TABLE OF LEARNING MATERIALS I-1 MATHEMATICS (6A-2A) / PENCIL SKILLS PROGRAMME (ZI-ZII) The black mark ( ) indicates Starting Points. SCT: Standard Completion Time (Min./Sheet) This is the time in which the student should complete each worksheet, including time taken for corrections. (SCT is not used in Levels 6A-5A and ZI-ZII.) December 2012 Pencil Skills Programme ZI ZII 6A 5A 4A SCT 3A SCT 2A SCT 1-010 Colouring 1 001-010 Counting (Up to 5) 1 Number Reading Exercises (Up to 30) 1 Number Tracing Exercises 1 0.5–2 Numbers up to 100 Part 1 0.5–2 Review up to 3A 1–2 11-020 Colouring 2 011-020 Counting (Up to 5) 2 Number Reading Exercises (Up to 30) 2 Number Tracing Exercises 2 0.5–2 Numbers up to 100 Part 2 0.5–2 Adding 4 Part 1 (Up to 12+4) 1–2 21-030 Straight Lines 1 021-030 Counting (Up to 5) 3 Number Reading Exercises (Up to 30) 3 Number Tracing Exercises 3 0.5–2 Numbers up to 100 Part 3 0.5–2 Adding 4 Part 2 (Up to 16+4) 1–2 31-040 Straight Lines 2 031-040 Counting (Up to 10) 1 Number Reading Exercises (Up to 30) 4 Number Tracing Exercises 4 0.5–2 Numbers up to 100 Part 4 0.5–2 Adding 5 Part 1 (Up to 12+5) 1–2 41-050 Straight Lines 3 041-050 Counting (Up to 10) 2 Number Reading Exercises (Up to 30) 5 Number Writing Exercises up to 10 Part 1 0.5–2 Numbers up to 100 Part 5 0.5–2 Adding 5 Part 2 (Up to 15+5) 1–2 51-060 Curved Lines 1 051-060 Counting (Up to 10) 3 Number Reading Exercises (Up to 30) 6 Number Writing Exercises up to 10 Part 2 0.5–2 Numbers up to 100 Part 6 0.5–2 Adding up to 5 Part 1 1–2 61-070 Curved Lines 2 061-070 Counting (Up to 10) 4 Number Reading Exercises (Up to 30) 7 Number Writing Exercises up to 10 Part 3 0.5–2 Numbers up to 120 1–2 Adding up to 5 Part 2 1–2 71-080 Curved Lines 3 071-080 Counting (Up to 10) 5 Number Reading Exercises (Up to 30) 8 Number Writing Exercises up to 10 Part 4 0.5–2 Adding 1 Part 1 (Up to 12+1) 1–2 Adding 6 Part 1 (Up to 12+6) 1–2 81-090 Curved Lines 4 081-090 Counting (Up to 10) 6 Number Reading Exercises (Up to 30) 9 Number Writing Exercises up to 10 Part 5 0.5–2 Adding 1 Part 2 (Up to 18+1) 1–2 Adding 6 Part 2 (Up to 14+6) 1–2 91-100 Curved Lines 5 091-100 Counting (Up to 10) 7 Number Reading Exercises (Up to 30) 10 Number Writing Exercises up to 10 Part 6 0.5–2 Adding 1 Part 3 (Up to 24+1) 1–2 Adding 7 Part 1 (Up to 11+7) 1–2 1-010 Shapes and Pictures 1 101-110 Number Reading Exercises (Up to 10) 1 Sequence of Numbers (Up to 30) 1 Number Writing Exercises up to 20 Part 1 0.5–2 Adding 1 Part 4 (Up to 30+1) 1–2 Adding 7 Part 2 (Up to 13+7) 1–2 11-020 Shapes and Pictures 2 111-120 Number Reading Exercises (Up to 10) 2 Sequence of Numbers (Up to 30) 2 Number Writing Exercises up to 20 Part 2 0.5–2 Adding 1 Part 5 (Up to 60+1) 1–2 Adding up to 7 Part 1 1–2 21-030 Shapes and Pictures 3 121-130 Number Reading Exercises (Up to 10) 3 Sequence of Numbers (Up to 30) 3 Number Writing Exercises up to 30 Part 1 0.5–2 Adding 1 Part 6 (Up to 1000+1) 1–2 Adding up to 7 Part 2 1–2 31-040 Shapes and Pictures (Stories) 1 131-140 Number Reading Exercises (Up to 10) 4 Sequence of Numbers (Up to 40) 1 Number Writing Exercises up to 30 Part 2 0.5–2 Adding 2 Part 1 (Up to 14+2) 1–2 Adding 8 Part 1 (Up to 11+8) 1–2 41-050 Shapes and Pictures (Stories) 2 141-150 Number Reading Exercises (Up to 10) 5 Sequence of Numbers (Up to 40) 2 Numbers up to 50 Part 1 0.5–2 Adding 2 Part 2 (Up to 18+2) 1–2 Adding 8 Part 2 (Up to 12+8) 1–2 51-060 Shapes and Pictures (Stories) 3 151-160 Number of Dots (Up to 10) 1 Sequence of Numbers (Up to 40) 3 Numbers up to 50 Part 2 0.5–2 Adding 2 Part 3 (Up to 32+2) 1–2 Adding 9 (Up to 12+9) 1–2 61-070 Back and Forth 1 161-170 Number of Dots (Up to 10) 2 Sequence of Numbers (Up to 50) 1 Numbers up to 50 Part 3 0.5–2 Adding 3 Part 1 (Up to 14+3) 1–2 Adding 9 and 10 (Up to 12+9 and 15+10) 1–2 71-080 Back and Forth 2 171-180 Number of Dots (Up to 10) 3 Sequence of Numbers (Up to 50) 2 Numbers up to 50 Part 4 0.5–2 Adding 3 Part 2 (Up to 21+3) 1–2 Adding up to 10 Part 1 1–2 81-090 Corners and Curves 1 181-190 Number of Dots (Up to 10) 4 Sequence of Numbers (Up to 50) 3 Numbers up to 50 Part 5 0.5–2 Adding up to 3 Part 1 1–2 Adding up to 10 Part 2 1–2 91-100 Corners and Curves 2 191-200 Number of Dots (Up to 10) 5 Large Numbers Numbers up to 50 Part 6 0.5–2 Adding up to 3 Part 2 1–2 Adding up to 10 Part 3 1–2 Levels ZI & ZII (Shapes and Pictures) Level 6A (Counting) Z II 11a 6 A 1a Draw a line from the circle to the star. Count the pictures aloud, “1, 2,” while pointing to each one. Level 5A (Reading Numbers) 5 A 24b Level 3A (Adding 1) Level 4A (Writing Numbers) ` Write the number that comes next. Write the numbers. 13 3 + 1 = Three plus (1) tree To the parent(s): First demonstrate how to point to the pictures and count them. After finishing the exercise on each side of the worksheet, tick the box at the bottom. 13 14 15 (1) 4 + 5 = (2) 5 + 5 = (3) 3 + 5 = (4) 3 + 6 = (5) 6 + 6 = (6) 8 + 6 = (7) 5 + 7 = (8) 7 + 7 = (9) 9 + 7 = ( 10 ) 8 + 7 = one equals 4 + 1 = 5 Four 12 ` Add. 3 11 12 13 14 15 11 Level 2A (Adding up to 10) 2 A 200a 3 A 74b 4 A 104a Read the numbers. 