PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits LEARNING MODULE 02: Limits CALCULUS 1 – DIFERENTIAL CALCULUS Prepared by: AERO FACULTY 1|Page PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits TABLE OF CONTENTS Time allotment Title Introduction Limits Properties of limits Example on limits Activity 1 One-sided limits Limits at infinity Vertical asymptote Activity 2 Tangent line Derivatives Examples on derivatives Activity 3 Assignment Online quiz TOTAL 25 mins 20 mins 15 mins 40 mins 40 mins 20 mins 20 mins 20 mins 30 mins 90 mins 90 mins 30 mins 90 mins 107 mins 90 mins 707 mins Page 4 6 7 8 9 9 10 11 12 12 14 16 17 17 Na 2|Page PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits TABLE OF REFERENCES References No. Ron Larson and Bruce Edwards, 2018 Calculus 11e Ron Larson and David C. Falvo, 2009 Calculus An applied approach 8e James stewart, 2016 CALCULUS 8e John C. Sparks, 2005 Calculus without limits-Almost Elliot Mendelson, PhD., 1998 Schaum’s outline of calculus Ron Larson and Bruce Edwards, 2018 Calculus 11e 1 2 3 4 5 6 Table of figures Figure no. 1 2 3 4 5 6 7 8 9 Title Graph of a function Limits approaching on both sides Graph of x^3 – 1 / x - 1 Theorem of limits Limits approaching on 1 side Limits approaching to infinity Tangent line Secant lines to tangent line General graph on derivatives Sources Google graphs James stewart, 2016 CALCULUS 8e James stewart, 2016 CALCULUS 8e James stewart, 2016 CALCULUS 8e James stewart, 2016 CALCULUS 8e James stewart, 2016 CALCULUS 8e James stewart, 2016 CALCULUS 8e James stewart, 2016 CALCULUS 8e James stewart, 2016 CALCULUS 8e 3|Page PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits This Module aims the understanding of limits and a wider scope with Continuity and theorems LEARNING OUTCOMES Course Learning Outcomes [CLO] CLO 1 Analyze the function of continuity by applying limit theorem. CLO 4 Evaluate algebraic and/or transcendental functions by applying differentiation formulas. CLO 7 Formulate a systematic solution by determining the appropriate steps and strategies in solving a problem CLO 8 Exhibit analytical skills through the calculation of mathematical problems. CLO 10 Display a professional commitment to ethical practice through the submission of classwork, requirements, and activities CLO 11 Display acquired knowledge and skills by incorporating it into future aeronautical engineering duties. Module Learning Outcomes [MLO] Topic Learning Outcomes [TLO] MLO 1. Evaluate limits as it approach a continuity or infinity by applying strategies such as substitution, using TLO 3: Compute limits using tables, simplification and/or one sided substitution, properties and continuity. limits. TLO 4: Compute limits as a function approaches infinity using substitution MLO 2. Solve derivative of algebraic and other approach such one sided limits. functions through application of basic TLO 5: Compute the derivatives of differentiation rules. functions by using constant, power, product, and quotient rules. HONESTY CLAUSE “As members of the academic community, students are expected to recognize and uphold standards of intellectual and academic integrity. The state college assumes that as a basic and minimum standard of conduct in academic matters, the students should be honest and that they submit for credit the products only of their own efforts.” _______________________________ Student’s Signature over Printed Name 4|Page PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits INTRODUCTION: Over the past years, we somehow see equations like this , where What does it imply? As you can see, if we directly equate x as negative one, y will be equal to undefined (0/0). ( ( ) ) Can we just simplify the equation? The answer is no! Why? Simplifying the equation above gives you . The original and simplified equation might be the same but it differs at some point. Literally, it differs at a point. Shown below are the graphs of 2 equations. Figure 1 𝑦 𝑦 𝑥 𝑥 𝑥 Let me show you a solution that will prove my argument. Let’s say a=b ( )( ) ( ) 5|Page PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits ( )( ( ) ) ( ( ) ) Definitely, two will not be equal to one. Our mistake is that we divide the equation by ( ) which is equal to 0. Don’t get me wrong; even if you apply limits on this equation, it will never be right. Limits may exist or not, but in this case it doesn’t exist. By definition: If ( ) becomes arbitrarily close to a single number as side, the limit of ( ) as approaches is . we write approaches ( ) from either The concept of a limit plays a fundamental role in the development of calculus. In this lesson, we define limits and show how to evaluate them. We will also discuss properties of limits and look at different ways that a limit can fail