Q6. F(A,B,C,D) = ∑( m0, m1, m2, m4, m5, m6, m8, m9, m12, m13, m14 )
CD\AB | 00 | 01 | 11 | 10
----------------------------00
| X
| X
| X
|
----------------------------01
| X
| X
| X
|
----------------------------11
| X
| X
| X
|
----------------------------10
| X
| X
| X
|
1. Group 1: F(A, B, C, D) = A'B'CD' + A'BC'D + AB'CD
Group 2: F(A, B, C, D) = BCD' + AB'CD
2. Now, combine the two groups into a single simplified expression:
F(A, B, C, D) = A'B'CD' + A'BC'D + AB'CD + BCD' + AB'CD
3. Finally, eliminate any redundant terms:
F(A, B, C, D) = A'B'CD' + A'BC'D + AB'CD + BCD'
So, the simplified Boolean expression for F(A, B, C, D) is:
F(A, B, C, D) = A'B'CD' + A'BC'D + AB'CD + BCD'
Q7.