11 12 jp.yagi.ka 2021/03/19 sg.wendy 2019/11/27 09:28:23 13:46:22 DD DR # plus one equals (2) 5 + 1 = (3) 6 + 1 = (4) 8 + 1 = © 2016 Kumon Institute of Education KIE KIE 2016 GB M_TLM_1.indd 1 2016/10/26 10:11 TABLE OF LEARNING MATERIALS I-2 MATHEMATICS (A-F) The black mark ( ) indicates Starting Points. SCT: Standard Completion Time (Min./Sheet) This is the time in which the student should complete each worksheet, including time taken for corrections. # October 2016 A SCT B SCT C SCT D SCT E SCT F SCT 001-010 Addition 1 (Review up to 2A) 1–2 Addition (Review up to A) 1–2 Review up to B 2–3 Review up to C 2–3 Review up to D 2–3 Review up to E 1 3–5 011-020 Addition 2 (Up to sum of 12) 1–2 Addition to 100 Part 1 1–2 Multiplication up to 3 2–3 Multiplication: 2 Digits * 2 Digits 1 2–4 Addition of Fractions 1 2–3 Review up to E 2 3–5 021-030 Addition 3 (Up to sum of 15) 1–2 Addition to 100 Part 2 2–3 Multiplication up to 5 2–3 Multiplication: 2 Digits * 2 Digits 2 2–4 Addition of Fractions 2 3–4 Multiplication and Division of 3 Fractions 4–6 031-040 Addition 4 (Up to sum of 18) 1–2 Addition to 100 Part 3 2–3 Multiplication up to 7 2–3 Multiplication: 2 Digits * 2 Digits 3 3–4 Addition of Fractions 3 3–4 Addition of 3 Fractions 1 3–5 041-050 Addition 5 (Up to sum of 20) 1–2 Addition of 2-Digit Numbers 1 2–3 Multiplication up to 9 2–3 Multiplication: 3 Digits * 2 Digits 3–5 Addition of Fractions 4 3–4 Addition of 3 Fractions 2 4–6 051-060 Addition 6 (Up to sum of 24) 1–2 Addition of 2-Digit Numbers 2 2–3 Multiplication: 2 Digits * 1 Digit 1 2–4 Addition and Subtraction 2–4 Addition of Fractions 5 3–5 Addition and Subtraction of 3 Fractions 4–6 061-070 Addition 7 (Up to sum of 28) 1–2 Addition of 2-Digit Numbers 3 2–3 Multiplication: 2 Digits * 1 Digit 2 2–4 Multiplication and Division 1 3–4 Addition of Fractions 6 3–5 Order of Operations (3 Fractions) 1 3–5 071-080 Addition 8 (Summary of addition) 2–3 Addition of 3-Digit Numbers 1 2–4 Multiplication: 2 Digits * 1 Digit 3 2–4 Multiplication and Division 2 3–4 Addition of Fractions 7 3–5 Order of Operations (3 Fractions) 2 3–5 081-090 Subtraction 1 (Subtracting 1) 1–2 Addition of 3-Digit Numbers 2 2–4 Multiplication: 2 Digits * 1 Digit 4 2–4 Division by 2-Digit Numbers 1 3–4 Addition of Fractions 8 3–5 Order of Operations (3 Fractions) 3 3–5 091-100 Subtraction 2 (Subtracting 2) 1–2 Addition of 3-Digit Numbers 3 3–5 Multiplication: 2 Digits * 1 Digit 5 2–4 Division by 2-Digit Numbers 2 3–5 Addition of Fractions 9 4–6 Order of Operations (3-or-More Fractions) 1 4–6 101-110 Subtraction 3 (Subtracting 3) 1–2 Subtraction 1 (Review up to A) 1–2 Multiplication: 3 or 4 Digits * 1 Digit 3–5 Division by 2-Digit Numbers 3 3–5 Subtraction of Fractions 1 3–4 Order of Operations (3-or-More Fractions) 2 4–6 111-120 Subtraction 4 (Subtracting up to 3) 1–2 Subtraction 2 (Review up to A) 2–3 Introduction to Division 2–3 Division by 2-Digit Numbers 4 3–5 Subtraction of Fractions 2 3–5 Order of Operations (3-or-More Fractions) 3 4–6 121-130 Subtraction 5 (Subtracting up to 5) 1–2 Subtraction of 2-Digit Numbers 1 2–3 Division with Remainders 1 2–3 Division by 2-Digit Numbers 5 3–5 Subtraction of Fractions 3 3–5 Order of Operations (3-or-More Fractions) 4 4–6 131-140 Subtraction 6 (From numbers up to 10) 1–2 Subtraction of 2-Digit Numbers 2 2–3 Division with Remainders 2 2–3 Division: Quotients of 2-or-More Digits 1 3–5 Addition and Subtraction of Fractions 4–6 Fractions and Decimals 1 3–5 141-150 Subtraction 7 (From numbers up to 11) 1–2 Subtraction of 2-Digit Numbers 3 2–3 Division with Remainders 3 2–3 Division: Quotients of 2-or-More Digits 2 4–6 Multiplication of Fractions 1 3–4 Fractions and Decimals 2 4–6 151-160 Subtraction 8 (From numbers up to 12) 1–2 Addition and Subtraction of 2-Digit Numbers 2–4 Division with Remainders 4 2–3 Fractions 3–5 Multiplication of Fractions 2 3–5 Fractions and Decimals 3 4–6 161-170 Subtraction 9 (From numbers up to 14) 1–2 Subtraction of 3-Digit Numbers 1 2–3 Division: 2 Digits / 1 Digit 1 2–3 Reduction 1 2–3 Division of Fractions 3–5 Solving Word Problems 1 4–6 171-180 Subtraction 10 (From numbers up to 16) 1–2 Subtraction of 3-Digit Numbers 2 2–4 Division: 2 Digits / 1 Digit 2 2–3 Reduction 2 2–3 Multiplication and Division of Fractions 3–5 Solving Word Problems 2 5–7 181-190 Subtraction 11 (From numbers up to 20) 1–2 Subtraction of 3-Digit Numbers 3 2–4 Division: 3 Digits / 1 Digit 1 3–4 Reduction 3 2–4 Four Operations of 2 Fractions 1 3–5 Decimals 1 3–5 191-200 Subtraction 12 (Summary of subtraction) 2–3 Subtraction of 3-Digit Numbers 4 3–5 Division: 3 Digits / 1 Digit 2 3–5 Reduction 4 2–4 Four Operations of 2 Fractions 2 3–5 Decimals 2 3–5 Level A (Subtraction) B 2B 1 a(Addition # Level to 100) Addition up to sum of 2-Digit Numbers 2 B 21 # C 5C 2 a(Multiplication) Level Multiplication: 2 Digits × 1 Digit 1 Name A 200a 1$2 (1) (4) jp.yagi.ka 2021/03/19 sg.wendy 2019/11/27 09:28:23 13:46:22 DD DR (5) 12 - 7 = 15 - 4 = 16 - 8 = (6) 13 - 7 = (7) 17 - 9 = (8) 14 - 5 = (9) 18 - 6 = ( 10 ) 19 - 2 = ( 11 ) 20 - 3 = © 2012 Kumon Institute of Education KIE KIE 2012 GB © 2012 Kumon Institute of Education KIE KIE 2012 GB (3) Time (1) (2) (3) (3) (4) (4) (5) (5) + 1$2 1 5 5 3$6 1 5 5 2 5 + 5 + 2 5 + 5 3 5 + 5 3 5 5 4 5 + 5 + 4 5 + 5 5 5 + 5 5 5 + 5 *: B 2 1 ( 6 ) *: B 2 1 ( 6 ) M_TLM_1.indd 2 : to 1$2 7 $ 10 11 $ 20 ( 6Date ) Time (6) (7) (7) (8) (8) (9) (9) ( 10 ) ( 10 ) 3$6 C 52a B 21 7 $ 10 11 $ 20 1/ 5 : + 1 5to 1 + 1 2 + 1 2 + 1 3 + 1 3 + 1 4 + 1 4 + 1 5 + 1 5 + 1 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 / (1) : * (2) (2) (3) (3) 3 2 2 1$2 3$6 (4) (4) (5) (5) 3 2 2 4 2 * 2 * 7 $ 10 (6) 11 $ 20 (6) (7) (7) 5 2 2 (8) 6 2 2 (9) 6 2 2 (9) 7 2 2 ( 10 ) * * * * 7 2 2 Date * Time 4 2 2 5 2 * 2 * * Time : / : to 1 (8) ( 10 ) 5 3/ :3 5 3 3 6 3 * 3 6 3 3 7 3 * 3 * * 7 3 3 * 8 3 3 * * 5$8 9 $ 16 8 3 3 9 3 3 9 3 3 / to (1) : / Date / : Time : to E 70a 1 D 81 2 1 2$4 ) ` Divide. (1) 2 1 ) (2) 4 5 4 2 2 3 4 5 4 2 2 3 4 7 4 