Assignment 3.0
“Unit IV: Laboratory Test in Reinforced Steel Bar”
Direction: Answer the following question correctly in the space provided.
1. Using the Unit Weight of Steel which is equals to 7850 kg per m³, determine the
constant K (weight per linear meter) of 10mm, 12mm, 16mm, 20mm, 25mm, 32mm
and 36mm bar diameter with respect to its diameter-cross-sectional area. Present
your solution in the space provided.
SOLUTION:
WHEN ⌀ = 𝟏𝟎 𝐦𝐦
WHEN ⌀ = 𝟏𝟐 𝐦𝐦
𝛾 = 7850 𝑘𝑔/𝑚3
𝛾 = 7850 𝑘𝑔/𝑚3
⌀ = 10mm – 0.010m
⌀ = 12mm – 0.012m
𝐾
𝑠𝐿
𝐾
𝛾=𝐴
𝛾=𝐴
𝑠𝐿
𝐾
7850 𝑘𝑔/𝑚3 = 𝜋(0.012𝑚)2
𝐾
7850 𝑘𝑔/𝑚3 = 𝜋(0.010𝑚)2
4
(1𝑚)
K= 0.617 kg. per linear meter
4
K= 0.888 kg. per linear meter
WHEN ⌀ = 𝟏𝟔 𝐦𝐦
WHEN ⌀ = 𝟐𝟎 𝐦𝐦
𝛾 = 7850 𝑘𝑔/𝑚3
𝛾 = 7850 𝑘𝑔/𝑚3
⌀ = 16mm – 0.016m
⌀ = 20mm – 0.020m
𝛾=
𝐾
𝐴𝑠 𝐿
(1𝑚)
𝐾
𝑠𝐿
𝛾=𝐴
𝐾
7850 𝑘𝑔/𝑚3 = 𝜋(0.016𝑚)2
4
𝐾
(1𝑚)
K= 1.578 kg. per linear meter
7850 𝑘𝑔/𝑚3 = 𝜋(0.020𝑚)2
4
(1𝑚)
K= 2.466 kg. per linear meter
WHEN ⌀ = 𝟐𝟓 𝐦𝐦
WHEN ⌀ = 𝟑𝟐 𝐦𝐦
𝛾 = 7850 𝑘𝑔/𝑚3
𝛾 = 7850 𝑘𝑔/𝑚3
⌀ = 25mm – 0.025m
⌀ = 32mm – 0.032m
𝐾
𝑠𝐿
𝐾
𝑠𝐿
𝛾=𝐴
𝛾=𝐴
𝐾
𝐾
7850 𝑘𝑔/𝑚3 = 𝜋(0.025𝑚)2
4
7850 𝑘𝑔/𝑚3 = 𝜋(0.032𝑚)2
(1𝑚)
4
K= 3.853 kg. per linear meter
(1𝑚)
K= 6.313 kg. per linear meter
WHEN ⌀ = 𝟑𝟔 𝐦𝐦
𝛾 = 7850 𝑘𝑔/𝑚3
⌀ = 36mm – 0.036m
𝐾
𝑠𝐿
𝛾=𝐴
𝐾
7850 𝑘𝑔/𝑚3 = 𝜋(0.036𝑚)2
4
(1𝑚)
K= 7.990 kg. per linear meter