Zhang
YunyiPledger
:
Class No
BJUT
:
IOTI
1
Student ID
UCDStadentID
Questiont
short
1)
21371117
:
:
:
circuit
-
鬭
the load
⼀
0L
世
i
⼝
_
Ia
⼝
Find
21207375
the Isc
6
三
Isc
4 2
-
:
+
=
五A
R
division
the
Find
[ ( 4114 )
=
+
source
4 J 112
3n
=
equiralent of
Norton
resistance
the
,
circuit
,
瀬
) z
2
=
Vo
=
3
+π )
正
Z
H
3 t
11 (
S
=
)
si
-
1l
sL
(S)
=
+4
+π
崖开
S
×π
+
1
s
)
3
:
Vo ( t )
=
π
V
,
Vo 0
5
(t )
=
'
∵
10
vo ( t
)
TB
_
+ 4 tj
正
Z
×
Vi
=
m上φ
5
“
V
,
:
-
:
4
)
Vi
68420 r
=
Vi
(t )
,
68 sinct
=
-
420 ) V
.
vi
Λ
)
⼗
:
⼀
:
⼀
⼀⼀
…
「
…
⼀
⼀
下
⼀
!
1
,
-
10
⼀
;
L
⼀
⼀
Vo
1
∵
1
—
…
—
;
1
…
t …
…
-
8
.
5V
-
1
Question
Iwhen
iV
…
…
…
1
:
!!
2
;
ts alone
rit ' a.
θ
Vi 品品⼝7
-
⽌
七⼀内⼆⼟
⼀
⼀
vab
Vab
=台X
'
when
i (t )
Uab
=
: Uab
Rab
“
_
2 )-
=
t+× 3
1
继V
,
b
冗
nt
run 2uF
1
=
tt ]
22
52
↓
bRabL
VoCt )
alone
a
⾃
Oab ⑤
(
i
= 2 sin ( ω
“
.
,
6×
—
nV
1
=
)
acts
31/ 6
=
γt
_
上
=
—
_
—
Rab + Ru +ω l + Wc
10
ewcV
嘉
,
X
5
,
3)
1
f
=
Iπ
Bw
4)
:
⻘
f
⼀
.
dLC
79
上
=
1
=
79 6 KHz
:
站
=
IMH
C
=
.
2 MHz
whenXc
maximum Power
L
=
106 Hz
×
555
-
-
-
can
)
IJµ F
,
U
U , ( t)
= U +=
O
U
-
-
⼀
RI
U
-
-
Uo ( t)
⼆⼀
÷
*
,
=
o
U , (t )
Rz
-
亠
⼆
R9
⼗
xc
obtain
be
Question 了 :
1
=
jxc
,
U
=
( t)
0
=
-
I
.U
-
⼆⼗⼆
R9
jXc
-
2
) f
=
c
⼆
i π R+
=
·
=
C
流t 所
(t )
,
KHz
20
—
—
=
—
20 ×103× 2 ×10
Zπ×
-
≈ 3
]
3
-
U
jxc
=
-
=
Ux
Uz ( t )
-
=
U
-
.
98
O
U , (t )
.
-
U
U
-
亠
应坑
,
,
uzt
+
R,
F
j的
—
— ←
R
× 10
9
了
—
Ui ( t )
-
O
=
后
—
-
-
H 0 (t
)
⼀
—
—
*
)
H0 (
0
—
-
t
÷
⼀
厨*
c
U 01 t
1
=
*
⾚
- (
21 )
R,
1
⼀
00 *
⼆
U
器 U⻔
×(
吉
tiefrt
-
- it )
⼀
4000
4
R
1
2K
2
三□
⼀
Rf
⽐⼀du
1
u
忙
⼝
=
2
—
=
4k2
Ril
1
⼠
( Uz ( t
)
-UI
—
R
,
RL
=
1o
!
U
。
←
嘴
—
红
⼀
Ri
⼗
.
—
imat
102
1
⻉ 壮
、
kr
θ
“
t
Ro
⼑
000
←
R2
—
11 ←
1
Ln
⼼⼀
-
—
0
(t )
⼝⼀
HI
-
l
。
⼗⼀
亠
亠
Rft jwc
-
U = ( t)
-
llI
f
⼀
2000
lz
(t)
)
-
U
fllI
⼀
⼀
1 × 106
UI
UI
⼆
—
( × 106
⼗
⼗
UI
-
⼀
U
jωc
0
⼀
丄
⼗
≡
-jWc
。
ω
c
库坊
4
凹世
Au
+
⼀丝 Uz
⼀
⼀
RL
Ro
=
⼀
以羉
R,
Ri
…
U (
±
⼀
←
…
llitt) tlr
-
…
…
豳园
—
,
)
tf - ll
R
)
亠
1
Rf
1000
⼀
uo ( t
-
⼀
⼀
⼀
⼗—
2000
llo
UI
lI
⼀
lU , ( t
⼀
HI
-
1000
lUI
-
C1 , (t )
,
…
…
HI
-
L
—
UI