1 Aluminium sulfate, Al2(SO4)3, is used to help relieve the pain caused by bites and stings. Look at the equation. It shows how aluminium sulfate can be made. (i) Show that the relative formula mass, Mr, of aluminium sulfate is 342. The relative atomic mass, Ar, of Al = 27, O = 16 and S = 32. [1] (ii) Look at the table of relative formula masses, Mr. Formula Mr Al(OH)3 78 H2SO4 98 Al2(SO4)3 342 H2O 18 Use the information in the table, and the balanced symbol equation, to show that mass is conserved when aluminium sulfate is made. [1] © OCR 2021. You may photocopy this page. 1 of 22 Created in ExamBuilder 2 Iron and steel are typical metals. Iron and steel are good conductors of heat, have a high density and are hard. Iron and steel are used to make cutting tools called saws. Describe four other physical properties of metals. Explain why iron and steel are suitable to make cutting tools such as saws. The quality of written communication will be assessed in your answer to this question. © OCR 2021. You may photocopy this page. 2 of 22 Created in ExamBuilder [6] 3 Both diamond and graphite have giant molecular structures. Silicon dioxide also has a giant molecular structure. Look at the structure of silicon dioxide. Explain, using ideas about structure and bonding, why silicon dioxide has a high melting point. [2] © OCR 2021. You may photocopy this page. 3 of 22 Created in ExamBuilder 4 Hydrogen peroxide solution breaks down to make water and oxygen. hydrogen peroxide → water + oxygen The molecular formula for hydrogen peroxide is H2O2. Calculate the relative formula mass, Mr, of hydrogen peroxide. The relative atomic mass of H = 1 and of O = 16 relative formula mass = 5 [1] Look at the diagram. It shows how the reaction between hydrochloric acid and marble chips (calcium carbonate) can be monitored. © OCR 2021. You may photocopy this page. 4 of 22 Created in ExamBuilder The reading on the balance decreases during the reaction. Which of these statements is the best explanation? A Acid escapes from the flask. B A gas called hydrogen is made which leaves the flask. C A gas called carbon dioxide is made which leaves the flask. D The temperature in the laboratory changes. Your answer © OCR 2021. You may photocopy this page. [1] 5 of 22 Created in ExamBuilder 6 Look at the diagram. It shows a structure of carbon. Which structure of carbon is shown in the diagram? A diamond B fullerene C graphene D graphite Your answer © OCR 2021. You may photocopy this page. [1] 6 of 22 Created in ExamBuilder 7 Hex-1-ene is a carbon-based compound with the formula C6H12. 20.0 g of hex-1-ene is burned in oxygen. Carbon dioxide and water are made. Look at the equation for this reaction. C6H12 + 9O2 → 6CO2 + 6H2O (i) Calculate the number of molecules in 20.0 g of hex-1-ene. Avogadro’s constant = 6.02 × 1023 mol–1 Give your answer to 3 significant figures. Number of molecules of C6H12 = .............................. [4] (ii) Hex-1-ene was burned using a spirit burner in the laboratory. The diagram shows the spirit burner. Burning 20.0 g of hex-1-ene should produce 62.9 g of carbon dioxide. The actual mass of carbon dioxide produced in the reaction was 48.4 g. © OCR 2021. You may photocopy this page. 7 of 22 Created in ExamBuilder [1] 10 Which statement about phosphorus is correct? Use the Periodic Table to help you answer this question. A A phosphorus atom has 15 protons and 16 electrons. B The phosphorus-31 isotope has 16 neutrons. C Phosphorus is a metal. D The symbol for phosphorus is Po. Your answer 11 [1] Fluorine is the most reactive element in Group 7 (Group 17). Why? A Fluorine atoms gain an electron more readily than the other Group 7 elements. B Fluorine is a gas. C Fluorine exists as diatomic molecules. D Fluorine atoms lose electrons more readily than the other Group 7 elements. Your answer © OCR 2021. You may photocopy this page. [1] 9 of 22 Created in ExamBuilder 12 Sodium, Na, reacts with oxygen, O2, to make sodium oxide. Sodium oxide contains the ions, Na+ and O2?. The electronic structure for sodium is 2.8.1. The electronic structure for oxygen is 2.6. Use ‘dot and cross’ models to describe the bonding in both sodium oxide and in a molecule of oxygen, O2. You only need