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Mathematics: Applications & Interpretation SL & HL
1 Page Formula Sheet – First Examinations 2021 – Updated Version 1.1
Topic 3: Geometry and trigonometry – SL & HL
Prior Learning SL & HL
Area: Parallelogram
Area: Triangle
Area: Trapezoid
Area: Circle
Circumference: Circle
Volume: Cuboid
𝐴 = π‘β„Ž , 𝑏 = base, β„Ž = height
1
𝐴 = 2 (π‘β„Ž) , 𝑏 = base, β„Ž = height
1
𝐴 = 2 (π‘Ž + 𝑏)β„Ž , π‘Ž, 𝑏 = parallel sides, β„Ž = height
𝐴 = πœ‹π‘Ÿ 2 , π‘Ÿ = radius
𝐢 = 2πœ‹π‘Ÿ, π‘Ÿ = radius
𝑉 = π‘™π‘€β„Ž , 𝑙 = length, 𝑀 = width, β„Ž = height
Distance between 2 points
𝑑 = √(π‘₯1 − π‘₯2 )2 + (𝑦1 − 𝑦2 )2 + (𝑧1 − 𝑧2 )2
(π’™πŸ , π’šπŸ , π’›πŸ ) , (π’™πŸ , π’šπŸ , π’›πŸ )
Coordinates of midpoint
of a line with endpoints
(π’™πŸ , π’šπŸ , π’›πŸ ) , (π’™πŸ , π’šπŸ , π’›πŸ )
Volume: Right cone
Area: Cone curve
Distance between two
𝑑 = √(π‘₯1 − π‘₯2 )2 + (𝑦1 − 𝑦2 )2
points (π’™πŸ , π’šπŸ ) , (π’™πŸ , π’šπŸ )
𝐴 = 2πœ‹π‘Ÿβ„Ž , π‘Ÿ = radius, β„Ž = height
Surface area: Sphere
Prior Learning HL only
Cosine rule
Volume: Prism
Area: Cylinder curve
Coordinates of midpoint
Solutions of a quadratic
equation in the form
π’‚π’™πŸ + 𝒃𝒙 + 𝒄 = 𝟎
𝑉 = π΄β„Ž , 𝐴 = cross-section area, β„Ž = height
(
π‘₯1 +π‘₯2 𝑦1 +𝑦2
2
,
2
−𝑏 ± √𝑏2 − 4π‘Žπ‘
π‘₯=
,π‘Ž ≠ 0
2π‘Ž
Area: Triangle
Topic 1: Number and algebra - SL & HL
The 𝒏th term of an
arithmetic sequence
Sum of 𝒏 terms of an
arithmetic sequence
The 𝒏th term of a
geometric sequence
Sum of 𝒏 terms of a
finite geometric seq.
Compound interest
Length of an arc
𝑒𝑛 = 𝑒1 + (𝑛 − 1)𝑑
𝑠𝑛 =
𝑛
𝑛
(2𝑒1 + (𝑛 − 1)𝑑) = (𝑒1 + 𝑒𝑛 )
2
2
𝑒𝑛 = 𝑒1 π‘Ÿ 𝑛−1
𝑠𝑛 =
Volume: Sphere
Sine rule
), for endpoints (π‘₯1 , 𝑦1), (π‘₯2 , 𝑦2 )
𝑒1 (π‘Ÿ 𝑛 − 1) 𝑒1 (1 − π‘Ÿ 𝑛 )
=
,π‘Ÿ ≠ 1
π‘Ÿ−1
1−π‘Ÿ
π‘Ÿ π‘˜π‘›
𝐹𝑉 = 𝑃𝑉 × (1 +
)
100π‘˜
𝐹𝑉 is future value, 𝑃𝑉 is present value, 𝑛
is the number of years, π‘˜ is the number of
compounding periods per year, π‘Ÿ% is the
nominal annual rate of interest
Area of a sector
Length of an arc
Area of a sector
Identities
for π‘Ž, π‘₯, 𝑦 > 0
The sum of an infinite
geometric sequence
