11/27/2023 24 FOURAH BAY COLLEGE ELECTRICAL & ELECTRONIC ENGINEERING DEPARTMENT APPLIED ELECTRICITY I (EENG212) LECTURE NOTES PARALLEL DC NETWORKS 25 FOURAH BAY COLLEGE ELECTRICAL & ELECTRONIC ENGINEERING DEPARTMENT APPLIED ELECTRICITY I (EENG212) LECTURE NOTES Lesson 2.3. (Parallel Circuit) I2 I I I1 R1 V I = I1 + I2 = + R2 V RT V =V 1 1 1 = + 𝑅𝑇 R1 R2 + 𝑅𝑇 = 1 11/27/2023 26 FOURAH BAY COLLEGE ELECTRICAL & ELECTRONIC ENGINEERING DEPARTMENT APPLIED ELECTRICITY I (EENG212) LECTURE NOTES Example 1. Calculate the current I, I1 and I2. I 𝑅𝑇 = I2 NODE I1 12v 15Ω 𝑅𝑇 = , 𝑅𝑇 = 10 Ω I= NODE For parallel circuits, the current flowing towards a Junction is divided into branches Kirchhoff Current Law (KCL) states that “The algebraic sum of the currents flowing to a node is zero” Current flowing towards the junction are positive Current flowing away from the junction are negative I – I1 – I2 = 0 𝑽 , 𝑰= 𝑹𝑻 I1 = I2 = 𝑽 𝑹𝟏 𝑽 𝑹𝟐 ∗ 𝑅𝑇 = 6 Ω , 𝟏𝟐 𝟔 , 𝑰𝟏 = , 𝑰𝟐 = =𝟐𝑨 𝟏𝟐 𝟏𝟓 𝟏𝟐 𝟏𝟎 = 𝟎. 𝟖 𝑨 = 𝟏. 𝟐 𝑨 I1 + I2 = 0.8 + 1.2 = 2A 27 FOURAH BAY COLLEGE ELECTRICAL & ELECTRONIC ENGINEERING DEPARTMENT APPLIED ELECTRICITY I (EENG212) LECTURE NOTES Example 2. Calculate effective resistance of the circuit. R1 I V NODE 1 R1 R3 I I2 I1 R2 R4 V NODE 1 I1 R2 I2 R5 NODE 0 NODE 0 Note: R3 and R4 are in series R3 + R4 = R5 (R5 // R2) = RT = R1 + 2 11/27/2023 28 FOURAH BAY COLLEGE ELECTRICAL & ELECTRONIC ENGINEERING DEPARTMENT APPLIED ELECTRICITY I (EENG212) LECTURE NOTES Example 3. Calculate the current I, I1 and I2. 14 Ω I 12Ω 8Ω NODE 1 I2 I1 7Ω 10 Ω 160V I 160 v NODE 1 14 Ω I1 I2 18 Ω 10 Ω NODE 0 NODE 0 RT = 14 + [10 // (8 + 7)] I= RT = 14 + 10 // 15 RT = 14 + 6 = 20 Ω I= I=8A , , CLASSWORK 29 FOURAH BAY COLLEGE ELECTRICAL & ELECTRONIC ENGINEERING DEPARTMENT APPLIED ELECTRICITY I (EENG212) LECTURE NOTES Example 2 Compute the current I in the figure below I 8A + 24V -- 16Ω 16Ω 16Ω 3 11/27/2023 30 FOURAH BAY COLLEGE ELECTRICAL & ELECTRONIC ENGINEERING DEPARTMENT APPLIED ELECTRICITY I (EENG212) LECTURE NOTES Current Divider Rule IT IR1 R1 V To find IR1 IR2 IT = V( R2 V = IT /( IT = I1 + I2 ) + V = IT /( 𝑉 V V = + 𝑅𝑇 R1 R2 ) V = IT ( I1 = ) + ) = [IT ( IR1 = IT ( To find IR2 IR2 = )]( ) = [IT ( IR2 = IT ( ) )]( ) ) 31 FOURAH BAY COLLEGE ELECTRICAL & ELECTRONIC ENGINEERING DEPARTMENT APPLIED ELECTRICITY I (EENG212) LECTURE NOTES Example 1 Calculate the current I, I1, I2 and I3 in the figure below using the Current Divider Rule I 24V + -- 12Ω I3 I2 I1 10Ω 18Ω 4