Ordinary Differential Equations Lecture 1: Introduction and direction fields. Basic concepts of ODEs. Initial value problems and boundary value problems. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 1 / 33Ba Course: MAT 205 Ordinary differential equations Instructor: Aishabibi Dukenbayeva email: a.dukenbayeva@sdu.edu.kz Assessments: Midterm 1: 7th week of study 20p Midterm 2: 13th week of study 20p Homework: 20p Final: 40p Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 2 / 33Ba Course description In this introductory course on Ordinary Differential Equations, we first provide Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 3 / 33Ba Course description In this introductory course on Ordinary Differential Equations, we first provide basic terminologies on the theory of differential equations; Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 3 / 33Ba Course description In this introductory course on Ordinary Differential Equations, we first provide basic terminologies on the theory of differential equations; proceed to methods of solving various types of ordinary differential equations; Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 3 / 33Ba Course description In this introductory course on Ordinary Differential Equations, we first provide basic terminologies on the theory of differential equations; proceed to methods of solving various types of ordinary differential equations; first order differential equations; Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 3 / 33Ba Course description In this introductory course on Ordinary Differential Equations, we first provide basic terminologies on the theory of differential equations; proceed to methods of solving various types of ordinary differential equations; first order differential equations; second and higher order linear differential equations; Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 3 / 33Ba Course description In this introductory course on Ordinary Differential Equations, we first provide basic terminologies on the theory of differential equations; proceed to methods of solving various types of ordinary differential equations; first order differential equations; second and higher order linear differential equations; systems of differential equations; Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 3 / 33Ba Course description In this introductory course on Ordinary Differential Equations, we first provide basic terminologies on the theory of differential equations; proceed to methods of solving various types of ordinary differential equations; first order differential equations; second and higher order linear differential equations; systems of differential equations; discuss some related concrete mathematical modeling problems, which can be handled by the methods introduced in this course; Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 3 / 33Ba Course description In this introductory course on Ordinary Differential Equations, we first provide basic terminologies on the theory of differential equations; proceed to methods of solving various types of ordinary differential equations; first order differential equations; second and higher order linear differential equations; systems of differential equations; discuss some related concrete mathematical modeling problems, which can be handled by the methods introduced in this course; Laplace transform if time permits. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 3 / 33Ba Textbooks The main books are Elementary Differential Equations and Boundary Value Problems, Eleventh edition by William E. Boyce, Richard C. Diprima and Douglas B. Meade. Ordinary Differential Equation, by Morris Tenenbaum and Harry Pollard. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 4 / 33Ba Other resources Ordinary Differential Equations, Third Edition by Shepley L. Ross; Ordinary Differential Equations, by Vladimir I. Arnold (for more advanced students). If necessary, you may use any other introductory level textbook on ordinary differential equations. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 5 / 33Ba Introduction The study of differential equations has attracted the attention of many of the world’s greatest mathematicians during the past three centuries. On the other hand, it is important to recognize that differential equations remains a dynamic field of inquiry today, with many interesting open questions. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 6 / 33Ba Many of the principles, or laws, or processes underlying the behavior of the natural world are statements or relations involving rates at which things happen. When expressed in mathematical terms, the relations are equations and the rates are derivatives. Equations containing derivatives are differential equations. Therefore, to understand and to investigate problems involving the motion of fluids, the flow of current in electric circuits, the dissipation of heat in solid objects, the propagation and detection of seismic waves, or the increase or decrease of populations, among many others, it is necessary to know something about differential equations. A differential equation that describes some physical process is often called a mathematical model of the process, and many such models are discussed throughout this course. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 7 / 33Ba Basic Concepts Mathematical modeling of physical, economical, biological etc phenomena often produces an equation which involves an ordinary or partial derivatives of some unknown function. Such an equation is called a differential equation. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 8 / 33Ba Basic Concepts Mathematical modeling of physical, economical, biological etc phenomena often produces an equation which involves an ordinary or partial derivatives of some unknown function. Such an equation is called a differential equation. A differential equation is an ordinary differential equation (ODE) if the unknown function depends on only one independent variable. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 8 / 33Ba Basic Concepts Mathematical modeling of physical, economical, biological etc phenomena often produces an equation which involves an ordinary or partial derivatives of some unknown function. Such an equation is called a differential equation. A differential equation is an ordinary differential equation (ODE) if the unknown function depends on only one independent variable. If the unknown function depends on two or more independent variables, the differential equation is a partial differential equation (PDE). The primary focus of this course will be ordinary differential equations. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 8 / 33Ba Basic Concepts Mathematical modeling of physical, economical, biological etc phenomena often produces an equation which involves an ordinary or partial derivatives of some unknown function. Such an equation is called a differential equation. A differential equation is an ordinary differential equation (ODE) if the unknown function depends on only one independent variable. If the unknown function depends on two or more independent variables, the differential equation is a partial differential equation (PDE). The primary focus of this course will be ordinary differential equations. The order of a differential equation is the order of the highest derivative appearing in the equation. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 8 / 33Ba Example Example 1. Newton’s second low of motion applied to a free falling body leads to an ODE dv d2 h = −mg. =m dt2 dt where m is the mass of the object, g the gravitational acceleration, h the height of the object, and v = dh dt the velocity. m Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 9 / 33Ba Example Example 1. Newton’s second low of motion applied to a free falling body leads to an ODE dv d2 h = −mg. =m dt2 dt where m is the mass of the object, g the gravitational acceleration, h the height of the object, and v = dh dt the velocity. m Example Example 2. Modeling of vibrating strings, under some ideal conditions, leads to a PDE, called the wave equation 2 ∂2u 2∂ u − c = 0. ∂t2 ∂x2 where t is the time, x the location along the string, c the wave speed, and u = u(x, t) the displacement of the string. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 9 / 33Ba Simplest PDE examples A few examples of second order linear PDEs in 2 variables are: α2 uxx = ut (one-dimensional heat conduction equation) a2 uxx = utt (one-dimensional wave equation) uxx + uyy = 0 (two-dimensional Laplace/potential equation) Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 10 / 33Ba Example Example 3. Equations (1) through (4) are examples, of ODEs, since the unknown function y depends solely on the variable x. Equation (5) is a PDE, since y depends on both the independent variables t and x. dy = 5x + 3 dx 2 d2 y dy ey 2 + 2 =1 dx dx d3 y d2 y 4 3 + (sinx) 2 + 5xy = 0 dx dx 2 3 7 2 dy dy d y 3 + 3y + y = 5x dx2 dx dx ∂2y ∂2y −4 2 =0 2 ∂t ∂x (1) (2) (3) (4) (5) Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 11 / 33Ba Example Example 3. Equations (1) through (4) are examples, of ODEs, since the unknown function y depends solely on the variable x. Equation (5) is a PDE, since y depends on both the independent variables t and x. dy = 5x + 3 dx 2 d2 y dy ey 2 + 2 =1 dx dx d3 y d2 y 4 3 + (sinx) 2 + 5xy = 0 dx dx 2 3 7 2 dy dy d y 3 + 3y + y = 5x dx2 dx dx ∂2y ∂2y −4 2 =0 2 ∂t ∂x (1) (2) (3) (4) (5) Example Example 4. Equation (1) is a first-order DE; (2),(4), and (5) are second-order DE. Equation (3) is a third-order DE. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 11 / 33Ba Notation The expressions y 0 , y 00 , y 000 , y 4 , ..., y n are often used to represent, respectively, the first, second, third, fourth, ..., nth derivatives of y with respect to the d2 y independent variable under consideration. Thus, y represents dx 2 if the 2 independent variable is x, but represents ddpy2 if the independent variable is p. Observe that parentheses are used in y (n) to distinguish it from the nth power, y n . If the independent...variable is time, usually denoted by t, primes are often replaced by dots ẏ, ÿ, y , .... Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 12 / 33Ba Linear ODEs Definition A linear ordinary differential equation of order n, in the dependent variable y and the independent variable x, is an equation that is in, or can be expressed in, the form a0 (x) dn−1 y dy dn y + a1 (x) n−1 + · · · + an−1 (x) + an (x)y = b(x) n dx dx dx where a0 is not identically zero. Observe that the dependent variable y and its derivatives occur to the first degree only; that no products of y and/or any of its derivatives are present; that no transcendental functions of y and/or its derivatives occur. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 13 / 33Ba Example Example 5. The following ordinary differential equations are both linear. In each case y is the dependent variable. Observe that y and its various derivatives occur to the first degree only and that no products of y and/or any of its derivatives are present. dy d2 y +5 + 6y = 0 2 dx dx (6) 3 d4 y dy 2d y + x + x3 = xex 4 3 dx dx dx (7) Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 14 / 33Ba Linear ordinary differential equations are further classified according to the nature of the coefficients of the dependent variables and their derivatives. For example, Equation (6) is said to be linear with constant coefficients, while Equation (7) is linear with variable coefficients. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 15 / 33Ba Nonlinear ODEs Definition A nonlinear ordinary differential equation is an ordinary differential equation that is not linear. Example Example 6. The following ordinary differential equations are all nonlinear: d2 y dy + 6y 2 = 0 +5 dx2 dx 3 d2 y dy + 5 + 6y = 0 dx2 dx d2 y dy + 5y + 6y = 0 dx2 dx (8) (9) (10) Equation (8) is nonlinear because the dependent variable y appears to the second degree in the term 6y 2 . Equation (9) owes its nonlinearity to the presence of the term 5(dy/dx)3 , which involves the third power of the first derivative. Finally, equation (10) is nonlinear because of the term 5y(dy/dx), which involves the product of theDukenbayeva dependenta.dukenbayeva@sdu.edu.kz variable and its first derivative. Aishabibi Ordinary Differential Equations Lecture 1: Introduction and direction fields. 16 / 33Ba Application of DE Differential equations occur in connection with numerous problems that are encountered in the various branches of science and engineering. For example The problem of determining the motion of a projectile, rocket, satellite, or planet. The problem of determining the charge or current in an electric circuit. The problem of the conduction of heat in a rod or in a slab. The problem of determining the vibrations of a wire or a membrane. The study of the rate of decomposition of a radioactive substance or the rate of growth of a population. The study of the reactions of chemicals. The problem of the determination of curves that have certain geometrical properties. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 17 / 33Ba Solutions A solution of a differential equation in the unknown function y and the independent variable x on the interval I, is a function y(x) that satisfies the differential equation identically for all x in I. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 18 / 33Ba Solutions A solution of a differential equation in the unknown function y and the independent variable x on the interval I, is a function y(x) that satisfies the differential equation identically for all x in I. Example Example 7. Is y(x) = c1 sin 2x + c2 cos 2x, where c1 and c2 are arbitrary constants, a solution of y 00 + 4y = 0? Differentiating y, we find y 0 = 2c1 cos 2x − 2c2 sin 2x and y 00 = −4c1 sin 2x − 4c2 cos 2x Hence, y 00 + 4y = (−4c1 sin 2x − 4c2 cos 2x) + 4 (c1 sin 2x + c2 cos 2x) = (−4c1 + 4c1 ) sin 2x + (−4c2 + 4c2 ) cos 2x =0 Thus, y = c1 sin 2x + c2 cos 2x satisfies the differential equation for all values of x and is a solution on the interval (−∞, ∞). Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 18 / 33Ba Example Example 8. Determine whether y = x2 − 1 is a solution of (y 0 )4 + y 2 = −1. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 19 / 33Ba Example Example 8. Determine whether y = x2 − 1 is a solution of (y 0 )4 + y 2 = −1. Note that the left side of the differential equation must be nonnegative for every real function y(x) and any x, since it is the sum of terms raised to the second and fourth powers, while the right side of the equation is negative. Since no function y(x) will satisfy this equation, the given differential equation has no solution. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 19 / 33Ba We see that some differential equations have infinitely many solutions (Example 7), whereas other differential equations have no solutions (Example 8). It is also possible that a differential equation has exactly one solution. Consider (y 0 )4 + y 2 = 0, which for reasons identical to those given in Example 8 has only one solution y = 0. It is customary to call a solution which contains n constants c1 , c2 , ..., cn an n-parameter family of solutions, and to refer to the constants c1 to cn as parameters. For the classes of differential equations we shall consider, we can now assert: a differential equation of the nth order has an n-parameter family of solutions. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 20 / 33Ba Definition A solution of a differential equation will be called a particular solution if it satisfies the equation and does not contain arbitrary constants. Definition An n-parameter family of solutions of differential equation will be called a general solution if it contains every particular solution. So a particular solution of a differential equation is any one solution. The general solution of a differential equation is the set of all solutions. Example The general solution to the differential equation in Example (9) can be shown to be y = c1 sin 2x + c2 cos 2x. That is, every particular solution of the differential equation has this general form. A few particular solutions are:(a) y = 5 sin 2x − 3 cos 2x (choose c1 = 5 and c2 = −3), (b) y = sin 2x (choose c1 = 1 and c2 = 0 ), and (c) y = 0 (choose c1 = c2 = 0). Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 21 / 33Ba Initial-value and boundary-value problems We shall begin this section by considering the rather simple problem of the following example. Example Find a solution f of the differential equation dy = 2x dx (11) such that at x = 1 this solution f has the value 4. Explanation. We seek a real function f which fulfills the two following requirements: The function f must satisfy the differential equation (11). That is the function f must be such that f 0 (x) = 2x for all real x in a real interval I. The function f must have the value 4 at x = 1. That is, that function f must be such that f (1) = 4. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 22 / 33Ba Solution. We observe that the differential equation has one-parameter family of solutions y = x2 + c, (12) where c is an arbitrary constant. Let us now determine the constant c so that (12) satisfies requirement 2, that is y(1) = 4. By simpel calculation, we find that f (x) = x2 + 3. If all of the associated supplementary conditions relate to one x value, the problem is called an initial-value problem (or one-point boundary-value problem). If the condition relate to two different x values, the problem is called a two-point boundary-value problem (or simply a boundary-value problem) Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 23 / 33Ba Example d2 y +y =0 dx2 y(1) = 3, y 0 (1) = −4. Both of this conditions relate to one x value, namely, x = 1. Thus, this is an initial-value problem. Example d2 y +y =0 dx2 y(0) = 1, π y( ) = 5. 2 The conditions relate to the two different x values, 0 and boundary-value problem. π . 2 Thus, this is a Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 24 / 33Ba Now we turn to a more detailed consideration of the initial-value problem for a first-order differential equation. Definition Consider the first-order differential equation dy = f (x, y) dx (13) where f is a continuous function of x and y in some domain D of the xy plane; and let (x0 , y0 ) be a point of D. The initial-value problem associated with (13) is to find a solution φ of the differential equation (13), defined on some real interval containing x0 , and satisfying the initial condition φ (x0 ) = y0 In the customary abbreviated notation, this initial-value problem may be written dy = f (x, y) dx y (x0 ) = y0 Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 25 / 33Ba Geometric interpretation of the initial-value problem To solve this problem, we must find a function φ that not only satisfies differential equation (13) but that also satisfies the initial condition that it has the value y0 when x has value x0 . The geometric interpretation of the initial condition, and hence of the entire initial-value problem, is easily understood. The graph of the desired solution φ must pass through the point with coordinates (x0 , y0 ). That is, interpreted geometrically, the initial-value problem is to find an integral curve of the differential equation (13) that passes through the point (x0 , y0 ). Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 26 / 33Ba Example Solve the initial-value problem dy x =− dx y (14) y(3) = 4 (15) given that the DE (14) has a one-parameter family of solutions x2 + y 2 = c 2 (16) The pair of values (3, 4) must satisfy the relation (16). Substituting x = 3 and y = 4 into (16), we find 9 + 16 = c2 or c2 = 25 Now substituting this value of c2 into (16), we have x2 + y 2 = 25 Solving this for y, we obtain y=± p 25 − x2 Obviously the positive sign must be chosen to give y the value +4 at x = 3. Thus the function f defined by p f (x) = 25 − x2 , −5 < x < 5 is the solution of the problem. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 27 / 33Ba Existence of Solutions Do all initial-value and boundary-value problems have solutions? We can easily check that the following boundary-value problem d2 y +y =0 dx2 y(0) = 1 y(π) = 5 has no solution! Thus arises the question of existence of solutions: given an initial-value or boundary-value problem, does it actually have a solution? Every initial-value problem that satisfies the definition given above has at least one solution. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 28 / 33Ba But now another question is suggested, the question of uniqueness. Does such a problem ever have more than one solution? Let us consider the initial-value problem dy = y 1/3 dx y(0) = 0 One may verify that the functions f1 and f2 defined, respectively, by f1 (x) = 0 and f2 (x) = 2 x 3 for all real x 3/2 , x ≥ 0; f2 (x) = 0, x≤0 are both solutions of this initial-value problem! In fact, this problem has infinitely many solutions! The answer to the uniqueness question is clear: the initial-value problem, as stated, need not have a unique solution. In order to ensure uniqueness, some additional requirement must certainly be imposed. We shall see that in the following theorem. Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 29 / 33Ba Basic existence and uniqueness theorem Hypothesis. Consider the differential equation dy = f (x, y) dx (17) where 1. The function f is a continuous function of x and y in some domain D of the xy plane, and 2. The partial derivative ∂f /∂y is also a continuous function of x and y in D; and let (x0 , y0 ) be a point in D. Conclusion. There exists a unique solution φ of the differential equation (17). defined on some interval |x − x0 | ≤ h, where h is sufficiently small, that satisfies the condition φ (x0 ) = y0 (18) Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 30 / 33Ba Explanation of the theorem 1. It is an existence and uniqueness theorem. This means that it is a theorem which tells us that under certain conditions (stated in the hypothesis) something exists and is unique. It gives no hint whatsoever concerning how to find this solution but merely tells us that the problem has a solution. 2. The hypothesis tells us what conditions are required of the quantities involved. It deals with two objects: the differential equation (17) and the point (ẋ0 , y0 ). As far as the differential equation (17) is concerned, the hypothesis requires that both the function f and the function ∂f /∂y must be continuous in some domain D of the xy plane. As far as the point (x0 , y0 ) is concerned, it must be a point in this same domain D, where f and ∂f /∂y are so well behaved (that is, continuous). 3. The conclusion tells us of what we can be assured when the stated hypothesis is satisfied. It tells us that we are assured that there exists one and only one solution φ of the differential equation, which is defined on some interval |x − x0 | ≤ h centered about x0 and which assumes the value y0 when x takes on the value x0 . That is, it tells us that, under the given hypothesis on f (x, y), the initial-value problem dy = f (x, y) dx y (x0 ) = y0 has a unique solution that is valid in some interval about the initial point x0 . Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 31 / 33Ba Example Consider the initial-value problem dy = x2 + y 2 dx y(1) = 3 Let us apply Theorem 1.1. We first check the hypothesis. Here (x,y) = 2y. Both of the functions f and ∂f /∂y are f (x, y) = x2 + y 2 and ∂f ∂y continuous in every domain D of the xy plane. The initial condition y(1) = 3 means that x0 = 1 and y0 = 3, and the point (1, 3) certainly lies in some such domain D. Thus all hypotheses are satisfied and the conclusion holds. That is, there is a unique solution φ of the differential equation dy/dx = x2 + y 2 , defined on some interval |x − 1| ≤ h about x0 = 1, which satisfies that initial condition, that is, which is such that φ(1) = 3 Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 32 / 33Ba End of Lecture 1 Aishabibi Dukenbayeva a.dukenbayeva@sdu.edu.kz Ordinary Differential Equations Lecture 1: Introduction and direction fields. 33 / 33Ba