2 2 2 1 ) 2 1 ) 4 7 4 2 2 1 ) 4 8 2 1 ) 4 8 (2) 3 R 5$8 R (4) 21*2 34 5 -4 2 R R R (3) / 21*2 45 -4 2 2 1 ): 6 R / 5 to R (5) 2 1 ) 6 5 (6) 2 1 ) 6 7 2 1 ) 6 7 2 1 ) 6 8 2 1 ) 6 8 (6) (7) (7) ) 4 9 2 1 ) 4 9 (4) F 1 2F1 a(Order of# Level Operations) Order of Operations (3-or-More Fractions) 4 : (1) 3 8 + 1 (1) ) 6 9 2 1 ) 6 9 3 2$3 3 (2) 34 (3) 10 (3) (4) 2 + + + 4$6 Time 7 = = 3 1 94 16 = = 11 20 +4 21 7 $ 12 / : F 121a E 70 : to = 1$2 3$4 / : / to / Date # 5$8 : Time Order of Operations (3-or-More Fractions) 4 ` Calculate. Date Time 3 9 + = 71 0 1 11 6 + 20 = 10 : ( 23 - 14 )*6 ` Calculate. = (1) = ( 23 - 14 )*6 3 8 (2) = (2) = = *4 3 8 F 121 : Name 1$2 (1) / to *4 - 3 10 3 10 3$4 5$8 (3) Date 5 6 Time = (3) ÷ 3:- 1 1 / 1 ÷3 -1 1 5 2 2 * 3 - 1 3 ÷2 = (4) = : 5 6 = (4) 1 / 1to 0 1 1 1 5 1 10 2 9 2 2 * 3 - 1 3 ÷2 2 9 4 5 (8) = 38 39 + 14 4 6 2 1 2 9 ` Add. (2) / Date # 7 $ 12 F 121 Name Name (4) 51 0 (5) + (8) 2 1 4$6 ` Add. ( 5Date ) Time R (3) 9 $ 16 2$3 Addition of Fractions 6 Name 2 1 E 70 Name # Division by 2-Digit Numbers 1 ` Divide. * * 2$4 D 81a C 52 Name ` Multiply. (1) / Date # Multiplication: 2 Digits × 1 Digit 1 ` Multiply. Name ` Add. (2) / : Level of Fractions) E 7 0Ea (Addition# Addition of Fractions 6 © 2016 Kumon Institute of Education KIE KIE 2016 GB © 2016 Kumon Institute of Education KIE KIE 2016 GB 11 - 6 = / Date # D 81 Name © 2016 Kumon Institute of Education KIE KIE 2016 GB © 2016 Kumon Institute of Education KIE KIE 2016 GB (2) 11 $ 20 ` Add. D 8D 1 a(Division) # Level Division by 2-Digit Numbers 1 © 2012 Kumon Institute of Education KIE KIE 2012 GB © 2012 Kumon Institute of Education KIE KIE 2012 GB 10 - 3 = 7 $ 10 Addition up to sum of 2-Digit Numbers 2 © 2012 Kumon Institute of Education KIE KIE 2012 GB © 2012 Kumon Institute of Education KIE KIE 2012 GB (1) 3$6 B 21a ` Subtract. C 52 Name (5) 76 + 72 1 = (6) + = 8 24 D 83 ( 3 ) (6) 7 8 + 7 24 = D 83 ( 3 ) 2016/10/26 10:11 TABLE OF LEARNING MATERIALS II-1 (Level G to L) The black mark ( ) indicates most suitable Starting Points. SCT: Standard Completion Time (Min./Sheet) This is the set time in which the student should complete each worksheet, including time taken for correction. October 2016 G SCT H SCT I SCT J SCT K SCT L SCT 001-010 Review up to F 1 3–5 Basics for Level H Mathematics 1 4–6 Basics for Level I Mathematics 4–6 Expansion of Polynomial Products 5–8 Review of Linear Functions 4–6 Logarithmic Functions 6–12 011-020 Review up to F 2 3–5 Basics for Level H Mathematics 2 4–6 Multiplication of Polynomials 4–6 Factorisation I 5–8 Review of Quadratic Functions 5–8 Graphs of Logarithmic Functions 7–14 021-030 Addition and Subtraction of Positive and Negative Numbers 1 2–4 Literal Equations 1 4–6 Multiplication Using Formulas 4–6 Factorisation II 5–8 Quadratic Functions and Graphs 6–12 Logarithmic Equations and Inequalities 8–16 031-040 Addition and Subtraction of Positive and Negative Numbers 2 3–5 Literal Equations 2 4–6 Factorisation 1 4–6 Factorisation III 6–10 Determining Equations of Quadratic Functions 7–14 Modulus Functions 8–16 041-050 Addition and Subtraction of Positive and Negative Numbers 3 3–5 Simultaneous Equations in Two Variables 1 4–6 Factorisation 2 4–6 Factorisation IV 6–10 Maxima and Minima of Quadratic Functions I 7–14 Limits and Derivatives 8–16 051-060 Addition and Subtraction of Positive and Negative Numbers 4 4–6 Simultaneous Equations in Two Variables 2 4–6 Factorisation 3 4–6 Factorisation V 7–12 Maxima and Minima of Quadratic Functions II 7–14 Tangents 12–24 061-070 Multiplication of Positive and Negative Numbers 3–5 Simultaneous Equations in Two Variables 3 4–6 Factorisation 4 4–6 Fractional Expressions 6–10 Maxima and Minima of Quadratic Functions III 8–16 Relative Maxima and Minima I 15–30 071-080 Division of Positive and Negative Numbers 4–6 Simultaneous Equations in Two Variables 4 4–6 Factorisation 5 4–6 Irrational Numbers I 5–8 Quadratic Functions and Equations 7–14 Relative Maxima and Minima II 15–30 081-090 Four Operations with Positive and Negative Numbers 1 4–6 Simultaneous Equations in Two Variables 5 4–6 Square Roots 1 4–6 Irrational Numbers II 6–10 Quadratic Functions and Inequalities 7–14 Maxima and Minima I 15–30 091-100 Four Operations with Positive and Negative Numbers 2 4–6 Simultaneous Equations in Three and Four Variables 1 4–6 Square Roots 2 4–6 Quadratic Equations I 5–8 Quadratic Functions and Solutions of Quadratic Equations 8–16 Maxima and Minima II 15–30 101-110 Values of Algebraic Expressions 1 4–6 Simultaneous Equations in Three and Four Variables 2 4–6 Square Roots 3 4–6 Quadratic Equations II 6–10 Higher Degree Functions 6–12 111-120 Values of Algebraic Expressions 2 4–6 Application of Equations 4–6 Quadratic Equations 1 4–6 Quadratic Equations and Complex Numbers 6–10 121-130 Simplifying Algebraic Expressions 1 3–5 Inequalities 1 4–6 Quadratic Equations 2 4–6 Discriminant 6–10 Graphs of Fractional Functions I 131-140 Simplifying Algebraic Expressions 2 3–5 Inequalities 2 4–6 Quadratic Equations 3 4–6 Root-Coefficient Relationships 6–10 141-150 Simplifying Algebraic Expressions 3 4–6 Functions and Graphs 1 4–6 Graphs of Quadratic Functions 1 4–6 Simultaneous Equations 151-160 Simplifying Algebraic Expressions 4 4–6 Functions and Graphs 2 4–6 Graphs of Quadratic Functions 2 4–6 161-170 Linear Equations 1 3–5 Functions and Graphs 3 4–6 Graphs of Quadratic Functions 3 171-180 Linear Equations 2 4–6 Functions and Graphs 4 4–6 181-190 Linear Equations 3 4–6 Simplifying Monomials and Polynomials 1 191-200 Linear Equations 4 4–6 Simplifying Monomials and Polynomials 2 H-041-050 Level G # G 145a (Simplifying Algebraic Expressions) Simplifying Algebraic Expressions 3 G 145 Name G 145a 1 5$8 # 9 16 $ 1 Time : H-041-050 : / Date 2$4 5$8 9 $ 16 Time : Ex. R100% { : 5a - 4 ( 3a - 2b ) = 3a - 2 ( 4a - b ) = 3a - 8a + 2b = - 5a + 2b Date Time Name Grade Date Mistakes / : / to B1 70% B1 70% / : [Sol] 1-2x= 16/03/18 18:04 y= Ans.