Uploaded by Hassan Ali

673222-equation-sheet

advertisement
Oxford Cambridge and RSA
June 2023 only
GCSE (9–1) Physics A (Gateway Science)
J249 01/02/03/04
Equation Sheet
* 9 9 8 8 6 0 6 9 0 6 *
INSTRUCTIONS
• Do not send this Equation Sheet for marking. Keep it in the centre or recycle it.
INFORMATION
• This Equation Sheet is for the June 2023 examination series only.
• This Equation Sheet has 4 pages.
© OCR 2023 [601/8651/3]
DC (PQ) 327839/2
OCR is an exempt Charity
Turn over
© OCR 2023
J249 01/02/03/04
change in velocity
time
v–u
t
power =
work done
time
work done = force × distance (along the line of action of the force)
P=
W
t
W = Fs
p = mv
F = ma
force = mass × acceleration
HT momentum = mass × velocity
E = 2 m v2
1
v2 – u2 = 2 a s
a=
s = vt
kinetic energy = 2 × mass × (speed)2
1
(final velocity)2 – (initial velocity)2 = 2 × acceleration × distance
acceleration =
distance travelled = speed × time
P2 Forces
p = hρg
p V = constant
for a given mass of gas at a constant temperature:
pressure × volume = constant
HT pressure due to a column of liquid = height of column × density of liquid × gravitational field strength
E = ml
thermal energy for a change in state = mass × specific latent heat
V
ρ=m
ΔE = m c Δθ
mass
volume
change in thermal energy = mass × specific heat capacity × change in temperature
density =
P1 Matter
Key: HT = Higher Tier only
Equations in physics
2
© OCR 2023
J249 01/02/03/04
V = IR
E = QV
P = VI
P = I2 R
E = Pt
potential difference = current × resistance
energy transferred = charge × potential difference
power = potential difference × current
power = (current)2 × resistance
energy transferred = power × time
Vs
=
Turn over
Ns
Np
Vp
HT
potential difference across primary coil
number of turns in primary coil
=
potential difference across secondary coil
number of turns in secondary coil
F = BIl
HT force on a conductor (at right angles to a magnetic field) carrying a current:
force = magnetic flux density × current × length
P4 Magnetism and magnetic fields
Q = It
M = Fd
F
A
charge flow = current × time
P3 Electricity
moment of a force = force × distance (normal to direction of the force)
P=
E = mgh
gravitational potential energy = mass × gravitational field strength × height
force normal to a surface
area of that surface
W = mg
gravitational force = mass × gravitational field strength
pressure =
E = 2 k x2
1
F = kx
energy transferred in stretching = 2 × spring constant × (extension)2
1
force exerted by a spring = spring constant × extension
P2 Forces
3
© OCR 2023
useful output energy transfer
input energy transfer
J249 01/02/03/04
Vp Ip = Vs Is
v = fλ
OCR is part of Cambridge University Press & Assessment, which is itself a department of the University of Cambridge.
For queries or further information please contact The OCR Copyright Team, The Triangle Building, Shaftesbury Road, Cambridge CB2 8EA.
If OCR has unwittingly failed to correctly acknowledge or clear any third-party content in this assessment material, OCR will be happy to correct its mistake at the earliest possible opportunity.
OCR is committed to seeking permission to reproduce all third-party content that it uses in its assessment materials. OCR has attempted to identify and contact all copyright holders whose work is used in this paper. To avoid the issue of disclosure of answer-related information
to candidates, all copyright acknowledgements are reproduced in the OCR Copyright Acknowledgements Booklet. This is produced for each series of examinations and is freely available to download from our public website (www.ocr.org.uk) after the live examination series.
Copyright Information
Oxford Cambridge and RSA
potential difference across primary coil × current in primary coil = potential difference across secondary coil × current in secondary coil
P8 Global challenges
efficiency =
P7 Energy
wave speed = frequency × wavelength
P5 Waves in matter
4
Download