MAKERS’ EDUCATION
RECENT MATH QUESTION BANK
59th Intake of MBA
Institute of Business Administration, University of Dhaka
November-December 2017
26. If selling price is doubled, profit triples. Find the profit in percentage.
A) 50
B) 100
C) 150
D) 200
E) None of these.
27. A is three years older than B who is twice as old as C. If the total of the ages of A, B and C is
38, how old is B.
A) 10
B) 12
C) 14
D) 15
E) None of these.
28. The cost price of two articles, P and Q are in the ratio 5:7 and their selling prices, in the
ratio2:5 respectively. If the losses of both the products are the same, what is the ratio between
the cost price and the selling price of Q?
A) 5:4
B) 7:3
C) 8:3
D) 15:4
E) None of these.
29. In a race, the speeds of A and B are in the ratio 3:4, A takes 30 minutes more than B takes to
reach the destination. What is the time taken by A to reach the destination in hours?
A) 1.
B) 1.5
C) 2
D) 3
E) None of these.
30. Two train starting at the same time from 2 stations 200 km apart and going towards each
other at a distance of 110 km from one of the stations. What is the ratio of their speeds?
A) 11:9
B) 13:11
C) 3:2
D) 7:5
E) None of these.
31. The average of ten numbers is x and the average of five of the members is y. if the average
of the remaining five is z, then
A) x = y + z
B) z = x + 2y C) x = 2y + 2x D) 2x = y + z E) None of these.
32. A is twice as good a workman as B and is therefore able to finish a job in 18 days less than B.
In how many days they can finish the job working together?
A) 8
B) 12
C) 15
D) 18
E) None of these.
33. In a club, 20% of members are below 25 years of age. The number of members above 15
years of age is 16, which is two- third of number of members of 25 years of age. What is the total
number of members in the club?
A) 50
B) 52
C) 60
D) 72
E) None of these.
34. Given that EF=5cm and AB=12cm, what is the area of the parallelogram in sq.cm?
A) 30
B) 45
C) 60
D) 72
E) None of these.
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35. Two numbers individually are less than the third number by 60% and 74% respectively. By
what percentage is the second number less than the first?
A) 18
B) 27
C) 30
D) 35
E) None of these.
36. In a class, 200 chocolates were distributed equally among the students in such a way that the
number of chocolates received by each student is 12.5% of the total number of the students. How
many chocolates did each student receive?
A) 4
B) 5
C) 8
D) 10
E) None of these.
37. If 30% of (x – y) = 20% of (x + y), then what is the ratio of x to y?
A) 5:1
B) 3:1
C) 4:1
D) 5:2
E) None of these.
38. If x is a product of 4 consecutive integers, and x is divisible by 11, which of the following is
not necessarily a divisor of x?
A) 12
B) 22
C) 24
D) 33
E) None of these.
39. In a group, 30% of the men are more than 25 years old and 80% of the men are less than or
equal to 50 years old. Twenty percentage of all men play football. If 20% of the men above the
age of 50 play football, what percentage of the football players are less than or equal to 50 years?
A) 50%
B) 60%
C) 75%
D) 80%
E) None of these.
40. In an exam, A scoring 40% marks fails by 10 marks, B scoring 50% marks gets 10% more
than the passing marks. What was the total mark in the exam?
A) 88
B) 100
C) 160 D) 200
E) None of these.
41. The weight of a box is estimated by three persons. According to A, the weight lies between 50
and 60 kgs. According to B, the weight is more than 45 kgs but less than 58 kgs. C estimates that
the weight cannot be greater than 56 kgs. If all of them are correct in their estimation, what is
the average of different probable weights of the box?
A) 52
B) 53
C) 54
D) 55
E) None of these.
42. The average age of 8 students is 20. The average age of first two students is 19 and that of the
next three students is 21. If the age of the sixth student is less than that of the seventh and eighth
student by 2 and 3 respectively, then find the age of the eighth student.
A) 18
B) 21
C) 24
D) 27
E) None of these.
43. Arif went to a restaurant along with his 5 friends. He paid Tk. 100 and all the other paid an
equal amount. The average bill per person was Tk. 10 more than what was paid by each of his
friends. How much money did each of his friends pays?
A) 30
B) 32
C) 36
D) 40
E) None of these.
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44. A train when moves at an average speed of 75 km/hr. reaches its destination on time. When
its average speed becomes 50 km/hr. it takes 1 more hour to reach its destination. Find the length
of journey the journey in km.
A) 150
B) 180
C) 200
D) 240
E) None of these.
45. In a box, 40% of the pens are red. If half of the red pens are removes, the percentage of red
pens in the box will be:
A) 20%
B) 22.5%
C) 25%
D) 30%
E) None of these
46. In the figure <ABC = 24°, and <FCE = < BCD. Find <ECF.
A) 33°
B) 35°
C) 44°
D) 52°
E) None of these
47. In a group of civil, mechanical and electrical engineers, all but 20 are civil engineers, all but
15 are mechanical engineers, and all but 25 are electrical engineers. How many of them are
electrical engineers?