(x,y)=( Definite Integrals II 12–24 6–10 Fractional Equations and Inequalities 8–16 Areas I 15–30 Dividing Polynomials 6–10 Graphs of Irrational Functions 7–14 Areas II 15–30 4–6 Remainder Theorem 6–10 Irrational Equations and Inequalities 8–16 Volumes 15–30 The Pythagorean Theorem 1 4–6 Factor Theorem 6–10 Exponential Functions 6–12 Velocity and Distance 15–30 4–6 The Pythagorean Theorem 2 4–6 Proof of Identities 6–10 Graphs of Exponential Functions 7–14 Summary of Differentiation and Integration I 30–60 4–6 The Pythagorean Theorem 3 4–6 Proof of Inequalities 7–12 Exponential Equations and Inequalities 8–16 Summary of Differentiation and Integration II 30–60 50% D Substituting x=this into 1 , , I-041-050 ) +3y=30 y= y= Ans.(x,y)=( , 2:08 PM I 44 Page 8 Name Date / Time Name R100% Grade 0 Factorisation 2 ` Factorise using the following formula. 100% Date Mistakes A1~2 : 90% Time B3~6 / : A1~2 B3~6 Formula 0 x¤+(a+b)x+ab=(x+a)(x+b) ` Factorise using the following formula. 49% Grade Mistakes 90% / to 70% to 70% C 7/30/09 2:00 PM Page 8 J_131-140*.q 7/30/09 2:00 PM Page 8 J 134å I 44 : 50% 7~11 / C J_131-140*.q Level J (Root-Coefficient Relationships) 50% 49% 12~22 : 7~11 D (3+2) 3'2 ( 2 ) x¤+7x+10= ( 1 ) x¤+5x+6=(x+ (3+2) 3'2 ( 3 ) x¤+8x+15= ( 2 ) x¤+7x+10= ( 4 ) x¤+3x+2= ( 3 ) x¤+8x+15= ( 5 ) x¤+5x+4= ( 4 ) x¤+3x+2= ( 6 ) x¤-5x+6=(x-3)(x( 5 ) x¤+5x+4= ( 7 ) x¤-6x+8= ( 6 ) x¤-5x+6=(x-3)(x( 8 ) x¤-7x+10= ( 7 ) x¤-6x+8= ( 9 ) x¤-8x+15= ( 8 ) x¤-7x+10= (10) x¤-7x+12= ( 9 ) x¤-8x+15= jp.chosa.yu 2016/11/01 14:24:08 R )(x+2) (10) x¤-7x+12= ) ) ME_TLM_2.indd 1 Date Time Name Grade mistakes D 49% 12~22 100 0 % Date / / : B 70% /1 50% 2~3 / D % 70% (1) (å-∫)¤ å¤+∫¤=(å+∫)¤-2å∫=4¤-2*5=6 [Sol] (å-∫)¤=(å+∫)¤-4å∫ =4¤-4*5 =-4 [Sol] (å-∫)¤=(å+∫)¤-4å∫ =4¤-4*5 =-4 (1) (2) (å-∫)¤ å¤∫+å∫¤ [Sol] å¤∫+å∫¤=å∫(å+∫) =5*4 =20 [Sol] å¤∫+å∫¤=å∫(å+∫) =5*4 =20 ( 3 ) å¤+å∫+∫¤=(å+∫)¤-å∫ =16-5 =11 ( 3 ) å¤+å∫+∫¤=(å+∫)¤-å∫ =16-5 =11 (2) å¤∫+å∫¤ jp.chosa.yu 2016/11/01 14:24:55 R jp.chosa.yu 2016/11/01 14:24:31 R jp.chosa.yu 2016/11/01 14:23:40 R jp.chosa.yu 2016/11/01 14:24:55 R jp.chosa.yu 2016/11/01 14:24:08 R Date R Grade / Time Name 100 0 : % Date / /1 70% C : 2/ 1 L_061-070* 50% D 2 [Sol] y=x¤-6x+4 Ex. =(x-3)¤-5 When 2≤x≤6. Since 2≤x≤6, the graph is the solid curve shown on the figure [Sol] y=x¤-6x+4 below. =(x-3)¤-5 Since 2≤x≤6, y the graph is the solid curve shown on the figure 4 below. O 4 -4 -5 O y 2 3 2 3 6 6 x x From the graph: • There is-4 a maximum value of 4, -5 at x=6. • There a minimum value of From theis graph: -5, atisx=3. • There a maximum value of 4, Therefore, at x=6. the range is •-5≤y≤4. There is a minimum value of -5, at x=3. Therefore, the range is -5≤y≤4. O y -5 O -1 the figure below. 3 5 3 5 x x From the graph: • There is a maximum value of -5 4, at x=0. • There a minimum value of From theis graph: -5, atisx=3. • There a maximum value of Therefore, the range is 4, at x=0. •-5≤y≤4. There is a minimum value of -5, at x=3. Therefore, the range is -5≤y≤4. • The set of x values is called the domain. The set of y values is called the range. • The domain is normally written in brackets next to the function, e.g. y=x¤-6x+4 (2≤x≤6) • The set of x values is called the domain. The set of y values is called the range. • The domain is normally written in brackets next to the function, e.g. y=x¤-6x+4 (2≤x≤6) Page 12 Date L 66 / Time Name R Grade 100 0 / : Grade 100 C 70% /1 Relative Maxima and Minima I Time : 1. Given y=-x‹+x¤+x-1, complete the questions below. (1) B % L 66 to B % Date : 50% 2/ 70% C 49% D 49% 3~4 to 0 1 Create a variation table to findmistakes the relative extreme values. D : 50% 2 3~4 1. Given y=-x‹+x¤+x-1, complete the questions below. [Sol] From y`=-3x¤+2x+1=-(3x+1)(x-1)=0, 1 Createx=a variation , 1table to find the relative extreme values. 3 [Sol] From y`=-3x¤+2x+1=-(3x+1)(x-1)=0, … -1 … … x 1 1 3 x=- , 1 y` - 3 0 0 + - (1) Since 0 ≤x≤ 5 , draw the 4 -1 4:55 PM mistakes 3~5 Since 0 ≤x≤ 5 , draw the [Sol] y=x¤-6x+4 graph on the figure below. y= (x-3)¤-5 y Page 12 Relative Maxima and Minima I 49% y= 0≤x≤5. (x-3)¤-5 When graph4 on 4/27/09 L 66å 49% 3~5 [Sol] y=x¤-6x+4 (1) 4:55 PM Name K 43 to B 4/27/09 Level L (Relative R and Minima) L 66å Maxima Ex. 1. Given y=x¤-6x+4, draw the graph corresponding to each given When 2≤x≤6. ( 1 )set of When 0≤x≤5. condition. Then find the corresponding y values (the range). Ex. [Sol] å+∫=4, å∫=5 K 43 Page 6 0 49% expressions. å¤+∫¤ å¤+∫¤=(å+∫)¤-2å∫=4¤-2*5=6 å¤+∫¤ 11:21 AM Maxima and Minima of Quadratic Functions I Time to : 1. Given y=x¤-6x+4, draw the graph corresponding to: each given Grade 100 condition. Then find the corresponding set of% y values (the 70% C 50% D B range). mistakes 49% mistakes [Sol] å+∫=4, å∫=5 L_061-070* mistakes 4~6 50% 05.3.11 K 43å : C Page 6 Name J 134 to 11:21 AM Maxima and Minima of Quadratic Functions I 1. Ex. If the roots of x¤-4x+5=0 are å and ∫, evaluate the following jp.chosa.yu 2016/11/01 14:24:31 R MNT_M_WS_G_141.indd 9 Root-Coefficient Relationships J 134å R K_041-050 J 134 Name 05.3.11 Level K R of Quadratic Functions) (Maxima K 43åand Minima Time to : 1. If the roots of x¤-4x+5=0 are å and ∫, evaluate :the following Grade 100 C D B expressions. 