to exist. PART 1 LIMITS LESSON: To sketch the graph of the function ( ) for values other than , you can use standard curve-sketching techniques. At , however, it is not clear what to expect. To get an idea of the behaviour of the graph of near , you can use two sets of x-values—one set that approaches 1 from the left and one set that approaches 1 from the right, as shown in the table. Figure 2 6|Page PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits Figure 3 The graph of is a parabola that has a hole at the point ( ), as shown in the Figure. Although cannot equal , you can move arbitrarily close to , and as a result ( ) moves arbitrarily close to . Using limit notation, you can write ( ) There are many ways to find a limit. The first is the table method, which is shown above, second is simplifying method and let me show it to you. From the above problem ( , we know that ( ( )( )( ) ) ) PROPERTIES OF LIMITS We learned that the limit of ( ) as approaches does not depend on the value of at . It may happen, however, that the limit is precisely ( ). In such cases, you can evaluate the limit by direct substitution. Let and be real numbers, and let be a positive integer. 1. 2. 3. 7|Page PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits Figure 4 IMPORTANT CONSIDERATIONS 1. Learn to recognize which limits can be evaluated by direct substitution 2. When the limit of f(x) as x approaches c cannot be evaluated by direct substitution, try to find a function g that agrees with f for all x other than x = c. [Choose g such that the limit of g(x) can be evaluated by direct substitution.] Then apply Theorems to conclude analytically that ( ) ( ) ( ) 3. Use a graph or table to reinforce your conclusion. EXAMPLE: 1. ( ) 2. ( ) 1.9 1.99 1.999 0.3448 0.3344 0.3334 √ 2 ? 2.001 2.01 2.1 0.3332 0.3322 0.3226 0 ? 0.001 0.01 0.1 0.2887 0.2884 0.2863 √ -0.1 -0.01 -0.001 0.2911 0.2889 0.2887 √ √ √ 3. ( ) 2.9 2.99 2.999 -0.0641 -0.0627 -0.0625 3 ? 3.001 3.01 3.1 -0.0625 -0.0623 -0.0610 8|Page PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits 4. ( ) -0.1 -0.01 0.9983 0.99998 -0.001 1.000 0 ? 0.001 1.000 0.01 1 0.99998 0.9983 *Use radian mode for all trigonometric functions 5. ( ) ( * ) ( ( ) )+ ( ) ( ) 6. ( ) ( ( ) ) ( ) ( ) ( ) ( ) ( ) ( ) ( ) Activity 1 Write it on a clean paper and answer the problems lengthwise. Please write your name on the top left corner and your course, year level, and the section below. Insert at the top center of the paper before the honesty clause. Copy the problem first before you show your solutions. Place the honesty clause and your signature at the beginning of your work. No erasures or alterations allowed. Box all your final answers. Submit your scanned work to the provided link in the google classroom. Solve the following Limits. (10 points each) 1. 2. 3. √ 4. 5. 9|Page PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits PART 2 CONTINUITY, ONE-SIDED LIMITS, AND LIMITS AT INFINITY LESSON: Let’s approach limits on only one side We write ( ) and say the left-hand limit of ( ) as approaches a [or the limit of ( ) as approaches a from the left] is equal to if we can make the values of ( ) arbitrarily close to by taking to be sufficiently close to a with less than . Notice that Definition of one sided limits differs from the definition of limits only in that we require to be less than a. Similarly, if we require that be greater than , we get “the right-hand limit of ( ) as x approaches a is equal to ” and we write ( ) Thus the notation means that we consider only greater than . Figure 5 LET’S APPROACH LIMITS TO INFINITY Let be a function defined on both sides of , except possibly at itself. Then ( ) means that the values of ( ) can be made arbitrarily large negative by taking sufficiently close to , but not equal to . Figure 6 10 | P a g e PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits The vertical line is called vertical asymptote of the curve one of the following statements is true: ( ) if at least DEFINITION OF VERTICAL ASYMPTOTE If ( ) approaches infinity (or negative infinity) as approaches from the right or the left, then the line is a vertical asymptote of the graph of . EXAMPLE 1. Find and If is close to but larger than , then the denominator is a small positive number and is close to . So the quotient is a large positive number. [For instance, if then .] Thus, intuitively, we see that Likewise, if is close to but smaller than , then but is still a positive number (close to ). So is a small negative number is a numerically large negative number. Thus The line is a vertical asymptote. 