A) 5
B) 10
C) 15
D) 20
E)None of these.
48. If -1<x<1 and x≠0, which of the following must be true?
I. 𝑥3<𝑥2
II. 𝑥5<1 – x
III. 𝑥4<𝑥2
A) I only
B) I and II only
C) II and III only D) I and III only
E) I, II and III
49. Babu made a profit of 20% by selling a product. If he had purchased that product for 10%
less and sold it at a profit of 40%, he would have received Tk. 24 more. What was his original
selling price in taka?
A) 400
B) 480
C) 520
D) 600
E)None of these.
SO L U T I O N
26. Solution: (B)
Let original selling price = 100 and original profit = p
Then the selling being doubled, the selling price would be = 200
And the profit would be = 3x
So 3x – x = 200- 100
Or, x = 50
Hence original cost price = original selling price – profit
Then
= 100 – 50
= 50
50
So profit % = 50 × 100 = 100%
27. Solution: (C)
Let the age of C = P years
Then the age of B = 2P
Then the age of A = 2P+3
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Now P+2P+2P+3 = 38
Or, 5P = 38-3
Or, P =
35
=7
5
So the age of B = 2×7 = 14 years.
28. Solution: (E)
We know that cost price – selling price = loss
Let the cost price of P and Q = 5x and 7x respectively
And the selling price of P and Q = 2y and 5y respectively
According to the question we can write,
5x – 2y = 7x – 5y
Or, 7x – 5x = 5y – 2y
Or, 2x = 3y
𝑥
𝑦
=
3
2
So we got x= 3 and y = 2
Now putting the value of x and y
So cost price of Q = 7x = 7× 3 = 21
And the selling price of Q = 5y = 5× 2 = 10
∴ Required ratio = 21:10
29. Solution: (C)
Let the speed of A and B = 3x and 4x respectively
So time taken by A and B = 4x and 3x respectively
Now according to the question,
4x – 3x = 30
∴ x = 30
So 4x = 4× 30 = 120 minutes or
120
60
= 2 hours
30. Solution: (A)
Hence the distance between two station = 200km
So one train covered = 110km
So another train will cover = 200-110 = 90km
Hence the required ratio = 110:90 = 11:9
31. Solution :(D)
According to the question,
Average =
Or,
Or,
=
(𝑦+𝑧)
2
5𝑦+5𝑧
10
5(𝑦+𝑧)
10
=x
=x
=x
∴ 2x = y+z
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32. Solution: (B)
Let B’s efficiency = p
And A’s efficiency = 2p
So 2p – p = 18 days
∴ p = 18
And 2p = 36
Now LCM of 18 and 36 = 36
The efficiency of A =
And efficiency o B =
36
18
36
36
= 2 units
= 1 unit
So their one day’s job = 2+1= 3 units
∴ Time required to complete 36 units job =
36
3
= 12 days.
33. Solution :(A)
20% of the members = below 25 years
So above 15 years and exactly 25 years = 100-20 = 80%
Now let exactly age of 25 years = x
So above 15 years =
2𝑥
3
= 16
Or, x = 24
So above 15 years and exactly 25 years = 16+24 = 40
So we can say 80% of the members = 40
∴ 100% of the members =
40×100
80
= 50
34. Solution: C
35. Solution: (D)
Let the 3rd number = 100
So 2nd number = 100 – 74%of 100 = 26
And 1st number = 100- 60% of 100 = 40
So 2nd number less than the 1st number = 40 – 26 = 14
∴ the percentage less than 2 nd number by 1st number =
14×100
40
= 35%
36. Solution :(B)
Let total students = P
So each student got = 12.5% of P or,
25p
According to the question, 200 =
12.5
100
25𝑝
× 𝑃 or 200
200
P
Or 25P 2 = 40000
or, p2 =
40000
25
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or, p2 = 1600
or, p = √1600
∴ P = 40
So we got the number of students = 40
∴ The chocolate got by each student =
25𝑝
200
=
25×40
200
=5
37. Solution: (A)
30(𝑥−𝑦)
100
=
20(𝑥+𝑦)
100
Or, 30 (x-y) = 20 (x+y)
Or, 30x – 30y = 20x+20y
Or, 10x = 50y
Or,
𝑥
𝑦
=
50
10
∴ x: y = 50:10 = 5:1
38. Solution: (E)
The number divisible by 11 that is also divisible by 22 and 33 so we can eliminate option (B) and (D)
We know that the product of 4 consecutive number must be divisible by = 1× 2 × 3 × 4 = 24
So we can also eliminate option (A) and (C) So the answer is (E)
39. Solution: (D)
It’s so easy!