Complex numbers
Discriminant
Modulus-argument
(polar) & Exponential
(Euler) form
Determinant of a
2×2 matrix
Inverse of a
2×2 matrix
Power formula for a
matrix
𝑠∞ =
Gradient formula
Axis of symmetry of a
quadratic function
𝑏
) ⇒ det 𝑨 = |𝑨| = π‘Žπ‘‘ − 𝑏𝑐
𝑑
1
𝑏
𝑑
(
) ⇒ 𝑨−1 =
𝑑
det 𝑨 −𝑐
−𝑏
)
π‘Ž
𝑴𝑛 = 𝑷𝑫𝑛 𝑷−1 , where 𝑷 is the matrix of
eigenvectors and 𝑫 is the diagonal matrix
of eigenvalues
𝑦 = π‘šπ‘₯ + 𝑐 ; π‘Žπ‘₯ + 𝑏𝑦 + 𝑑 = 0 ;
𝑦 − 𝑦1 = π‘š(π‘₯ − π‘₯1 )
𝑦2 − 𝑦1
π‘š=
π‘₯2 − π‘₯1
𝑓(π‘₯) = π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐 ⇒ π‘₯ = −
Topic 2: Functions – HL only
Logistic function
𝑓(π‘₯) =
𝐿
1 + 𝐢𝑒 −π‘˜π‘₯
π‘Ž
sin𝐴
=
𝑏
sin𝐡
=
sin𝐢
𝑐 2 = π‘Ž2 + 𝑏2 − 2π‘Žπ‘ cos 𝐢
cos 𝐢 =
π‘Ž2 + 𝑏2 − 𝑐 2
2π‘Žπ‘
1
𝐴 = π‘Žπ‘ sin 𝐢
2
πœƒ
× 2πœ‹π‘Ÿ
360
πœƒ = angle in degrees, π‘Ÿ = radius
𝑙=
πœƒ
𝐴=
× πœ‹π‘Ÿ 2
360
πœƒ = angle in degrees, π‘Ÿ = radius
𝑙 = π‘Ÿπœƒ
π‘Ÿ = radius, πœƒ = angle in radians
1
𝐴 = π‘Ÿ2 πœƒ
2
π‘Ÿ = radius, πœƒ = angle in radians
cos 2 πœƒ + sin2 πœƒ = 1
sin πœƒ
tan πœƒ =
cos πœƒ
1 0
)
0 π‘˜
Λ’ vertical stretch with scale factor of π‘˜
(
π‘˜ 0
) , centre (0,0)
0 π‘˜
Λ’ enlargement with scale factor of π‘˜
(
𝑏
2π‘Ž
, 𝐿, π‘˜, 𝐢 > 0
cos πœƒ sin πœƒ
) , clockwise rotation
−sin πœƒ cos πœƒ
of angle πœƒ about the origin (πœƒ > 0)
(
Magnitude of a vector
Vector equ. of a line
Parametric form of the
equation of a line
Scalar product
Angle between two
vectors
Vector product
Area of a
parallelogram
|𝒗| = √𝑣1 + 𝑣2 + 𝑣3
2
2
2
Complementary events
P(𝐴) + P(𝐴′ ) = 1
Combined events
Mutually exclusive events
Conditional probability
Binomial distribution
Mean ; Variance
𝒗 βˆ™ π’˜ = |𝒗||π’˜| cos πœƒ
𝑣1 𝑀1 + 𝑣2 𝑀2 + 𝑣3 𝑀3
|𝒗||π’˜|
Linear combinations of 𝒏
independent random
variables, π‘ΏπŸ , π‘ΏπŸ , … . 𝑿𝒏
Unbiased estimate of
population variance
Poisson distribution
Mean ; Variance
Transition matrices
P(𝐴 ∩ 𝐡)
P(𝐡)
P(𝐴 ∩ 𝐡) = P(𝐴)P(𝐡)
E(𝑋) = ∑ π‘₯ P(𝑋 = π‘₯)
𝑋~B(𝑛, 𝑝)
E(𝑋) = 𝑛𝑝 ; Var(𝑋) = 𝑛𝑝(1 − 𝑝)
E(π‘Ž1 𝑋1 ± π‘Ž2 𝑋2 ±. . . ±π‘Žπ‘› 𝑋𝑛 ) =
π‘Ž1 E(𝑋1 ) ± π‘Ž2 E(𝑋2 )± . . . ±π‘Žπ‘› E(𝑋𝑛 )
Var(π‘Ž1 𝑋1 ± π‘Ž2 𝑋2 ±. . . ±π‘Žπ‘› 𝑋𝑛 ) =
