AXIALLY LOADED MEMBERS OUTLINE • Axially Loaded Members • Changes in lengths of axially loaded members • Bars with intermediate axial loads • Bars consisting of prismatic segments 2/21/2024 DO Oyejobi 2 In our previous lessons: • Normal stress and normal strain • Mechanical properties of materials • Elasticity and Plasticity • Hooke’s Law and Poisson’s ratio • Shear stress, bearing stress and shear strain • Shear and bearing capacity of a connection • Allowable stresses and allowable loads 2/21/2024 DO Oyejobi 3 OUTCOME At the end of the lecture: • students should understand what axially loaded members are and • their useful properties necessary for analysis and design • Should know techniques for determining changes in lengths of axially loaded members in uniform and non-uniform conditions 2/21/2024 DO Oyejobi 4 Axially Loaded Members 2/21/2024 DO Oyejobi 5 Axially loaded members are structural components subjected only to tension or compression. Solid bars with straight longitudinal axes are the most common type, although cables and coil springs also carry axial loads. Examples of axially loaded bars are truss members, connecting rods in engines, spokes in bicycle wheels, columns in buildings, and struts 2/21/2024 DO Oyejobi in aircraft engine mounts. 6 Calculation of changes in lengths of axially loaded members 2/21/2024 7 • When a load is applied along the axis of a spring, as shown in Fig.1, the spring gets longer or shorter depending upon the Springs direction of the load. • If the load acts away from the spring, the spring elongates and we say that the spring is loaded in tension. If the load acts toward the spring, the spring shortens and we say it is in compression 2/21/2024 DO Oyejobi Fig.1 Spring subjected to an axial load P 8 DO Oyejobi • The elongation of a spring is pictured in Fig. 2, where the upper part of the figure shows a spring in its natural length L, and the lower part of the figure shows the effects of applying a tensile load. • Under the action of the force P, the spring lengthens by an amount δ and its final length becomes L + δ. • If the material of the spring is linearly elastic, the load and elongation will be proportional: Fig. 2: Elongation of an axially loaded spring where “k and f” are constants of proportionality 2/21/2024 9 The constant ‘k’ is called the stiffness of the spring and is defined as the force required to produce a unit elongation, that is, k = P/δ. Similarly, the constant ‘f’ is known as the flexibility and is defined as the elongation produced by a load of unit value, that is, f = δ/P. From the above, it is apparent that the stiffness and flexibility of a spring are the reciprocal of each other: 2/21/2024 DO Oyejobi 10 A prismatic bar is a structural member having a straight longitudinal axis and constant cross section throughout its length. Prismatic Bars Fig.3: Typical cross sections of structural members Structural members may have a variety of cross-sectional shapes, such Fig. 4: Prismatic bar of circular cross section as those shown in Fig. 3. To analyze this behavior, let us consider the prismatic bar shown in Fig. 4 2/21/2024 DO Oyejobi 11 The elongation δ of a prismatic bar subjected to a tensile load P is shown in Fig. 5. If the load acts through the centroid of the end cross section, the uniform normal stress at cross sections away from the ends is given by the formula σ = P/A, where A is the cross-sectional area. Fig. 5: Elongation of a prismatic bar in tension Furthermore, if the bar is made of a homogeneous material, the axial strain is ε = δ/L, where δ is the elongation and L is the length of the bar. 2/21/2024 DO Oyejobi 12 Assuming the material is linearly elastic, Combining these basic relationships, we get the following equation for the elongation of the bar: The product EA is known as the axial rigidity of the bar. The stiffness and flexibility of a prismatic bar are defined in the same way as for a spring. 2/21/2024 DO Oyejobi 13 Cables are used to transmit large tensile forces, for Cables example raising elevators, guying towers, and supporting suspension bridges. Unlike springs and prismatic bars, cables cannot resist compression. When determining the elongation of a cable from the effective modulus should be used for E and the effective area should be used for A. 2/21/2024 DO Oyejobi 14 DO Oyejobi 1. Draw the free-body diagram for the Techniques for calculating changes in length part or the given body as necessary 2. Apply equations of equilibrium 3. Draw displacement diagram 4. Use formulas for calculating changes in length 2/21/2024 15 Example 1 The device shown in Fig. 6 consists of a horizontal beam ABC supported by two vertical bars BD and CE. Bar CE is pinned at both ends but bar BD is fixed to the foundation at its lower end. The distance from A to B is 450 mm and from B to C is 225 mm. Bars BD and Fig. 6: Horizontal beam ABC CE have lengths of 480 mm and 600 mm, respectively, supported by two vertical bars and their cross-sectional areas are and Assuming that beam ABC is rigid: (a) Find the maximum allowable load respectively. The bars are made of steel if the displacement of point A is limited to 1.0 mm having a modulus of elasticity E 205 GPa. 2/21/2024 DO Oyejobi 16 Bars with Intermediate Axial Loads Fig. 7: Bar with external loads acting at intermediate points 2/21/2024 DO Oyejobi 17 When a prismatic bar of linearly elastic material is loaded only at the ends, we can obtain its change in length from the equation δ = PL/EA. Suppose, for instance, that a prismatic bar is loaded by one or more axial loads acting at intermediate points along the axis (Fig. 7). We can determine the change in length of this bar by adding algebraically the elongations shortenings of the individual segments. 2/21/2024 DO Oyejobi and Fig. 7: Bar with external loads acting at intermediate points 18 The procedure is as follows: 1. Identify the segments of the bar: Segments AB, BC, and CD as segments 1, 2, and 3, respectively. 2/21/2024 DO Oyejobi 19 2. Determine the internal axial forces in segments 1, 2, and 3, respectively, from the free-body diagrams of Figs. 7b, c, and d. By summing forces in the vertical direction 2/21/2024 Fig. 7 (b), (c), and (d) free-body diagrams showing the internal axial forces N1, N2, and N3 DO Oyejobi 20 3. Determine the changes in the lengths of the segments from 2/21/2024 DO Oyejobi Fig. 7 (b), (c), and (d) free-body diagrams showing the internal axial forces N1, N2, and N3 21 4. Add δ1, δ2, and δ3 to obtain δ, the change in length of the entire bar: 2/21/2024 DO Oyejobi Fig. 7 (b), (c), and (d) free-body diagrams showing the internal axial forces N1, N2, and N3 22 Bars Consisting of Prismatic Segments 2/21/2024 DO Oyejobi 23 Fig. 8: Bar consisting of prismatic segments having different axial forces, different dimensions, and different materials 2/21/2024 DO Oyejobi 24 Fig. 8: Bar consisting of prismatic segments having different axial forces, different dimensions, and different materials 2/21/2024 DO Oyejobi 25 Thank you 2/21/2024 DO Oyejobi 26