CLASSROOM CONTACT PROGRAMME
(Academic Session : 2023 - 2024)
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ENTHUSIAST ADVANCE COURSE
PHASE : MEA,PS,B,C,D,F,G,H,I,P,Q, & MER
TARGET : PRE MEDICAL 2024
Test Type : MAJOR
Test Pattern : NEET (UG)
TEST DATE : 02-01-2024
ANSWER KEY
Q.
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
A.
3
3
1
1
1
1
3
1
2
4
1
2
2
3
1
4
3
3
1
4
2
1
3
3
4
3
1
3
2
1
Q. 31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
A.
3
3
3
3
1
3
4
2
2
3
1
1
1
3
1
1
1
2
3
1
2
2
3
4
4
1
3
3
4
1
Q. 61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
1
4
3
3
1
3
4
4
1
4
1
2
1
2
4
3
3
3
1
1
2
4
1
2
2
3
1
3
4
3
Q. 91
A.
92
93
94
95
96
97
98
99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120
A.
3
4
1
4
3
1
3
1
4
1
4
2
4
1
2
2
3
4
2
4
3
1
1
2
3
3
1
4
1
2
Q. 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150
A.
2
2
4
1
3
2
4
3
4
2
2
2
4
3
3
2
4
1
1
2
3
2
1
3
4
4
3
4
3
2
Q. 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180
A.
2
2
3
3
4
4
1
1
3
3
1
3
3
3
2
1
2
4
3
3
1
4
3
4
2
3
4
2
4
3
Q. 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200
A.
4
1
3
1
3
4
4
1
3
1
4
1
1
2
1
1
1
4
3
2
HINT – SHEET
SUBJECT : PHYSICS
4.
t=
SECTION - A
1.
2.
Ans ( 3 )
436.32 + 227.2 + 0.301 = 663.821
Minimum significant fig. after decimal is one,
therefore appropriate significant fig. is 663.8
dx
= 2at − 3bt2
dt
dv
= 2a − 6bt = 0
a=
dt
a
⇒t=
3b
3.
6.
Ans ( 1 )
g
Sn = u + (2n – 1); when u = 0 then S1 : S2 :
2
S3 = 1 : 3 : 5
1001CMD303029230081
√
t
2h
⇒ 1
t2
g
=
√
h1
h2
=
√
1
2
=
1
√
2
Ans ( 1 )
F=
vdm
dt
⇒ 200 = 300
Ans ( 3 )
x = at2 – bt3
v=
Ans ( 1 )
dm
dt
dm
2
= ≃ 0.7 kg/s
3
dt
7.
Ans ( 3 )
α=
=
ω − ω0
t
2π
(n − n0 )
t
= 2π (52 − 20)
16
= 4 π rad/s2
⎡
Here :
n0 =
1200
60
n=
3120
60
⎢
⎢
⎣
= 20 rps
⎤
⎥
⎥
= 52 rps
⎦
HS-1/7
TARGET:PRE MEDICAL 2024/02-01-2024
8.
Ans ( 1 )
gh =
(
g
h
R
1+
1+
R
)
4
⇒ w' =
9.
10.
Ans ( 2 )
17.
Ans ( 3 )
KA(90 − θ)
1
1
E = × F × Δℓ = × 100 × 1 × 10−3 = 0.05 J
2
2
Ans ( 4 )
Q = const.
Ans ( 1 )
2T ℓ = mg ⇒ ℓ =
ℓ
=
KA(θ − 30)
ℓ
+
KA(θ − 0)
ℓ
+
KA(θ − 60)
ℓ
90 – θ = 3 θ – 90°
θ = 45°
18.
mg
2T
Ans ( 3 )
A = √32 + 4 2 = 5
1
1
1
∝
∝
2
A
D2
R
2
V
2D
=(
) = 4
′
D
V
V
V′=
4
13.
Ans ( 4 )
W = +250 J
T = constant ( Δ U = 0)
According to FLOT
Q = W + Δ U ⇒ Q = W = +250 J
It means 250 J of heat has been added to the gas.
4
× 63 = 28 N
9
v∝
12.
16.
4
(mg)
9
Av = const.
11.
Ans ( 1 )
Area ∝ T4
2
R/2
⇒ gh = g
9
⇒ mgh =
15.
2
g
(
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Ans ( 3 )
γ = αx + αy + αZ
γ = α1 + α2 + α2
= α1 + 2 α2
)
At h = R/2
⇒ gh =
14.
19.
Ans ( 1 )
Distance between consecutive threads = pitch
LC = 0.005 mm = P itch
100
⇒ Pitch = 0.5 mm
=
1 × 1000
2 × 70
20.