π‘Ž1 2 Var(𝑋1 ) + π‘Ž2 2 Var(𝑋2 ) + β‹― +
π‘Žπ‘› 2 Var(𝑋𝑛 )
2
𝑠𝑛−1
=
𝑛
𝑠2
𝑛−1 𝑛
Sample statistics
𝑋~Po(π‘š)
E(𝑋) = π‘š ; Var(𝑋) = π‘š
𝑻𝑛 𝒔0 = 𝒔𝑛 , where 𝒔0 is the initial state
𝑓(π‘₯) = π‘₯ 𝑛 ⇒ 𝑓′(π‘₯) = 𝑛π‘₯ 𝑛−1
Area enclosed by a
curve and the 𝒙-axis
𝐴 = ∫ 𝑦 𝑑π‘₯ ,
Integral of 𝒙𝒏
The trapezoidal rule
where β„Ž =
𝑏−π‘Ž
𝑛
∫ π‘₯ 𝑛 𝑑π‘₯ =
𝑏
𝑏
π‘₯ 𝑛+1
+ 𝐢 , 𝑛 ≠ −1
𝑛+1
π‘Ž
∫ 𝑦 𝑑π‘₯ ≈
where 𝑓(π‘₯) > 0
π‘Ž
1
β„Ž((𝑦0 + 𝑦𝑛 ) + 2(𝑦1 + 𝑦2 +. . . +𝑦𝑛−1 ))
2
Topic 5: Calculus – HL only
Derivative of 𝐬𝐒𝐧 𝒙
𝑓(π‘₯) = sin π‘₯ ⇒ 𝑓′(π‘₯) = cos π‘₯
Derivative of 𝐭𝐚𝐧 𝒙
𝑓(π‘₯) = tan π‘₯ ⇒ 𝑓′(π‘₯) =
Derivative of 𝐜𝐨𝐬 𝒙
Derivative of 𝒆𝒙
Derivative of π₯𝐧 𝒙
Chain rule
Product rule
Quotient rule
Standard integrals
𝑓(π‘₯) = cos π‘₯ ⇒ 𝑓′(π‘₯) = − sin π‘₯
𝑓(π‘₯) = 𝑒 π‘₯ ⇒ 𝑓′(π‘₯) = 𝑒 π‘₯
Volume of revolution
about 𝒙 or π’š-axes
Distance; Displacement
travelled from π’•πŸ to π’•πŸ
Euler’s method
Euler’s method for
coupled systems
Exact solution for
coupled linear
differential equations
1
cos 2 π‘₯
1
π‘₯
𝑑𝑦
𝑑𝑦 𝑑𝑒
𝑦 = 𝑔(𝑒) , 𝑒 = 𝑓(π‘₯) ⇒
=
×
𝑑π‘₯
𝑑𝑒 𝑑π‘₯
𝑑𝑦
𝑑𝑣
𝑑𝑒
𝑦 = 𝑒𝑣 ⇒
=𝑒
+𝑣
𝑑π‘₯
𝑑π‘₯
𝑑π‘₯
𝑑𝑣
𝑑𝑒
𝑒
𝑑𝑦 𝑣 𝑑π‘₯ − 𝑒 𝑑π‘₯
𝑦=
⇒
=
𝑣2
𝑣
𝑑π‘₯
1
∫ 𝑑π‘₯ = ln|π‘₯| + 𝐢
π‘₯
𝑓(π‘₯) = ln π‘₯ ⇒ 𝑓′(π‘₯) =
∫ sin π‘₯ 𝑑π‘₯ = − cos π‘₯ + 𝐢
∫ cos π‘₯ 𝑑π‘₯ = sin π‘₯ + 𝐢
∫
Acceleration
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P(𝐴|𝐡) =
Derivative of 𝒙𝒏
where πœƒ is the angle between 𝒗 and π’˜
IB Math Practice Exams (Full Length)
IB Math Practice Exams by Topic
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P(𝐴 ∪ 𝐡) = P(𝐴) + P(𝐡)
Topic 5: Calculus - SL & HL
Area enclosed by a
curve and 𝒙 or π’š-axes
𝐴 = |𝒗 × π’˜| , where 𝒗 and π’˜ form two
adjacent sides of a parallelogram
P(𝐴 ∪ 𝐡) = P(𝐴) + P(𝐡) − P(𝐴 ∩ 𝐡)
Linear transformation of a E(π‘Žπ‘‹ + 𝑏) = π‘ŽE(𝑋) + 𝑏
single random variable
Var(π‘Žπ‘‹ + 𝑏) = π‘Ž2 Var(𝑋)
𝑣2 𝑀3 − 𝑣3 𝑀2
𝒗 × π’˜ = (𝑣3 𝑀1 − 𝑣1 𝑀3 )
𝑣1 𝑀2 − 𝑣2 𝑀1
|𝒗 × π’˜| = |𝒗||π’˜| sin πœƒ
= ∑π‘˜π‘–=1 𝑓𝑖
, where 𝑛
Topic 4: Statistics and probability – HL only
where πœƒ is the angle between 𝒗 and π’˜
cos πœƒ =
𝑛
𝑛(𝐴)
P(𝐴) =
𝑛(𝑒)
Probability of an event 𝑨
