Assignment 3.0 “Unit IV: Laboratory Test in Reinforced Steel Bar” Direction: Answer the following question correctly in the space provided. 1. Using the Unit Weight of Steel which is equals to 7850 kg per m³, determine the constant K (weight per linear meter) of 10mm, 12mm, 16mm, 20mm, 25mm, 32mm and 36mm bar diameter with respect to its diameter-cross-sectional area. Present your solution in the space provided. SOLUTION: WHEN ⌀ = 𝟏𝟎 𝐦𝐦 WHEN ⌀ = 𝟏𝟐 𝐦𝐦 𝛾 = 7850 𝑘𝑔/𝑚3 𝛾 = 7850 𝑘𝑔/𝑚3 ⌀ = 10mm – 0.010m ⌀ = 12mm – 0.012m 𝐾 𝑠𝐿 𝐾 𝛾=𝐴 𝛾=𝐴 𝑠𝐿 𝐾 7850 𝑘𝑔/𝑚3 = 𝜋(0.012𝑚)2 𝐾 7850 𝑘𝑔/𝑚3 = 𝜋(0.010𝑚)2 4 (1𝑚) K= 0.617 kg. per linear meter 4 K= 0.888 kg. per linear meter WHEN ⌀ = 𝟏𝟔 𝐦𝐦 WHEN ⌀ = 𝟐𝟎 𝐦𝐦 𝛾 = 7850 𝑘𝑔/𝑚3 𝛾 = 7850 𝑘𝑔/𝑚3 ⌀ = 16mm – 0.016m ⌀ = 20mm – 0.020m 𝛾= 𝐾 𝐴𝑠 𝐿 (1𝑚) 𝐾 𝑠𝐿 𝛾=𝐴 𝐾 7850 𝑘𝑔/𝑚3 = 𝜋(0.016𝑚)2 4 𝐾 (1𝑚) K= 1.578 kg. per linear meter 7850 𝑘𝑔/𝑚3 = 𝜋(0.020𝑚)2 4 (1𝑚) K= 2.466 kg. per linear meter WHEN ⌀ = 𝟐𝟓 𝐦𝐦 WHEN ⌀ = 𝟑𝟐 𝐦𝐦 𝛾 = 7850 𝑘𝑔/𝑚3 𝛾 = 7850 𝑘𝑔/𝑚3 ⌀ = 25mm – 0.025m ⌀ = 32mm – 0.032m 𝐾 𝑠𝐿 𝐾 𝑠𝐿 𝛾=𝐴 𝛾=𝐴 𝐾 𝐾 7850 𝑘𝑔/𝑚3 = 𝜋(0.025𝑚)2 4 7850 𝑘𝑔/𝑚3 = 𝜋(0.032𝑚)2 (1𝑚) 4 K= 3.853 kg. per linear meter (1𝑚) K= 6.313 kg. per linear meter WHEN ⌀ = 𝟑𝟔 𝐦𝐦 𝛾 = 7850 𝑘𝑔/𝑚3 ⌀ = 36mm – 0.036m 𝐾 𝑠𝐿 𝛾=𝐴 𝐾 7850 𝑘𝑔/𝑚3 = 𝜋(0.036𝑚)2 4 (1𝑚) K= 7.990 kg. per linear meter