Let total = 100
So play football = 20% of 100 = 20
Above the age of 50 = 20% of 20 = 4
The football players are less than or equal to 50 years = 20-4 = 16
∴ The percentage of the football players are less than or equal to 50 years =
16×100
20
= 80%
Shortcut: Among the 100% football players, 20% above 50 years so 100%-20% = 80% are less than
or equal to 50 years. (Simple)
40. Solution: (D) or (E)
GB g¨v_wU†Z GKUz Rv‡gjv Av‡Q!! hw` GLv‡b 10% more than bv e‡j more than 10 ej‡Zv Zvn‡j mgvavb n‡Zv wbgœiƒct
Let total marks = P
According to the question,
50% of P – 10 = 40% of P +10
Or, 50% of P – 40% of P = 20
Or, 10% of P = 20
So 100% of P =
20×100
10
= 200
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wKš‘ hw` cÖkœ wVK _v‡K Zvn‡j mgxKiYwU n‡e wbgœiƒct
50% of P – 10% of P = 40% of P + 10
Or 40% of P – 40% of P = 10
0 = 10 e¨vcviUv †Kgb nj?! Avm‡j GB ai‡bi g¨v_ w`‡j cÖvß b¤^‡ii cv_©K¨Uv Av‡iK Uz †ewk n‡q _v‡K|
†bvUt GLb eyS‡Z cvi‡jb †Zv? hw` cÖkœ wVK _v‡K Zvn‡j DËi n‡e (E) None of these.
Abyiƒc Av‡iKwU g¨v_ †`Lyb--Proof math: In an exam, A student who gets 20% marks fails by 10 marks but another student who
gets 42% marks gets 12% more than the passing marks. What was the total mark in the exam?
a.50
b.100
c.150
d.200
e.none of these
40. Solution: (b)
Let total mark = P
According to the question,
42% of P – 12% of P = 20% of P + 10
or, 30% of p = 20% of p + 10
or, 30% of p – 20% of p = 10
or, 10% of p = 10
or, 100% of p =
10×100
10
= 100
∴ Total mark in the exam = 100
†bvUt GLb eyS‡Z cvi‡jb†Zv? hw` cÖkœ wVK _v‡K Zvn‡j DËi n‡e (E) None of these.
41. Solution: ( E)
Let the weight of box = Pkg
Now according to the condition A = 50<p<60
According to the condition B = 45<p<58
According to the condition C = p≤56
Now for abiding the condition of all A B and C we can write
51 , 52 ,53 ,54 ,55 ,56
∴ Required average =
51+52+53+54+55+56
6
= 53.5kg
42. Solution: (B)
The average age of 8 students = 20 years
So the sum of the age of 8 students = 20× 8 =160
Average age of first two students is = 19
So the sum of first two students is = 19× 2 = 38
A sum of next three students is = 21× 3 = 63
So the sum of remaining three students = 160 – (38+63)
= 59
Let the age of sixth student = p
Seventh student = p+2
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And eighth student = p+3
So p+p+2+p+3 = 59
Or, 3p+ 5 = 59
Or, 3p = 54
Or, p =
54
3
= 18 years
So the age of eighth student = p+3 = 18+3 = 21 years.
43. Solution: (D)
Let the average bill = P
Now
100+5𝑝
6
= (p+10)
or, 6(p+10) = 100+5p
or, 6p+60 = 100+5p
or, 6p-5p = 100-60
∴p = 40
44. Solution: (A)
Let the distance be = p
𝑝
𝑝
Now - = 1
or,
50 75
3𝑝−2𝑝
150
=1
or, 3p – 2p = 150
∴ p = 150 km.
45. Solution: (C)
Let total pen = 100
So red pen = 40 of 100 = 40
If half of the reds are remove, the remaining red will be = 40 – 20 = 20
Now total pen = 100- 20 = 80
20
And the percentage of red pen now = 80 × 100 = 25%
46. Solution: A
47. Solution: (A)
According to the question,
M+E = 20------------------(1)
C+E = 15------------------(2)
M+C = 25-----------------(3)
Now by adding all equation, we got 2(M+C+E) = 20+15+25
or, 2(m+c+e) = 60
or, m+c+e
= 30
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So electrical engineers (E) = (M+C+E) – (M+C) = 30 – 25 = 5
Note: M= Mechanical engineer, C= Civil engineer, and E = Electrical engineer.
48. Solution: (E)
Hence, the value of x can be negative or positive fraction. For this reason, the value of x going to be
decreased when the value of power will be increased. So we can say that the condition III. 𝑥4<𝑥2 is
correct. At the same way the condition (I) and (II) also correct so the correct answer (E)
49. Solution: (A)
Let 1st cost price = 100
The 1st selling price = 120
2nd selling price = 100 – 10% of 100 = 90
2nd selling price = 90+40% of 90 = 126
Now difference of two selling price = 126-120 = 6
So we can say that 6% of cost price = 24
∴ 100% of cost price =
24×100
6
= Tk.400
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