PHYS 410 Optics Homework Set #1 (Ch. 2) (Due date: March 4, 2024) 1. [5 pts] Show that π(π₯, π¦, π§, π‘) = π [π(πΌπ₯ + π½π¦ + πΎπ§) − ππ‘] is a plane wave solution of the three-dimensional (3-D) wave equation, where π is an arbitrary twice-differentiable function. !(#$%&) 2. [5 pts] Show that π(π, π‘) = # is the spherical wave solution (centered at the origin and moving away from it with a speed π£) of the 3-D wave equation. Here π(π − π£π‘) is an arbitrary twice-differentiable function. ( 3. Consider the disturbance profile π(π¦, 0) = )* ! +,. (a) [3 pts] Write the expression for the corresponding progressive wave moving with a speed of 5 m/s in the positive π¦-direction. (b) [2 pts] Verify that the answer above is indeed a solution to the wave equation. 4. Consider two plane waves, π, (π§, π‘) = π΄ cos(ππ§ − ππ‘) and π) (π§, π‘) = π΄ cos(ππ§ + ππ‘). (a) [3 pts] When the two waves overlap in some region of space, what is the resulting wave? (b) [2 pts] In what direction is the resulting wave propagating? 5. [5 pts] Hecht 2.36 6. [5 pts] Hecht 2.41 7. [5 pts] Hecht 2.49 8. [5 pts] Hecht 2.51 9. [5 pts] Hecht 2.59 . 10. The speed of light (phase velocity) in a medium is given as π£- = /, where c is the speed of light in vacuum and n is the refractive index of the medium. The refractive index of a medium varies with frequency or wavelength, i.e., π(π) or π(π), and this phenomenon is . 0 called dispersion. The phase velocity is therefore π£- = / = 1 . The group velocity is given as, ππ π π ππ π ππ ππ π ππ π£2 = = ?ππ£- @ = A C= − ) = π£- A1 − C. ππ ππ ππ π π π ππ π ππ Derive the following. 3% (a) [5 pts] π£2 = π£- − π 34" . , 4# 3/ " . 34# (b) [10 pts] π£2 = A% − $, C , where π5 is the vacuum wavelength.