to draw the outer shell electrons. The quality of written communication will be assessed in your answer to this question. [6] © OCR 2021. You may photocopy this page. 10 of 22 Created in ExamBuilder 13 Which statement best describes an atom? A The nucleus is small compared to the atom and contains little of the atom’s mass. B The nucleus is large compared to the atom and contains little of the atom’s mass. C The nucleus is small compared to the atom and contains most of the atom’s mass. D The nucleus is large compared to the atom and contains most of the atom’s mass. Your answer [1] 14 This question is about atomic structure. (i) What is meant by relative atomic mass? [1] (ii) What two things can you work out from the atomic number of an element? 1 2 [2] © OCR 2021. You may photocopy this page. 11 of 22 Created in ExamBuilder 15 The mass number of an element is 23. The atomic number of the same element is 11. (i) How many protons and how many neutrons are there in an atom of this element? Number of protons: _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ Number of neutrons: _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ [2] (ii) This element forms an ion with a charge of +1. Work out the number of electrons in an ion of this element. Number of electrons: _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ [1] END OF QUESTION PAPER © OCR 2021. You may photocopy this page. 12 of 22 Created in ExamBuilder Mark Scheme Question 1 i Answer/Indicative content Marks [2 × 27] + [3 × 32 ] + [12 × 16] (= 342) (1) 1 Guidance answer is for the working out not the answer allow correct working out e.g. 54 + 96 +192 (= 342) allow [2 × 27] + [3 × 96] (= 342) allow 54 + 288 (= 342) allow 272 (32 + 164)3 Examiner's Comments Candidates that set out the calculations carefully were able to show that the relative formula mass of aluminium sulphate is 342. ii any one from: 1 [2 × 78] + [3 × 98] = 342 + [6 × 18] (1) allow correct numbers to show that mass of the reactants equals mass of the products 156 + 294 = 342 + 108 (1) Examiner's Comments 450 = 450 (1) Candidates were able to use the information in the table and the balanced equation to show that mass is conserved. Candidate's answers were well structured and clearly showed the steps involved in the calculation. Total © OCR 2021. You may photocopy this page. 2 13 of 22 Created in ExamBuilder Mark Scheme Question 2 Answer/Indicative content Marks Level 3 Describes four physical properties of metals AND explains why iron or steel can be used to make saws Quality of written communication does not impede communication of the science at this level. Guidance This question is targeted at grades up to C. Indicative scientific points may include: Physical properties of metals good conductor of electricity high boiling point high melting point (ignore heat resistant) high tensile strength / strong malleable (ignore bendy / flexible) lustrous / shiny ductile / can be drawn into wires sonorous (5–6 marks) Level 2 Describes four physical properties of metals OR describes two physical properties of metals and attempts to explain why iron and steel are used to make saws Quality of written communication partly impedes communication of the science at this level. ignore good conductor of heat / high density / hard (stem of question) ignore easy to shape or bend / durable / magnetic as properties (3–4 marks) Level 1 Describes two physical properties of metals OR attempts to explain why iron and steel are used to make saws Quality of written communication impedes communication of the science at this level. Explanation linked to use of iron or steel as a saw iron or steel is hard iron or steel can be sharpened iron is strong (so the saw won't break) ignore iron or steel is flexible (1–2 marks) Level 0 Insufficient or irrelevant science. Answer not worthy of credit. Use the L1, L2, L3 annotations in RM Assessor; do not use ticks. (0 marks) Total © OCR 2021. You may photocopy this page. 6 14 of 22 Created in ExamBuilder Mark Scheme Question 3 Answer/Indicative content Marks strong covalent bonds (1) 2 Guidance strong bonds not sufficient covalent on its own not sufficient allow covalent bonds are strong not giant ionic or giant metallic not intermolecular forces allow lots of heat needed to break the bonds ignore harder to break bonds ignore more heat needed to break bonds ignore high temperature not lots of energy needed to break ionic or metallic bonds lots of energy needed to break the bonds (1) Examiner's Comments This answer required candidates to write about strong covalent bonds and lots of energy needed to break these strong covalent bonds. Many candidates wrote about bonds but were not specific about them being strong covalent bonds. They also wrote about needing more energy to break them but not about the need for lots of energy. 