Uploaded by keshagajadhar2002

AMS Proof

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Mutually
events
exclusive
don'tshare
outcomes
events
I
↓
exclusive
exclusive
happen together notmutually
cannot
mutual
happen together
ly
can
-
-
2
4
-
D
or
happen
cannot
#
mut
=
-
&
3
more
1,2,3,4,5,6
8
A&D
(y,3,4,5,6
-
=
nn
1, 2, 3,4, 5,
?
④
18,3,4,5,6 =
A
-
B
-
1,2,3,45,6
C
D
4,5,6
1,3,5
E
1,2
A B mr+
=
BC
=
no mut
=
+
mut
not
BD
CB
AD:mut
mut
AE=
mut
not
not
AC
=
notmut
=
CD =
2
D
↓
or
*
2
A mut
4
1,2,3,4,5,6
more
at
most
-
not mut
Emut
①
BE
=
not
mut
mut
A
#
&
C
②
mutu
=not
- >
1,2, 3, 4, 5,
oFIF
1,2,3,4,5,6
6x6 possibilities
⑫
⑫
P(2/2
dice
Iwo ways
wll
24
36
=
tossed)
=
%
1=
2
possibilities①
35
same
⑭
=
only
number:
⑤
Or
totel
one
possible
outcome
①
038
B
⑬
4
2
⑬ 4
O
⑰
④P
(A or B) P(A) P(P) p(A
=
@
④
+
0.
=
=
② P(not () P(,)
0.45.0.2
+
=
⑩as
P(noTA)
1
-
B)
and
1
P(A)
1
=
P(A)
⑥ P(A
1- 0.7
⑩3
PCA and
no
-
-
P(B)
0.45
①55
and
no
B) P(A) P(Aand
-
=
0.7
=
-
0.2
⑩5
B)
B)
②
B)
P(ad
1
-
=
P(nd()
10.2
⑪
P(A1k)
⑤
P(A)P(B)
b) P(AVB)
+
0.25
1
-
=
P(B) 1
①
=
=
P(A) P(b)
=
=
② PCF)
0
=
-
② p(AV)
P(A)
1
0.0%
0%.
10.25
⑮5
1
=
-
0.65
85
p(ArB)
-
1
⑦ P(A15)
0.65+
+
=
P(B)
=
(PA1B)
+
P(A)
=
·
0.9 0.10
=
-
-
P(AvB)
0.25
-
0
⑫
⑥
PCEand
F
P(F) XPE/F
=
P(E and F)
⑫
=
x.6
⑦
Total =
52
26:black
ace= black
1/52:
52
-
1st
1
card
ace
club
5/
=
Total 61ck:26
↓
Sec.
is
z5
51
⑩ P(E)
black
-
given
1:25
first:ace club
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