MATH IV FORMULAS STRAIGHT LINE Distance between 2 points Coordinates of a point inside a segment (midpoint r=1) π = √(π¦2 − π¦1 )2 + (π₯ 2 − π₯ 1 )2 π₯= π₯ 1 + ππ₯ 2 1+π Slope-intercept Point-slope Symmetric π¦ = ππ₯ + π π¦ − π¦1 = π(π₯ − π₯ 1 ) π₯ π¦ + =1 π π Slope Angle with the horizontal Angle between 2 lines π= π¦2 − π¦1 π₯2 − π₯1 π¦= General π΄π₯ + π΅π¦ + πΆ = 0 Distance from a line to a point π2 − π1 π‘πππ = | | 1 + π1 ∗ π2 π = tan−1 π π¦1 + ππ¦2 1 +π π= |π΄π₯ 1 + π΅π¦1 + πΆ | √π΄2 + π΅ 2 Area of an obtuse or acute triangle π΄ = | π1 π2 + π2 π1 + π2 π1 − π1 π2 − π2 π1 − π1 π2 |/2 Convert from polar to rectangular coordinates π₯ = ππππ π Convert from rectangular to polar coordinates π = tan−1 ( π¦⁄π₯ ) π = √π₯ 2 + π¦ 2 π¦ = ππ πππ CIRCUMFERENCE π₯ 2 + π¦ 2 = π2 π΄π₯ 2 + πΆπ¦ 2 + π·π₯ + πΈπ¦ + πΉ = 0 (π₯ − β)2 + (π¦ − π)2 = π2 ELLIPSE π΄π₯ 2 + πΆπ¦ 2 + π·π₯ + πΈπ¦ + πΉ = 0 π₯ 2 π¦2 + =1 π2 π 2 π₯ 2 π¦2 + =1 π 2 π2 π2 = π 2 + π 2 πΏπ = (π₯ − β)2 (π¦ − π)2 + =1 π2 π2 2π2 π π= π π (π₯ − β)2 (π¦ − π)2 + =1 π2 π2 PARABOLA π΄π₯ 2 + π·π₯ + πΈπ¦ + πΉ = 0 π₯ 2 = ±4ππ¦ πΆπ¦ 2 + π·π₯ + πΈπ¦ + πΉ = 0 π¦ 2 = ±4ππ₯ πΏπ = 4π (π₯ − β)2 = ±4π(π¦ − π) (π¦ − π)2 = ±4π(π₯ − β) HYPERBOLA 2π2 πΏπ = π π 2 = π2 + π 2 π= π΄π₯ 2 − πΆπ¦ 2 + π·π₯ + πΈπ¦ + πΉ = 0 π₯ 2 π¦2 − =1 π2 π 2 π¦2 π₯ 2 − =1 π2 π 2 Translation of the axis π₯′ = π₯ − β π¦′ = π¦ − π π π πΆπ¦ 2 − π΄π₯ 2 + π·π₯ + πΈπ¦ + πΉ = 0 ( π₯ − β) 2 π2 (π¦ − π)2 − =1 π2 (π¦ − π)2 (π₯ − β)2 − =1 π2 π2 Rotation of the axis π₯ = π₯ ′ πππ π − π¦′π πππ π¦ = π₯ ′ π πππ + π¦′πππ π π‘ππ 2θ = π΅ π΄−πΆ