Questions of 4Th Tutorial on Thevenin, Norton and Maximum Power Transfer
Theorem’s
Date: 7/9/2018
1. a) For the network shown in fig.1 (a), remove terminal ‘c’ and find Thevenin
equivalent across terminals ‘a’ & ‘b’.
b) Find the Thevenin equivalent circuit for the network shown in fig.1 (a) across
terminals ‘a’ & ‘b’.
Fig.1 (a)
Ans:
Fig.1 (b)
a) VTh= -2V & RTh = 6.6666 Ω
b) VTh= 83.4805 V & RTh = 8.5232 KΩ
2. Find the Thevenin and Norton equivalent circuits for the network shown in fig.2
(a) & fig.2 (b) respectively.
Fig.2 (a)
Ans:
Fig.2 (b)
2(a): VTH = 2 KV, IN = -20 mA & RTh = 100 KΩ
2(b): VTH = 20 V, IN = 3.3333 A & RTh = 6 Ω
3. Find the Thevenin and Norton equivalent circuits for the network shown in fig.3
(a) & fig.3 (b) respectively. And in fig.3 (b) while solving neglect the dotted line
part and find Norton equivalent seen by 2 K Ω.
Fig.3 (a)
Fig.3 (b)
Ans: 3(a): VTH = 0 V, & RTh = 192.3 Ω
3(b): IN = 0 A, & RTh = 47.62 Ω
4. Determine the RL for which maximum power is delivered from source, voltage
across RL and Maximum power drawn by load resistance for the circuit shown in
fig.4
Fig.4
Ans: RL= 16 Ω, VRL = 5V, & PMax = 1.5625 W
5. The variable resistor R in fig.5 is adjusted until it absorbs the maximum power
from the circuit.
a. Calculate the value of R for maximum power
b. Determine the maximum power absorbed by R
Fig.5
Ans: R = 25 Ω, & PMax = 7.84 W