4 5 6 Total 2 34 (1) 1 Total 1 C 1 Total 1 D 1 Total 1 © OCR 2021. You may photocopy this page. 15 of 22 ignore any units given Created in ExamBuilder Mark Scheme Question 7 i Answer/Indicative content FIRST CHECK THE ANSWER ON ANSWER LINE If answer = 1.44 × 1023 award 4 marks Atomic weight = (6×12) + (1×12) = 84g ✓ Marks Guidance 4 ALLOW correct answer to 3 sig figs from moles of hex-1-ene (0.24 / 0.238 / 0.2381) [0.238 gives 1.43 × 1023; 0.2381 gives 1.43 × 1023) (AO3 × 2.2) Moles of hex-1-exe = 20 ÷ 84 = 0.24 / 0.238 / 0.2381 ✓ ALLOW ECF from incorrect atomic weight Number of molecules = 0.24 × (6.02×1023) = 1.4448 × 1023 ✓ ALLOW ECF from incorrect number of moles = 1.44 × 1023 (3sf) ✓ (AO1.2) ECF if processing of data has given an incorrect value but expressed as 3SF Examiner’s Comments The calculation of atomic weight of Hex-1-ene was the section of the calculation where candidates gained the most credit. Fewer candidates could correctly calculate the number of moles of Hex-1-ene. The most common misconception here was the numbers being placed in the wrong place in the calculation. Even fewer candidates could then multiply by Avogadro’s Constant to give the number of molecules. Standard form could only be handled correctly by the higher ability candidates. A significant number of candidates gained in mark by the conversion of a calculated value to three significant figures. Exemplar 7 © OCR 2021. You may photocopy this page. 16 of 22 Created in ExamBuilder Mark Scheme Question Answer/Indicative content Marks Guidance This exemplar shows the expected steps of the calculation and was given 4 marks as it has the final answer to the correct number of significant figures. Exemplar 8 This exemplar shows all but the step where there should be a multiplication of Avogadro’s Constant. This was given 3 marks for just one error in missing a stage of the calculation. ii Not enough oxygen / oxygen was a limiting reactant ✓ 1 (AO3.2b) ALLOW idea that incomplete combustion occurred Examiner’s Comments A large number of candidates discussed the amount of oxygen present and tried to calculate its numerical value rather than simply stating that the mass of oxygen would be less or limited. Total © OCR 2021. You may photocopy this page. 5 17 of 22 Created in ExamBuilder Mark Scheme Question 8 Answer/Indicative content A✓ Marks 1 (AO2.1) Guidance ALLOW 9 Examiner’s Comments Most candidates correctly selected A, but a few thought that the relative atomic mass indicated the number of protons so chose C. 9 Total 1 C✓ 1 (AO 2.2) Examiner’s Comments Only higher ability candidates correctly identified 2.0 grams as the correct response. Those who did gain credit here often used the space at the side of the question for calculations. 10 Total 1 B✓ 1 (AO 2.1) Examiner’s Comments Approximately half of the candidates could use the periodic table as directed in the question to identify the isotope of phosphorous 31 as having 16 neutrons. The most commonly seen incorrect response was the imbalance of protons and electrons for an isotope, showing a misconception in the understanding of atomic mass and atomic number. 