0 1 2~3 4~6 (4+2) 4'2 Ex. x¤+6x+8=(x+4)(x+2) ( 1 ) x¤+5x+6=(x+ )(x+2) (4+2) 4'2 R Root-Coefficient Relationships Ex. x¤+6x+8=(x+4)(x+2) Formula x¤+(a+b)x+ab=(x+a)(x+b) ) ) 04.12.22 I 44å Substituting this into 1 , 3y= 3y= , Ans.(x,y)=( K_041-050 Page 8 Factorisation 2 49% x= +3y=30 ) 2:08 PM Level I (Factorisation) R I 44å 4~6 : C D '''2 [Sol] 1-2 : x= Substituting 3x= this into 1 , +3y=30 y= jp.chosa.yu 2016/11/01 14:23:40 R Mistakes x= {5x+2y=8 '''2 3y= , Ans.(x,y)=( 3x - 2 ( 4x - 3y ) = Grade { Substituting this into 1 , 3y= ( 7 ) 3x + 2 (- 4x + 3y ) = ( 8 ) 3x - 2 ( 4x - 3y ) = 50% ) same 8x+3y=30 '''1 7x+2y=12 '1the ones Note Two linear equations with( 2the variables, such''as 5x+3y=21 '''2 5x+2y=8 '''2 above, are called simultaneous linear equations in two variables. [Sol] 1-2 : [Sol] 1-2 : ( 1 ) 8x+3y=30 '''1 ( 2 ) 7x+2y=12 '''1 x=+3y=30 ( 6 ) 5x - 2 ( x - 3y ) = ( 7 ) 3x + 2 (- 4x + 3y ) = to 2~3 / { 3x= {5x+3y=21 7–14 © 2002 Kumon Institute of Education 2005 GB in Malaysia © 2002 Kumon Institute of KIE Education KIEPrinted 2005 GB Printed in Malaysia ( 5 ) 3x - 4 ( x - 2y ) = ( 6 ) 5x - 2 ( x - 3y ) = 100% { Graphs of Fractional Functions II H41 : C 2~3 4~6 < > Ex. 5x+2y=11 '''1 0 <Method 1. Number equation. ` Solve the following equations in theeach example. 3x+2y=5 '''2 as shown 2. Subtract one equation from the [Sol] 1-2 : <Method < other to>remove one variable. Ex. 5x+2y=11 '''1 1. Number5x+2y=11 each equation. 2x=6 3x+2y=5 '''2 2. Subtract one equation from the - 3x+2y=05 2x=3 : [Sol] 1-2 other ˘ to2x-2y=06 remove one variable. Substituting x. 5x+2y=11 2x=6 this into 1 , 3. Solve for - 3x+2y=05 5*3+2y=11 4. Substitute the value of x in one 2x=3 ˘ 2x-2y=06 of the given equations and solve 2y=-4 Substituting this into 1 , 3. for Solve y. for x. y=-2 5*3+2y=11 Substitute the value of x in one 5. Write the answer. Ans.(x,y)=( 3 ,-2) 4. of the given equations and solve 2y=-4 for same y. variables, such as the ones Note Two linear y=-2 equations with the Write the answer. Ans.are (x,y)=( 3 ,-2) 5. above, called simultaneous linear equations in two variables. (1) 12–24 © 2002 Kumon Institute of Education 2005 GB © 2002 Kumon Institute of KIE Education KIE 2005 GB ( 4 ) 4a - 2 (- 3a - 5b ) = ( 5 ) 3x - 4 ( x - 2y ) = Definite Integrals I © 2002 Kumon Institute of Education 2005 GB in Malaysia © 2002 Kumon Institute of KIE Education KIEPrinted 2005 GB Printed in Malaysia +22((-=) = 3a4a3a b )5b ((43)) 4a 7–14 © 1998 Kumon © 1998 Institute Kumon of Education Institute of KIE Education 2005 GB KIE 2005 GB -23((4a = 2a+ a+ ((32)) 3a -4b b ))= MNT_M_WS_G_141.indd 9 H41 Page 2 Simultaneous Equations in Two ` Solve the following equations as shown in the example. Time : Variables 1 -34((a 5a3a )= ((21)) 2a +4b2b )= (8) 6:47 PM 8–16 04.12.22 Higher Degree Equations and Inequalities 7–14 Applications to Equations and Inequalities 15–30 Indefinite and Definite Integrals I-041-050 0 ` Simplify. (1) Page 2 Simultaneous Equations in Two Variables 1 / to 04.12.22 H41å G 145 © 1998 Kumon © 1998 Institute Kumon of Education Institute of KIE Education 2005 GB KIE 2005 GB © 2016 Kumon Institute of Education KIE KIE 2016 GB © 2016 Kumon Institute of Education KIE KIE 2016 GB 3a - 2 ( 4a - b ) = 3a - 8a + 2b = - 5a + 2b 6:47 PM Name / to 04.12.22 Level H R (Simultaneous Equations) H41å Name ` Simplify. Ex. / Date 2$4 Simplifying Algebraic Expressions 3 sg.wendy 2021/03/19 09:28:23 DD R yx (2) 1 (2) 1 2 2 1 … - 32 3 27 … 10 1 32 Find x-intercept(s) and y-intercept, - 3graph. Thethe relative minimum value is - 27then , atdraw x= the . x-intercept(s) Find the -x‹+x¤+x-1=0, x-intercept(s) and y-intercept, then draw the graph. From -x¤(x-1)+(x-1)=0 x-intercept(s) -(x-1)¤(x+1)=0 From -x‹+x¤+x-1=0, x=1, -1 -x¤(x-1)+(x-1)=0 Ans. (1, 0), (-1, 0) -(x-1)¤(x+1)=0 x=1, -1 y-intercept Ans. (1, 0), (-1, 0) Substituting x=0, y=-1 Ans. (0, -1) y-intercept Substituting x=0, y=-1 jp.chosa.yu 2016/11/01 14:25:17 R … 0 0 y` + The relative maximum value is 0 , at x= 1 . y - 32 0 27 32 1 The relative minimum value is , at x= . The relative maximum value is 027 , at x= 1 3. Ans. (0, -1) y -1 -1 y1 1� 3 O 1 1� 3 O � � -1 32 27 -1 1 x 1 x 32 27 © 2016 Kumon Institute of Education KIE KIE 2018 GB jp.chosa.yu 2016/11/01 14:25:17 R 16/03/18 18:04 18/03/23 14:36 TABLE OF LEARNING MATERIALS II-2 (Level M to X) R SCT: Standard Completion Time (Min./Sheet) This is the set time in which the student should complete each worksheet, including time taken for correction. March 2018 XV SCT 001-010 Surface Vectors I 6–12 25–50 011-020 Surface Vectors II Concavity of Curves 25–50 021-030 15–30 Maxima and Minima 25–50 Recurrence Relations 20–40 Various Applications of Differentiation 15–30 Mathematical Induction 20–40 Loci II 15–30 Infinite Sequences 071-080 Regions 15–30 081-090 Trigonometric Ratios I 091-100 M SCT N SCT O SCT XM SCT XP SCT 001-010 Points and Lines I 10–20 Arithmetic Sequences 10–20 Tangents and Normals 20–40 01-010 Matrix Definitions, Addition and Subtraction 6–12 01-010 Introduction to Permutations 6–12 011-020 Points and Lines II 10–20 Geometric Sequences 10–20 Increasing/Decreasing Functions and Relative Extreme Values 8–16 11-020 Matrix Multiplication 8–16 11-020 Permutations 6–12 021-030 Points and Lines III 15–30 Various Sequences I 15–30 Surface Vectors III 8–16 21-030 Inverse Matrices 10–20 21-030 Permutations and Combinations 8–16 031-040 Circles I 15–30 Various Sequences II 031-040 Surface Vectors IV 10–20 31-040 