Ans ( 4 )
Viscosity of liquid decreases with increase in
temperature.
21.
Ans ( 2 )
= 7 cm
Ans ( 2 )
h = 1000 m ; ρ = 1000 kg/m3 ; g = 10 m/s2
P = P0 + ρ gh
P = 105 + 103 × 10 × 1000
P = 101 × 105 Pa ≈ 100 atm
miceLf = mbSb Δ T
mice(80) = (2400) (0.1) (500 – 0)
mice = 1500 gm = 1.5 kg
Ans ( 2 )
22.
Ans ( 1 )
→.V
→
P =F
=4W
24.
Q = 10 + 160 + 120 = 290 cal.
HS-2/7
Ans ( 3 )
mgh' = 25% of mgh
h' =
h
4
1001CMD303029230081
ENTHUSIAST ADVANCE COURSE/PHASE-MEA,PS,B,C,D,F,G,H,I,P,Q, & MER/02-01-2024
25.
Ans ( 4 )
FC =
28.
29.
34.
mv2
0.2 × 22
=
= 8N
r
0.1
S = ut +
S1 = 0 +
1
2
1
2
=
35.
Ans ( 1 )
mgh' = 75% of mgh
h' =
75
× 10 = 7.5 m
100
SECTION - B
at2
36.
× a × (10)2 = 50 a
and, S1 + S2 = 0 +
1
S1
=
S1 + S2
4
S1
1
⇒
=
S2
3
1
2
Ans ( 3 )
∣
∣
× a (20)2 = 200 a
38.
∴
31.
ℓ2 − 3ℓ1
51 − 3 × 16.5
51 − 49.5
=
=
2
2
2
1.5
= 0.75 cm
2
e=
Ans ( 3 )
[y] = [B] [t3]
L1 = [B] × T3
[B] = [LT – 3]
Ans ( 2 )
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Ans ( 3 )
^
^
A − B∣∣ = 2 × 1 × sin(
θ
θ
) = 2 sin(
)
2
2
Ans ( 2 )
Ans ( 3 )
wrt origin
→ =L
→ +L
→
L
sys
1
2
= – r1(mv) + r2(mv)
= mv(r2 – r1) = mvd
T sin 30° = 2 kg wt
⇒ T = 4 kg wt
T1 = T cos 30º
= 4 cos 30º
= 2 3 kg-wt
39.
Ans ( 2 )
√
32.
Ans ( 3 )
F = dP , force will be maximum where slope is
dt
maximum.
33.
Ans ( 3 )
1001CMD303029230081
m = 66 gm
40.
v ∝ √T
v1 √ T1
=
v2
T2
v
T
=√
T
+
800
√5v
1
T
= T = 200K
⇒
=
5
T + 800
By τ net = 0
10g (33) = mg (5)
Ans ( 3 )
V∞ = √v2 − v2e
∵ v = 3ve
V∞ = √9v2e − v2e
= 2 2ve
≈ 2.8 ve
≈ 31.4 Kms – 1
√
or
HS-3/7
TARGET:PRE MEDICAL 2024/02-01-2024
41.
Ans ( 1 )
Cp Δ T = Cv Δ T + Δ W
∴ Δ W = (Cp – Cv) Δ T
Fraction of heat converted into work
47.
h=
h=
(Cp − Cv )ΔT
ΔW
=
Cp ΔT
ΔQ
=1– 1 =1– 3 = 2
γ
5
5
=
42.
44.
2T cos 0∘
rρg
2 × 70
20 × 10−4 × 1 × 1000
h = 70 cm
48.
Ans ( 2 )
αΔT t
2
α(T − 15)t
5=
2
α(30 − T )t
10 =
2
Δt =
Ans ( 1 )
Let plank shifted by x then Δ xCM = 0, as there
is no external force on the system.
m(L – xplank) – Mxplank = 0
Xplank =
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Ans ( 1 )
....(2)
divide equation (1) by (2)
mL
M +m
1
T − 15
=
2
30 − T
3T = 60
T = 20°C
Ans ( 3 )
49.
