Edexcel MECHANICS 1 VECTORS Main ideas Given that ππ¨ is the position vector of the particle A , and ππ© is the position vector of the particle B 1) Given ππ¨ = (1 i – 4j ) and ππ© = ( 5 i ) , Find the bearings of B from A. 2) Given ππ¨ = ( 3 i + 4 j) and ππ© =( 8 i -1j ), Find the bearings of B from A. 3) Given ππ¨ =( - 1 i + 5 j) and ππ© = ( - 1 i - 7j ), Find the bearings of B from A. 4) Given ππ¨ = ( - 1i + 2 j ) and ππ© = ( - 6 i+ - 3j ), Find the bearings of B from A. 5) Given ππ¨ = ( 6 i + 3j ) and ππ© = ( 1 i + 3 j ) , Find the bearings of B from A. T.Shehab.MathVillage@gmail.com PAGE. 1 Edexcel MECHANICS 1 VECTORS 6) Given ππ¨ = ( 5 i+ 4j ) , ππ© =(-11i + kj ) and B is on a bearing of πππ° from A. Find the value of π 7) ππ¨ =( 5 i + 4 j ) and 8) ππ¨ ( 5 i + 14 j ) and 9) ππ¨ = ( 5 i + 14j ) and ππ© = (11 i + k j ) given B is due east of A ππ© ( k i + 5 j ) given B is due south of A ππ© ( k i + 5 j ) given B 15 distance units from of A 10) ππ¨ = ( 2- k)i + (-10 + 6 k ) j and ππ© = ( -26+3k ) i + ( 4+4 k ) j given B and A overlap T.Shehab.MathVillage@gmail.com PAGE. 2 Edexcel MECHANICS 1 VECTORS EXAMPLES TO APPLY 11) At π = π , player P and a ball B started to move , π seconds later the player and the ball have the position vectors πβ and πβ respectively , where πβ = ππ −ππ + ππ π , and πβ = m ππ ππ Given that the player intercepts the ball at point P .Find a) Show that when π = 2 the ball is on a bearing of πππ° from the player b) The value of π when they meet c) The position vector ( the location ) of P T.Shehab.MathVillage@gmail.com PAGE. 3 Edexcel MECHANICS 1 VECTORS 12) the position vector of a moving ship S is given by πβ = ππ + π ππ ππ – π A lighthouse L is located at the point with position vector (18i + 6j) km. When t = T, the ship S is 10 km from L. Find the possible values of T. T.Shehab.MathVillage@gmail.com PAGE. 4 Edexcel MECHANICS 1 VECTORS 13) A particle P is moving and its position is given by πβ = point with position vector (–4i – 7j) m. Find π − ππ π + ππ m . At time t = 6 s, P is at the a) the value of π and the value of π b) the distance of P from the origin at time t = 2 s. T.Shehab.MathVillage@gmail.com PAGE. 5 Edexcel MECHANICS 1 VECTORS 14) At time t hours after noon, the position vector of S is πβ km. . πβ = ππ − πππ −π + π. ππ A fixed beacon B is at the point with position vector (7i + 12.5j) km. a) Find the moment when S is due north of B. (2) b) Find the distance of S from B when S is due north of B. (2) T.Shehab.MathVillage@gmail.com PAGE. 6 Edexcel MECHANICS 1 VECTORS 15) Two ships P and Q are travelling at night with constant velocities. At midnight, P is at the point with position vector (20i +10j) km relative to a fixed origin O. At the same time, Q is at the point with position vector (14i –6j) km. . At time t hours after midnight, the position vectors of P and Q are p km and q km respectively. Given that π = (πππ + πππ) + (ππ + ππ)π And π = (πππ – ππ) + πππ π At time t hours after midnight, the distance between P and Q is π km. (a) By finding an expression for π·πΈβ show that π π = ππππ – πππ + πππ. (b) Find the time when the two ships are 18 km apart (c) Fin the time when the two ships are closest to each other T.Shehab.MathVillage@gmail.com PAGE. 7 Edexcel MECHANICS 1 VECTORS Remember that 1) the direction of motion is direction of velocity 2) the resultant force is parallel to the acceleration 3) if two particle A and B are due EAST OR WEST of each other i) then they have the same y-component or ii) the vector AB connecting them has the y-component zero 4) if two particle A and B are due NORTH OR SOUTH of each other i) then they have the same X-component or ii) the vector AB connecting them has the X-component zero 5) If B is due north east of A then AB is parallel to ( i + j ) T.Shehab.MathVillage@gmail.com PAGE. 8