Equations and Matrices 10–20 31-040 Combinations 10–20 041-050 Circles II 15–30 25–50 041-050 Coordinates in Space 6–12 41-050 Mapping I 8–16 41-050 Binomial Theorem 12–24 051-060 Loci I Indefinite Integrals I 15–30 051-060 Vectors in Space 8–16 51-060 Mapping II 10–20 51-060 Probability 8–16 061-070 10–20 Indefinite Integrals II 15–30 061-070 Basics of Inner Products of Vectors 8–16 61-070 Transformations I 8–16 61-070 Conditional Probability 10–20 Infinite Geometric Sequences 15–30 Integration by Substitution 15–30 071-080 Inner Products of Vectors 8–16 71-080 Transformations II 10–20 71-080 Independent Trials 12–24 10–20 Infinite Geometric Series 15–30 Integration by Parts 20–40 081-090 Applications and Summary of Vectors 10–20 81-090 Transformations III 10–20 81-090 Expected Value 12–24 Trigonometric Ratios II 10–20 Infinite Series 15–30 Definite Integrals 15–30 091-100 Vectors and Figures 10–20 101-110 Properties of Trigonometric Functions I 10–20 Limits of Functions I 15–30 Integration by Substitution for Definite Integrals 15–30 101-110 Equations of Lines and Planes in Space I 10–20 111-120 Properties of Trigonometric Functions II XS SCT 10–20 Limits of Functions II Integration by Parts for Definite Integrals and 15–30 20–40 Functions Represented by Definite Integrals 111-120 Equations of Lines and Planes in Space II 10–20 01-010 Introduction to Statistics 8–16 121-130 Trigonometric Equations 10–20 Limits of Trigonometric Functions 15–30 Integration by Quadrature and Proof of Inequalities 25–50 121-130 Equations of Lines and Planes in Space III 12–24 11-020 Binomial Distribution 8–16 131-140 Graphs of Trigonometric Functions 15–30 Continuous and Discontinuous Functions 20–40 Areas 25–50 131-140 Equations of Lines, Planes and Spheres 12–24 21-030 Probability Density Function 10–20 141-150 Trigonometric Inequalities 15–30 Differentiation I 15–30 Volumes 25–50 31-040 Standard Normal Distribution I 12–24 151-160 Addition Formulas I 15–30 Differentiation II 15–30 Length of a Curve, Velocity and Distance 25–50 41-050 Standard Normal Distribution II 12–24 161-170 Addition Formulas II 15–30 Differentiation of Trigonometric Functions 15–30 Differential Equations 25–50 51-060 Sampling 15–30 171-180 Addition Formulas III 15–30 Differentiation of Logarithmic and Exponential Functions 15–30 Natural/Social Science and Differential Equations 30–60 61-070 Hypothesis Testing 15–30 181-190 Sine and Cosine Rules 15–30 Applications of Calculus I 30–60 191-200 Area of Triangles 15–30 Applications of Calculus II 30–60 Differentiation of Various Functions 20–40 and Higher Order Derivatives Various Properties of Derivatives 25–50 XV 091-100* # 1 2 : to H b c 2 2 a =C H a+B H2+c 2-2bc cos A is true. Therefore, =b B a 2 B B =( b sin A ) 2+( c-b cos A ) 2 Answers: in order b sin A, b cos A, c-b cos A, b sin A, c-b cos A 2 2 sin A+ cos A=1 =b 2+c 2-2bc cos A 2 A is an obtuse WhenTherefore, true. B is an obtuse angle, a 2=bangle, +c 2-2bc cos A isWhen C H=b sin ( 180^-A )=b sin A C H=b sin A Answers: in order b sin A, b cos A, c-b cos A, b sin A, c-b cos A B H=A B+A H B H=A H-A B A is ancos When=c+b obtuse angle,) ( 180^-A When B is an obtuse angle, =b cos A-c C H=b sin A a 2=C H 2+B H 2 B H=A H-A2B =( b sin A ) +( b cos A-c ) 2 =b cos A-c =b 2+c 2-2bc cos A a 2=C H 2+B H 2 =c-b A C H=b 180^-A )=b sin A sin (cos 2 2 =C HB+A +B H a 2H=A B H =( b sin A ) +( c-b cos =c+b ( 180^-A ) A) cos 2 2 =b +c 2cos -2bc =c-b A cos A Ca 2 =C H 2+B H 2 c A B a B A A C H B b b Therefore, when either A or B is an obtuse angle, a 2=b 2+c 2-2bc cosaA. A B B A or B Bis a right A angle. A It His also true when either c c A B Similarly, b 2=c 2+a 2-2ca cos B and c 2=a 2+b 2-2ab cos C are true. 2 2 2 ARule. Therefore, when or B is an obtuse angle, a =b +c -2bc cos A. This is called the either Cosine It is also true when either A or B is a right angle. Similarly, b 2=c 2+a 2-2ca cos B and c 2=a 2+b 2-2ab cos C are true. H This is called the Cosine Rule. ME_WS_M_181.indd 7 ME_WS_M_181.indd 7 ME_TLM_2.indd 2 AA BB A B a a a a a a a a a a a a a a [ f ( x ) g ( x ) ]s=fs( x ) g ( x )+f ( x ) gs( x ) 1 n n b bb a b a a Using this constant value e, log e e 1 1 xA log a e= ys= = 1 When a=e, log therefore, from , x logA x e a= log e e=1 x ; log ea e ays= 1 When a=e, log e a= log e e=1; therefore, from A, ys= x x log a M= When a=e, log e a= log e e=1; therefore, from A, ys= 1 When examining the value of ( 1+k ) k1 by When examining value which of ( 1+k ) k byto 0, k withthe a value is close substituting a value which is closeonto 0, substituting it approachesk awith constant value as shown it approaches value as shown irrational number and on the right. e is aanconstant the right. e is an.irrational number and1 e=2.7182818 x the value of ( 1+k ) k by When examining e=2.7182818 x. substituting k with a value which is close to 0, it approaches a constant value as shown on the right. e is an irrational number and e=2.7182818x. ME_WS_N_171.indd 1 18/03/02 11:56 18/03/02 11:56 ME_WS_N_171.indd 1 ME_WS_N_171.indd 1 k k 1 x log b M log b a ( 1+k ) ( 1+k ) 0.1 2.59374x 0.1 2.59374x 0.01 2.70481 x 0.01 2.70481x 0.001 2.71692 x 0.001 2.71692x 1 0.0001 2.71814 k k ( 1+k ) x 0.0001 2.71814 0.00001 2.71826x x 0.00001 2.71826 0.1 2.59374x 0.01 2.70481x 0.001 2.71692x 0.0001 2.71814x 0.00001 2.71826x k k -0.1 -0.1 -0.01 -0.01 -0.001 -0.001 -0.0001 k -0.0001 -0.00001 -0.00001 -0.1 -0.01 -0.001 -0.0001 -0.00001 ( 1+k ) ( 1+k ) 2.86797x 2.86797x 2.73199 x 2.73199x 2.71964 x 2.71964x 1 2.71841 k ( 1+k ) x 2.71841 2.71829x