Uploaded by yaamer54

MECHANICS (1)

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Given :
ito lang
P
diameter
ng steel
200
=
/
↑
-
b18
fS
=
Es
Ec
-
29410psi
=
ds
82
=
.
=
psi
.
=
.
8s
Oc
=
1
20
Ps
=
=
=
0
7 025 x 10 9 Ps
.
0
.
6949Ps
.
> O
is
is
.
.
P
121lbs
=
P
00)o
+8
e
=
+
.
Gin
Ps
=
2
OcAc
+ Os
using the
Ests
As
>
-
O
E
=
Os 24 038 966lbs
.
.
.
Pc
*
,
=
=
·
s
6949Ps + Ps
6 = 0 5 in
-
.
SOLIN
=
=
psi
1 000
499)
2900
-
Ps(0 6949 + 1)
118 001 Kips
PC = 0
Pc
=
Pc + Ps - Q
200 =
200
=
PS - Oc
-
.
=
.
(i)(4)
FilS(6 52-G2)(29xr04)
011 x 158 Pc
Pc
(81
6 5
=
dc
T
=
PLA
.
.
=
ds
Oc
Exob)
0
=
5 in
bin
:
=
Ec = 3 5 x 100
P 200 kips
5 x103
6 5in-bin
=
de
SOLN
3
=
Given :
Es 24 X104
psi
kips
6949(1/8 001)
82
:
O
.
②
81 999
kips
.
P
=
P
=
(Os ) Act Ts As
,
Os)
200x1000=
Q
-
Ac +
As)
0s[(#)(4) + #(4 52
.
Ts
Oc
=
24035 114
.
Psi
-
4
24
=
,
075
.
2900
Ille/10
psi
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