π‘₯ = π‘₯0 + πœ†π‘™, 𝑦 = 𝑦0 + πœ†π‘š, 𝑧 = 𝑧0 + πœ†π‘›
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π‘₯Μ… =
𝒓 = 𝒂 + πœ†π’ƒ
𝒗 βˆ™ π’˜ = 𝑣1 𝑀1 + 𝑣2 𝑀2 + 𝑣3 𝑀3
∑π‘˜
𝑖=1 𝑓𝑖 π‘₯𝑖
Μ… , of a set of data
Mean, 𝒙
Expected value of a
discrete random variable X
𝑐
IQR = 𝑄3 − 𝑄1
Interquartile range
Independent events
𝐴 = 4πœ‹π‘Ÿ 2 , π‘Ÿ = radius
cos πœƒ − sin πœƒ
) , anticlockwise rotation
sin πœƒ cos πœƒ
of angle πœƒ about the origin (πœƒ > 0)
𝑧 = π‘Ÿ(cos πœƒ + 𝑖 sin πœƒ) = π‘Ÿπ‘’ π‘–πœƒ = π‘Ÿcisπœƒ
Topic 2: Functions – SL & HL
Equations of a
straight line
4
𝑉 = 3 πœ‹π‘Ÿ 3 , π‘Ÿ = radius
(
βˆ† = 𝑏2 − 4π‘Žπ‘
π‘Ž
𝑨=(
𝑐
𝐴 = πœ‹π‘Ÿπ‘™ , π‘Ÿ= radius, 𝑙 = slant height
π‘˜ 0
)
0 1
Λ’ horizontal stretch by scale factor of π‘˜
𝑧 = π‘Ž + 𝑏𝑖
π‘Ž
𝑐
𝑉 = 3 πœ‹π‘Ÿ β„Ž , π‘Ÿ= radius, β„Ž = height
(
𝑒1
, |π‘Ÿ| < 1
1−π‘Ÿ
𝑨=(
2
cos 2πœƒ sin 2πœƒ
)
sin 2πœƒ −cos 2πœƒ
Λ’ reflection in the line 𝑦 = (tan πœƒ)π‘₯
Transformation
matrices
log π‘Ž π‘₯ π‘š = π‘š log π‘Ž π‘₯
1
(
Topic 1: Number and algebra - HL only
log π‘Ž π‘₯𝑦 = log π‘Ž π‘₯ + log π‘Ž 𝑦
π‘₯
log π‘Ž = log π‘Ž π‘₯ − log π‘Ž 𝑦
𝑦
1
Topic 3: Geometry and trigonometry – HL only
Exponents & logarithms π‘Ž π‘₯ = 𝑏 ⇔ π‘₯ = log π‘Ž 𝑏 , π‘Ž, 𝑏 > 0, π‘Ž ≠ 1
𝑣𝐴 − 𝑣𝐸
πœ€=|
| × 100%
𝑣𝐸
Percentage error
𝑣𝐴 = approximate value, 𝑣𝐸 = exact value
Laws of logarithms
π‘₯1 + π‘₯2 𝑦1 + 𝑦2 𝑧1 + 𝑧2
,
,
)
2
2
2
Volume: Right-pyramid 𝑉 = 3 π΄β„Ž , 𝐴 = base area, β„Ž = height
𝑉 = πœ‹π‘Ÿ 2 β„Ž , π‘Ÿ = radius, β„Ž = height
Volume: Cylinder
(
Topic 4: Statistics and probability - SL & HL
1
𝑑π‘₯ = tan π‘₯ + 𝐢
cos 2 π‘₯
∫ 𝑒 π‘₯ 𝑑π‘₯ = 𝑒 π‘₯ + 𝐢
𝑏
𝑏
𝐴 = ∫ |𝑦| 𝑑π‘₯ or 𝐴 = ∫ |π‘₯| 𝑑𝑦
π‘Ž
𝑏
π‘Ž
𝑏
𝑉 = ∫ πœ‹π‘¦ 2 𝑑π‘₯ or 𝑉 = ∫ πœ‹π‘₯ 2 𝑑𝑦
π‘Ž=
π‘Ž
d𝑣 d2 𝑠
d𝑣
=
=𝑣
d𝑑 d𝑑 2
d𝑠
π‘Ž
𝑑
𝑑
dist = ∫𝑑 2|𝑣(𝑑)| 𝑑𝑑 ; disp = ∫𝑑 2 𝑣(𝑑) 𝑑𝑑
1
1
𝑦𝑛+1 = 𝑦𝑛 + β„Ž × π‘“(π‘₯𝑛 , 𝑦𝑛 ); π‘₯𝑛+1 = π‘₯𝑛 + β„Ž
where β„Ž is a constant (step length)
π‘₯𝑛+1 = π‘₯𝑛 + β„Ž × π‘“1 (π‘₯𝑛 , 𝑦𝑛 , 𝑑𝑛 )
𝑦𝑛+1 = 𝑦𝑛 + β„Ž × π‘“2 (π‘₯𝑛 , 𝑦𝑛 , 𝑑𝑛 )
𝑑𝑛+1 = 𝑑𝑛 + β„Ž
where β„Ž is a constant (step length)
𝒙 = 𝐴𝑒 πœ†1 𝑑 𝒑1 + 𝐡𝑒 πœ†2𝑑 𝒑2
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