x 2.71829 2.86797x 2.73199x 2.71964x 2.71841x 18/03/02 2.71829 x 18/03/02 : Time 3$5 / : to / N 144 : / to : Integration by Parts Y This method called Integration Parts. f ( xis ) gs( x ) dx=f ( x ) g ( by x )fs( x ) g ( x ) dx Y Y Find the following indef inite integrals using Integration by Parts. This method is called Integration by Parts. Ex. Yx cos x dx=Yx ( sin x )s dx Y f ( x ) gs( x ) dx = x sin x -Y( x )s sin x dx sin x )s dx Yx cos x dx==xYx (xY f ( x ) gs( x ) dx sin f ( x ) g ( x ) -Y fs( x ) g ( x ) dx Y sin x dx = x sin x -Y( x )s sin x dx x+C =x sin x+ cos =x sin x-Y sin x dx f ( x ) g ( x ) -Y fs( x ) g ( x ) dx x ( x+ - cos xx+C )s dx Yx sin x dx==xYsin cos =-x cos x-Y( x )s( - cos x ) dx Yx sin x dx= Yx ( - cos x )s dx =-x cos x+Y cos x dx =-x cos x- ( x )s( - cos x ) dx =-x cos x+Y sin x+C =-x cos x+Y cos x dx Find the following indef inite integrals using Integration by Parts. Ex. (1) X V 99 Page 18 Name Date Time R Grade Mistakes Mistakes N 144 f ( x ) gs( x )=[ f ( x ) g ( x ) ]s-fs( x ) g ( x ) Y 4:05 PM Name 100 0 % / / : to B1 70% : C2 50% Level XM R X M 62å ) (Transformations 0 1 2 2^a≈ ·≈^¤=^ a≈ · b≈=0) Since BE AD≈=b≈^¤=(‘ 0 , “ 2AB¤=AC¤ 1 1 ”-a≈+ b≈’ · (a≈+b≈)=0 2 2 AC=@ 2 AB A 2^a≈^¤=^b≈^¤=(‘ a≈ · b≈=0) 2. Given ˚ABC, let M be the midpoint of side BC. Show that “ 2AB¤=AC¤ AB¤+AC¤=2(AM¤+BM¤) using the following two methods. AC=@ 2 AB [Sol 1] Let AB≈=a≈ and AC≈=b≈. 2. Given ˚ABC, let M be the midpoint of side BC. Show that LHS=^a≈^¤+^b≈^¤ AB¤+AC¤=2(AM¤+BM¤) using the following two methods. ¤ ¤ 1 1 RHS=2ï„ (a≈+b≈)„ +„ (b≈-a≈)„ ö [Sol 1] Let AB≈=a≈ 2and AC≈=b≈. 2 B 1a≈^¤+^b≈^¤ LHS=^ RHS= (^a≈^¤+2a≈ · b≈+^b≈^¤+^a≈^¤-2a≈ · b≈+^b≈^¤) 2 ¤ ¤ 1 1 RHS=2 a b b a ï „ ( + )„ +„ ( )„ ö ≈ ≈ ≈ ≈ RHS=^a≈^¤+^ 2 b≈^¤ 2 B “ LHS=RHS 1 RHS= (^a≈^¤+2a≈ · b≈+^b≈^¤+^a≈^¤-2a≈ · b≈+^b≈^¤) 2 a≈ and BM≈=b≈. [Sol 2] Let AM≈= B A A M C M C jp.chosa.yu 2016/11/01 14:26:58 R AB¤+AC¤=2(AM¤+BM¤) % / / : to B1 70% : C2 50% 0 -y· y y`=0 · x+ (-1) ˛ Rewriting, The matrix equation is: x`x` =1 · x+0 1 ·y 0 x ”=” ”” ” 0 -1 y`y` =0 · x+ (-1) · yy ˛ Í̧ ” The matrix equation is: x` 1 0 x ” ”=” ”” ” y` 0 -1 y 7/23/09 2:48 PM X P 24 Page 8 1 2 y O O x Q(x`, y`) x Q(x`, y`) 2. Given that P(x, y) is mapped to Q(x`, y`) by the reflection in the origin, find the matrix equation relating the two points. [Sol] Since (x, y) is mapped to (x`, y`) by the reflection in the origin, 2. Given that P(x, y) is mapped to Q(x`, y`) by the reflection in the origin, find x`=-x,=y`=-y the matrix equation relating the two points. Rewriting, [Sol] Since (x, y) is mapped x`=(-1) · x+0 to · y (x`, y`) by the reflection in the origin, x` =-y y`=-x,=y` =0 · x+(-1) ·y ˛ Rewriting, The matrix equation is: x`x` =(-1)-1 · x+0 · y0 x Í̧ ” ”=” ”” ” 0 -1 y`y` =0 · x+(-1) ·y y ˛ Í̧ Grade Mistakes / : Name 100 0 / to B1 % 0 Mistakes 70% X P 24 : C2~3 D4~6 2~3 4~6 50% 49% 1 [Sol] Examining 5 of the possibilities, 1. Find the number of ways 5Epeople A, B,DC, D and E can sit around aB round A C table. B E A D E C [Sol] Examining 5 of the possibilities, C A D B E C A D D B B E C A C A D B E Since the E seating B A relationship D E of theCpeople D in each B ofC the above A possibilities is the same, D BshowCthe same A seating B arrangement. E A all C 5 possibilities D E Since the seating relationship the people in each of the above Therefore, if we were to use 5! of to find the number of ways, it would possibilities is large. the same, be 5 times too 5! all 5 possibilities show of theways sameis:seating = arrangement. Thus, the total number 24 5 the number of ways, it would Therefore, if we were to use 5! to find Number Circular Permutations be 5oftimes too large. The ways of arranging differentofobjects in a 5! ring = are called circular Thus, the total number ways is: 24 permutations. 5 The numberof ofCircular circular permutations of n objects is: Number Permutations The ways n! of arranging different objects in a ring are called circular =(n-1)! n permutations. The number of circular permutations of n objects is: 2. Find the number of ways 6 people can sit around a round table. n! =(n-1)! 6! [Sol] n Using the formula, the number of ways is: =5!=120 6 2. Find the number of ways 6 people can sit around a round table. 3. Find the number of ways 8 people can sit around a6! round table. [Sol] Using the formula, the number of ways is: =5!=120 6 8! [Sol] Using the formula, the number of ways is: =7!=5040 8 3. Find the number of ways 8 people can sit around a round table. Note: In general, when S is a set, the mapping from S to S is called a transformation of S. jp.chosa.yu 2016/11/01 14:27:22 R R Date / / Permutations and Combinations Time 1. Find the number of ways 5 people A, B, C, D and E: can sittoaround a: round table. Grade 100 % B 70% C 50% D 49% 3~4 P(x, y) Date Time X P 24å 49% [Sol] Since (x, y) is mapped to (x`, y`) by the reflection in the x-axis, 1. Given that P(x, y) is mapped to Q(x`, y`) by the reflection in the x-axis, find y x`=x,=y`= -y the matrix equation relating the two points. Rewriting, P(x, y) [Sol] Since (x, y) is· x+0 mapped x`=1 · y to (x`, y`) by the reflection in the x-axis, Í̧ x`=x,=y`= Page 8 Permutations and Combinations X M 62 D3~4 The matrix equation is: x` -1 0 x ” ”=” ”” ” y` 0 -1 y AB¤+AC¤=^AB≈^¤+^AC≈^¤ AB¤+AC¤=2(AM¤+BM¤) AB¤+AC¤=^a≈-b≈^¤+^a≈+b≈^¤ AB¤+AC¤=2(^a≈^¤+^b≈^¤) Name 100 0 Mistakes RHS=^ a≈^¤+^b≈^¤ AB≈^¤+^AC≈^¤ AB¤+AC¤=^ “ LHS=RHS AB¤+AC¤=^a≈-b≈^¤+^a≈+b≈^¤ [Sol 2] Let AM = a≈ and BM≈=ab≈^¤+^ ≈ ≈. AB¤+AC¤=2(^ b≈^¤) =-x cos x+ sin x+C Grade Mistakes 2:48 PM Level XP R X P 24å and Combinations) (Permutations XP 021-030* Date / / Transformations I Time : : find 1. Given that P(x, y) is mapped to Q(x`, y`) by the reflection intothe x-axis, the matrix equation relating the Grade two points. 