1.
2.
3.
4.
5400  4995  100%  7.5%
(a)
3  280  280  P560
M1A1
(c)
100  52.80
 P 60.00
88
M2A1
(a)
9.8  10 4
 2  10 3
7
4.9  10
M1A1
(c)
(i)
9.8  10 4  1.05  1.029  10 5
M1A1A1
(ii)
9.8  10 4  1.05 2  1.08  10 5
M1A1
(a)
(i)
Tangent
(b)
8.2
 5.33
tan 57
290
860
B1
(b)
(b)
(ii)
5400


1
4.9  10 7  2.45  10 7
2
900
M1A1
M1A1
B1
M1A1
(c)
(i)
(ii)
angles in the same segment are equal
B1B1
opposite angles in a cyclic quad are supplementary. B1B1
(i)
25 x  20 y  1100
B2
(ii)
20 x  25 y  1150
B1
(iv)
20+30=50
B1
225 y  6750
(iii)
y  30
M1A1A1
x  20
5.
Check graph paper
6.
(a)
7x  5
x  13x  1
7.
(a)
=11.6
(c)
ON  3.62
 231
2 xy  Ax  b
M2A1
(b)
M1A1
(b)
2.32  27.5
 2.66
7.4 2
M1A1
(d)
(i)
x
(ii)
1
M2A1
b
2y  A
M2A1
340
= 22
ON  3.6
340  200
ON  3.62
 294
A1
M1A1
8.
(a)
(i)
29 ; 41
B1B1
(ii)
n 2  3n  1
M2A1
n 2  3n  88  0
(b)
1805
n  11 or n  8
B1
M2A1
diagram 8
9.
10.
11.
12.
Check graph
d=9
B1
(f)
correct tangent M =2
M2A1
M1A1
(a)
u = 99.6
M3A1
(b)
4
17
 13.2
(c)
(i)
M2A1
(ii)
P181.26
(a)
30
t
B1
(b)
(i)
(b)
(ii)
30
t  1.5
(c)
(i)
Show that B3 NWW or fiddles
(ii)
 3  369
4
 4.05 or  5.55
B5
(iii)
5.41
B1
(a)
(i)
9x
B1
(ii)
4y
B1
(b)
9 x  4 y  36
B1
(c)
(i)
B1
(ii)
126 y
B1
(iii)
38.2
t  1.5
B1
B1
98 x
98 x  126 y  882
7 x  9 y  63
tan 1
NWW B2
(d)
yx
(e)
(i)
Correct lines and shading and region
D3D1
(ii)
6,2
M1A1
B1
9  6  4  2  62
2
M2A1
13.
1
 20V  320
2
V  16
(i)
(a)
(c)
1.6 m/s2
(ii)
32T  320  24T
T  40
M2A1
B1
M2A1
3
(b)
V =16
M1A1