Ans ( 3 )
y = a[sin ω t + cos ω t]
1
y = a√ 2 (
√
2
sin ωt +
y = a√2 sin(ωt +
50.
wrt instantaneous axis of rotation, velocity of
any point on the body is
v = ωr ⇒ vαr
Here
∵ rA = rC > rB
∴ vA = vC > vB
174))
2gh



π
)
4
2
cos ωt)
Ans ( 1 )
2mv0 = mv1 + mv2
v1 + v2 = 2v0 ......(i)
v2 – v1 = e2v0 ......(ii)
From (i) + (ii)
2v2 = 2v0 (1 + e)
v2 = v0 (1 + e)
From (i) – (ii)
2v1 = 2v0 (1 – e)
v1 = v0 (1 – e)
⎷
(
1+
k2
R2
)
∵ h1 = h2
All hints are according to old NCERT (2022-23)
∴ V1 = V2
SECTION - A
2
(b) t = 1 √ 2h (1 + k
sin θ
g
R2
Ans. (1)
HS-4/7
√
SUBJECT : BOTANY
Ans ( 1 )
(a) v =
1
v1
1−e
=
v2
1+e
(Reference: NCERT Class-XI (part-I Page No.
45.
...(1)
v 1 = v 2 & t1 < t2
∵ θ1 > θ2
51.
Ans ( 2 )
NCERT-XI Pg # 6
52.
Ans ( 2 )
NCERT-XI Pg. No. 06
)
t1 < t2
1001CMD303029230081
ENTHUSIAST ADVANCE COURSE/PHASE-MEA,PS,B,C,D,F,G,H,I,P,Q, & MER/02-01-2024
53.
Ans ( 3 )
NCERT-XI Pg # 21
71.
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Ans ( 4 )
NCERT-XI Pg # 163
54.
Ans ( 4 )
NCERT XIth, Page : 23, 24, Para-2.3.1, 2.3.3
72.
55.
Ans ( 4 )
NCERT-XI, Pg. # 7
73.
56.
Ans ( 1 )
NCERT XI page no.-35
57.
Ans ( 3 )
NCERT-XI, Pg#38
58.
Ans ( 3 )
NCERT-XIth Pg# 35,36
Ans ( 3 )
NCERT-XI Pg. # 163, 10.1.1
Ans ( 3 )
NCERT-XI Page # 166
Ans ( 1 )
NCERT-XI Pg#207,208,210
Ans ( 3 )
NCERT-XI Page No. # 211
Ans ( 4 )
NCERT-XI Pg # 215
Ans ( 4 )
NCERT-XI Pg.#227-228
59.
74.
75.
76.
77.
Ans ( 4 )
NCERT (XIth) Pg. # 68
78.
60.
Ans ( 1 )
NCERT XIth Pg.#72
Ans ( 1 )
NCERT (XIth) Pg. # 232
79.
61.
Ans ( 4 )
NCERT-XI Pg. # 80 (Fig. 5.22-f)
Ans ( 4 )
NCERT-XI Pg.# 250
80.
62.
Ans ( 1 )
NCERT-XI Pg. # 77
81.
63.
Ans ( 2 )
NCERT-XI Pg. # 89
Ans ( 1 )
NCERT-XI Pg.#242
Ans ( 2 )
NCERT-XI Pg. # 157, 158
82.
64.
Ans ( 2 )
NCERT (XIth) Pg. # 89
Ans ( 1 )
NCERT XIth Pg.# 146 (E), 146 (H)
83.
65.
Ans ( 3 )
NCERT-XI Pg # 97
Ans ( 2 )
NCERT-XI Pg. # 148
84.
66.
Ans ( 1 )
NCERT XI Pg. 93
Ans ( 4 )
NCERT XI Pg.# 145
85.
67.
Ans ( 3 )
NCERT-XI Pg. No. 94
Ans ( 3 )
NCERT XI, Pg # 150
68.
Ans ( 4 )
NCERT-XI Pg # 134, 135 para 8.5.4
86.
Ans ( 3 )
NCERT-XI Pg # 4,5
69.
Ans ( 3 )
NCERT-XI Pg#136,137
87.
Ans ( 3 )
NCERT-XI Pg # 20
70.
Ans ( 1 )
NCERT-XI Pg. # 138
88.
Ans ( 1 )
NCERT-XI Pg # 23-24
1001CMD303029230081
SECTION - B
HS-5/7
TARGET:PRE MEDICAL 2024/02-01-2024
89.
Ans ( 1 )
NCERT XI Pg.#22, 26 and 27
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117. Ans ( 1 )
NCERT Pg. # 270,17.1.1
90.
Ans ( 2 )
NCERT XI Pg # 39
120. Ans ( 2 )
NCERT-XII, Pg. # 294
91.
Ans ( 4 )
NCERT (XI) Pg. # 19, 31
122. Ans ( 2 )
XIth NCERT Page No. – 279
92.
Ans ( 3 )
NCERT XI Pg.# 66
124. Ans ( 1 )
NCERT-XII, Pg. # 308
93.