100 % B 70% C 50% D 49% 3~4 a R 7/23/09 Name Date Time X M 62å 49% a X M 62 Name Transformations I X V 99 D3~4 [Sol] Let AB≈=a≈ and AC≈=b≈. C 1. Given ˚ABC where A=90°, 1 let D and E be the midpoints of BC and CA BE≈=-a≈+ b≈ 2 respectively. Show that if AD†BE, AC=@ 2 AB. b 1 AD≈= (a≈+b≈) D 2 AC≈=b≈. [Sol] Let AB≈=a≈ and E C 1 Since BE AD≈= BE≈≈·=a≈+0 ,b≈ 2 b 1 1 ”· b≈)(a≈+b≈)=0 ≈+ 12 (ba≈’≈+ AD≈a= D 2 2 B EA XP 021-030* XM 061-070* 08.6.23 0:33 PM Page 4 Date / / Vectors and Figures Time : toof BC and : 1. Given ˚ABC where A=90°, let D and E be the midpoints CA respectively. Show that if AD†BE, Grade AC= 100 %@ 2 AB. B 70% C 50% D 49% If both sides following f ( xare ) gs(integrated, x ) dx=f (then x ) gthe ( x )fs( x )formula g ( x ) dxis obtained. Integration by Parts X V 99å O 81 If both sides are integrated, then the following formula is obtained. can be rearranged into (1) 1 k 1 k 2 f ( x ) gs( x )=[ f ( x ) g ( x ) ]s-fs( x ) g ( x ) [ f ( x ) g ( x ) ]s=fs( x ) g ( x )+f ( x ) gs( x ) log a a=1 1 k 1 k Time Name 3$5 Date can be rearranged into The Product Rule n a 2 The Product Rule a / Date # Integration by Parts 1 08.7.10 Vectors and Figures Name O 81a a B c Integration by Parts N 171 2 3$4 Differentiation of 1Logarithmic and Using the def inition of the derivative, differentiate y= log a x. ( x > 0 ) Exponential Functions Using the def inition of the derivative, differentiate y= log / a x. ( x > / 0) Date log a ( x+h )- log a x [Sol] ys= lim : : log a3x$ 4 Time to h c 0 log a1( x+h h )2 M [Sol] ys= lim log M- log N= log hc0 h N M 1 x+h log M- log N= log =def lim 1 log aofx+h Using the inition the derivative, differentiate y= log a x. ( xN> 0 ) hc0 h log a x = lim hc0 h x h log a x 1log a ( x+h )= lim 1 log a 1+ x h c0 h [Sol] ys= h lim hc0 log a 1+ = lim h M hc0 x log M- log N= log h h N 1 . As hx+h Let= h =k c 0, k c 0; therefore, log lim a x 0 h . As h c Let h c=k x 0, k c 0; therefore, x 1 log h 1 ys=klim ) a ( 1+k 1 a 1+ c 0 kx log = lim log a ( 1+k ys= ) h c lim 0 h x c n log M= log M k 0 kx 1 1 n log M= log M h lim ( 1+k ) ;k1 therefore, 1 hlog k c 0 . As Let = =k c a0(, 1+k k c 0) k x log = a x klim c0 x 1 1 k is known to approach a constant value, which is Asys= k clim 0, ( 1+k ) 1 log a ( 1+k ) As k ck c0,0 (kx 1+k ) k is known to approach a constant value, which is n log M= log M expressed as1e. 1 expressed as e. log1a ( 1+k ) k = lim c0 So, e=k klim (x 1+k ) k1 c0 So, e=klim ( 1+k )1k c0 k As k cthis is known Using e, to approach a constant value, which is 0, (constant 1+k ) value Using this constant value e, log M log e e 1 e. 1 log M= expressed log ys= 1 aslog log M a a e= log e e = 1 a xA log M= 1 x log x log ea = e xA ys= x log a e= log a=1 log a k So, e=klim ( 1+k ) log e a x log e a x x log a=1 c0 b =b 2+c 2-2bc cos A b 2+c 2-2bc cos A =b A C H C =( b sin A ) 2+( b cos A-c ) 2 2 =( b sin A ) 2+( a c-b cos A ) : : XM 061-070* 08.6.23 0:33 PM Page 4 © 2006 Kumon © 2006 Institute Kumon of Education Institute ofNorth Education America North KIEAmerica 2008 GBKIE Printed 2008 GB Printed in Malaysia in Malaysia A 2 sin A+ cos A=1 A A H c / / to to Page 18 © 2006 Kumon © 2006 Institute Kumon of Education Institute ofNorth Education America North KIEAmerica 2008 GBKIE 2008 GB in Malaysia in Malaysia B 3$4 / / : : # 2 4:05 PM Level XV X V 99å andR Figures) (Vectors XV 091-100* O 81 © 2006 Kumon Institute ofNorth Education North © 2006 Kumon Institute of Education America KIEAmerica 2008 GBKIE 2008 GB in Malaysia in Malaysia 2 C 2H= A H= b cos A a =C Hb2sin +BAH , 2 C A 2 b sinB-A A ) 2H= +( c-b Also,=( B H=A c-bcos cosAA ) In qB , 2-2bc cos A C 2H+c =b 2 a b [Sol] In a perpendicular qABBH=A C, drop Also, B-A H= c-b cosCAH from to, A B. In qA C H, vertex In qB C CH 1 © 2016 Kumon © 2016 Institute Kumon of Education Institute of Education KIE KIE 2018 KIE GB KIE 2018 GB 2 © 2016 © 2016 Kumon Kumon Institute © 2016 Institute Kumon of Education of Education Institute KIE of KIE Education KIEKIE 2018 2018 GB KIE GBKIE 2018 GB © 2016 Kumon © 2016 Institute Kumon of Education Institute of KIE Education KIE 2018 KIE GBKIE 2018 GB 2 C H= b sin a =b +c -2bc A.,A H= b cos A cosA 2 N 171a M 184 As shown in the diagram below, when A and prove that / DateB are both/ acute angles, a2=b 2+c 2-2bc cos A. : : Time to 1 2 C [Sol] In qA B C, drop a perpendicular C H from , vertex A B. In qA C Hwhen A and B are both acute angles, prove that As shown in C thetodiagram below, 2 sg.wendy 2021/03/19 09:28:23 DD Exponential Functions / : Time Name Name Name Date Date Time Time Name Answers: all x / Date # Level O by Parts# ) (Integration O 81a N 171 N 171 Name M 184a Sine and Cosine Rules Level N # N 171a # N 1 7 1 a of Logarithmic Differentiation and of Logarithmic Functions) (Differentiation Differentiation of Logarithmic and Exponential Functions M 184 Answers: all x Answers: all x Level M M 1 8 4Rule a ) (Cosine Sine and Cosine Rules 08.7.10 [Sol] Using the formula, the number of ways is: jp.chosa.yu 2016/11/01 14:27:45 R Note: In general, when S is a set, the mapping from S to S is called a transformation of S. 8! =7!=5040 8 11:56 11:56 18/03/02 11:56 ME_WS_O_081.indd 1 18/03/02 11:59 ME_WS_O_081.indd 1 18/03/02 11:59 jp.chosa.yu 2016/11/01 14:26:58 R jp.chosa.yu 2016/11/01 14:27:22 R jp.chosa.yu 2016/11/01 14:27:45 R 18/03/23 14:36