Standard deviation Standard Normal Distribution • If each data value of a normally distributed random variable x is transformed into a z-score, the result will be the standard normal distribution. Normal Distribution σ z x x Standard Normal Distribution σ1 0 z • Use the Standard Normal Table to find the cumulative area under the standard normal curve. © 2012 Pearson Education, Inc. All rights reserved. 16 of 105 Example (page 196) Given that Z ~ N(0, 1), find P(Z < 1.23) and 𝑃(𝑍 ≥ 1.23) Example (page 196) Example (page 198) Given that Z ~ N(0, 1), find the value of a such that P(Z < a ) = 0.9072 Look at the table! closest to 0.9072 Example (page 196) Given that Z ~ N(0, 1), find the value of b such that 𝑃 𝑍 ≥ 𝑏 = 0.7113 Homework (A4) Page 199 • Answer 8B numbers 1 a-f, 2 a-f ANSWERS The time spent by shoppers in a large shopping centre has a normal distribution with mean 96 minutes and standard deviation 18 minutes. (a) Find the probability that a shopper chosen at random spends between 85 and 100 minutes in the shopping centre. 88% of shoppers spend more than t minutes in the shopping centre. (b) Find the value of t Cambridge International AS & A Level Mathematics 9709 Paper 52 Q3 November 2021 Past Papers Cambridge International AS & A Level Mathematics 9709 Paper 52 Q3 November 2021 Past Papers Cambridge International AS & A Level Mathematics 9709 Paper 52 Q3 November 2021 Do Exercise 8A page 191-192 • Answer numbers 3 a, e, I 4 a, c, e Standardising a Normal Distribution Value Mean x z Standard deviation Area = 1 –3 –2 –1 z 0 1 2 3 • Any x-value can be transformed into a z-score by using the formula Standardising a Normal Distribution Standardising transforms the distribution X ~ N(µ, σ2 ) to Z ~ N(0, 1) Useful Graphs Example (page 201) Given that X ~ N(11, 25), find P(X < 18) correct to 3 significant figures Example (page 201) Given that X ~ N(20, 7), find P(X ≤ 16.6) correct to 3 significant figures. Example (page 201) Given that X ~ N(5, 5), find 𝑃(2 ≤ 𝑧 < 9 correct to 3 significant figures Example (page 202) Given that Y ~ N(𝜇, 𝜎 2 ), P(Y <10) = 0.75 and 𝑃 𝑌 ≥ 12 = 0.1, find the values of µ and σ . A mathematical puzzle is given to a large number of students. The times taken to complete the puzzle are normally distributed with mean 14.6 minutes and standard deviation 5.2 minutes. (a) In a random sample of 250 of the students, how many would you expect to have taken more than 20 minutes to complete the puzzle? Cambridge International AS & A Level Mathematics 9709 Paper 51 Q4 May 2023 A mathematical puzzle is given to a large number of students. The times taken to complete the puzzle are normally distributed with mean 14.6 minutes and standard deviation 5.2 minutes. All the students are given a second puzzle to complete. Their times, in minutes, are normally distributed with mean - and standard deviation 3. It is found that 20% of the students have times less than 14.5 minutes and 67% of the students have times greater than 18.5 minutes. (b) Find the value of - and the value of 3. Cambridge International AS & A Level Mathematics 9709 Paper 51 Q4 May 2023 Past Papers • Cambridge International AS & A Level Mathematics 9709 Paper 51 Q4 May 2023 Past Papers • Cambridge International AS & A Level Mathematics 9709 Paper 51 Q4 May 2023 Do Exercise 8C page 204 • Answer numbers 1 a, b 2 a, c, f Homework (A4) Page 199 • Answer 8C numbers 3 a-d 4 a-d 7 9 11 12