Ans ( 4 )
NCERT-XI Pg.# 78, 79, 80
126. Ans ( 2 )
NCERT (XI) Pg. # 311
94.
Ans ( 1 )
NCERT-XI Pg # 90
131. Ans ( 2 )
NCERT Page # 334
95.
Ans ( 4 )
NCERT (XI) Pg. # 95 (Fig.)
132. Ans ( 2 )
NCERT Pg.# 334
96.
Ans ( 3 )
NCERT XI Pg # 125, 126
134. Ans ( 3 )
NCERT Pg.# 337, 338
97.
Ans ( 1 )
NCERT-XI, Pg. # 134, 135, 136, 139
98.
Ans ( 3 )
NCERT-XI Pg. # 168
Ans ( 1 )
NCERT (XIth) Pg. (E) # 229 (Figure of glycolysis)
99.
100. Ans ( 1 )
NCERT-XI, Pg-158
SUBJECT : ZOOLOGY
SECTION - A
103. Ans ( 4 )
NCERT XI, Pg. No. 46
105. Ans ( 2 )
NCERT XIth Pg.#56 (E&H)
106. Ans ( 2 )
NCERT-XI, Pg # 58
107. Ans ( 3 )
NCERT XI Pg # 101
114. Ans ( 2 )
NCERT Pg. No.117/7.5.2
HS-6/7
SECTION - B
136. Ans ( 2 )
NCERT XIth Page # 50
140. Ans ( 2 )
NCERT Pg. No.118/7.5.2
141. Ans ( 3 )
New NCERT update
142. Ans ( 2 )
NCERT Pg. # 293
143. Ans ( 1 )
NCERT-XII, Pg. # 297
146. Ans ( 4 )
NCERT Pg.No.311
SUBJECT : CHEMISTRY
SECTION-A
151. Ans ( 2 )
n-Butane → Isobutane (x) →
1001CMD303029230081
ENTHUSIAST ADVANCE COURSE/PHASE-MEA,PS,B,C,D,F,G,H,I,P,Q, & MER/02-01-2024
154. Ans ( 3 )
A = CH2=CH – CH2 – Br,
B = CH2=CH – CH2 – CH2 – CH=CH2
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180. Ans ( 3 )
pH =
1
2
(pKw + pKa – pKb)
(formic
156. Ans ( 4 )
acid)
⇒ pH =
158. Ans ( 1 )
A = C6H6, B = C6H6Cl6 (BHC)
159. Ans ( 3 )
Acid > Phenol acidic strength
160. Ans ( 3 )
A = Benzene B = Friedel craft reaction
161. Ans ( 1 )
A = CH3 – CH3 B = CH3 – CH2 – Cl
C = CH2=CH2 D =
166. Ans ( 1 )
Hint :- Size of H is smaller So C = C > C – H
168. Ans ( 4 )
Hint :- NF3 is pyramidal
169. Ans ( 3 )
Hint :- SP hybridisation is known as diagonal
hybridisation.
172. Ans ( 4 )
Hint :- Carbon suboxide (C3O2)
O=C=C=C=O
57.82
12
H
O
3.6
1
38.58
16
4.81
3.6
E.F ⇒ C4H3O2
1001CMD303029230081
1
(14 + 3.8 − 4.8) = 6.5
2
182. Ans ( 1 )
3 replacable H-atoms are present in H3PO4 are
replaced by Na
∴n=3
M. wt. of H3 P O4
98
=
3
3
eq. wt. of H3PO4 =
184. Ans ( 1 )
NCERT Pg. # 277
185. Ans ( 3 )
KOH + HNO3 → KNO3 + H2O
0.4 mol 0.5 mol
163. Ans ( 3 )
Hint :- Left to Right in Period non-metallic
character increases.
165. Ans ( 2 )
Hint :- Size of nitrogen is larger than oxygen
176. Ans ( 3 )
C
(Ammonia)
2.4
(L.R.)
Δ Hneut. = – 57.2 × 0.4
= – 22.88 kJ
So heat released is 22.88 kJ
SECTION-B
188. Ans ( 1 )
A = CH3 – CH=CH2
B = CH3 – CHO, C = CH2=O
196. Ans ( 1 )
h ν = h ν 0 + k.E
k.E = h( ν – ν 0)
= 6.626 × 10 – 34 (1 × 1015 – 8 × 1014)
= 1.325 × 10 – 19 J
200. Ans ( 2 )
6.626 × 10−34
λ= h =
mv
(
20
1000
× 50)
= 6.626 × 10 – 34 m
HS-7/7