11 Total 1 A✓ 1 (AO 1.1) Total 1 © OCR 2021. You may photocopy this page. 18 of 22 Examiner’s Comments Most candidates answered this correctly. Created in ExamBuilder Mark Scheme Question 12 Answer/Indicative content Marks [Level 3] Use the dot and cross model to explain the covalent bonding in an oxygen molecule AND draw the electronic structures of the sodium ion and the oxide ion Quality of written communication does not impede communication of the science at this level 6 (5 – 6 marks) [Level 2] Use the dot and cross model to explain the covalent bonding in an oxygen molecule OR Uses the dot and cross model to draw the electronic structures of the sodium ion and the oxide ion Quality of written communication partly impedes communication of the science at this level (3 – 4 marks) [Level 1] States or shows that O2 is bonded covalently OR Na2O by ionic bonding Quality of written communication impedes communication of the science at this level (1 – 2 marks) [Level 0] Insufficient or irrelevant science. Answer not worthy of credit. Guidance This question is targeted at grades up to A*. Indicative scientific points at all levels 2 and 3 could include: Dot and cross diagram for oxygen Electronic structure of sodium ion (no need to have charge but if shown must be correct) Electronic structure of oxide ion (no need to have charge but if shown must be correct) Idea that positive sodium ion attracts a negative oxide ion allow Na+ or an empty shell for electronic structure of sodium ion ignore inner shells if drawn Indicative scientific points at level 1 could include: O2 has covalent bonding O2 has shared pairs of electrons Na2O has ionic bonding Na2O bonding involves electron transfer Na loses electron and O gains electrons Use the L1, L2, L3 annotations in scoris. Do not use ticks. See next page for dot and cross diagrams. (0 marks) © OCR 2021. You may photocopy this page. 19 of 22 Created in ExamBuilder Mark Scheme Question Answer/Indicative content Marks Guidance At level 2 and 3, if dot and cross diagram shows the same electron on the sodium ion and the oxide ion then answer is limited to lower mark within level Credit word descriptions however for level 2 or 3 correct electron structures must be described eg Na+ 2.8 O2? 2.8 Examiner's Comments In many answers ideas about covalent and ionic bonding were mixed up. Some candidates did not realise that two models were required, and instead attempted to integrate the two. The few candidates that attempted the structure of O2 scored well. 13 Total 6 C✓ 1 (AO1.1) Total © OCR 2021. You may photocopy this page. Examiner’s Comments Almost half of candidates correctly selected C. A common misconception is that the nucleus is large compared to the size of the atom with B and D being common choices. 1 20 of 22 Created in ExamBuilder Mark Scheme Question 14 i ii Answer/Indicative content Marks Guidance The mean mass of an atom compared to 1/12th of the mass of an atom of Carbon-12 ✓ 1 (AO1.1) ALLOW The mean or average mass of an atom compared to Carbon-12 (Number of) protons ✓ (Number of) electrons ✓ 2 (AO2 × 1.1) Examiner’s Comments Most candidates confused this with mass number and referred to the number of protons and neutrons. Almost no candidates managed to explain correctly or even mentioned carbon 12. Many thought it was the mass of one atom. ALLOW position in the Periodic Table because you can identify the element ALLOW number of electrons in the outer shell ALLOW number of (electron) shells / period number Examiner’s Comments This question differentiated well with higher ability candidates scoring 2 marks for number of protons and number of electrons. Most candidates scored at least one mark for stating the number of protons. However, many candidates confused atomic number and mass number and referred to the number of neutrons. A few candidates put more than 2 answers which resulted in a loss of credit e.g. 1. Number of protons and neutrons (no mark) 2. Number of electrons (1 mark). Some just wrote ‘protons’ rather than ‘number of protons’, but were credited with the mark. Some candidates interpreted the question differently and stated things they could deduce e.g. the number of electrons in the outer shell, number of electron shells, period number. They did gain credit for this, although it was not what the question had intended. Total © OCR 2021. You may photocopy this page. 3 21 of 22 Created in ExamBuilder Mark Scheme Question 15 Answer/Indicative content i Protons = 11 (1) Neutrons = 12 (1) 2 ii 10 1 Total 3 © OCR 2021. You may photocopy this page. Powered by TCPDF (www.tcpdf.org) Marks 22 of 22 Guidance ECF number of electrons/protons minus 1 (1 ) Created in ExamBuilder