11 | P a g e PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits Activity 2 Write it on a clean paper and answer the problems lengthwise. Please write your name on the top left corner and your course, year level, and the section below. Insert at the top center of the paper before the honesty clause. Copy the problem first before you show your solutions. Place the honesty clause and your signature at the beginning of your work. No erasures or alterations allowed. Box all your final answers. Submit your scanned work to the provided link in the google classroom. Solve for the vertical asymptote of each functions. (10 points each) 1. ( ) 2. ( ) 3. ( ) 4. ( ) 5. ( ) ( ) Part 3 DERIVATIVES TANGENT LINE A secant line is a line that intersects a graph at two points, while the tangent line touches the graph at a single point. Here is an example of a secant line: Figure 7 To find the slope of a secant line, we must use the formula “change in y over change in x” or “rise over run”. ( ) ( ) 12 | P a g e PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits To find the tangent line at point P we let Q approach P along the curve C by letting x approach a. Figure 8 The tangent line to the curve P with slope ( ) at the point Psa, ( ( ) ( )) is the line through ( ) provided that this limit exists. Find a slope of the tangent line to the parabola ( ) ( ) ( )( ( at the point P(1,1). ) ) There is another expression for the slope of a tangent line that is sometimes easier to use. If , then and so the slope of the secant line PQ is ( ) ( ) Notice that as x approaches a, h approaches 0 (because ) and so the expression for the slope of the tangent line in Definition becomes ( ) ( ) 13 | P a g e PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits Figure 9 Find a slope of the tangent line to the parabola ( ) ( ) at the point P(1,1) using . ( ) ( ) ( ) ( ) ( ) ( ) DERIVATIVES The shortcut on finding the slope of tangent line is to find the derivative. Let’s study the basic derivatives. Derivatives can be denoted as ( ) . can be read as dy over dx or (first) derivative of y with respect to x ( ) can be read as f prime of x or (first) derivative of function of x can be read as y prime or (first) derivative of y 14 | P a g e PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits 1. ( ) 2. ( ) 3. ( ) 4. ( ) 5. ( 6. ( 7. ( ) ) ) What are these formulas? 1. The derivative of a constant is always zero 2. The derivative of any variable with respect to its variable is 1 3. The derivative of a constant multiplied by a variable has a constant not equal to zero. 4. Power rule which can be associated as chain rule 5. Sum of derivatives 6. Product rule 7. Quotient rule Apply power rule on finding the derivative of . Let; Then, *𝑥’ follows rule no. 2 From the above example ( ) As you can see, from finding the equation of sloe of tangent line using both method are the same. Therefore, finding the derivatives is finding the slope of tangent line. 15 | P a g e PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits EXAMPLES Derive the following functions 1. 2. ( ) 1. ( ) ( ( ) ) ( ( ) ) ( ) ( ) 2. ( ) ( ) [ ( ) ( ( )* ( ) ( )+ )( ) ] ( ( ) ( )* ( ) )( ) ( )+ ) ) ( ( ) ( ) ( ) ( ( ) ) ( ( ( ) ) 16 | P a g e PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits Activity 3 Write it on a clean paper and answer the problems lengthwise. Please write your name on the top left corner and your course, year level, and the section below. Insert at the top center of the paper before the honesty clause. Copy the problem first before you show your solutions. Place the honesty clause and your signature at the beginning of your work. No erasures or alterations allowed. Box all your final answers. Submit your scanned work to the provided link in the google classroom. Solve for the Derivative of each functions. (10 points each) 1. 2. 3. 4. ( ( ( ( ) ) ) ) 5. ( ) 6. 7. 8. ( ) ( ) ( ) 9. ( ) 10. ( ) √ √ ( ( ) ) )( Assignment Write it on a clean paper and answer the problems lengthwise. Please write your name on the top left corner and your course, year level, and the section below. Insert “Midterm Assignment” at the top center of the paper before the honesty clause. Copy the problem first before you show your solutions. Place the honesty clause and your signature at the beginning of your work. No erasures or alterations allowed. Box all your final answers. Submit your scanned work to the provided link in the google classroom. Solve the following differentiation problems covered in the Midterm Modules. A. Solve the following limits a. b. √ c. d. e. B. Solve for the vertical Asymptote of each functions a. ( ) b. ( ) c. ( ) 17 | P a g e PHILIPPINE STATE COLLEGE OF AERONAUTICS INSTITUTE OF ENGINEERING AND TECHNOLOGY AERONAUTICAL ENGINEERING DEPARTMENT Learning Module 02: Limits d. ( ) e. ( ) C. Solve for the derivative of each functions 1. ( ) 2. ( ) 3. ( ) 4. ( ) 5. ( ) 6. ( ) 7. ( ) 8. ( ) √ √ ( ) 9. ( ) 10. ( ) ( ) )( ( ) 18 | P a g e